This question already has answers here:
Checking if my Windows application is running
(9 answers)
Closed 8 years ago.
I tried to do it this way:
using System;
using System.Collections.Generic;
using System.Linq;
using System.Windows.Forms;
using System.Diagnostics;
using DannyGeneral;
namespace mws
{
static class Program
{
/// <summary>
/// The main entry point for the application.
/// </summary>
[STAThread]
static void Main()
{
try
{
if (IsApplicationAlreadyRunning() == true)
{
MessageBox.Show("The application is already running");
}
else
{
Application.EnableVisualStyles();
Application.SetCompatibleTextRenderingDefault(false);
Application.Run(new Form1());
}
}
catch (Exception err)
{
Logger.Write("error " + err.ToString());
}
}
static bool IsApplicationAlreadyRunning()
{
string proc = Process.GetCurrentProcess().ProcessName;
Process[] processes = Process.GetProcessesByName(proc);
if (processes.Length > 1)
{
return true;
}
else
{
return false;
}
}
}
}
But I'm getting some problems.
First, when I'm loading my project in Visual Studio and then running my program it's detecting the vshost.exe file of my project for example: My project.vshost
And I want that it will detect if my program is running only when I'm running the program only if it find the .exe for example: My project.exe not the vshost.
Have a look at using a mutex.
static class Program {
static Mutex mutex = new Mutex(true, "{8F6F0AC4-B9A1-45fd-A8CF-72F04E6BDE8F}");
[STAThread]
static void Main() {
if(mutex.WaitOne(TimeSpan.Zero, true)) {
try
{
Application.EnableVisualStyles();
Application.SetCompatibleTextRenderingDefault(false);
Application.Run(new Form1());
}
finally
{
mutex.ReleaseMutex();
}
} else {
MessageBox.Show("only one instance at a time");
}
}
}
If our app is running, WaitOne will return false, and you'll get a message box.
As #Damien_The_Unbeliever pointed out correctly, you should change the Guid of the mutex for each application you write!
Source: http://sanity-free.org/143/csharp_dotnet_single_instance_application.html
Could you please try below snippet?
private static void Main(string[] args)
{
if (IsApplicationAlreadyRunning())
{
Console.Write("The application is already running");
}
else
{
Console.Write("The application is not running");
}
Console.Read();
}
static bool IsApplicationAlreadyRunning()
{
return Process.GetProcesses().Count(p => p.ProcessName.Contains(Assembly.GetExecutingAssembly().FullName.Split(',')[0]) && !p.Modules[0].FileName.Contains("vshost")) > 1;
}
Related
This question already has an answer here:
How to ignore win32 exception? module process
(1 answer)
Closed 5 years ago.
I tried to create to look dll that loaded in process, but I got an error when getting process with system.dll. It throws this error message:
System.ComponentModel.Win32Exception: 'Unable to enumerate the process modules.'
My code:
using System;
using System.Diagnostics;
using System.Threading;
namespace dll
{
class Program
{
static void Main(string[] args)
{
Process[] processlist = Process.GetProcesses();
foreach (Process process in processlist)
{
foreach (ProcessModule module in process.Modules)
{
if (module.FileName.Contains("foo.dll"))
{
Console.WriteLine(module.FileName);
Console.ReadLine();
}
}
}
}
}
}
What is this? How to fix this?
This is not the final answer but better fits here then in a comment.
Try using this code to catch the exception and print it to the console. Then you can see the full stacktrace in the console. With this stacktrace you can further resolve the error.
You probably trying to access a MainModule where you don't have access too.
using System;
using System.ComponentModel;
using System.Diagnostics;
using System.Threading;
namespace dll {
class Program {
static void Main(string[] args) {
try {
Process[] processlist = Process.GetProcesses();
foreach(Process process in processlist) {
foreach(ProcessModule module in process.Modules) {
if(module.FileName.Contains("foo.dll")) {
Console.WriteLine(module.FileName);
}
}
}
}
catch(Win32Exception ex) {
Console.WriteLine(ex.ToString());
}
Console.ReadLine();
}
}
}
It probably fails on this line: foreach(ProcessModule module in process.Modules) so you know it can't access one or more of the modules. Probably due to system restrictions.
