I have a file named "Alarm.wav" and I want to play it with media player, media player can't open a file with getting path, it only gets URI. I rally don't know how to make this file location to URI. Furthermore, I need it because software location can change. Here is the code:
MediaPlayer alarm = new MediaPlayer();
var uri = new Uri("file://Alarm.wav");
alarm.Open(uri);
alarm.Play();
But works if code be like this:
MediaPlayer alarm = new MediaPlayer();
var uri = new Uri("file://D:/apps/repos/BorderRaduis/BorderRaduis/bin/Debug/net5.0-windows/Alarm.wav");
alarm.Open(uri);
alarm.Play();
Relative path is what you are looking for.
So if you have a folder named e.g. Videos your path should be “videos/alarms.wav”
I am trying to play a sound file in my WPF application. Currently I have the following call:
private void PlaySound(string uriPath)
{
Uri uri = new Uri(#"pack://application:,,,/Media/movepoint.wav");
var player = new MediaPlayer();
player.Open(uri);
player.Play();
}
Now if I specify Media/movepoint.wav as build action Content and load it as a relative or absolute file path it works fine, so I suspect this has something to do with the Pack URI, but I cannot for the life of me figure out what.
The objective is to store the file as a resource so that its not available in the output directory. I can provide either the WAV copy or the MP3 copy.
I tried this with an image file, which works the same as a sound file as far as the uri is concerned because it's just another resource. I used the code below which essentially matches what you have.
new Uri(#"pack://application:,,,/Resources/logo.png")
Make sure that your 'Media' folder is not nested in any other folder. If it is, you need to include that folder as well.
Using .NET Framework 4.0, VS2012.
This link gives a pretty good description of the whole "pack" scheme of things.
EDIT
More research on this topic seems to indicate that what you want to do might not be possible with audio or video files. The excerpt below is taken from the remarks section of this MSDN page.
Although you can declare an instance of this class in Extensible
Application Markup Language (XAML), you cannot load and play its media
without using code. To play media in XAML only, use a MediaElement.
Also, if you declare an instance in XAML, the only practical use is to
fill property element syntax for the Player property.
When distributing media with your application, you cannot use a media
file as a project resource. In your project file, you must instead set
the media type to Content and set CopyToOutputDirectory to
PreserveNewest or Always.
MediaPlayer can be used in two different modes, depending on what is
driving the player: independent mode or clock mode. In independent
mode, the MediaPlayer is analogous to an image and the media opened
through the Open method drives playback. In Clock mode, the
MediaPlayer can be thought of as a target for an animation, and thus
it will have corresponding Timeline and Clock entries in the Timing
tree which controls playback. For more information on media modes, see
the Multimedia Overview.
MediaPlayer is different from a MediaElement in that it is not a
control that can be added directly to the user interface (UI) of an
application. To display media loaded using MediaPlayer, a VideoDrawing
or DrawingContext must be used.
The following seems to work in .NET Framework 4.5:
var sri = Application.GetResourceStream(new Uri("pack://application:,,,/MyAssemblyName;component/Resources/CameraShutter.wav"));
if ((sri != null))
{
using (s == sri.Stream)
{
System.Media.SoundPlayer player = new System.Media.SoundPlayer(s);
player.Load();
player.Play();
}
}
CameraShutter.wav is embedded as Resource in my project (and resides inside Resources subfolder, as indicated in the pack URI).
You can also load a Stream into the SoundPlayer if the .wav file is an Embedded Resource. Note that in this example the resources are in a folder called Resources that is in the root of the project, that is why it is written {0}.Resources.{1}.
//the wav filename
string file = "emergency_alarm_002.wav";
//get the current assembly
var assembly = System.Reflection.Assembly.GetExecutingAssembly();
//load the embedded resource as a stream
var stream = assembly.GetManifestResourceStream(string.Format("{0}.Resources.{1}", assembly.GetName().Name, file));
//load the stream into the player
var player = new System.Media.SoundPlayer(stream);
//play the sound
player.Play();
This also seems to work and is maybe simpler to remember than that long line of pack or assembly stuff..
I opened the Resources.resx and dragged a sound file in there called aa_pickup.wav Then set the properties of it to Copy to Output Dir = Copy Always.
System.IO.Stream str = Properties.Resources.aa_pickup;
System.Media.SoundPlayer snd = new System.Media.SoundPlayer(str);
snd.Play();
Now.. if I could only work out how to change the volume.
I am trying to play a sound file when I click on a button. The file is located in the Assets folder and the build action is set to content. I tried the following:
Option 1:
element.Source = new Uri("ms-appx:///Assets/alarm.wav");
Option 2:
Windows.Storage.StorageFolder folder = await Windows.ApplicationModel.Package.Current.InstalledLocation.GetFolderAsync("Assets");
Windows.Storage.StorageFile file = await folder.GetFileAsync("alarm.wav");
var stream = await file.OpenAsync(Windows.Storage.FileAccessMode.Read);
element.SetSource(stream, file.ContentType);
The second option works, but it takes a long time before the sound plays when I click on the button. According to other questions the first option should work, but the sound is not played and there is no exception.
Any suggestions?
EDIT:
I am using a Xamarin template for cross-platform development. So I have the following structure:
App (PCL)
App.Droid
App.iOS
App.UWP
App.WinPhone
With DependencyService I try to play sound on each platform, but with App.UWP option 1 doesn't work.
you can try this way
Uri uri = new Uri(AppDomain.CurrentDomain.BaseDirectory + "Assets/alarm.wav");
var player = new MediaPlayer();
player.Open(uri);
player.Play();
I have stored an audio file in the resources folder of my application but when I use the below path I get a file no found exception.
Can someone explain if this is the correct way to reference a file in resources or if I need to set the path differently?
This is the code that take the audio file as a parameter:
SoundPlayer player = new SoundPlayer("Resources/Audio/punchSound.wav");
player.Load();
player.Play();
You can use resource string:
var music = Properties.Resources.punchSound;
And then use SoundPlayer like this:
var player = new SoundPlayer(new MemoryStream(music));
I'm trying to play a small video file in my windows phone application. Is pretty basic
void StartMediaPlayer()
{
MediaPlayerLauncher mediaPlayerLauncher = new MediaPlayerLauncher();
mediaPlayerLauncher.Media = new Uri("/Assets/video/video1.wmv", UriKind.Relative);
mediaPlayerLauncher.Location = MediaLocationType.Install;
mediaPlayerLauncher.Controls = MediaPlaybackControls.All;
mediaPlayerLauncher.Orientation = MediaPlayerOrientation.Landscape;
mediaPlayerLauncher.Show();
}
i call this void on image tap event, and this is what happend
the debugger show that the error is here: mediaPlayerLauncher.Show();
That error will be thrown the application can't find your file /Assets/video/video1.wmv in the install directory on the phone. Make sure that your video is in your project, and is set to build type "Content". You could open the XAP file to double-check it's in the correct relative location too (it's just a ZIP file archive renamed).
if some has the same problem, just a heads up the files should be in main directory
mediaPlayerLauncher.Media = new Uri("video1.wmv", UriKind.Relative);