I have an XML file that contains multiple URLs for different image file sizes, and I'm trying to get a single url to load into a picture box. My issue is that the child nodes are named similarly, and the parent nodes are named similarly as well. For example, I want to pull the first medium image (ending in SL160_.jpg). See below for XML code
<Items>
<SmallImage>
<URL>http://ecx.images-amazon.com/images/I/51TAL%2Bn7AqL._SL75_.jpg</URL>
</SmallImage>
<MediumImage>
<URL>http://ecx.images-amazon.com/images/I/51TAL%2Bn7AqL._SL160_.jpg</URL>
</MediumImage>
<LargeImage>
<URL>http://ecx.images-amazon.com/images/I/51TAL%2Bn7AqL.jpg</URL>
</LargeImage>
<MediumImage>
<URL>http://ecx.images-amazon.com/images/I/51TAL%2Bn7AqL._SL162_.jpg</URL>
</MediumImage>
<LargeImage>
<URL>http://ecx.images-amazon.com/images/I/51TAL%2Bn7AqL.jpg</URL>
</LargeImage>
</Items>
I've tried using GetElementsByTag, as well as trying to call something like doc.SelectSingleNode("LargeImage").SelectSingleNode("URL").InnerText, and GetElementByID. All of these have given me an Object set to null reference exception.
What can I do to specify that I want the url from the first found MediumImage node?
Use LinqToXMLïĵIt is rather simple
string xml = #"<Items>
<SmallImage>
<URL>http://ecx.images-amazon.com/images/I/51TAL%2Bn7AqL._SL75_.jpg</URL>
</SmallImage>
<MediumImage>
<URL>http://ecx.images-amazon.com/images/I/51TAL%2Bn7AqL.01_SL160_.jpg</URL>
</MediumImage>
<LargeImage>
<URL>http://ecx.images-amazon.com/images/I/51TAL%2Bn7AqL.jpg</URL>
</LargeImage>
<MediumImage>
<URL>http://ecx.images-amazon.com/images/I/51TAL%2Bn7AqL.02_SL162_.jpg</URL>
</MediumImage>
<LargeImage>
<URL>http://ecx.images-amazon.com/images/I/51TAL%2Bn7AqL.jpg</URL>
</LargeImage>
</Items>";
XElement root = XElement.Parse(xml);
var ele = root.Elements("MediumImage").Where(e => e.Element("URL").Value.EndsWith("SL160_.jpg")).FirstOrDefault();
Console.WriteLine(ele);
In addition to Sky Fang's answer, I think the OP wants this:
var firstMedImg = root.Elements("MediumImage").First();
var imgUrl = firstMedImg.Element("URL").Value;
XmlDocument doc = new XmlDocument();
// PATH TO YOUR DOCUMENT
doc.Load("daco.xml");
// Select LIST ALL ELEMENTS SmallImage,MediumImage,LargeImage
XmlNodeList listOfAllImageElements = doc.SelectNodes("/Items/*");
foreach (XmlNode imageElement in listOfAllImageElements)
{
// Select URL ELEMENT
XmlNode urlElement= node.SelectSingleNode("URL");
System.Console.WriteLine(urlElement.InnerText);
}
Console.ReadLine();
If you want to select multiple url's
XmlDocument doc = new XmlDocument();
// PATH TO YOUR DOCUMENT
doc.Load("daco.xml");
// Select LIST ALL ELEMENTS SmallImage,MediumImage,LargeImage
XmlNodeList listOfAllImageElements = doc.SelectNodes("/Items/*");
foreach (XmlNode imageElement in listOfAllImageElements)
{
// Select URL's ELEMENTs
XmlNodeList listOfAllUrlElements = imageElement.SelectNodes("URL");
foreach (XmlNode urlElement in listOfAllUrlElements)
{
System.Console.WriteLine(urlElement.InnerText);
}
}
Console.ReadLine();
if you have specific namespace in your xml file
XmlDocument doc = new XmlDocument();
doc.Load("doc.xml");
XmlNamespaceManager man = new XmlNamespaceManager(doc.NameTable);
// reaplace http://schemas.microsoft.com/vs/2009/dgml with your namespace
man.AddNamespace("x", "http://schemas.microsoft.com/vs/2009/dgml");
// next you have to use x: in your path like this
XmlNodeList node = doc.SelectNodes("/x:Items/x:*, man);
Related
I have this XML:
<Feedback>
<Officer>Officer</Officer>
<Answers>My text</Answers>
<Date>20190917</Date>
</Feedback>
I want XML to look like this: (Lowercase first letter in main tag)
<feedback>
<Officer>Officer</Officer>
<Answers>My text</Answers>
<Date>20190917</Date>
</feedback>
How to do it using XMLDocument? I can't access this item
If using XmlDocument is not a hard requirement you can do it with linq fairly easily.