If you only want to check the modules and therefore accept that not all the modules are checked then you can do this.
using System;
using System.ComponentModel;
using System.Diagnostics;
using System.Threading;
namespace dll {
class Program {
static void Main(string[] args) {
int noErrorCount = 0;
int errorCount = 0;
Process[] processlist = Process.GetProcesses();
foreach(Process process in processlist) {
try {
foreach(ProcessModule module in process.Modules) {
if(module.FileName.Contains("foo.dll")) {
Console.WriteLine(module.FileName);
}
noErrorCount++;
}
}
catch(Win32Exception ex) {
errorCount++;
}
}
Console.WriteLine("Modules checked: " + noErrorCount);
Console.WriteLine("Modules with error(not checked): " + errorCount);
Console.ReadLine();
}
}
}
Code in an infinite loop
using System;
using System.ComponentModel;
using System.Diagnostics;
using System.Threading;
namespace dll {
class Program {
static void Main(string[] args) {
try {
while(true) {
int noErrorCount = 0;
int errorCount = 0;
Process[] processlist = Process.GetProcesses();
foreach(Process process in processlist) {
try {
foreach(ProcessModule module in process.Modules) {
if(module.FileName.ToLower().Contains("Kernel32.dll".ToLower())) {
Console.WriteLine(module.FileName);
}
//Console.WriteLine(module.FileName);
noErrorCount++;
}
}
catch(Win32Exception ex) {
errorCount++;
}
}
Console.WriteLine("Modules checked: " + noErrorCount);
Console.WriteLine("Modules with error(not checked): " + errorCount);
}
}
catch(Exception ex) {
Console.WriteLine(ex.ToString());
Console.ReadLine();
}
}
}
}
Here is my code
I tried in Debug Mode. It works.
While in release does not why? Its a WPF application
This piece of code i put in Main Method for checking if a application is running or not. I want single instance to be running only. I copied this code from Stack Overflow only.
[STAThread]
static void Main()
{
const string MutexName = "{8F6F0AC4-B9A1-45fd-A8CF-72F04E6BDE8F}";
try
{
Mutex mutex = new Mutex(true, MutexName);
if (mutex.WaitOne(TimeSpan.Zero, true))
{
mutex.ReleaseMutex();
//Here Application logic
}
else
{
MessageBox.Show("Application is alreadey running.");
Environment.Exit(1);
}
}
catch
{
Environment.Exit(1);
}
}
I don't know the exact reason. But this modification works
[STAThread]
static void Main()
{
const string MutexName = "8F6F0AC4-B9A1-45fd-A8CF-72F04E6BDE8F";
try
{
Mutex mutex;
if (!Mutex.TryOpenExisting(MutexName, out mutex))
{
mutex = new Mutex(true,MutexName);
var app = new App();
app.Run();
}
else
{
Environment.Exit(1);
}
}
catch
{
Environment.Exit(1);
}
}
The question is that, what happens to a thread when the function has already been executed and the thread is started in that function. (please see an example below)
public int Intialise ()
{
int i = startServer();
Thread readall = new Thread(readAllMessage);
if (i == 1)
readall.Start();
else
MessageBox.Show("Connection Error");
return i;
}
I want 'readall' to continue (forever or till the application is closed) even if the function is executed. Is it possible? Because for me the thread stops immediately even when the true condition is met. Please shed some light.
