How to manually convert Hexadecimal to Decimal in C#?

How to manually convert Hexadecimal to Decimal in C#? - c#

So we were asked to convert a Hexadecimal Value (stored in a String) to its Decimal Value. Each character in the String should be manually converted to decimal within a loop, and then post the total Decimal Value of the Hexadecimal Value. I got here the codes that I have written but I couldn't identify where I could have gone wrong for an "F4" Hexa (as an example) to have a Decimal Equivalent of "292" instead of "244". I have debugged everything, the code seems fine. Any ideas?
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
namespace AdvProgCS
{
class Program
{
static int dec=0;
static string hex;
static void Main(string[] args)
{
do{
Console.Write("[Press 0 to Stop] Hexadecimal Value: ");
hex = Console.ReadLine();
if (hex == "0") break;
int length = hex.Length;
for (int i = 0; i < length+1; i++)
{
if (hex[i] == 'A' || hex[i] == 'B' || hex[i] == 'C' || hex[i] == 'D' || hex[i] == 'E' || hex[i] == 'F')
{
if (hex[i] == 'A')
dec+= 10 * Convert.ToInt32(Math.Pow(16, length - 1));
if (hex[i] == 'B')
dec += 11 * Convert.ToInt32(Math.Pow(16, length - 1));
if (hex[i] == 'C')
dec += 12 * Convert.ToInt32(Math.Pow(16, length - 1));
if (hex[i] == 'D')
dec += 13 * Convert.ToInt32(Math.Pow(16, length - 1));
if (hex[i] == 'E')
dec += 14 * Convert.ToInt32(Math.Pow(16, length - 1));
if (hex[i] == 'F')
dec += 15 * (Convert.ToInt32(Math.Pow(16, length - 1)));
}
else
dec += hex[i];
length--;
}
Console.WriteLine("DECIMAL EQUIVALENT: " + dec + "\n");
}
while(hex != "0");
}
}
}

You forgot about the Math.Pow in the dec += hex[i] line where you also have to convert hex[i] from char into a number.
dec += (int)char.GetNumericValue(hex[i]) * (int)Math.Pow(16, length - 1);
Moreover, as observed by Partha:
Also add dec = 0; after your print statement. I think the dec values
are getting adding to itself for each iteration.

Personally, my brain likes it better like this:
static void Main(string[] args)
{
int dec;
string hex;
int decValue;
string hexReversed;
string hexValues = "0123456789ABCDEF";
do
{
Console.Write("[Press 0 to Stop] Hexadecimal Value: ");
hex = Console.ReadLine().ToUpper().Trim();
if (hex != "0")
{
dec = 0;
hexReversed = new String(hex.Reverse().ToArray());
for (int i = 0; i < hexReversed.Length; i++)
{
decValue = hexValues.IndexOf(hexReversed.Substring(i, 1));
if (decValue != -1)
{
dec = dec + (decValue * (int)Math.Pow(16, i));
}
else
{
Console.WriteLine("Invalid Hexadecimal Value!");
break;
}
}
if (dec != 0)
{
Console.WriteLine(String.Format("{0} hex = {1} dec", hex, dec.ToString()));
}
}
} while (hex != "0");
}

Here is my hex to decimal function, much smaller but it doesnt check if the input is a hex value or not.
private int hex2Decimal(string hex)
{
string hexV = "0123456789ABCDEF"; // For the hex values (ex: F=15)
hex = hex.ToUpper().Replace("0X", ""); // Get good string format
int res;
char[] cArr = hex.ToCharArray();
Array.Reverse(cArr); // Reverse hex string
List<int> iArr = new List<int>();
for (int i = hex.Length - 1; i > -1; i--) // Get the bits
iArr.Add(hexV.IndexOf(cArr[i]) * (int)Math.Pow(16, i)); // Calculate each bits and add to an array
res = iArr.ToArray().Sum(); // Calculate all the numbers and add to the final result
return res;
}

Related

How to convert a string of bits to a HEX [duplicate]

I'm looking for a way to convert a long string of binary to a hex string.
the binary string looks something like this "0110011010010111001001110101011100110100001101101000011001010110001101101011"
I've tried using
hex = String.Format("{0:X2}", Convert.ToUInt64(hex, 2));
but that only works if the binary string fits into a Uint64 which if the string is long enough it won't.
is there another way to convert a string of binary into hex?
Thanks