You can create a new XML document with the root node named how you want it then loop through the child nodes of the original and add them to your new XML object.
A simple example:
XDocument xDocument = XDocument.Parse("<Feedback><Officer>Officer</Officer><Answers>My text</Answers><Date>20190917</Date></Feedback>");
XDocument newDoc = new XDocument();
XElement rootElement = new XElement("feedback");
newDoc.Add(rootElement);
foreach (var node in xDocument.Root.Elements())
{
newDoc.Root.Add(node);
}
Console.WriteLine(newDoc);
Console.ReadLine();
However here is an example using XmlDocument if you really need to use that:
XmlDocument oldDoc = new XmlDocument();
XmlDocument newXmlDoc = new XmlDocument();
oldDoc.LoadXml("<Feedback><Officer>Officer</Officer><Answers>My text</Answers><Date>20190917</Date></Feedback>");
XmlElement newRoot = newXmlDoc.CreateElement("feedback");
newXmlDoc.AppendChild(newRoot);
XmlNode root = newXmlDoc.DocumentElement;
foreach (XmlNode node in oldDoc.FirstChild.ChildNodes)
{
XmlElement elem = newXmlDoc.CreateElement(node.Name);
elem.InnerText = node.InnerText;
//Add the node to the document.
root.AppendChild(elem);
}
XmlTextWriter writer = new XmlTextWriter(Console.Out);
writer.Formatting = Formatting.Indented;
newXmlDoc.WriteTo(writer);
writer.Flush();
Console.WriteLine();
Console.ReadLine();
In this case, you can change the name directly:
var XML = ""; // Your XML in string
var tempDoc = new XmlDocument();
tempDoc.LoadXml(XML);
tempDoc.InnerXml = tempDoc.InnerXml.Replace("Feedback>", "feedback>");
XML = tempDoc.OuterXml;
This is a simple way to change the name
Do not use in other situations because various errors may arise, e.g another element may end in the same name
I'm getting data from a web service in my phone application and get the response to xmldocument like below.
XmlDocument XmlDoc = new XmlDocument();
XmlDoc.LoadXml(newx2);
Ther result of XmlDoc is like below.now I want to get the values from this.
<root>
<itinerary>
<FareIndex>0</FareIndex>
<AdultBaseFare>4719</AdultBaseFare>
<AdultTax>566.1</AdultTax>
<ChildBaseFare>0</ChildBaseFare>
<ChildTax>0</ChildTax>
<InfantBaseFare>0</InfantBaseFare>
<InfantTax>0</InfantTax>
<Adult>1</Adult>
<Child>0</Child>
<Infant>0</Infant>
<TotalFare>5285.1</TotalFare>
<Airline>AI</Airline>
<AirlineName>Air India</AirlineName>
<FliCount>4</FliCount>
<Seats>9</Seats>
<MajorCabin>Y</MajorCabin>
<InfoVia>P</InfoVia>
<sectors xmlns:json="http://james.newtonking.com/projects/json">
</itinerary>
</root>
I tried with this.
XmlNodeList xnList = XmlDoc.SelectNodes("/root[#*]");
but it gives null result. the count is 0. how can I read the data from this.hope your help with this.thanx.
