I have a project where I am using NPOI to generate Excel document from my Angular application. I have the calls being made from my angular service to my webapi controller as follows:
function exportReportToExcel(report) {
return $http.post('reportlibrary/exportReport/', report, {
}).then(function (response) {
return response.data;
});
};
Within the controller I make the following call
[HttpPost]
public HttpResponseMessage ExportReport([FromBody]DTOs.Report report)
{
try
{
IReportPersistenceManager manager = ContainerConfigurator.Instance.Resolve<IReportPersistenceManager>();
MemoryStream ms = new MemoryStream();
//we have to pass to the NOPI assemble file type as well as file name
//since we only deal with excel for now we will set it but this could be configured later.
long id = report.ReportId;
string mimeType = "application/vnd.ms-excel";
string filename = "unknown";
manager.ExportDataToExcel(id, (name, mime) =>
{
mimeType = mime;
filename = name;
return ms;
});
ms.Position = 0;
var response = new HttpResponseMessage();
response.Content = new ByteArrayContent(ms.ToArray());
response.Content.Headers.ContentType = new MediaTypeHeaderValue("application/vnd.ms-excel");
return (response);
}
catch (Exception)
{
//error
return new HttpResponseMessage(System.Net.HttpStatusCode.BadRequest);
}
}
This is a migration from an MVC app and previously I was able to return the object using System.IO.File to return the object as well as close the stream.
I've never done this with Angular but from what I have read it appears I can drop the memorystream object into a byteArray and pass that back to the client.
If this is the correct approach how to I unravel this object once it comes back to the angular service and controller.
The goal here is to allow the user to download a previously saved report as an Excel file.
Am I on the right track? Is there a more efficient way to download a memory stream object? How can I pass this context to the browser?
thanks in advance
I had a similar problem. I solved that changing the endpoint to support GET and calling this method from a new tab.
So from your angular app you have to create a new tab pointing to the path that calls the method that generate your document. You can open a tab with the next code:
$window.open(path)
I think that in the next link you can have all the information that you need:
Download file from an ASP.NET Web API method using AngularJS
I hope that it helps.
Related
I am trying to download a simple xlsx file using web api but the file is always corrupt and I am yet to figure out why.I am using C# ClosedXML.Excel and following a basic example which can be found here:
ClosedXml examples
[HttpGet]
[Route("campaigns/{id}/contact-points/excel")]
[SwaggerResponse(491, "TokenInvalid")]
[SwaggerResponse(HttpStatusCode.NotFound)]
[SwaggerResponse(HttpStatusCode.Forbidden)]
[ResponseType(typeof(HttpResponseMessage))]
public async Task<IHttpActionResult> GetCampaignContactPointsExcel(int id, int frequency, string txtFrequency)
{
var wb = new XLWorkbook();
var ws1 = wb.Worksheets.Add("Sheet1");
ws1.Cell("A1").SetValue(1).AddToNamed("value1");
var ws2 = wb.Worksheets.Add("Sheet2");
ws2.Cell("A1").SetFormulaA1("=value1").AddToNamed("value2");
var responseMessage = new HttpResponseMessage(HttpStatusCode.OK);
using (var memoryStream = new MemoryStream())
{
wb.SaveAs(memoryStream);
responseMessage.Content = new ByteArrayContent(memoryStream.ToArray());
responseMessage.Content.Headers.ContentType = new MediaTypeHeaderValue("application/vnd.openxmlformats-officedocument.spreadsheetml.sheet");
responseMessage.Content.Headers.ContentDisposition = new ContentDispositionHeaderValue("attachment")
{
FileName = "ContactPoints.xlsx"
};
memoryStream.Close();
}
return ResponseMessage(responseMessage);
}
I am also using swagger and when I click on the link it downloads the file and opens it as a xlsx file but it always says it's corrupt.
There is nothing wrong in the backend code. On the frontend side you need to set responseType='blob'
Seems like this is an issue related to swagger ui 2. Please refer to [https://github.com/swagger-api/swagger-ui/issues/1605][1].
You can try curl or Postman to see if it downloads the file correctly.
While calling the service set Response type as 'blob'
return this.http.get(this.url +'PA/Downloadexcel/'+revisionId,{ responseType :'blob'});
The last 2 days, I have been trying to create an image upload system for my website. When I try to save an uploaded image in the "wwwroot" of my Api, everything goes as planned except that I get an empty image in my folder.
At the backend, I receive the filename I send in the frontend but the bytes of the image itself are not there. For some reason the the data of the stream I put in the post call is missing but I do receive the filename in the formfile.