I just knocked this up. Maybe you can use as a starting point...
public static string BinaryStringToHexString(string binary)
{
if (string.IsNullOrEmpty(binary))
return binary;
StringBuilder result = new StringBuilder(binary.Length / 8 + 1);
// TODO: check all 1's or 0's... throw otherwise
int mod4Len = binary.Length % 8;
if (mod4Len != 0)
{
// pad to length multiple of 8
binary = binary.PadLeft(((binary.Length / 8) + 1) * 8, '0');
}
for (int i = 0; i < binary.Length; i += 8)
{
string eightBits = binary.Substring(i, 8);
result.AppendFormat("{0:X2}", Convert.ToByte(eightBits, 2));
}
return result.ToString();
}

This might help you:
string HexConverted(string strBinary)
{
string strHex = Convert.ToInt32(strBinary,2).ToString("X");
return strHex;
}

Convert.ToInt32("1011", 2).ToString("X");
For string longer than this, you can simply break it into multiple bytes:
var binary = "0110011010010111001001110101011100110100001101101000011001010110001101101011";
var hex = string.Join(" ",
Enumerable.Range(0, binary.Length / 8)
.Select(i => Convert.ToByte(binary.Substring(i * 8, 8), 2).ToString("X2")));

I came up with this method. I am new to programming and C# but I hope you will appreciate it:
static string BinToHex(string bin)
{
StringBuilder binary = new StringBuilder(bin);
bool isNegative = false;
if (binary[0] == '-')
{
isNegative = true;
binary.Remove(0, 1);
}
for (int i = 0, length = binary.Length; i < (4 - length % 4) % 4; i++) //padding leading zeros
{
binary.Insert(0, '0');
}
StringBuilder hexadecimal = new StringBuilder();
StringBuilder word = new StringBuilder("0000");
for (int i = 0; i < binary.Length; i += 4)
{
for (int j = i; j < i + 4; j++)
{
word[j % 4] = binary[j];
}
switch (word.ToString())
{
case "0000": hexadecimal.Append('0'); break;
case "0001": hexadecimal.Append('1'); break;
case "0010": hexadecimal.Append('2'); break;
case "0011": hexadecimal.Append('3'); break;
case "0100": hexadecimal.Append('4'); break;
case "0101": hexadecimal.Append('5'); break;
case "0110": hexadecimal.Append('6'); break;
case "0111": hexadecimal.Append('7'); break;
case "1000": hexadecimal.Append('8'); break;
case "1001": hexadecimal.Append('9'); break;
case "1010": hexadecimal.Append('A'); break;
case "1011": hexadecimal.Append('B'); break;
case "1100": hexadecimal.Append('C'); break;
case "1101": hexadecimal.Append('D'); break;
case "1110": hexadecimal.Append('E'); break;
case "1111": hexadecimal.Append('F'); break;
default:
return "Invalid number";
}
}
if (isNegative)
{
hexadecimal.Insert(0, '-');
}
return hexadecimal.ToString();
}

Considering four bits can be expressed by one hex value, you can simply go by groups of four and convert them seperately, the value won't change that way.
string bin = "11110110";
int rest = bin.Length % 4;
if(rest != 0)
bin = new string('0', 4-rest) + bin; //pad the length out to by divideable by 4
string output = "";
for(int i = 0; i <= bin.Length - 4; i +=4)
{
output += string.Format("{0:X}", Convert.ToByte(bin.Substring(i, 4), 2));
}

If you want to iterate over the hexadecimal representation of each byte in the string, you could use the following extension. I've combined Mitch's answer with this.
static class StringExtensions
{
public static IEnumerable<string> ToHex(this String s) {
if (s == null)
throw new ArgumentNullException("s");
int mod4Len = s.Length % 8;
if (mod4Len != 0)
{
// pad to length multiple of 8
s = s.PadLeft(((s.Length / 8) + 1) * 8, '0');
}
int numBitsInByte = 8;
for (var i = 0; i < s.Length; i += numBitsInByte)
{
string eightBits = s.Substring(i, numBitsInByte);
yield return string.Format("{0:X2}", Convert.ToByte(eightBits, 2));
}
}
}
Example:
string test = "0110011010010111001001110101011100110100001101101000011001010110001101101011";
foreach (var hexVal in test.ToHex())
{
Console.WriteLine(hexVal);
}
Prints
06
69
72
75
73
43
68
65
63
6B

If you're using .NET 4.0 or later and if you're willing to use System.Numerics.dll (for BigInteger class), the following solution works fine:
public static string ConvertBigBinaryToHex(string bigBinary)
{
BigInteger bigInt = BigInteger.Zero;
int exponent = 0;
for (int i = bigBinary.Length - 1; i >= 0; i--, exponent++)
{
if (bigBinary[i] == '1')
bigInt += BigInteger.Pow(2, exponent);
}
return bigInt.ToString("X");
}

