Currently struggling to get this process working:
const string pdfkPath = "pdftk.exe";
var paths = new List<string>();
paths.Add(#"C:\test.pdf");
paths.Add(#"C:\testje.pdf");
var cmd = String.Join(" ", paths) + " cat output " + #"C:\lel.pdf";
Process p = new Process();
p.StartInfo.WorkingDirectory = Environment.CurrentDirectory;
p.StartInfo.FileName = pdfkPath;
p.StartInfo.Arguments = cmd;
p.StartInfo.UseShellExecute = false;
p.Start();
p.WaitForExit();
Executing the exe file with the arguments using command line works, so what am I doing wrong here?
Thanks!
Found it ourselves! The problem was the output being directly on the C:\, folder between fixed it
Related
I am trying to redirect the output of my command line program when it is called with Process.Start(). I've tried all permutations of RedirectStandardOutput, UseShellExecute and CreateNowWindow and had no luck.
I know there are other ways of accomplishing this such as reading StandardOutput after this but I would prefer to redirect it with arguments if possible into a file. I only care about the return code and only need the output of myprog.exe to go to a file. My program doesn't need to know what the output is.
var p = new Process();
p.StartInfo.FileName = #"myprog.exe";
p.StartInfo.Arguments = " " + InputFilename + " > " + OutputFilename;
p.StartInfo.RedirectStandardOutput = false;
p.StartInfo.UseShellExecute = false;
p.StartInfo.CreateNoWindow = true;
p.Start();
p.WaitForExit();
var result = p.ExitCode;
This will work for my issue. Get the output with p.StandardOutput.ReadToEnd() and write it to a file.
In C# WPF: I want to execute a CMD command, how exactly can I execute a cmd command programmatically?
Here's a simple example :
Process.Start("cmd","/C copy c:\\file.txt lpt1");
As mentioned by the other answers you can use:
Process.Start("notepad somefile.txt");
However, there is another way.
You can instance a Process object and call the Start instance method:
Process process = new Process();
process.StartInfo.FileName = "notepad.exe";
process.StartInfo.WorkingDirectory = "c:\temp";
process.StartInfo.Arguments = "somefile.txt";
process.Start();
Doing it this way allows you to configure more options before starting the process. The Process object also allows you to retrieve information about the process whilst it is executing and it will give you a notification (via the Exited event) when the process has finished.
Addition: Don't forget to set 'process.EnableRaisingEvents' to 'true' if you want to hook the 'Exited' event.
if you want to start application with cmd use this code:
string YourApplicationPath = "C:\\Program Files\\App\\MyApp.exe"
ProcessStartInfo processInfo = new ProcessStartInfo();
processInfo.WindowStyle = ProcessWindowStyle.Hidden;
processInfo.FileName = "cmd.exe";
processInfo.WorkingDirectory = Path.GetDirectoryName(YourApplicationPath);
processInfo.Arguments = "/c START " + Path.GetFileName(YourApplicationPath);
Process.Start(processInfo);
Using Process.Start:
using System.Diagnostics;
class Program
{
static void Main()
{
Process.Start("example.txt");
}
}
How about you creat a batch file with the command you want, and call it with Process.Start
dir.bat content:
dir
then call:
Process.Start("dir.bat");
Will call the bat file and execute the dir
You can use this to work cmd in C#:
ProcessStartInfo proStart = new ProcessStartInfo();
Process pro = new Process();
proStart.FileName = "cmd.exe";
proStart.WorkingDirectory = #"D:\...";
string arg = "/c your_argument";
proStart.Arguments = arg;
proStart.WindowStyle = ProcessWindowStyle.Hidden;
pro.StartInfo = pro;
pro.Start();
Don't forget to write /c before your argument !!
Argh :D not the fastest
Process.Start("notepad C:\test.txt");
Are you asking how to bring up a command windows? If so, you can use the Process object ...
Process.Start("cmd");
You can do like below:
var command = "Put your command here";
System.Diagnostics.ProcessStartInfo procStartInfo = new System.Diagnostics.ProcessStartInfo("cmd", "/c " + command);
procStartInfo.RedirectStandardOutput = true;
procStartInfo.UseShellExecute = false;
procStartInfo.WorkingDirectory = #"C:\Program Files\IIS\Microsoft Web Deploy V3";
procStartInfo.CreateNoWindow = true; //whether you want to display the command window
System.Diagnostics.Process proc = new System.Diagnostics.Process();
proc.StartInfo = procStartInfo;
proc.Start();
string result = proc.StandardOutput.ReadToEnd();
label1.Text = result.ToString();
In addition to the answers above, you could use a small extension method:
public static class Extensions
{
public static void Run(this string fileName,
string workingDir=null, params string[] arguments)
{
using (var p = new Process())
{
var args = p.StartInfo;
args.FileName = fileName;
if (workingDir!=null) args.WorkingDirectory = workingDir;
if (arguments != null && arguments.Any())
args.Arguments = string.Join(" ", arguments).Trim();
else if (fileName.ToLowerInvariant() == "explorer")
args.Arguments = args.WorkingDirectory;
p.Start();
}
}
}
and use it like so:
// open explorer window with given path
"Explorer".Run(path);
// open a shell (remanins open)
"cmd".Run(path, "/K");
UPDATED...
I want to call kdiff from Console application. So I'm building two files and want to compare they at the end of executing my program:
string diffCmd = string.Format("{0} {1}", Logging.FileNames[0], Logging.FileNames[1]);
// diffCmd = D:\vdenisenko\DbHelper\DbHelper\bin\Debug\Reports\16_Nov 06_30_46_DiscussionThreads_ORIGIN.txt D:\vdenisenko\DbHelper\DbHelper\bin\Debug\Reports\16_Nov 06_30_46_DiscussionThreads_ORIGIN.txt
System.Diagnostics.Process.Start(#"C:\Program Files (x86)\KDiff3\kdiff3.exe", diffCmd);
//specification is here http://kdiff3.sourceforge.net/doc/documentation.html
It runs kdiff3 tool, but something wrong with filenames or command... Could you please look on screenshot and say what is wrong?
