Develop Reference

Http post request to send form data in image format

Hi I have below code to send the data, but in return I get server error with error code 500, the file is
not getting sent through the request
Can anyone tell me what I am doing wrong
FileStream rdr = new FileStream("C:/Users/AR485UY/Desktop/Test1.pdf", FileMode.Open)
HttpWebRequest req = (HttpWebRequest)WebRequest.Create("url" );
string boundary = "----------------------------" + DateTime.Now.Ticks.ToString("x");
req.Method = "POST";
req.ContentLength = rdr.Length;
req.ContentType = "multipart/form-data; boundary=" +boundary;
req.AllowWriteStreamBuffering = true;
Stream reqStream = req.GetRequestStream();
byte[] inData = new byte[rdr.Length];
int len = Convert.ToInt32(rdr.Length);
int bytesRead = rdr.Read(inData, 0, len);
reqStream.Write(inData, 0, len);
rdr.Close();
req.GetResponse();
reqStream.Close();

HTTP 500 Internal Server Error server error response code indicates that the server encountered an unexpected condition that prevented it from fulfilling the request.
if it never work :
Most likely have to validate your server side api,script,logs,events,diagnostics trace,file size limits.
Also try another approach in c#:
try
{
using(WebClient client = new WebClient())
{
string myFile = #"C:/Users/AR485UY/Desktop/Test1.pdf";
client.Credentials = CredentialCache.DefaultCredentials;
client.UploadFile(url, "POST", myFile);
}
}
catch (Exception err)
{
MessageBox.Show(err.Message);
}

C# python http post to C# httpwebrequest

i try to figure it out the black box of the server side that code by python for sending http post. In C# i trying to use httpwebrequest and httpwebresponse to send and receive message back from the server side.
Below is the python code:
**# Request login to server**
import httplib, urllib, requests
import sys, time
from requests.adapters import HTTPAdapter
import select, socket
s = requests.Session()
url = 'http://192.168.1.1/request_login'
data = 'user.login(test,test)' #login account and password set here
r = s.post(url, data=data)
if r.status_code != 200:
print "Failed loging in (%d)" % (r.status_code)
sys.exit(-1)
**# send key file to server**
url = 'http://192.168.1.1/request_sendfile'
files = {'file': (data_xml, open(data_xml, 'rb'), 'application/x-binary', {'Expires': '0'})} # **Don't understand this format**
r = s.post(url, files=files, timeout=30.0)
if r.status_code != 200:
print "Failed sending data file (%d, %s)" % (r.status_code, r.reason)
url = 'http://192.168.1.1/request_sendfile'
data = 'reader.view_log(4)'
r = s.post(url, data=data)
if r.status_code != 200:
print "Failed loging in (%d)" % (r.status_code)
sys.exit(-3)
print "Logs: "
print r.content
sys.exit(-4)
Above is the code for login and sending file to server in one session, i try to use C# do the same way.
I set two http request at the same time, however for the login is success while try to get second http request i get an error of "400" doesn't understand context of verb.
Below is the C# code:
private void httpost()
{
try
{
string Url = "http://192.168.1.1/request_login";
string Urls = "http://192.168.1.1/request_sendfile";
HttpWebRequest request = HttpWebRequest.Create(Url) as HttpWebRequest;
HttpWebRequest requests = HttpWebRequest.Create(Urls) as HttpWebRequest;
string result = null;
request.Method = "POST";
request.KeepAlive = true;
request.ContentType = "login";
string param = "user.login(test,test)";
byte[] bs = Encoding.ASCII.GetBytes(param);
using (Stream reqStream = request.GetRequestStream())
{
reqStream.Write(bs, 0, bs.Length);
}
using (WebResponse response = request.GetResponse())
{
StreamReader sr = new StreamReader(response.GetResponseStream());
HttpWebResponse resp = (HttpWebResponse)request.GetResponse();
if(resp.StatusCode == HttpStatusCode.OK)
{
richTextBox1.AppendText("Login Response Status:" + resp.StatusCode + "\n");
}
else
{
richTextBox1.AppendText("Login Response Failed: " + resp.StatusCode + "\n");
}
request.KeepAlive = true;
result = sr.ReadToEnd();
sr.Close();
}
using (Stream importFile = requests.GetRequestStream())
{
FileStream fs = File.OpenRead(#"data.xml");
byte[] bytes = ReadWholeArray(fs); // turn xml file to byte function
requests.ContentType = "application/x-binary";
requests.Method = "POST";
importFile.Write(bytes, 0, bytes.Length);
}
using (WebResponse responses = requests.GetResponse())
{
StreamReader srs = new StreamReader(responses.GetResponseStream());
result = srs.ReadToEnd();
srs.Close();
}
}
catch (Exception ex)
{
richTextBox1.AppendText("Exception Throw:" + ex.Message);
}
}
I try the python code it request login and send file at the same time.
And below is the code that i don't understand.
files = {'file': (data_xml, open(data_xml, 'rb'), 'application/x-binary', {'Expires': '0'})}