Considering four bits can be expressed by one hex value, you can simply go by groups of four and convert them seperately, the value won't change that way.
string bin = "11110110";
int rest = bin.Length % 4;
bin = bin.PadLeft(rest, '0'); //pad the length out to by divideable by 4
string output = "";
for(int i = 0; i <= bin.Length - 4; i +=4)
{
output += string.Format("{0:X}", Convert.ToByte(bin.Substring(i, 4), 2));
}

static string BinToHex(string bin)
{
if (bin == null)
throw new ArgumentNullException("bin");
if (bin.Length % 8 != 0)
throw new ArgumentException("The length must be a multiple of 8", "bin");
var hex = Enumerable.Range(0, bin.Length / 8)
.Select(i => bin.Substring(8 * i, 8))
.Select(s => Convert.ToByte(s, 2))
.Select(b => b.ToString("x2"));
return String.Join(null, hex);
}

Using LINQ
string BinaryToHex(string binaryString)
{
var offset = 0;
StringBuilder sb = new();
while (offset < binaryString.Length)
{
var nibble = binaryString
.Skip(offset)
.Take(4);
sb.Append($"{Convert.ToUInt32(nibble.toString()), 2):X}");
offset += 4;
}
return sb.ToString();
}

You can take the input number four digit at a time. Convert this digit to ex ( as you did is ok ) then concat the string all together. So you obtain a string representing the number in hex, independetly from the size. Depending on where start MSB on your input string, may be the output string you obtain the way i described must be reversed.

Generating URL-friendly unique string with embedded datetime

I'm personally tired of reimplementing "a ticket" mechanism for my web projects for some one-time operations like account activation or password reset. I know it's simple but it requires me to keep (and persist!) two pieces of data: a ticket itself and an expiration date.
So I have this idea, to generate a unique string with embedded datetime (expiration date) in it, which we can check upon receiving as a part of url-request.
I've started with this:
var clearTicket = Convert.ToInt64(expiration.ToString("yyyyMMddhhmm")).ToString("x12") + key.ToString("N");
But I want it to be more compact. Something BaseXX-ish I suppose.
Any ideas how to implement this encoding/decoding efficiently (considering url-safe charset)?

It took me some time, so I hope it helps:
First of all, you should substract 200000000000 from "yyyyMMddhhmm", because you actually don't need the first two digits for the next 88 years.
Here is the implementation for encoding and decoding Base64, using only URL-safe characters.
If you have any questions, feel free to ask.
public string Base64Encode (Int64 Number)
{
string HelpString = "";
if (Number >= 64)
{
HelpString = Base64Encode(Number / 64);
}
return (HelpString += Base64EncodeHelper(Number % 64));
}
public string Base64EncodeHelper(Int64 Number)
{
string HelpString = "";
Number += 65;
if ((Number >= 65 && Number <= 90) || (Number >= 97 && Number <= 122)) // 0 - 25 and 32 - 57
{
HelpString = Convert.ToString((char)Number);
}
else if (Number >= 91 && Number <= 96) // 26 - 31
{
HelpString = Convert.ToString((char)(Number - 43));
}
else if (Number >= 123 && Number <= 126) // 58 - 61
{
HelpString = Convert.ToString((char)(Number - 69));
}
else if (Number == 127) // 62
{
HelpString = "-";
}
else // 63
{
HelpString = "_";
}
return (HelpString);
}
public Int64 Base64Decode(string Encoded)
{
Int64 Result = 0, HelpInt = 0;
int i = Encoded.Length - 1;
foreach (char Character in Encoded)
{
int CharInInt = (int)Character;
if (Character == '_')
{
HelpInt = 63;
}
else if (Character == '-')
{
HelpInt = 62;
}
else if (((CharInInt + 69) >= 123) && ((CharInInt + 69) <= 126))
{
HelpInt = CharInInt + 4;
}
else if (((CharInInt + 43) >= 91) && ((CharInInt + 43) <= 96))
{
HelpInt = CharInInt - 22;
}
else
{
HelpInt = CharInInt - 65;
}
Result += Convert.ToInt64((Math.Pow(64, Convert.ToDouble(i))) * HelpInt);
i--;
}
return Result;
}

