I am trying to write into a csv file row by row using C# language. Here is my function
string first = reader[0].ToString();
string second=image.ToString();
string csv = string.Format("{0},{1}\n", first, second);
File.WriteAllText(filePath, csv);
The whole function runs inside a loop, and every row should be written to the csv file. In my case, next row overwrites the existing row and in the end, I am getting an only single record in the csv file which is the last one. How can I write all the rows in the csv file?
UPDATE
Back in my naïve days, I suggested doing this manually (it was a simple solution to a simple question), however due to this becoming more and more popular, I'd recommend using the library CsvHelper that does all the safety checks, etc.
CSV is way more complicated than what the question/answer suggests.
Original Answer
As you already have a loop, consider doing it like this:
//before your loop
var csv = new StringBuilder();
//in your loop
var first = reader[0].ToString();
var second = image.ToString();
//Suggestion made by KyleMit
var newLine = string.Format("{0},{1}", first, second);
csv.AppendLine(newLine);
//after your loop
File.WriteAllText(filePath, csv.ToString());
Or something to this effect.
My reasoning is: you won't be need to write to the file for every item, you will only be opening the stream once and then writing to it.
You can replace
File.WriteAllText(filePath, csv.ToString());
with
File.AppendAllText(filePath, csv.ToString());
if you want to keep previous versions of csv in the same file
C# 6
If you are using c# 6.0 then you can do the following
var newLine = $"{first},{second}"
EDIT
Here is a link to a question that explains what Environment.NewLine does.
I would highly recommend you to go the more tedious route. Especially if your file size is large.
using(var w = new StreamWriter(path))
{
for( /* your loop */)
{
var first = yourFnToGetFirst();
var second = yourFnToGetSecond();
var line = string.Format("{0},{1}", first, second);
w.WriteLine(line);
w.Flush();
}
}
File.AppendAllText() opens a new file, writes the content and then closes the file. Opening files is a much resource-heavy operation, than writing data into open stream. Opening\closing a file inside a loop will cause performance drop.
The approach suggested by Johan solves that problem by storing all the output in memory and then writing it once. However (in case of big files) you program will consume a large amount of RAM and even crash with OutOfMemoryException
Another advantage of my solution is that you can implement pausing\resuming by saving current position in input data.
upd. Placed using in the right place
Writing csv files by hand can be difficult because your data might contain commas and newlines. I suggest you use an existing library instead.
This question mentions a few options.
Are there any CSV readers/writer libraries in C#?
I use a two parse solution as it's very easy to maintain
// Prepare the values
var allLines = (from trade in proposedTrades
select new object[]
{
trade.TradeType.ToString(),
trade.AccountReference,
trade.SecurityCodeType.ToString(),
trade.SecurityCode,
trade.ClientReference,
trade.TradeCurrency,
trade.AmountDenomination.ToString(),
trade.Amount,
trade.Units,
trade.Percentage,
trade.SettlementCurrency,
trade.FOP,
trade.ClientSettlementAccount,
string.Format("\"{0}\"", trade.Notes),
}).ToList();
// Build the file content
var csv = new StringBuilder();
allLines.ForEach(line =>
{
csv.AppendLine(string.Join(",", line));
});
File.WriteAllText(filePath, csv.ToString());
Instead of calling every time AppendAllText() you could think about opening the file once and then write the whole content once:
var file = #"C:\myOutput.csv";
using (var stream = File.CreateText(file))
{
for (int i = 0; i < reader.Count(); i++)
{
string first = reader[i].ToString();
string second = image.ToString();
string csvRow = string.Format("{0},{1}", first, second);
stream.WriteLine(csvRow);
}
}
You can use AppendAllText instead:
File.AppendAllText(filePath, csv);
As the documentation of WriteAllText says:
If the target file already exists, it is overwritten
Also, note that your current code is not using proper new lines, for example in Notepad you'll see it all as one long line. Change the code to this to have proper new lines:
string csv = string.Format("{0},{1}{2}", first, image, Environment.NewLine);
Instead of reinventing the wheel a library could be used. CsvHelper is great for creating and reading csv files. It's read and write operations are stream based and therefore also support operations with a big amount of data.