OK, here is your code slightly modified to include the loop.
internal class Program
{
public static int Intialise()
{
int i = startServer();
Thread readall = new Thread(readAllMessage);
readall.IsBackground = true; // so that when the main thread finishes, the app closes
if (i == 1)
readall.Start();
else
Console.WriteLine("Error");
return i;
}
public static void readAllMessage()
{
while (true)
{
Console.WriteLine("reading...");
Thread.Sleep(500);
}
}
public static int startServer()
{
return 1;
}
private static void Main(string[] args)
{
var i = Intialise();
Console.WriteLine("Init finished, thread running");
Console.ReadLine();
}
}
when you run it, it will print:
Init finished, thread running
reading...
reading...
reading...
and when you press enter (see Console.ReadLine()) it will stop running.
If you change the IsBackground to TRUE it would not exit the process.
Here is an example of what you ask
using System;
using System.Text;
using System.Threading;
using System.Threading.Tasks;
namespace ForeverApp
{
class SomeObj
{
public void ExecuteForever()
{
while (true)
{
Thread.Sleep(1000);
Console.Write(".");
}
}
}
class Program
{
static void Main(string[] args)
{
SomeObj so = new SomeObj();
Thread thrd = new Thread(so.ExecuteForever);
thrd.Start();
Console.WriteLine("Exiting Main Function");
}
}
}
I want my C# .NET application to have a form but not be a form.
When I normally startup a windows forms application, it's like the form is the master of everything else that follows:
static void Main()
{
Application.EnableVisualStyles();
Application.SetCompatibleTextRenderingDefault(false);
Application.Run(new Form1());
}
Instead, I'd like to startup my program, which is then able to show a form, but is not a form itself. In other words, I don't want the master controller of the applicatin being the form, I'd like it instead to be a non-visual logical container, which has the capability to show forms, but isn't a form itself.
I'm not sure if I'm posing the question in a clear way, but I'd like to hear thoughts.
You can just use Application.Run() to get a message-loop running. But you'll need to do something to listen for input - perhaps a systray etc.
You could use an ApplicationContext instead. That gets you the necessary message loop that will keep a form alive, once you decide to create one. Make your Program class look similar to this:
static class Program {
[STAThread]
static void Main() {
Application.EnableVisualStyles();
Application.SetCompatibleTextRenderingDefault(false);
AppContext = new ApplicationContext();
Application.Run(AppContext);
}
public static void Quit() {
AppContext.ExitThread();
}
public static ApplicationContext AppContext;
}
Beware that the app will not close automatically when you close the last window. Calling ExitThread explicitly is required.
It's fairly common to create a separate Bootstrapper component which you could move the display of the main form to:
using System;
using System.Windows.Forms;
namespace Example
{
internal static class Program
{
[STAThread]
private static void Main()
{
new Bootstrapper().Run();
}
}
public class Bootstrapper
{
public void Run()
{
// [Application initialization here]
ShowView();
}
private static void ShowView()
{
Application.EnableVisualStyles();
Application.SetCompatibleTextRenderingDefault(false);
Application.Run(new Form1());
}
}
}
As Mark_Gravell alluded to, Application.Run() blocks until the Form1 closes. You can open your forms on a separate thread, but that thread will be basically consumed by the form. And when you want the exe to exit, you'll have to manually kill each thread. See the following code. (It doesn't create a console window. I got this by creating a default WinForms app and changing the Program class)
using System;
using System.Collections.Generic;
using System.Linq;
using System.Windows.Forms;
using System.Threading;
namespace WindowsFormsApplication1
{
static class Program
{
static List<Thread> threads = new List<Thread>();
/// <summary>
/// The main entry point for the application.
/// </summary>
[STAThread]
static void Main()
{
for (int i = 0; i < 10; i++)
{
StartThread();
System.Threading.Thread.Sleep(500);
}
//kill each thread so the app will exit, otherwise, the app won't close
//until all forms are manually closed...
threads.ForEach(t => t.Abort());
}
static void StartThread()
{
Thread t = new Thread(ShowForm);
threads.Add(t);
t.Start();
}
static void ShowForm()
{
Application.EnableVisualStyles();
Application.SetCompatibleTextRenderingDefault(false);
Application.Run(new Form1());
}
}
}
Create the app as a console app and then call Application.Run as Marc said when you need a form.
