I'm working something in Visual Web Developer 2008 Exrepss Edition.
I have 2 aspx file, Default.aspx and Default2.aspx
In Defauly.aspx Design View i have one button, in her properties on option "PostBack URL" i choose Default2.aspx
When i run site and click on Button do not open Default2.aspx?
Can you help me!
Thanks
You can also do it by click event of the button
protected void Button1_Click(object sender, EventArgs e)
{
Response.Redirect("Default3.aspx");
}
make sure that "UseSubmitBehavior" property for the button is set to true.
Related
I am designing a web form for registration purpose with the drag and drop interface. When I add validation control like RegularExpressionValidator and required RequiredFieldValidator it shows this above titled message when I run it.
Turns out i found the solution.
You just need to write this in your C# code
protected void Page_Load(object sender, EventArgs e)
{
this.UnobtrusiveValidationMode = System.Web.UI.UnobtrusiveValidationMode.None;
}
for beginners just double click the components of your page while you are not in debugging mode double clicking a text field will direct you to the C# page.
I am working at a problem in ASP.NET.
I have to create 2 windows (i think that I need to make web forms, i don't know why they said windows) one is the login form, when i press ok and the username and password is ok, I need to
show my second window (webform)
How can I do that?
I tried to do
protected void Button1_Click(object sender, EventArgs e)
{
Form2 form = new Form2();
form.SetFocus("id");
}
But it gives me error
A form tag with runat=server must exist on the Page to use SetFocus() or the Focus property.
What should I do?
Am i right, I have to do separate webforms for thoose windows?
This is the picture from the problem that they provided
If you use webforms you can just use the following code to redirect to second form:
protected void Button1_Click(object sender, EventArgs e)
{
Response.Redirect("Webform2.aspx");
}
I put a linkbutton control named as "Logout" on my webpage with VS 2010.
When users press the "Logout" linkbutton , I want the system to do two things.
First is to trigger a server side click event to do some things such clear all session variables etc..
Second is to redirect to user to another page such logon.aspx
So I wrote following codes
protected void Page_Load(object sender, EventArgs e)
{
if (!this.IsPostBack)
{
LinkButton1.PostBackUrl = "LogOn.aspx";
}
}
protected void LinkButton1_Click(object sender, EventArgs e)
{
Session.Abandon();
....
....
}
But when the programs runs , any user clicks the linkbutton.The codes of LinkButton1_Click never be executed, because the page has already been redirect to Logon.aspx page and never do the LinkButton1_Click()
My Question is why LinkButton1 offers PostBackUrl property and server-side click event , but it seems that they don't cooperate very well ~
This is because by setting the PostBackUrl you are saying that when the button is clicked that you want it to post to the LogOn.aspx page rather than posting back to itself. Since you are posting to LogOn.aspx you will never trigger the event.
Instead, you should use some type of redirect in your button click after your sesion.abandon.
Can you check if there's an event LinkButton1_Click subscribed to a LinkButton1's OnClick?
Then for your second concern since you're referring with ASP.Net, you can handle this with your Global.asax, where you will redirect any user to a login page every time session was destroyed. See reference links below:
1.) SessionStateModule.End Event
2.) Using Session in Global.asax
I'm not using the in-built browser control (ie wrapper) but i'm using Webkit.Net instead
When i click on button1, the WebkitBrowser will navigate to the link typed on textBox1
private void Button1_Click(object sender, EventArgs e)
{
backgroundWorker1.Navigate("https://www.facebook.com/cocacola");
}
Can i detect when user click on the Like button ? For example when the user likes the page, a MessageBox appears and says that the page has been successfully liked !
Anyhelp would be highly appreciated
I'm using Visual c# express 2010, I have 3 tabs and on the first tab there is a button that exits the program. I'm trying to call that button click on the 2nd and 3rd tab with
btnExit.PerformClick();
but since it isn't visible nothing happens. How would I call the invisible button click?
any help would be appreciated
EDIT:
Thanks for the replies, the two answers work great but I found a way that I think is easier and better.
instead of systematically changing tabs or calling a whole different method, I did this
btnExit_Click(sender, e);
I can put that in any other button click and it works great, very simple to.
I think it's better to create a method that actually has the code to exit the program, and call that method from btnExit click event and also other buttons click event, than PerformClick of the exit button.
void ExitApplication()
{
// code to exit the application
}
protected void btnExit_Click(object sender, EventArgs e)
{
ExitApplication();
}
protected void ButtonInOtherTab_Click(object sender, EventArgs e)
{
ExitApplication();
}
This way it's easier to read and understand.
myTabs.SelectedTab = specificTab;
btnExit.PerformClick();