You can write your csv like the following.
using(var textWriter = new StreamWriter(#"C:\mypath\myfile.csv"))
{
var writer = new CsvWriter(textWriter, CultureInfo.InvariantCulture);
writer.Configuration.Delimiter = ",";
foreach (var item in list)
{
writer.WriteField( "a" );
writer.WriteField( 2 );
writer.WriteField( true );
writer.NextRecord();
}
}
As the library is using reflection it will take any type and parse it directly.
public class CsvRow
{
public string Column1 { get; set; }
public bool Column2 { get; set; }
public CsvRow(string column1, bool column2)
{
Column1 = column1;
Column2 = column2;
}
}
IEnumerable<CsvRow> rows = new [] {
new CsvRow("value1", true),
new CsvRow("value2", false)
};
using(var textWriter = new StreamWriter(#"C:\mypath\myfile.csv")
{
var writer = new CsvWriter(textWriter, CultureInfo.InvariantCulture);
writer.Configuration.Delimiter = ",";
writer.WriteRecords(rows);
}
value1,true
value2,false
If you want to read more about the librarys configurations and possibilities you can do so here.
using System;
using System.Collections.Generic;
using System.Linq;
using System.Web;
using System.Web.UI;
using System.Web.UI.WebControls;
using System.Data;
using System.Configuration;
using System.Data.SqlClient;
public partial class CS : System.Web.UI.Page
{
protected void ExportCSV(object sender, EventArgs e)
{
string constr = ConfigurationManager.ConnectionStrings["constr"].ConnectionString;
using (SqlConnection con = new SqlConnection(constr))
{
using (SqlCommand cmd = new SqlCommand("SELECT * FROM Customers"))
{
using (SqlDataAdapter sda = new SqlDataAdapter())
{
cmd.Connection = con;
sda.SelectCommand = cmd;
using (DataTable dt = new DataTable())
{
sda.Fill(dt);
//Build the CSV file data as a Comma separated string.
string csv = string.Empty;
foreach (DataColumn column in dt.Columns)
{
//Add the Header row for CSV file.
csv += column.ColumnName + ',';
}
//Add new line.
csv += "\r\n";
foreach (DataRow row in dt.Rows)
{
foreach (DataColumn column in dt.Columns)
{
//Add the Data rows.
csv += row[column.ColumnName].ToString().Replace(",", ";") + ',';
}
//Add new line.
csv += "\r\n";
}
//Download the CSV file.
Response.Clear();
Response.Buffer = true;
Response.AddHeader("content-disposition", "attachment;filename=SqlExport.csv");
Response.Charset = "";
Response.ContentType = "application/text";
Response.Output.Write(csv);
Response.Flush();
Response.End();
}
}
}
}
}
}
Handling Commas
For handling commas inside of values when using string.Format(...), the following has worked for me:
var newLine = string.Format("\"{0}\",\"{1}\",\"{2}\"",
first,
second,
third
);
csv.AppendLine(newLine);
So to combine it with Johan's answer, it'd look like this:
//before your loop
var csv = new StringBuilder();
//in your loop
var first = reader[0].ToString();
var second = image.ToString();
//Suggestion made by KyleMit
var newLine = string.Format("\"{0}\",\"{1}\"", first, second);
csv.AppendLine(newLine);
//after your loop
File.WriteAllText(filePath, csv.ToString());
Returning CSV File
If you simply wanted to return the file instead of writing it to a location, this is an example of how I accomplished it:
From a Stored Procedure
public FileContentResults DownloadCSV()
{
// I have a stored procedure that queries the information I need
SqlConnection thisConnection = new SqlConnection("Data Source=sv12sql;User ID=UI_Readonly;Password=SuperSecure;Initial Catalog=DB_Name;Integrated Security=false");
SqlCommand queryCommand = new SqlCommand("spc_GetInfoINeed", thisConnection);
queryCommand.CommandType = CommandType.StoredProcedure;
StringBuilder sbRtn = new StringBuilder();
// If you want headers for your file
var header = string.Format("\"{0}\",\"{1}\",\"{2}\"",
"Name",
"Address",
"Phone Number"
);
sbRtn.AppendLine(header);
// Open Database Connection
thisConnection.Open();
using (SqlDataReader rdr = queryCommand.ExecuteReader())
{
while (rdr.Read())
{
// rdr["COLUMN NAME"].ToString();
var queryResults = string.Format("\"{0}\",\"{1}\",\"{2}\"",
rdr["Name"].ToString(),
rdr["Address"}.ToString(),
rdr["Phone Number"].ToString()
);
sbRtn.AppendLine(queryResults);
}
}
thisConnection.Close();
return File(new System.Text.UTF8Encoding().GetBytes(sbRtn.ToString()), "text/csv", "FileName.csv");
}
From a List
/* To help illustrate */
public static List<Person> list = new List<Person>();
/* To help illustrate */
public class Person
{
public string name;
public string address;
public string phoneNumber;
}
/* The important part */
public FileContentResults DownloadCSV()
{
StringBuilder sbRtn = new StringBuilder();
// If you want headers for your file
var header = string.Format("\"{0}\",\"{1}\",\"{2}\"",
"Name",
"Address",
"Phone Number"
);
sbRtn.AppendLine(header);
foreach (var item in list)
{
var listResults = string.Format("\"{0}\",\"{1}\",\"{2}\"",
item.name,
item.address,
item.phoneNumber
);
sbRtn.AppendLine(listResults);
}
}
return File(new System.Text.UTF8Encoding().GetBytes(sbRtn.ToString()), "text/csv", "FileName.csv");
}
Hopefully this is helpful.