You can also create your own ApplicationContext
static void Main()
{
Application.EnableVisualStyles();
Application.SetCompatibleTextRenderingDefault(false);
Application.Run(AppController.Instance);
}
And within AppController.cs
namespace MyApplication
{
public class AppController
{
static AppController _AppController;
public LoginWIndow LoginWIndow;
//Constructor
public void AppController()
{
//Do what you will here, Start login form, bind events, w.e :)
if(true) //Your check
{
ShowLoginWindow();
}
}
public void ShowLoginWindow()
{
LoginWIndow = new LoginWIndow();
LoginWIndow.ClosedForm += new FormClosedEventHander(ExitApplication);
LoginWIndow.Show();
}
public void ExitApplication(Object Sender, FormClosedEventArgs Args)
{
//Some shutdown login Logic, then
Application.Exit();
}
static AppController Instance
{
get
{
if(_AppController == null)
{
_AppController = new AppController();
}
return _AppController;
}
}
}
}
I have a program which only needs a NotifyIcon to work as intended. So I've been trying to get the main form to hide when the program starts.
In frmMain_Load, I tried both
this.Hide();
this.Visible = false;
without success.
They work in other methods, like in the NotifyIcon_MouseClick-method, but I want it to hide at Load.
I saw in another question here at SO where Matias suggested this:
BeginInvoke(new MethodInvoker(delegate
{
Hide();
}));
This works, but when I launch the program I can see the form flashing real fast. It's better than nothing, but I wonder if there is any better solution to this.
Thanks.
// In Your Program.cs Convert This
static void Main()
{
Application.EnableVisualStyles();
Application.SetCompatibleTextRenderingDefault(false);
Application.Run(new Form1());
}
// To This
static void Main()
{
Application.EnableVisualStyles();
Application.SetCompatibleTextRenderingDefault(false);
Form1 TheForm = new Form1();
Application.Run();
}
// Call Application.Exit() From Anywhere To Stop Application.Run() Message Pump and Exit Application
There is an easy way, if your program has the default Visual Studio generated Program.cs file:
[STAThread]
static void Main()
{
Application.EnableVisualStyles ();
Application.SetCompatibleTextRenderingDefault (false);
Application.Run (new MainForm ());
}
the simple fact of calling Run will, indeed make the form visible. Try doing the following in the properties of your form:
Set WindowState to Minimized
Set ShowInTaskbar to false
This should do the trick!
Don't call Show or ShowDialog on your form, you can have your Application.Run target a custom class that then instantiates a form and doesn't show or creates a NotifyIcon instance and handles everything from there.
You can also put this.hide = true in the form_shown event. I believe that event is fired once only and after the load event. You might see alittle flicker though if your form has a lot of controls and/or the computer is slow.
If your program doesn't require a form to run, then the best method is to not have a form at all.
Setup your NotifyIcon in the Program code, and enter a loop until you want to exit the program by setting some value, or calling some method.
In this example setting UserExitCalled to true (Program.UserExitCalled = true) will cause the program to quit.
Here is a brief example:
static class Program {
internal static Boolean UserExitCalled;
/// <summary>
/// The main entry point for the application.
/// </summary>
[STAThread]
static void Main() {
Application.EnableVisualStyles();
Application.SetCompatibleTextRenderingDefault(false);
// Setup your tray icon here
while (!UserExitCalled) {
Application.DoEvents(); // Process windows messages
Thread.Sleep(1);
}
return;
}
}
Here the full program class from one of my system tray applications as a working example.
// *********************************************************************
// [DCOM Productions .NET]
// [DPDN], [Visual Studio Launcher]
//
// THIS FILE IS PROVIDED "AS-IS" WITHOUT ANY WARRANTY OF ANY KIND. ANY
// MODIFICATIONS TO THIS FILE IN ANY WAY ARE YOUR SOLE RESPONSIBILITY.