You can extend string like this:
public static string ToURLParameter(this string text)
{
if (String.IsNullOrEmpty(text)) return "";
// to lowercase, trim extra spaces
text = text.Trim();
var len = text.Length;
var sb = new StringBuilder(len);
bool prevdash = false;
char c;
//
text = text.Replace('Å', 'A');
text = text.Replace('å', 'a');
text = text.Replace('Ä', 'A');
text = text.Replace('ä', 'a');
text = text.Replace('Ö', 'O');
text = text.Replace('ö', 'o');
for (int i = 0; i < text.Length; i++)
{
c = text[i];
if (c == ' ' || c == ',' || c == '.' || c == '/' || c == '\\' || c == '-')
{
if (!prevdash)
{
sb.Append('-');
prevdash = true;
}
}
else if ((c >= 'a' && c <= 'z') || (c >= '0' && c <= '9') || (c >= 'A' && c <= 'Z'))
{
sb.Append(c);
prevdash = false;
}
if (i == 80) break;
}
text = sb.ToString();
// remove trailing dash, if there is one
if (text.EndsWith("-"))
text = text.Substring(0, text.Length - 1);
return text;
}
and then you can use it on any variable that is string like:
string something = "asdfljasdklf";
<%= something.ToUrlParameter() %>

I've finally created a solution using techniques described in these answers:
Compressing big number (or string) to small value
How do you convert Byte Array to Hexadecimal String, and vice versa?
Works great!
Thanks you all for your help!

Converting long string of binary to hex c#

I'm looking for a way to convert a long string of binary to a hex string.
the binary string looks something like this "0110011010010111001001110101011100110100001101101000011001010110001101101011"
I've tried using
hex = String.Format("{0:X2}", Convert.ToUInt64(hex, 2));
but that only works if the binary string fits into a Uint64 which if the string is long enough it won't.
is there another way to convert a string of binary into hex?
Thanks

I just knocked this up. Maybe you can use as a starting point...
public static string BinaryStringToHexString(string binary)
{
if (string.IsNullOrEmpty(binary))
return binary;
StringBuilder result = new StringBuilder(binary.Length / 8 + 1);
// TODO: check all 1's or 0's... throw otherwise
int mod4Len = binary.Length % 8;
if (mod4Len != 0)
{
// pad to length multiple of 8
binary = binary.PadLeft(((binary.Length / 8) + 1) * 8, '0');
}
for (int i = 0; i < binary.Length; i += 8)
{
string eightBits = binary.Substring(i, 8);
result.AppendFormat("{0:X2}", Convert.ToByte(eightBits, 2));
}
return result.ToString();
}

This might help you:
string HexConverted(string strBinary)
{
string strHex = Convert.ToInt32(strBinary,2).ToString("X");
return strHex;
}

Convert.ToInt32("1011", 2).ToString("X");
For string longer than this, you can simply break it into multiple bytes:
var binary = "0110011010010111001001110101011100110100001101101000011001010110001101101011";
var hex = string.Join(" ",
Enumerable.Range(0, binary.Length / 8)
.Select(i => Convert.ToByte(binary.Substring(i * 8, 8), 2).ToString("X2")));

I came up with this method. I am new to programming and C# but I hope you will appreciate it:
static string BinToHex(string bin)
{
StringBuilder binary = new StringBuilder(bin);
bool isNegative = false;
if (binary[0] == '-')
{
isNegative = true;
binary.Remove(0, 1);
}
for (int i = 0, length = binary.Length; i < (4 - length % 4) % 4; i++) //padding leading zeros
{
binary.Insert(0, '0');
}
StringBuilder hexadecimal = new StringBuilder();
StringBuilder word = new StringBuilder("0000");
for (int i = 0; i < binary.Length; i += 4)
{
for (int j = i; j < i + 4; j++)
{
word[j % 4] = binary[j];
}
switch (word.ToString())
{
case "0000": hexadecimal.Append('0'); break;
case "0001": hexadecimal.Append('1'); break;
case "0010": hexadecimal.Append('2'); break;
case "0011": hexadecimal.Append('3'); break;
case "0100": hexadecimal.Append('4'); break;
case "0101": hexadecimal.Append('5'); break;
case "0110": hexadecimal.Append('6'); break;
case "0111": hexadecimal.Append('7'); break;
case "1000": hexadecimal.Append('8'); break;
case "1001": hexadecimal.Append('9'); break;
case "1010": hexadecimal.Append('A'); break;
case "1011": hexadecimal.Append('B'); break;
case "1100": hexadecimal.Append('C'); break;
case "1101": hexadecimal.Append('D'); break;
case "1110": hexadecimal.Append('E'); break;
case "1111": hexadecimal.Append('F'); break;
default:
return "Invalid number";
}
}
if (isNegative)
{
hexadecimal.Insert(0, '-');
}
return hexadecimal.ToString();
}