You can use System.Xml.Linq.XElement to parse an xml:
XElement xRoot = XElement.Parse(xmlText);
XElement xItinerary = xRoot.Elements().First();
// or xItinerary = xRoot.Element("itinerary");
foreach (XElement node in xItinerary.Elements())
{
// Read node here: node.Name, node.Value and node.Attributes()
}
If you want to use XmlDocument you can do like this:
XmlDocument xmlDoc = new XmlDocument();
xmlDoc.LoadXml(xmlText);
XmlNode itinerary = xmlDoc.FirstChild;
foreach (XmlNode node in itinerary.ChildNodes)
{
string name = node.Name;
string value = node.Value;
// you can also read node.Attributes
}
You can get the value of a particular element like,
var fareIndex = XmlDoc.SelectSingleNode("/root/itinerary/FareIndex").InnerText;
If you want to get the list of all elements that come under root/itinerary -
XmlNodeList xnList = XmlDoc.SelectNodes("/root/itinerary/*");
This link might help you.
I have a XML file which contains about 850 XML nodes. Like this:
<NameValueItem>
<Text>Test</Text>
<Code>Test</Code>
</NameValueItem>
........ 849 more
And I want to add a new Childnode inside each and every Node. So I end up like this:
<NameValueItem>
<Text>Test</Text>
<Code>Test</Code>
<Description>TestDescription</Description>
</NameValueItem>
........ 849 more
I've tried the following:
XmlDocument doc = new XmlDocument();
doc.Load(xmlPath);
XmlNodeList nodes = doc.GetElementsByTagName("NameValueItem");
Which gives me all of the nodes, but from here am stuck(guess I need to iterate over all of the nodes and append to each and every) Any examples?
You need something along the lines of this example below. On each of your nodes, you need to create a new element to add to it. I assume you will be getting different values for the InnerText property, but I just used your example.
foreach (var rootNode in nodes)
{
XmlElement element = doc.CreateElement("Description");
element.InnerText = "TestDescription";
root.AppendChild(element);
}
You should just be able to use a foreach loop over your XmlNodeList and insert the node into each XmlNode:
foreach(XmlNode node in nodes)
{
node.AppendChild(new XmlNode()
{
Name = "Description",
Value = [value to insert]
});
}
This can also be done with XDocument using LINQ to XML as such:
XDocument doc = XDocument.Load(xmlDoc);
var updated = doc.Elements("NameValueItem").Select(n => n.Add(new XElement() { Name = "Description", Value = [newvalue]}));
doc.ReplaceWith(updated);
If you don't want to parse XML using proper classes (i.e. XDocument), you can use Regex to find a place to insert your tag and insert it:
string s = #"<NameValueItem>
<Text>Test</Text>
<Code>Test</Code>
</NameValueItem>";
string newTag = "<Description>TestDescription</Description>";
string result = Regex.Replace(s, #"(?<=</Code>)", Environment.NewLine + newTag);
but the best solution is Linq2XML (it's much better, than simple XmlDocument, that is deprecated at now).
string s = #"<root>
<NameValueItem>
<Text>Test</Text>
<Code>Test</Code>
</NameValueItem>
<NameValueItem>
<Text>Test2</Text>
<Code>Test2</Code>
</NameValueItem>
</root>";
var doc = XDocument.Load(new StringReader(s));
var elms = doc.Descendants("NameValueItem");
foreach (var element in elms)
{
element.Add(new XElement("Description", "TestDescription"));
}
var text = new StringWriter();
doc.Save(text);
Console.WriteLine(text);
<Report xmlns="Microsoft.SystemCenter.DataWarehouse.Report.Alert" xmlns:p1="w3.org/2001/XMLSchema-instance"; Name="Microsoft.SystemCenter.DataWarehouse.Report.Alert" p1:schemaLocation="Microsoft.SystemCenter.DataWarehou?Schema=True">
<Title>Alert Report</Title>
<Created>6/27/2013 9:32 PM</Created>
<StartDate>6/1/2013 9:29 PM</StartDate>
<EndDate>6/27/2013 9:29 PM</EndDate>
<TimeZone>(UTC)</TimeZone>
<Severity>Warning, Critical</Severity>
<Priority>Low, Medium, High</Priority>
<AlertTable>
<Alerts>
<Alert>
<AlertName></AlertName>
<Priority></Priority>
</Alert>
</Alerts>
</AlertTable>
</Report>
So I'm trying to pull down the list of nodes that appear under Alerts child. So /Report/AlertTable/Alerts.