This is a simple tutorial on creating csv files using C# that you will be able to edit and expand on to fit your own needs.
First you’ll need to create a new Visual Studio C# console application, there are steps to follow to do this.
The example code will create a csv file called MyTest.csv in the location you specify. The contents of the file should be 3 named columns with text in the first 3 rows.
https://tidbytez.com/2018/02/06/how-to-create-a-csv-file-with-c/
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.IO;
namespace CreateCsv
{
class Program
{
static void Main()
{
// Set the path and filename variable "path", filename being MyTest.csv in this example.
// Change SomeGuy for your username.
string path = #"C:\Users\SomeGuy\Desktop\MyTest.csv";
// Set the variable "delimiter" to ", ".
string delimiter = ", ";
// This text is added only once to the file.
if (!File.Exists(path))
{
// Create a file to write to.
string createText = "Column 1 Name" + delimiter + "Column 2 Name" + delimiter + "Column 3 Name" + delimiter + Environment.NewLine;
File.WriteAllText(path, createText);
}
// This text is always added, making the file longer over time
// if it is not deleted.
string appendText = "This is text for Column 1" + delimiter + "This is text for Column 2" + delimiter + "This is text for Column 3" + delimiter + Environment.NewLine;
File.AppendAllText(path, appendText);
// Open the file to read from.
string readText = File.ReadAllText(path);
Console.WriteLine(readText);
}
}
}
public static class Extensions
{
public static void WriteCSVLine(this StreamWriter writer, IEnumerable<string> fields)
{
const string q = #"""";
writer.WriteLine(string.Join(",",
fields.Select(
v => (v.Contains(',') || v.Contains('"') || v.Contains('\n') || v.Contains('\r')) ? $"{q}{v.Replace(q, q + q)}{q}" : v
)));
}
public static void WriteCSVLine(this StreamWriter writer, params string[] fields) => WriteCSVLine(writer, (IEnumerable<string>)fields);
}
This should allow you to write a csv file quite simply. Usage:
StreamWriter writer = new ("myfile.csv");
writer.WriteCSVLine("A", "B"); // A,B
Here is another open source library to create CSV file easily, Cinchoo ETL
List<dynamic> objs = new List<dynamic>();
dynamic rec1 = new ExpandoObject();
rec1.Id = 10;
rec1.Name = #"Mark";
rec1.JoinedDate = new DateTime(2001, 2, 2);
rec1.IsActive = true;
rec1.Salary = new ChoCurrency(100000);
objs.Add(rec1);
dynamic rec2 = new ExpandoObject();
rec2.Id = 200;
rec2.Name = "Tom";
rec2.JoinedDate = new DateTime(1990, 10, 23);
rec2.IsActive = false;
rec2.Salary = new ChoCurrency(150000);
objs.Add(rec2);
using (var parser = new ChoCSVWriter("emp.csv").WithFirstLineHeader())
{
parser.Write(objs);
}
For more information, please read the CodeProject article on usage.