HttpWebResponse not responding from PHP

So I have this code in C#.
private void SendMessage()
{
// this is what we are sending
string post_data = "loginIdPost=" + 2 + "&" + "contentPost=" + absenceInputField.text;
string uri = "<URI IS HERE>";
HttpWebRequest request = (HttpWebRequest)
WebRequest.Create(uri); request.KeepAlive = false;
request.ProtocolVersion = HttpVersion.Version10;
request.Method = "POST";
byte[] postBytes = Encoding.ASCII.GetBytes(post_data);
request.ContentType = "application/x-www-form-urlencoded";
request.ContentLength = postBytes.Length;
Stream requestStream = request.GetRequestStream();
requestStream.Write(postBytes, 0, postBytes.Length);
requestStream.Close();
HttpWebResponse response = (HttpWebResponse)request.GetResponse();
Console.WriteLine(new StreamReader(response.GetResponseStream()).ReadToEnd());
Debug.Log(new StreamReader(response.GetResponseStream()).ReadToEnd());
Debug.Log(response.StatusCode);
Console.WriteLine(response.StatusCode);
}
It sends some information to a PHP file, which then puts data into my database. The data is being successfully sent, but the HttpWebResponse is coming back blank. It returns "", an empty string.
This is my PHP code.
<?php
//Id
if (isset($_POST["loginIdPost"]))
{
$loginId = $_POST["loginIdPost"];
}
else
{
$loginId = null;
}
//Content
if (isset($_POST["contentPost"]))
{
$content = $_POST["contentPost"];
}
else
{
$content = null;
}
try
{
$conn = new PDO("Connection String");
$conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
}
catch (PDOException $e)
{
print("Error connecting to SQL Server.");
die(print_r($e));
}
$sth = $conn->prepare('Sql Query is here');
$sth->execute('details of execution are here');
echo "Success";
//Check Connection
if(!$conn)
{
die("Connection Failed. ". mysqli_connect_error());
}
?>
Does anyone know why I'm getting an empty string back, when I'd expect to be getting "Success" back. Again, no errors in the php code as the SQL query does insert data into my database.

I managed to fix it by just removing Console.Writeline.

Parsing POST request data with FiddlerCore

I'm tring to capture a local POST requset and parse its data.
For testing only, the FiddlerCore should only response with the data it has parsed.
Here's the code of the FidlerCore encapsulation:
private void FiddlerApplication_BeforeRequest(Session oSession)
{
if (oSession.hostname != "localhost") return;
eventLog.WriteEntry("Handling local request...");
oSession.bBufferResponse = true;
oSession.utilCreateResponseAndBypassServer();
oSession.oResponse.headers.HTTPResponseStatus = "200 Ok";
oSession.oResponse["Content-Type"] = "text/html; charset=UTF-8";
oSession.oResponse["Cache-Control"] = "private, max-age=0";
string body = oSession.GetRequestBodyAsString();
oSession.utilSetResponseBody(body);
}
Here's the code of the request sender:
const string postData = "This is a test that posts this string to a Web server.";
try
{
WebRequest request = WebRequest.Create("http://localhost/?action=print");
byte[] byteArray = Encoding.UTF8.GetBytes(postData);
request.ContentLength = byteArray.Length;
request.ContentType = "text/html";
request.Method = "POST";
using (Stream stream = request.GetRequestStream())
{
stream.Write(byteArray, 0, byteArray.Length);
}
using (WebResponse response = request.GetResponse())
{
txtResponse.Text = ((HttpWebResponse)response).StatusDescription;
using (Stream stream = response.GetResponseStream())
{
using (StreamReader streamReader = new StreamReader(stream))
{
string responseFromServer = streamReader.ReadToEnd();
streamReader.Close();
txtResponse.Text = responseFromServer;
}
}
}
}
catch (Exception ex)
{
txtResponse.Text = ex.Message;
}
I'm getting the following error:
The server committed a protocol violation. Section=ResponseStatusLine
What am I doing wrong?