You need to use Process.Start():
string kdiffPath = #"c:\Program Files\Kdiff3.exe"; // here is full path to kdiff utility
string fileName = #"d:\file1.txt";
string fileName2 = #"d:\file2.txt";
Process.Start(kdiffPath,String.Format("\"{0}\" \"{1}\"",fileName,fileName2));
Arguments as described in the docs: kdiff3 file1 file2
var args = String.Format("{0} {1}", fileName, fileName2);
Process.Start(kdiffPath, args);
string kdiffPath = #"c:\Program Files\Kdiff3.exe"; // here is full path to kdiff utility
string fileName = #"d:\file1.txt";
string fileName2 = #"d:\file2.txt";
ProcessStartInfo psi = new ProcessStartInfo(kdiffPath);
psi.RedirectStandardOutput = true;
psi.WindowStyle = ProcessWindowStyle.Hidden;
psi.UseShellExecute = false;
psi.Arguments = fileName + " " + fileName2;
Process app = Process.Start(psi);
StreamReader reader = app.StandardOutput;
//get reponse from console app in your app
do
{
string line = reader.ReadLine();
}
while(!reader.EndOfStream);
app.WaitForExit();
This will run the program from your console app
Process p = new Process();
p.StartInfo.FileName = kdiffPath;
p.StartInfo.Arguments = "\"" + fileName + "\" \"" + fileName2 + "\"";
p.Start();
Unless you are trying to do something else, in which case you need to provide more details.
I have this BAT file "iARP.BAT"
Content Begin
#ECHO OFF
npg -vv -f %1 -d %2
Content End
And I'm trying to pass a file name (in a loop) as the first argument and device name (variable previously declared) as the second argument. I'm trying to do this:
for (int i = 1; i < arpFiles.Count; i++) {
p = new Process();
p.StartInfo.UseShellExecute = false;
p.StartInfo.RedirectStandardOutput = true;
p.StartInfo.WorkingDirectory = Application.StartupPath;
p.StartInfo.FileName = Application.StartupPath + "\\iARP.bat";
String argument1 = Application.StartupPath + "\\" + arpFiles[0].Name;
p.StartInfo.Arguments = argument1 + deviceName;
p.StartInfo.Verb = "runas";
p.StartInfo.CreateNoWindow = true;
p.Start();
}
BTW arpFiles = List
but it is not executing can anyone help me with this?
You need to specify them all in the Arguments property:
p.StartInfo.Arguments = string.Format("{0} {1}", argument1, argument2);
All I am trying to do is send a command that opens a model with the program.exe
Supposed to be super simple!
Ex:
"C:\Program Files (x86)\River Logic\Enterprise Optimizer 7.4 Developer\EO74.exe" "C:\PauloXLS\Constraint Sets_1.cor"
The line above works well if pasted on the command prompt window.
However, when trying to pass the same exact string on my code it gets stuck on C:\Program
string EXE = "\"" + #tbx_base_exe.Text.Trim() + "\"";
string Model = "\"" + #mdl_path.Trim()+ "\"";
string ExeModel = EXE + " " + Model;
MessageBox.Show(ExeModel);
ExecuteCommand(ExeModel);
ExeModel is showing te following line on Visual Studio:
"\"C:\\Program Files (x86)\\River Logic\\Enterprise Optimizer 7.4 Developer\\EO74.exe\" \"C:\\PauloXLS\\Constraint Sets_1.cor\""
To me looks like it is the string I need to send in to the following method:
public int ExecuteCommand(string Command)
{
int ExitCode;
ProcessStartInfo ProcessInfo;
Process Process;
ProcessInfo = new ProcessStartInfo("cmd.exe", "/K " + Command);
ProcessInfo.CreateNoWindow = true;
ProcessInfo.UseShellExecute = true;
Process = Process.Start(ProcessInfo);
Process.WaitForExit();
ExitCode = Process.ExitCode;
Process.Close();
return ExitCode;
}
Things I've tried:
Pass only one command at a time (works as expected), but not an option since the model file will open with another version of the software.
Tried to Trim
Tried with # with \"
Can anyone see any obvious mistake? Thanks.
It's pretty straightforward. You just create a command line object then write to it, then to execute it you read back from it using SR.ReadToEnd():
private string GETCMD()
{
string tempGETCMD = null;
Process CMDprocess = new Process();
System.Diagnostics.ProcessStartInfo StartInfo = new System.Diagnostics.ProcessStartInfo();
StartInfo.FileName = "cmd"; //starts cmd window
StartInfo.WindowStyle = ProcessWindowStyle.Hidden;
StartInfo.CreateNoWindow = true;
StartInfo.RedirectStandardInput = true;
StartInfo.RedirectStandardOutput = true;
StartInfo.UseShellExecute = false; //required to redirect
CMDprocess.StartInfo = StartInfo;
CMDprocess.Start();
System.IO.StreamReader SR = CMDprocess.StandardOutput;
System.IO.StreamWriter SW = CMDprocess.StandardInput;
SW.WriteLine("#echo on");
SW.WriteLine("cd\\"); //the command you wish to run.....
SW.WriteLine("cd C:\\Program Files");
//insert your other commands here
SW.WriteLine("exit"); //exits command prompt window
tempGETCMD = SR.ReadToEnd(); //returns results of the command window
SW.Close();
SR.Close();
return tempGETCMD;
}
Why are you opening a command prompt (cmd.exe)? Just pass the name of the executable.