One simple way to get rid of the overwriting issue is to use File.AppendText to append line at the end of the file as
void Main()
{
using (System.IO.StreamWriter sw = System.IO.File.AppendText("file.txt"))
{
string first = reader[0].ToString();
string second=image.ToString();
string csv = string.Format("{0},{1}\n", first, second);
sw.WriteLine(csv);
}
}
enter code here
string string_value= string.Empty;
for (int i = 0; i < ur_grid.Rows.Count; i++)
{
for (int j = 0; j < ur_grid.Rows[i].Cells.Count; j++)
{
if (!string.IsNullOrEmpty(ur_grid.Rows[i].Cells[j].Text.ToString()))
{
if (j > 0)
string_value= string_value+ "," + ur_grid.Rows[i].Cells[j].Text.ToString();
else
{
if (string.IsNullOrEmpty(string_value))
string_value= ur_grid.Rows[i].Cells[j].Text.ToString();
else
string_value= string_value+ Environment.NewLine + ur_grid.Rows[i].Cells[j].Text.ToString();
}
}
}
}
string where_to_save_file = #"d:\location\Files\sample.csv";
File.WriteAllText(where_to_save_file, string_value);
string server_path = "/site/Files/sample.csv";
Response.ContentType = ContentType;
Response.AppendHeader("Content-Disposition", "attachment; filename=" + Path.GetFileName(server_path));
Response.WriteFile(server_path);
Response.End();
You might just have to add a line feed "\n\r".
I'd like to try the performance of MySqlBulkLoader knowing that the Adapter.update() method i'm using is taking roughly 30 mn to run.
I understand you have to go through a file to do it so here is my code :
private void button14_Click(object sender, EventArgs e)
{
string fileName = #"C:\Users\Utilisateur\ds.txt";
if (File.Exists(fileName))
{
File.Delete(fileName);
}
using (StreamWriter sw = File.CreateText(fileName))
{
foreach (DataRow row in Globals.ds.Tables[0].Rows)
{
foreach (object item in row.ItemArray)
{
string itemstr = item.ToString();
sw.Write((string)itemstr + "\t");
}
sw.WriteLine();
}
}
using (var conn = new MySqlConnection(Globals.connString))
{
conn.Open();
MySqlCommand comm = new MySqlCommand("TRUNCATE Song",conn);
comm.ExecuteNonQuery();
var bl = new MySqlBulkLoader(conn)
{
TableName = Globals.ds.Tables[0].ToString(),
Timeout = 600,
FieldTerminator = "\t",
LineTerminator = "\n",
FileName = fileName
};
var numberOfInsertedRows = bl.Load();
Console.WriteLine(numberOfInsertedRows);
}
}
The file is generated ok. but at the var numberOfInsertedRows = bl.Load(); line, i have the following error at run time :
MySql.Data.MySqlClient.MySqlException: 'Can't get stat of '/var/packages/MariaDB10/target/mysql/disk/C:\Users\Utilisateur\ds.txt' (Errcode: 2 "No such file or directory")'
I tried to put "/" instead of "\" in the fileName but it's the same error.
I have no idea what's going on, anyone can help ?
Thanks
By default, MySqlBulkLoader loads a file from the server's file system. To use a local file, set bl.Local = true; before calling bl.Load().
To enable this, you will need to set AllowLoadLocalInfile = True in your connection string; see https://mysqlconnector.net/troubleshooting/load-data-local-infile/
Finally, if you switch to MySqlConnector, you can use its MySqlBulkCopy API to load data directly from a DataTable, instead of first saving it to a local CSV file, then loading that file.
I have a compressed file .rar .7z, .tar and .zip and I want to rename physical file name available in above compressed archived using C#.
I have tried this using a sharpcompress library but I can't find such a feature for rename file or folder name within .rar .7z, .tar and .zip file.
I also have tried using the DotNetZip library but its only support.Zip see what I have tried using DotNetZip library.
private static void RenameZipEntries(string file)
{
try
{
int renameCount = 0;
using (ZipFile zip2 = ZipFile.Read(file))
{
foreach (ZipEntry e in zip2.ToList())
{
if (!e.IsDirectory)
{
if (e.FileName.EndsWith(".txt"))
{
var newname = e.FileName.Split('.')[0] + "_new." + e.FileName.Split('.')[1];
e.FileName = newname;
e.Comment = "renamed";
zip2.Save();
renameCount++;
}
}
}
zip2.Comment = String.Format("This archive has been modified. {0} files have been renamed.", renameCount);
zip2.Save();
}
}
catch (Exception ex)
{
MessageBox.Show(ex.ToString());
}
}
But actually the same as above I also want for .7z, .rar and .tar, I tried many libraries but still I didn't get any accurate solution.
Please help me.
This is a simple console application to rename files in .zip
using System;
using System.IO;
using System.IO.Compression;
using System.Linq;
using System.Text;
namespace Renamer
{
class Program
{
static void Main(string[] args)
{
using var archive = new ZipArchive(File.Open(#"<Your File>.zip", FileMode.Open, FileAccess.ReadWrite), ZipArchiveMode.Update);
var entries = archive.Entries.ToArray();
//foreach (ZipArchiveEntry entry in entries)
//{
// //If ZipArchiveEntry is a directory it will have its FullName property ending with "/" (e.g. "some_dir/")
// //and its Name property will be empty string ("").
