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file xml inside multiple xml in one line

I have a file .xml inside multiple xml in one line.
How can I read this file and convert to object?
I tried with this code it works if there is only one.
Please help and thank you all
[XmlRoot(ElementName = "DepartmentMaster")]
public class DepartmentMaster
{
[XmlElement(ElementName = "DepartmentId")]
public int DepartmentId { get; set; }
[XmlElement(ElementName = "Name")]
public string Name { get; set; }
[XmlElement(ElementName = "Description")]
public string Description { get; set; }
[XmlElement(ElementName = "test")]
public int Test { get; set; }
}
//string xml = "<DepartmentMaster><DepartmentId>267854</DepartmentId><Name>Purchase</Name><Description>Purchase Department</Description><test>1</test></DepartmentMaster>";
string xml = "<DepartmentMaster><DepartmentId>267854</DepartmentId><Name>Purchase</Name><Description>Purchase Department</Description><test>1</test></DepartmentMaster><DepartmentMaster><DepartmentId>267855</DepartmentId><Name>Purchase5</Name><Description>Purchase Department5</Description><test>5</test></DepartmentMaster>";
using (TextReader reader = new StringReader(xml))
{
System.Xml.Serialization.XmlSerializer deserializer = new System.Xml.Serialization.XmlSerializer(typeof(DepartmentMaster));
var model = (DepartmentMaster)deserializer.Deserialize(reader);
}
image from the database
image from the database

Here it is two approaches below.
The first is using setting to accept XML data with multiple root elements (ConformanceLevel.Fragment).
private static IList<DepartmentMaster> DeserializeFragment(string xml)
{
var settings = new XmlReaderSettings
{
ConformanceLevel = ConformanceLevel.Fragment
};
XmlReader reader = XmlReader.Create(new MemoryStream(Encoding.ASCII.GetBytes(xml)), settings);
var serializer = new XmlSerializer(typeof(DepartmentMaster));
var list = new List<DepartmentMaster>();
while (serializer.Deserialize(reader) is DepartmentMaster element)
{
list.Add(element);
}
return list;
}
And the second by adding a root element to deserialize a well-formed XML document.
public class DepartmentMasters
{
[XmlElement("DepartmentMaster")]
public List<DepartmentMaster> Items;
}
private static DepartmentMasters DeserializeWellFormedXML(string xml)
{
var text = #"<?xml version=""1.0""?><DepartmentMasters>" + xml + "</DepartmentMasters>";
var serializer = new XmlSerializer(typeof(DepartmentMasters));
return (DepartmentMasters)serializer.Deserialize(new StringReader(text));
}

C# Xml Deserialize, ignore data in XML

During de-serialization, how do I ignore a property? In my case, I don't want the FullName property to get initialized at all. I am not looking for [XMLIgnore] solutions - think it as a scenario where I don't have access to change the class.
Here's my class:
public class Person
{
public int Id { get; set; }
public string FullName { get; set; }
}
Here's how I am initializing:
Person p1 = new Person() { Id = 1, FullName = "P1" };
Person p2 = new Person() { Id = 2, FullName = "P2" };
List<Person> persons = new List<Person> { p, q }; //this object is xml serialized.
And here's my XML: ( I got it though the XML Serialization)
<?xml version="1.0" encoding="utf-8"?>
<ArrayOfPerson xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<Person>
<Id>1</Id>
<FullName>P1</FullName>
</Person>
<Person>
<Id>2</Id>
<FullName>P2</FullName>
</Person>
</ArrayOfPerson>

You can use a custom XmlReader in the deserialization process that will simply skip over the FullName elements. Something like this:
public class MyXmlReader : XmlTextReader
{
public MyXmlReader(string filePath) : base(filePath)
{
}
public override bool Read()
{
if (base.Read())
{
if (Name == "FullName")
return base.Read();
return true;
}
return false;
}
}
Then use it like this
var serializer = new XmlSerializer(typeof(List<Person>));
using (var reader = new MyXmlReader("XMLFile.xml"))
{
var person = (List<Person>)serializer.Deserialize(reader);
}
You can implement a different constructor to take a stream or whatever you have. It doesn't have to be a file path.