Considering four bits can be expressed by one hex value, you can simply go by groups of four and convert them seperately, the value won't change that way.
string bin = "11110110";
int rest = bin.Length % 4;
if(rest != 0)
bin = new string('0', 4-rest) + bin; //pad the length out to by divideable by 4
string output = "";
for(int i = 0; i <= bin.Length - 4; i +=4)
{
output += string.Format("{0:X}", Convert.ToByte(bin.Substring(i, 4), 2));
}

If you want to iterate over the hexadecimal representation of each byte in the string, you could use the following extension. I've combined Mitch's answer with this.
static class StringExtensions
{
public static IEnumerable<string> ToHex(this String s) {
if (s == null)
throw new ArgumentNullException("s");
int mod4Len = s.Length % 8;
if (mod4Len != 0)
{
// pad to length multiple of 8
s = s.PadLeft(((s.Length / 8) + 1) * 8, '0');
}
int numBitsInByte = 8;
for (var i = 0; i < s.Length; i += numBitsInByte)
{
string eightBits = s.Substring(i, numBitsInByte);
yield return string.Format("{0:X2}", Convert.ToByte(eightBits, 2));
}
}
}
Example:
string test = "0110011010010111001001110101011100110100001101101000011001010110001101101011";
foreach (var hexVal in test.ToHex())
{
Console.WriteLine(hexVal);
}
Prints
06
69
72
75
73
43
68
65
63
6B

If you're using .NET 4.0 or later and if you're willing to use System.Numerics.dll (for BigInteger class), the following solution works fine:
public static string ConvertBigBinaryToHex(string bigBinary)
{
BigInteger bigInt = BigInteger.Zero;
int exponent = 0;
for (int i = bigBinary.Length - 1; i >= 0; i--, exponent++)
{
if (bigBinary[i] == '1')
bigInt += BigInteger.Pow(2, exponent);
}
return bigInt.ToString("X");
}

Considering four bits can be expressed by one hex value, you can simply go by groups of four and convert them seperately, the value won't change that way.
string bin = "11110110";
int rest = bin.Length % 4;
bin = bin.PadLeft(rest, '0'); //pad the length out to by divideable by 4
string output = "";
for(int i = 0; i <= bin.Length - 4; i +=4)
{
output += string.Format("{0:X}", Convert.ToByte(bin.Substring(i, 4), 2));
}

static string BinToHex(string bin)
{
if (bin == null)
throw new ArgumentNullException("bin");
if (bin.Length % 8 != 0)
throw new ArgumentException("The length must be a multiple of 8", "bin");
var hex = Enumerable.Range(0, bin.Length / 8)
.Select(i => bin.Substring(8 * i, 8))
.Select(s => Convert.ToByte(s, 2))
.Select(b => b.ToString("x2"));
return String.Join(null, hex);
}

Using LINQ
string BinaryToHex(string binaryString)
{
var offset = 0;
StringBuilder sb = new();
while (offset < binaryString.Length)
{
var nibble = binaryString
.Skip(offset)
.Take(4);
sb.Append($"{Convert.ToUInt32(nibble.toString()), 2):X}");
offset += 4;
}
return sb.ToString();
}

You can take the input number four digit at a time. Convert this digit to ex ( as you did is ok ) then concat the string all together. So you obtain a string representing the number in hex, independetly from the size. Depending on where start MSB on your input string, may be the output string you obtain the way i described must be reversed.

Function to generate alpha numeric sequence number based on input number

I am trying to develope a routine in C# that will take a given input integer and return a 6 character alpha numeric string based on a predefined possible set of characters.
The possible characters to use are:
"0123456789ABCDEFGHJKLMNPQRSTUVWXYZ" (note that the letter "I" and "O" are not in the set.)
Therefore given the input of 1, the output should be "000001", input of 9 would output "000009", input of 10 would output "00000A", input of 12345 would output "000AP3", and so on.
I am having a hard time coming up with an elegant solution to this problem. I know I must be approaching this the hard way so I'm looking for some help.
Thanks!

int value = 12345;
string alphabet = "0123456789ABCDEFGHJKLMNPQRSTUVWXYZ";
var stack = new Stack<char>();
while (value > 0)
{
stack.Push(alphabet[value % alphabet.Length]);
value /= alphabet.Length;
}
string output = new string(stack.ToArray()).PadLeft(6, '0');

The direct solution would simply be to iteratively divide your input value by N (the size of the character set), and take the remainder each time to index into the character set, and build up the output string character-by-character.