Got it to work by changing:
WebRequest request = WebRequest.Create("http://localhost/?action=print");
to
WebRequest request = WebRequest.Create("http://localhost:8877/?action=print");
Calling this URL from a browser is intercepted by FiddlerCore correctly, without having to specify the port number. I did not think I should have inserted the listening port, since FiddlerCore should intercept all traffic, right?

How do I copy a HttpRequest to another web service?

I have two identical web services currently installed on the same PC for testing purposes. A request that is received by the first service, is suposed go to the second one as well. My intention was to do this using a HttpModule. I handle the request during application.BeginRequest.
public void AsyncForwardRequest(HttpRequest request)
{
try
{
// Prepare web request...
HttpWebRequest req = (HttpWebRequest)WebRequest.Create(WSaddress);
req.Credentials = CredentialCache.DefaultCredentials;
req.Headers.Add("SOAPAction", request.Headers["SOAPAction"]);
req.ContentType = request.Headers["Content-Type"];
req.Accept = request.Headers["Accept"];
req.Method = request.HttpMethod;
// Send the data.
long posStream = request.InputStream.Position;
long len = request.InputStream.Length;
byte[] buff = new byte[len];
request.InputStream.Seek(0, SeekOrigin.Begin);
if (len < int.MaxValue && request.InputStream.Read(buff, 0, (int)len) > 0)
{
using (Stream stm = req.GetRequestStream())
{
stm.Write(buff, 0, (int)len);
}
request.InputStream.Position = posStream;
DebugOutputStream(request.InputStream);
request.InputStream.Seek(0, SeekOrigin.Begin);
IAsyncResult result = (IAsyncResult)req.BeginGetResponse(new AsyncCallback(RespCallback), req);
}
}
catch (Exception ex)
{
App.Error2(String.Format("RequestDuplicatorModule - BeginRequest; ERROR begin request: {0}", ex.Message), ex);
}
private static void RespCallback(IAsyncResult asynchronousResult)
{
try
{
// State of request is asynchronous.
var req = (HttpWebRequest)asynchronousResult.AsyncState;
WebResponse resp = (HttpWebResponse)req.EndGetResponse(asynchronousResult);
Stream responseStream = resp.GetResponseStream();
System.IO.Stream stream = responseStream;
Byte[] arr = new Byte[1024 * 100];
stream.Read(arr, 0, 1024 * 100);
if (arr.Length > 0)
{
string body = (new ASCIIEncoding()).GetString(arr);
Debug.Print(body);
}
}
catch (WebException ex)
{
App.Error2(String.Format("RequestDuplicatorModule - BeginRequest; ERROR begin request: {0}", ex.Message), ex);
}
}
This (HttpWebResponse)req.EndGetResponse(asynchronousResult) throws an exception: 500 Internal Server Error and fails. The original request goes through fine.
request.InnerStream:
...
Does this have anything to do with the web service addresses being different? In my case they're:
http://localhost/WS/service.asmx
http://localhost/WS_replicate/service.asmx

I would at least implement this, to be able to read the content of a httpwebrequest that has a status 500:
catch (WebException ex)
{
HttpWebResponse webResponse = (HttpWebResponse)ex.Response;
Stream dataStream = webResponse.GetResponseStream();
if (dataStream != null)
{
StreamReader reader = new StreamReader(dataStream);
response = reader.ReadToEnd();
}
}
Not answering your question though, i would suggest having a simple amsx that reads the request, and posts the request to the two different web services. If you need some code for that let me know.
Additional advantages would be that the asmx will be easier to support for the developer as well as the one dealing with the deployment. You could add configuration options to make the actual url's dynamic.

Was able to modify the AsyncForwardRequest method so that I can actually edit the SoapEnvelope itself:
string buffString = System.Text.UTF8Encoding.UTF8.GetString(buff);
using (Stream stm = req.GetRequestStream())
{
bool stmIsReadable = stm.CanRead; //false, stream is not readable, how to get
//around this?
//solution: read Byte Array into a String,
//modify <wsa:to>, write String back into a
//Buffer, write Buffer to Stream
buffString = buffString.Replace("http://localhost/WS/Service.asmx", WSaddress);
//write modded string to buff
buff = System.Text.UTF8Encoding.UTF8.GetBytes(buffString);
stm.Write(buff, 0, (int)buff.Length);
}