// if (!string.IsNullOrEmpty(entry.Name))
// {
// var newEntry = archive.CreateEntry($"{entry.FullName.Replace(entry.Name, $"{RandomString(10, false)}{Path.GetExtension(entry.Name)}")}");
// using (var a = entry.Open())
// using (var b = newEntry.Open())
// a.CopyTo(b);
// entry.Delete();
// }
//}
Parallel.ForEach(entries, entry =>
{
//If ZipArchiveEntry is a directory it will have its FullName property ending with "/" (e.g. "some_dir/")
//and its Name property will be empty string ("").
if (!string.IsNullOrEmpty(entry.Name))
{
ZipArchiveEntry newEntry = archive.CreateEntry($"{entry.FullName.Replace(entry.Name, $"{RandomString(10, false)}{Path.GetExtension(entry.Name)}")}");
using (var a = entry.Open())
using (var b = newEntry.Open())
a.CopyTo(b);
entry.Delete();
}
});
}
//To Generate random name for the file
public static string RandomString(int size, bool lowerCase)
{
StringBuilder builder = new StringBuilder();
Random random = new Random();
char ch;
for (int i = 0; i < size; i++)
{
ch = Convert.ToChar(Convert.ToInt32(Math.Floor(26 * random.NextDouble() + 65)));
builder.Append(ch);
}
if (lowerCase)
return builder.ToString().ToLower();
return builder.ToString();
}
}
}
Consider 7zipsharp:
https://www.nuget.org/packages/SevenZipSharp.Net45/
7zip itself supports lots of archive formats (I believe all you mentioned) and 7zipsharp uses the real 7zip. I've used 7zipsharp for .7z files only but I bet it works for others.
Here's a sample of a test that appears to rename a file using ModifyArchive method, I suggest you go to school in it:
https://github.com/squid-box/SevenZipSharp/blob/f2bee350e997b0f4b1258dff520f36409198f006/SevenZip.Tests/SevenZipCompressorTests.cs
Here's the code simplified a bit. Note that the test compresses a 7z file for its test; that's immaterial it could be .txt, etc. Also note it finds the file by index in the dictionary passed to ModifyArchive. Consult documentation for how to get that index from a filename (maybe you have to loop and compare).
var compressor = new SevenZipCompressor( ... snip ...);
compressor.CompressFiles("tmp.7z", #"Testdata\7z_LZMA2.7z");
compressor.ModifyArchive("tmp.7z", new Dictionary<int, string> { { 0, "renamed.7z" }});
using (var extractor = new SevenZipExtractor("tmp.7z"))
{
Assert.AreEqual(1, extractor.FilesCount);
extractor.ExtractArchive(OutputDirectory);
}
Assert.IsTrue(File.Exists(Path.Combine(OutputDirectory, "renamed.7z")));
Assert.IsFalse(File.Exists(Path.Combine(OutputDirectory, "7z_LZMA2.7z")));
I am reading an excel file using my controller. I am storing all the lines of CSV file in an array. When I print it out, I can see the contents of array. But when I iterate through each of the lines and split by comma, I get nothing and as a result I can't store read values.
Here is a sample of my output along with code:
VAWC Neptune flat file is my file. 206 are number of lines in file. Then I am printing line along with its length. And when this line is splitted by commas, I see only first output else everything is empty.
However as we keep on reading other lines, this splitted array doesn't appear.
Here is the section of code which I am using:
//files is only having a single file named VAWC Neptune flat file - new meters for inventory.csv
public ActionResult ReadFile(IEnumerable<HttpPostedFileBase> files)
{
var fileName = Path.GetFileName(files.First().FileName);
var destinationPath = Path.Combine(Server.MapPath("~/App_Data"), fileName);
files.First().SaveAs(destinationPath);
try
{
string[] read = System.IO.File.ReadAllLines(destinationPath);
System.Diagnostics.Debug.WriteLine(read.Length);
for (int i = 0; i < read.Length; i++)
{
System.Diagnostics.Debug.WriteLine(read[i]);
List<string> s = read[i].Replace(Environment.NewLine,"").Split(new char[] { ',' }, StringSplitOptions.None).ToList<string>();
System.Diagnostics.Debug.WriteLine("Length of words in line:" + s.Capacity);
for (int j = 0; j < s.Capacity; j++)
{
System.Diagnostics.Debug.WriteLine("Data:s[" + j + "]" + s[j]);
}
}
}
I have tried so many possible ways but nothing has worked.