internal class Program {
private static void Main(string[] args) {
int value = 38;
const string alphabet = "0123456789ABCDEFGHJKLMNPQRSTUVWXYZ";
string result = ToBase(value, alphabet);
Console.WriteLine(result);
}
private static string ToBase(int value, string alphabet) {
if (value == 0) return alphabet[0].ToString();
var result = new StringBuilder();
while (value > 0) {
int digit = value % alphabet.Length;
value = (value - digit) / alphabet.Length;
result.Insert(0, alphabet[digit]);
}
return result.ToString();
}
}
you do zero-padding

LukeH answer modified for Generating Alphanemuric to numeric and vice versa
int value = 12345;
string alphabet = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ";
var stack = new Stack<char>();
while (value > 0)
{
int index = value % alphabet.Length;
stack.Push(alphabet[index]);
value /= alphabet.Length;
}
string output = new string(stack.ToArray()).PadLeft(6, '0');
double intNumber = 0;
int charPos = 0;
for (var i = output.Length-1; i >=0;i--)
{
int val = output[i];
if (val >= 48 && val <= 57)
intNumber += (val - 48) * (Math.Pow(36, charPos++));
else if (val >= 65 && val <= 90)
intNumber += (val - 55) * (Math.Pow(36, charPos++));
}

How to convert numbers between hexadecimal and decimal

How do you convert between hexadecimal numbers and decimal numbers in C#?

To convert from decimal to hex do...
string hexValue = decValue.ToString("X");
To convert from hex to decimal do either...
int decValue = int.Parse(hexValue, System.Globalization.NumberStyles.HexNumber);
or
int decValue = Convert.ToInt32(hexValue, 16);

Hex -> decimal:
Convert.ToInt64(hexString, 16);
Decimal -> Hex
string.Format("{0:x}", intValue);

It looks like you can say
Convert.ToInt64(value, 16)
to get the decimal from hexdecimal.
The other way around is:
otherVar.ToString("X");

If you want maximum performance when doing conversion from hex to decimal number, you can use the approach with pre-populated table of hex-to-decimal values.
Here is the code that illustrates that idea. My performance tests showed that it can be 20%-40% faster than Convert.ToInt32(...):
class TableConvert
{
static sbyte[] unhex_table =
{ -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1
,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1
,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1
, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9,-1,-1,-1,-1,-1,-1
,-1,10,11,12,13,14,15,-1,-1,-1,-1,-1,-1,-1,-1,-1
,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1
,-1,10,11,12,13,14,15,-1,-1,-1,-1,-1,-1,-1,-1,-1
,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1
};
public static int Convert(string hexNumber)
{
int decValue = unhex_table[(byte)hexNumber[0]];
for (int i = 1; i < hexNumber.Length; i++)
{
decValue *= 16;
decValue += unhex_table[(byte)hexNumber[i]];
}
return decValue;
}
}

From Geekpedia:
// Store integer 182
int decValue = 182;
// Convert integer 182 as a hex in a string variable
string hexValue = decValue.ToString("X");
// Convert the hex string back to the number
int decAgain = int.Parse(hexValue, System.Globalization.NumberStyles.HexNumber);

String stringrep = myintvar.ToString("X");
int num = int.Parse("FF", System.Globalization.NumberStyles.HexNumber);

If it's a really big hex string beyond the capacity of the normal integer:
For .NET 3.5, we can use BouncyCastle's BigInteger class:
String hex = "68c7b05d0000000002f8";
// results in "494809724602834812404472"
String decimal = new Org.BouncyCastle.Math.BigInteger(hex, 16).ToString();
.NET 4.0 has the BigInteger class.

Hex to Decimal Conversion
Convert.ToInt32(number, 16);
Decimal to Hex Conversion
int.Parse(number, System.Globalization.NumberStyles.HexNumber)
For more details Check this article

Try using BigNumber in C# - Represents an arbitrarily large signed integer.
Program
using System.Numerics;
...
var bigNumber = BigInteger.Parse("837593454735734579347547357233757342857087879423437472347757234945743");
Console.WriteLine(bigNumber.ToString("X"));
Output
4F30DC39A5B10A824134D5B18EEA3707AC854EE565414ED2E498DCFDE1A15DA5FEB6074AE248458435BD417F06F674EB29A2CFECF
Possible Exceptions,
ArgumentNullException - value is null.
FormatException - value is not in the correct format.
Conclusion
You can convert string and store a value in BigNumber without constraints about the size of the number unless the string is empty and non-analphabets