Edit:
To clear things up about my application, I'm working with an Asp.Net Mvc as frontend and Asp.Net Api as backend. I know this isn't how you are supposed to use Asp.Net but this is a school project and I have to do it like this. Normally i would work with Angular or something else but that is not an option for me right now.
So, I'm sending data from the Asp.Net Mvc (frontend) to the Asp.Net Api (backend) and I'm trying to do it by sending it as form data. That means there is no real form that is being submitted.
This is the guide I tried to use:
https://ilclubdellesei.blog/2018/02/14/how-to-upload-images-to-an-asp-net-core-rest-service-with-xamarin-forms/
Backend
ImageController:
[HttpPost("upload")]
public async Task<IActionResult> UploadImage([FromForm(Name = "file")] IFormFile file)
{
if (file.Length == 0)
return BadRequest("Empty file");
string imageName = file.FileName;
using (var fs = new FileStream("wwwroot/" + imageName, FileMode.Create, FileAccess.Write))
{
await file.CopyToAsync(fs);
}
return Ok();
}
Frontend
Method that uploads 1 image as a MemoryStream to the server
private async Task<string> Upload(Stream image, string name, string contentType)
{
_httpClient = _clientFactory.CreateClient("ProjectApi");
HttpContent fileStreamContent = new StreamContent(image);
fileStreamContent.Headers.ContentDisposition = new System.Net.Http.Headers.ContentDispositionHeaderValue("form-data") { Name = "file", FileName = name };
fileStreamContent.Headers.ContentType = new System.Net.Http.Headers.MediaTypeHeaderValue(contentType);
using (var formData = new MultipartFormDataContent())
{
formData.Add(fileStreamContent);
HttpResponseMessage response = await _httpClient.PostAsync("api/images/upload", formData);
var input = await response.Content.ReadAsStringAsync();
return input;
}
}
The content doesn't seem to be empty:
The filename has been successfully send to the Api but the bytes of the image have not been send:
Structure after uploading some images without checking the size of the formfile (They are empty):
I am not 100% sure but I suppose the reason why you get empty file is that you did not set what type data your api endpoint will consume and maybe the form encryption type & method attributes. My suggestion is that you should update your code to below. ,
[Consumes("multipart/form-data")]
private async Task<string> Upload(Stream image, string name, string contentType)
And in case you forget to add form attributes to your html section, please set attributes as follows <form method="post" enctype="multipart/form-data">. Hope this solves your problem.
I am trying to send a file to a server over a REST API. The file could potentially be of any type, though it can be limited in size and type to things that can be sent as email attachments.
I think my approach will be to send the file as a binary stream, and then save that back into a file when it arrives at the server. Is there a built in way to do this in .Net or will I need to manually turn the file contents into a data stream and send that?
For clarity, I have control over both the client and server code, so I am not restricted to any particular approach.
I'd recommend you look into RestSharp
http://restsharp.org/
The RestSharp library has methods for posting files to a REST service. (RestRequst.AddFile()). I believe on the server-side this will translate into an encoded string into the body, with the content-type in the header specifying the file type.
I've also seen it done by converting a stream to a base-64 string, and transferring that as one of the properties of the serialized json/xml object. Especially if you can set size limits and want to include file meta-data in the request as part of the same object, this works really well.
It really depends how large your files are though. If they are very large, you need to consider streaming, of which the nuances of that is covered in this SO post pretty thoroughly: How do streaming resources fit within the RESTful paradigm?
You could send it as a POST request to the server, passing file as a FormParam.