I've done very similar before but in this format it is not working for some reason. Can someone point me out in the right direction?
XmlDocument Log = new XmlDocument();
Log.Load("test.xml");
XmlNodeList myLog = Log.DocumentElement.SelectNodes("//Report/AlertTable/Alerts");
foreach (XmlNode alert in myLog)
{
Console.Write("HERE");
Console.WriteLine(alert.SelectNodes("AlertName").ToString());
Console.WriteLine(alert.SelectNodes("Priority").ToString());
Console.Read();
}
EDIT:
One of the responses had me try to use a bunch of namespace with p1 but had no such luck.
EDIT:
Did not work either:
var name = new XmlNamespaceManager(log.NameTable);
name.AddNamespace("Report", "http://www.w3.org/2001/XMLSchema-instance");
XmlNodeList xml = log.SelectNodes("//Report:Alerts", name);
From a site:
nodename Selects all nodes with the name "nodename"
/ Selects from the root node
// Selects nodes in the document from the current node that match the selection no matter where they are
So I believe
"/AlertTable/Alerts"
would work, as that would be 'from the root node' as well as
"Report/AlertTable/Alerts"
XPath Site
Figured this sucker out.
It had to do with the namespace of "Microsoft.SystemCenter.DataWarehouse.Report.Alert". Changing this to anything but that won't read the XML properly.
XmlDocument log = new XmlDocument();
log.Load(#"C:\Users\barranca\Desktop\test.xml");
// XmlNodeList xml = log.SelectNodes("//ns1:Alerts");
var name = new XmlNamespaceManager(log.NameTable);
name.AddNamespace("ns1", "Microsoft.SystemCenter.DataWarehouse.Report.Alert");
XmlNodeList xml = log.SelectNodes("//ns1:Alert", name);
foreach (XmlNode alert in xml)
{
Console.Write("HERE");
XmlNode test = alert.SelectSingleNode("//ns1:AlertName",name);
string testing = test.InnerText;
Console.Write(testing);
}
I have an XML File like below
<Attachment>
<FileName>Perimeter SRS.docx</FileName>
<FileSize>15572</FileSize>
<ActivityName>ActivityNamePerimeter SRS.docx</ActivityName>
<UserAlias>JameelM</UserAlias>
<DocumentTransferId>7123eb83-d768-4a58-be46-0dfaf1297b97</DocumentTransferId>
<EngagementName>EAuditEngagementNameNew</EngagementName>
<Sender>JameelM#orioninc.com</Sender>
</Attachment>
I read these xml file like below
var doc = new XmlDocument();
doc.Load(files);
foreach (XmlElement pointCoord in doc.SelectNodes("/Attachment"))
{
}
I need to get each child node value inside the Attachment node. How can i get these xml elements from the xml node list?
I need to get each child node value inside the Attachment node.
Your question is very unclear, but it looks like it's as simple as:
foreach (XmlNode node in doc.DocumentElement.ChildNodes)
{
}
After all, in the document you've shown us, the Attachment is the document element. No XPath is required.
As an aside, if you're using .NET 3.5 or higher, LINQ to XML is a much nicer XML API than the old DOM (XmlDocument etc) API.
try this
var data = from item in doc.Descendants("Attachment")
select new
{
FileName= item.Element("FileName").Value,
FileSize= item.Element("FileSize").Value,
Sender= item.Element("Sender").Value
};
foreach (var p in data)
Console.WriteLine(p.ToString());
var doc = new XmlDocument();
doc.Load(files);
foreach (XmlElement pointCoord in doc.SelectNodes("/Attachment"))
{
if(pointCoord!=null)
{
var valueOfElement=pointCoord.InnerText;
}
}
if you want to run conditional logic against the element names (UserAlias, etc) then use the Name property of the XmlElement.