//
// [Copyright (C) DCOM Productions .NET All rights reserved.]
// *********************************************************************
namespace VisualStudioLauncher
{
using System;
using System.Collections.Generic;
using System.Linq;
using System.Windows.Forms;
using System.Threading;
using VisualStudioLauncher.Common.Objects;
using VisualStudioLauncher.Forms;
using System.Drawing;
using VisualStudioLauncher.Common.Data;
using System.IO;
static class Program
{
#region Properties
private static ProjectLocationList m_ProjectLocationList;
/// <summary>
/// Gets or Sets the ProjectsLocationList
/// </summary>
public static ProjectLocationList ProjectLocationList
{
get
{
return m_ProjectLocationList;
}
set
{
m_ProjectLocationList = value;
}
}
private static ShellProcessList m_ShellProcessList = null;
/// <summary>
/// Gets or Sets the ShellProcessList
/// </summary>
public static ShellProcessList ShellProcessList
{
get
{
return m_ShellProcessList;
}
set
{
m_ShellProcessList = value;
}
}
private static NotifyIcon m_TrayIcon;
/// <summary>
/// Gets the programs tray application.
/// </summary>
public static NotifyIcon TrayIcon
{
get
{
return m_TrayIcon;
}
}
private static bool m_UserExitCalled;
/// <summary>
/// Gets a value indicating whether the user has called for an Application.Exit
/// </summary>
public static bool UserExitCalled
{
get
{
return m_UserExitCalled;
}
set
{
m_UserExitCalled = value;
}
}
// TODO: Finish implementation, then use this for real.
private static ApplicationConfiguration m_ApplicationConfiguration = null;
/// <summary>
/// Gets the application configuration
/// </summary>
public static ApplicationConfiguration ApplicationConfiguration
{
get
{
if (m_ApplicationConfiguration == null)
m_ApplicationConfiguration = ApplicationConfiguration.LoadConfigSection(#"./settings.config");
return m_ApplicationConfiguration;
}
}
#endregion
/// <summary>
/// The main entry point for the application.
/// </summary>
[STAThread]
static void Main(string[] args)
{
if (args.Length > 0)
{
if (args[0].ToLower() == "-rmvptr")
{
for (int i = 1; i < args.Length; i++) {
try {
if (File.Exists(Application.StartupPath + #"\\" + args[i])) {
File.Delete(Application.StartupPath + #"\\" + args[i]);
}
}
catch { /* this isn't critical, just convenient */ }
}
}
}
Application.EnableVisualStyles();
Application.SetCompatibleTextRenderingDefault(false);
SplashForm splashForm = new SplashForm();
splashForm.Show();
while (!UserExitCalled)
{
Application.DoEvents();
Thread.Sleep(1);
}
if (m_TrayIcon != null)
{
m_TrayIcon.Icon = null;
m_TrayIcon.Visible = false;
m_TrayIcon.Dispose();
GC.Collect();
}
}
#region System Tray Management
public static void SetupTrayIcon()
{
m_TrayIcon = new NotifyIcon();
m_TrayIcon.Text = Resources.UserInterfaceStrings.ApplicationName;
m_TrayIcon.Visible = false; // This will be set visible when the context menu is generated
m_TrayIcon.MouseDoubleClick += new MouseEventHandler(m_TrayIcon_MouseDoubleClick);
if (Orcas.IsInstalled)
{
m_TrayIcon.Icon = Orcas.Icon;
}
else if (Whidbey.IsInstalled) {
m_TrayIcon.Icon = Whidbey.Icon;
}
else {
m_TrayIcon.Icon = SystemIcons.Warning;
m_TrayIcon.Text = "Visual Studio is not installed. VSL cannot run properly.";
}
}
static void m_TrayIcon_MouseDoubleClick(object sender, MouseEventArgs e)
{
if (e.Button != MouseButtons.Left)
{
return;
}
SettingsForm settingsForm = new SettingsForm();
settingsForm.Show();
}
#endregion
}
}