static string chex(byte e) // Convert a byte to a string representing that byte in hexadecimal
{
string r = "";
string chars = "0123456789ABCDEF";
r += chars[e >> 4];
return r += chars[e &= 0x0F];
} // Easy enough...
static byte CRAZY_BYTE(string t, int i) // Take a byte, if zero return zero, else throw exception (i=0 means false, i>0 means true)
{
if (i == 0) return 0;
throw new Exception(t);
}
static byte hbyte(string e) // Take 2 characters: these are hex chars, convert it to a byte
{ // WARNING: This code will make small children cry. Rated R.
e = e.ToUpper(); //
string msg = "INVALID CHARS"; // The message that will be thrown if the hex str is invalid
byte[] t = new byte[] // Gets the 2 characters and puts them in seperate entries in a byte array.
{ // This will throw an exception if (e.Length != 2).
(byte)e[CRAZY_BYTE("INVALID LENGTH", e.Length ^ 0x02)],
(byte)e[0x01]
};
for (byte i = 0x00; i < 0x02; i++) // Convert those [ascii] characters to [hexadecimal] characters. Error out if either character is invalid.
{
t[i] -= (byte)((t[i] >= 0x30) ? 0x30 : CRAZY_BYTE(msg, 0x01)); // Check for 0-9
t[i] -= (byte)((!(t[i] < 0x0A)) ? (t[i] >= 0x11 ? 0x07 : CRAZY_BYTE(msg, 0x01)) : 0x00); // Check for A-F
}
return t[0x01] |= t[0x00] <<= 0x04; // The moment of truth.
}

This is not really easiest way but this source code enable you to right any types of octal number i.e 23.214, 23 and 0.512 and so on. Hope this will help you..
public string octal_to_decimal(string m_value)
{
double i, j, x = 0;
Int64 main_value;
int k = 0;
bool pw = true, ch;
int position_pt = m_value.IndexOf(".");
if (position_pt == -1)
{
main_value = Convert.ToInt64(m_value);
ch = false;
}
else
{
main_value = Convert.ToInt64(m_value.Remove(position_pt, m_value.Length - position_pt));
ch = true;
}
while (k <= 1)
{
do
{
i = main_value % 10; // Return Remainder
i = i * Convert.ToDouble(Math.Pow(8, x)); // calculate power
if (pw)
x++;
else
x--;
o_to_d = o_to_d + i; // Saving Required calculated value in main variable
main_value = main_value / 10; // Dividing the main value
}
while (main_value >= 1);
if (ch)
{
k++;
main_value = Convert.ToInt64(Reversestring(m_value.Remove(0, position_pt + 1)));
}
else
k = 2;
pw = false;
x = -1;
}
return (Convert.ToString(o_to_d));
}

This one worked for me:
public static decimal HexToDec(string hex)
{
if (hex.Length % 2 == 1)
hex = "0" + hex;
byte[] raw = new byte[hex.Length / 2];
decimal d = 0;
for (int i = 0; i < raw.Length; i++)
{
raw[i] = Convert.ToByte(hex.Substring(i * 2, 2), 16);
d += Math.Pow(256, (raw.Length - 1 - i)) * raw[i];
}
return d.ToString();
return d;
}

Decimal - Hexa
var decValue = int.Parse(Console.ReadLine());
string hex = string.Format("{0:x}", decValue);
Console.WriteLine(hex);
Hexa - Decimal (use namespace: using System.Globalization;)
var hexval = Console.ReadLine();
int decValue = int.Parse(hexval, NumberStyles.HexNumber);
Console.WriteLine(decValue);

FOUR C# native ways to convert Hex to Dec and back:
using System;
namespace Hexadecimal_and_Decimal
{
internal class Program
{
private static void Main(string[] args)
{
string hex = "4DEAD";
int dec;
// hex to dec:
dec = int.Parse(hex, System.Globalization.NumberStyles.HexNumber);
// or:
dec = Convert.ToInt32(hex, 16);
// dec to hex:
hex = dec.ToString("X"); // lowcase: x, uppercase: X
// or:
hex = string.Format("{0:X}", dec); // lowcase: x, uppercase: X
Console.WriteLine("Hexadecimal number: " + hex);
Console.WriteLine("Decimal number: " + dec);
}
}
}