#POST
#Path("/upload")
//#Consumes(MediaType.MULTIPART_FORM_DATA)
#Consumes("application/x-www-form-urlencoded")
public Response uploadFile( #FormParam("uploadFile") String script, #HeaderParam("X-Auth-Token") String STtoken, #Context HttpHeaders hh) {
// local variables
String uploadFilePath = null;
InputStream fileInputStream = new ByteArrayInputStream(script.getBytes(StandardCharsets.UTF_8));
//System.out.println(script); //debugging
try {
uploadFilePath = writeToFileServer(fileInputStream, SCRIPT_FILENAME);
}
catch(IOException ioe){
ioe.printStackTrace();
}
return Response.ok("File successfully uploaded at " + uploadFilePath + "\n").build();
}
private String writeToFileServer(InputStream inputStream, String fileName) throws IOException {
OutputStream outputStream = null;
String qualifiedUploadFilePath = SIMULATION_RESULTS_PATH + fileName;
try {
outputStream = new FileOutputStream(new File(qualifiedUploadFilePath));
int read = 0;
byte[] bytes = new byte[1024];
while ((read = inputStream.read(bytes)) != -1) {
outputStream.write(bytes, 0, read);
}
outputStream.flush();
}
catch (IOException ioe) {
ioe.printStackTrace();
}
finally{
//release resource, if any
outputStream.close();
}
return qualifiedUploadFilePath;
}
Building on to #MutantNinjaCodeMonkey's suggestion of RestSharp. My use case was posting webform data from jquery's $.ajax method into a web api controller. The restful API service required the uploaded file to be added to the request Body. The default restsharp method of AddFile mentioned above caused an error of The request was aborted: The request was canceled. The following initialization worked:
// Stream comes from web api's HttpPostedFile.InputStream
(HttpContext.Current.Request.Files["fileUploadNameFromAjaxData"].InputStream)
using (var ms = new MemoryStream())
{
fileUploadStream.CopyTo(ms);
photoBytes = ms.ToArray();
}
var request = new RestRequest(Method.PUT)
{
AlwaysMultipartFormData = true,
Files = { FileParameter.Create("file", photoBytes, "file") }
};
Detect the file/s being transported with the request.
Decide on a path where the file will be uploaded (and make sure CHMOD 777 exists for this directory)
Accept the client connect
Use ready library for the actual upload
Review the following discussion:
REST file upload with HttpRequestMessage or Stream?
First, you should login to the server and get an access token.
Next, you should convert your file to stream and post the stream:
private void UploadFile(FileStream stream, string fileName)
{
string apiUrl = "http://example.com/api";
var formContent = new MultipartFormDataContent
{
{new StringContent(fileName),"FileName"},
{new StreamContent(stream),"formFile",fileName},
};
using HttpClient httpClient = new HttpClient();
httpClient.DefaultRequestHeaders.Add("Authorization", accessToken);
var response = httpClient.PostAsync(#$"{apiUrl}/FileUpload/save", formContent);
var result = response.Result.Content.ReadAsStringAsync().Result;
}
In this example, we upload the file to http://example.com/api/FileUpload/save and the controller has the following method in its FileUpload controller:
[HttpPost("Save")]
public ActionResult Save([FromForm] FileContent fileContent)
{
// ...
}
public class FileContent
{
public string FileName { get; set; }
public IFormFile formFile { get; set; }
}
I have a c# controller that returns a status file for the system. It prompts the user to open or download the file. The return type for the controller is actually System.Net.Http.HttpResponseMessage.
I set up the route like this: /api/logging/status/{reqID}
If I goto the route directly in my web browser, http://mysite//api/logging/status/12345678, it works fine.
How can I get the URL to the file via jquery so that I can put that url in an achor tag like:
Download Status
Here is the controller:
[Route("/api/logging/status/{reqID}")]
public IHttpActionResult GetStatus(Int32 reqID)
{
Stream stream;
stream = new MemoryStream();
var reqStatus = serializer.SerializeToString(req);
var bytes = System.Text.Encoding.UTF8.GetBytes(reqStatus);
stream.Write(bytes, 0, bytes.Length);
stream.Seek(0, SeekOrigin.Begin);
}
var response = new HttpResponseMessage(HttpStatusCode.OK);
response.Content = new StreamContent(stream);
response.Content.Headers.ContentType = new MediaTypeHeaderValue("application/octet-stream");
response.Content.Headers.Add("Content-Disposition", String.Format("attachment; filename=\"{0}\"", "status.txt"));
response.Content.Headers.ContentDisposition = new ContentDispositionHeaderValue("attachment");
return ResponseMessage(response);
}
Is there something I'm missing?
Thanks!
Have you already tried the following?
$.get('/api/logging/status/12345678', function (data) {
console.log(data);
});
#999cm999,
It seems to me that you need another service method to serve the path to the txt file. You only have a method that serves the file itself as a download. That's how the browser example works.
However, if you want to insert the path to the txt file (http://path.to.my.status.file/status.txt) in an anchor tag of your HTML page, the method that you have does not fit. Create another method that returns the path to the file as a string. Then you can grab that and put it in the HREF attribute of your hyperlink element using jQuery or your favorite JS approach.
Let me know of your findings.
Hi and thanks for looking!
Background
I am using the Rotativa pdf tool to read a view (html) into a PDF. It works great, but it does not natively offer a way to save the PDF to a file system. Rather, it only returns the file to the user's browser as a result of the action.