From Excel to CSV, right. This is how I would do it.
using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;
using Excel = Microsoft.Office.Interop.Excel;
namespace WindowsFormsApplication1
{
public partial class Form1 : Form
{
public Form1()
{
InitializeComponent();
}
private void button1_Click(object sender, EventArgs e)
{
Excel.Application xlApp = new Excel.Application();
Excel.Workbook xlWorkBook = xlApp.Workbooks.Open(#"C:\Users\Ryan\Desktop\Coding\DOT.NET\Samples C#\Excel Workbook - Save Each Sheet as a CSV File\Book1.xlsx");
xlApp.Visible = true;
foreach (Excel.Worksheet sht in xlWorkBook.Worksheets)
{
sht.Select();
xlWorkBook.SaveAs(string.Format("{0}{1}.csv", #"C:\Users\Ryan\Desktop\Coding\DOT.NET\Samples C#\Excel Workbook - Save Each Sheet as a CSV File to CSV\", sht.Name), Excel.XlFileFormat.xlCSV, Excel.XlSaveAsAccessMode.xlNoChange);
}
xlWorkBook.Close(false);
}
}
}
I am building a front end to parse some text files using Stanford Core NLP in C#. I open a file selection dialog and select some text files. Then the following method works from there on.
using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Windows.Forms;
using System.IO;
using System.Text.RegularExpressions;
using java.util;
using java.io;
using edu.stanford.nlp.pipeline;
namespace Parser_SVO
{
public partial class Form1 : Form
{
public static List<string> textFiles = new List<string>();
public Form1()
{
InitializeComponent();
}
private void button1_Click(object sender, EventArgs e)
{
OpenFileDialog openFileDialog1 = new OpenFileDialog();
openFileDialog1.ShowReadOnly = true;
openFileDialog1.Filter = "Text Files|*.txt";
if (openFileDialog1.ShowDialog() == System.Windows.Forms.DialogResult.OK)
{
textFiles.AddRange(openFileDialog1.FileNames);
}
parseText();
}
public static void parseText()
{
label2.Text = "Stanford Parser....";
// Path to the folder with models extracted from `stanford-corenlp-3.7.0-models.jar`
string jarRoot = "";
string prettyPrint = "";
if (textFiles.Count != 0)
{
jarRoot = Path.GetDirectoryName(textFiles[0]) + #"\Models\";
prettyPrint = Path.GetDirectoryName(textFiles[0]);
Directory.CreateDirectory(prettyPrint + #"\PrettyPrint\");
prettyPrint = prettyPrint + #"\PrettyPrint\";
}
// Annotation pipeline configuration
var props = Properties();
props.setProperty("annotators", "tokenize, ssplit, pos, lemma, ner, parse, dcoref");
props.setProperty("ner.useSUTime", "0");
// We should change current directory, so StanfordCoreNLP could find all the model files automatically
var curDir = Environment.CurrentDirectory;
Directory.SetCurrentDirectory(jarRoot);
var pipeline = new StanfordCoreNLP(props);
Directory.SetCurrentDirectory(curDir);
foreach (string file in textFiles)
{
label3.Text = file;
// Text for processing
var text = System.IO.File.ReadAllText(file);
// Annotation
var annotation = new Annotation(text);
pipeline.annotate(annotation);
// Result - Pretty Print
string output = prettyPrint + Path.GetFileName(file);
using (var stream = new ByteArrayOutputStream())
{
pipeline.prettyPrint(annotation, new PrintWriter(stream));
System.IO.File.AppendAllText(output, stream.toString()+Environment.NewLine);
stream.close();
}
}
}
}
}
I have modified the example from official StanfordCoreNLP .Net port here.
Since I am using Windows Forms instead of Console application, this line of code is creating problem: var props = Properties();. I am not sure how to find the namespace of this method to provide a complete namespace.class.method path to disambiguate.
Another minor problem is that I want to update label text as in label2.Text = "Stanford Parser...."; but visual studio says that "An object reference is required" while I am in the same class (Forms1.cs). Your help will be greatly appreciated.
The Properties() class is java.util.Properties.
Simply remove static from the method name to access windows forms objects like text box or label.