My version is I think a little more understandable because my C# knowledge is not so high.
I'm using this algorithm: http://easyguyevo.hubpages.com/hub/Convert-Hex-to-Decimal (The Example 2)
using System;
using System.Collections.Generic;
static class Tool
{
public static string DecToHex(int x)
{
string result = "";
while (x != 0)
{
if ((x % 16) < 10)
result = x % 16 + result;
else
{
string temp = "";
switch (x % 16)
{
case 10: temp = "A"; break;
case 11: temp = "B"; break;
case 12: temp = "C"; break;
case 13: temp = "D"; break;
case 14: temp = "E"; break;
case 15: temp = "F"; break;
}
result = temp + result;
}
x /= 16;
}
return result;
}
public static int HexToDec(string x)
{
int result = 0;
int count = x.Length - 1;
for (int i = 0; i < x.Length; i++)
{
int temp = 0;
switch (x[i])
{
case 'A': temp = 10; break;
case 'B': temp = 11; break;
case 'C': temp = 12; break;
case 'D': temp = 13; break;
case 'E': temp = 14; break;
case 'F': temp = 15; break;
default: temp = -48 + (int)x[i]; break; // -48 because of ASCII
}
result += temp * (int)(Math.Pow(16, count));
count--;
}
return result;
}
}
class Program
{
static void Main(string[] args)
{
Console.Write("Enter Decimal value: ");
int decNum = int.Parse(Console.ReadLine());
Console.WriteLine("Dec {0} is hex {1}", decNum, Tool.DecToHex(decNum));
Console.Write("\nEnter Hexadecimal value: ");
string hexNum = Console.ReadLine().ToUpper();
Console.WriteLine("Hex {0} is dec {1}", hexNum, Tool.HexToDec(hexNum));
Console.ReadKey();
}
}

Convert binary to Hex
Convert.ToString(Convert.ToUInt32(binary1, 2), 16).ToUpper()

You can use this code and possible set Hex length and part's:
const int decimal_places = 4;
const int int_places = 4;
static readonly string decimal_places_format = $"X{decimal_places}";
static readonly string int_places_format = $"X{int_places}";
public static string DecimaltoHex(decimal number)
{
var n = (int)Math.Truncate(number);
var f = (int)Math.Truncate((number - n) * ((decimal)Math.Pow(10, decimal_places)));
return $"{string.Format($"{{0:{int_places_format}}}", n)}{string.Format($"{{0:{decimal_places_format}}}", f)}";
}
public static decimal HextoDecimal(string number)
{
var n = number.Substring(0, number.Length - decimal_places);
var f = number.Substring(number.Length - decimal_places);
return decimal.Parse($"{int.Parse(n, System.Globalization.NumberStyles.HexNumber)}.{int.Parse(f, System.Globalization.NumberStyles.HexNumber)}");
}

An extension method for converting a byte array into a hex representation. This pads each byte with leading zeros.
/// <summary>
/// Turns the byte array into its Hex representation.
/// </summary>
public static string ToHex(this byte[] y)
{
StringBuilder sb = new StringBuilder();
foreach (byte b in y)
{
sb.Append(b.ToString("X").PadLeft(2, "0"[0]));
}
return sb.ToString();
}

Here is my function:
using System;
using System.Collections.Generic;
class HexadecimalToDecimal
{
static Dictionary<char, int> hexdecval = new Dictionary<char, int>{
{'0', 0},
{'1', 1},
{'2', 2},
{'3', 3},
{'4', 4},
{'5', 5},
{'6', 6},
{'7', 7},
{'8', 8},
{'9', 9},
{'a', 10},
{'b', 11},
{'c', 12},
{'d', 13},
{'e', 14},
{'f', 15},
};
static decimal HexToDec(string hex)
{
decimal result = 0;
hex = hex.ToLower();
for (int i = 0; i < hex.Length; i++)
{
char valAt = hex[hex.Length - 1 - i];
result += hexdecval[valAt] * (int)Math.Pow(16, i);
}
return result;
}
static void Main()
{
Console.WriteLine("Enter Hexadecimal value");
string hex = Console.ReadLine().Trim();
//string hex = "29A";
Console.WriteLine("Hex {0} is dec {1}", hex, HexToDec(hex));
Console.ReadKey();
}
}

My solution is a bit like back to basics, but it works without using any built-in functions to convert between number systems.
public static string DecToHex(long a)
{
int n = 1;
long b = a;
while (b > 15)
{
b /= 16;
n++;
}
string[] t = new string[n];
int i = 0, j = n - 1;
do
{
if (a % 16 == 10) t[i] = "A";
else if (a % 16 == 11) t[i] = "B";
else if (a % 16 == 12) t[i] = "C";
else if (a % 16 == 13) t[i] = "D";
else if (a % 16 == 14) t[i] = "E";
else if (a % 16 == 15) t[i] = "F";
else t[i] = (a % 16).ToString();
a /= 16;
i++;
}
while ((a * 16) > 15);
string[] r = new string[n];
for (i = 0; i < n; i++)
{
r[i] = t[j];
j--;
}
string res = string.Concat(r);
return res;
}

Develop Reference

C# (C-Sharp) is a programming language developed by Microsoft that runs on the .NET Framework.

How to manually convert Hexadecimal to Decimal in C#? - c#

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