Here is what that code looks like:
public ActionResult PrintQuote(FormCollection fc)
{
int revisionId = Int32.Parse(Request.QueryString["RevisionId"]);
var pdf = new ActionAsPdf(
"Quote",
new { revisionId = revisionId })
{
FileName = "Quote--" + revisionId.ToString() + ".pdf",
PageSize = Rotativa.Options.Size.Letter
};
return pdf;
}
This code is calling up another actionresult ("Quote"), converting it's view to a PDF, and then returning the PDF as a file download to the user.
Question
How do I intercept the file stream and save the PDF to my file system. It is perfect that the PDF is sent to the user, but my client also wants the PDF saved to the file system simultaneously.
Any ideas?
Thanks!
Matt
I have the same problem, here's my solution:
You need to basically make an HTTP request to your own URL and save the output as a binary file. Simple, no overload, helper classes, and bloated code.
You'll need this method:
// Returns the results of fetching the requested HTML page.
public static void SaveHttpResponseAsFile(string RequestUrl, string FilePath)
{
try
{
HttpWebRequest httpRequest = (HttpWebRequest)WebRequest.Create(RequestUrl);
httpRequest.UserAgent = "Mozilla/5.0 (compatible; MSIE 9.0; Windows NT 6.1; Trident/5.0)";
httpRequest.Headers.Add(HttpRequestHeader.AcceptEncoding, "gzip,deflate");
HttpWebResponse response = null;
try
{
response = (HttpWebResponse)httpRequest.GetResponse();
}
catch (System.Net.WebException ex)
{
if (ex.Status == WebExceptionStatus.ProtocolError)
response = (HttpWebResponse)ex.Response;
}
using (Stream responseStream = response.GetResponseStream())
{
Stream FinalStream = responseStream;
if (response.ContentEncoding.ToLower().Contains("gzip"))
FinalStream = new GZipStream(FinalStream, CompressionMode.Decompress);
else if (response.ContentEncoding.ToLower().Contains("deflate"))
FinalStream = new DeflateStream(FinalStream, CompressionMode.Decompress);
using (var fileStream = System.IO.File.Create(FilePath))
{
FinalStream.CopyTo(fileStream);
}
response.Close();
FinalStream.Close();
}
}
catch
{ }
}
Then inside your controller, you call it like this:
SaveHttpResponseAsFile("http://localhost:52515/Management/ViewPDFInvoice/" + ID.ToString(), "C:\\temp\\test.pdf");
And voilĂ ! The file is there on your file system and you can double click and open the PDF, or email it to your users, or whatever you need.
return new Rotativa.ActionAsPdf("ConvertIntoPdf")
{
FileName = "Test.pdf", PageSize = Rotativa.Options.Size.Letter
};
Take a look at the MVC pipeline diagram here:
http://www.simple-talk.com/content/file.ashx?file=6068
The method OnResultExecuted() is called after the ActionResult is rendered.
You can override this method or use an ActionFilter to apply and OnResultExecuted interceptor using an attribute.
Edit:
At the end of this forum thread you will find a reply which gives an example of an ActionFilter which reads (and changes) the response stream of an action. You can then copy the stream to a file, in addition to returning it to your client.
I successfully used Aaron's 'SaveHttpResponseAsFile' method, but I had to alter it, as the currently logged in user's credentials weren't applied (and so it was forwarding to MVC4's login url).
public static void SaveHttpResponseAsFile(System.Web.HttpRequestBase requestBase, string requestUrl, string saveFilePath)
{
try
{
*snip*
httpRequest.Headers.Add(HttpRequestHeader.AcceptEncoding, "gzip,deflate");
httpRequest.Headers.Add(HttpRequestHeader.Cookie, requestBase.Headers["Cookie"]);
*snip*</pre></code>
Then in your calling Controller method, simply add 'Request' into the SaveHttpResponseAsFile call.
You can also do it using Rotativa, which is actually quite easy.
Using Rotativa;
...
byte[] pdfByteArray = Rotativa.WkhtmltopdfDriver.ConvertHtml( "Rotativa", "-q", stringHtmlResult );
File.WriteAllBytes( outputPath, pdfByteArray );
I'm using this in a winforms app, to generate and save the PDFs from Razor Views we also use in our web apps.
I was able to get Eric Brown - Cal 's solution to work, but I needed a small tweak to prevent an error I was getting about the directory not being found.
(Also, looking at the Rotativa code, it looks like the -q switch is already being passed by default, so that might not be necessary, but I didn't change it.)
var bytes = Rotativa.WkhtmltopdfDriver.ConvertHtml(Server.MapPath(#"/Rotativa"), "-q", html);