How do i add data from XML to list<>?

I try to read from an xml file, but its very clonky and a lot of the data I get is in bunch from a child. I get the Name, Age, and so on in one and therefor I can't add it to a list.
My xml-file looks like this:
<?xml version="1.0" encoding="UTF-8"?><People>
<Person>
<Age>30</Age>
<Name>Boy</Name>
<Sex>Male</Sex>
</Person>
<Person>
<Age>28</Age>
<Name>Girl</Name>
<Sex>Female</Sex>
</Person>
And in my xaml.cs file I have:
List<listTest> a = new List<listTest>();
var localFolder = ApplicationData.Current.LocalFolder;
XmlDocument xmlDocument;
var file = await localFolder.TryGetItemAsync("FoodData.xml") as IStorageFile;
xmlDocument = await XmlDocument.LoadFromFileAsync(file);
And with that I need to make a setup where I can take data from the XML and put it into list<> like this:
a.add(listTest {Name = "*DATA FROM XML*", Age ="*DATA FROM XML*", Sex="*DATA FROM XML*"});
I have tried to use LINQ and use p.NodeName == "xxx" to make searches, but I don't seem to get any data out.
Can some one show me how to get the data from my xml to a list?

Let's assume you have this class:
public class Person
{
public string Name { get; set; }
public string Sex { get; set; }
public int Age { get; set; }
}
Then, to load your XML file, you could do something like:
var doc = XDocument.Load("path to your file");
var people = doc.Root
.Descendants("person")
.Select(node => new Person
{
Name = node.Element("name").Value,
Sex = node.Element("sex").Value,
Age = int.Parse(node.Element("age").Value)
})
.ToList();
See https://msdn.microsoft.com/en-us/library/bb353813.aspx

Here is a simple example of an XML import. After this code executes, results will reflect if people were found (true or false), and msg will be a list of error messages (or empty if success).
var results = true;
var msg = new List<string>(0);
XDocument aDocument = null;
try
{
aDocument = XDocument.Load("");
}
catch (Exception e)
{
results = false;
msg.Add(string.Format("Unable to open file:{0}", ""));
msg.Add(e.Message);
}
if (aDocument != null)
{
var thePeople = aDocument.Descendants("Person").ToArray();
if (thePeople.Any())
{
// there were people in the file. People is an array of XML Nodes containing your person.
foreach (var pers in thePeople.Select(p => new Person().FromXML(p)))
{
// here is a person
}
}
else
{
results = false;
msg.Add("No people found.");
}
}
Hope this helps.
Addition.
You could do something like this in your Person Class. I've added code to the original to illustrate usage.
public class Person
{
public string Name { get; set; }
public int Age { get; set; }
public string Sex { get; set; }
public XElement ToXML()
{
return new XElement("Person", "Name", Name,
new XElement("Age", Age),
new XElement("Sex", Sex));
}
public Person FromXML(XElement node)
{
try { Name = node.Element("Name").Value; }
catch { Name = "Not Found"; }
try { Age = Convert.ToInt16(node.Element("Age").Value); }
catch { Age = -1; }
try { Sex = node.Element("Sex").Value; }
catch { Sex = ""; }
return this;
}
}

Convert a list from html into xml format

I am trying to convert a html list to xml format with a console application, but i did what i planned and now i dont know how to continue. I will share my code and explain a bit. What i dont know for now , and is confusing me is where the 'magic' happens. Ok i know i have to take that list from the page , read the list with all the tags inside, but what next, how can i transform that list into xml format? I am new to xml i know some basics so please help me.
Here is the application :
static void Main(string[] args)
{
string _url = "http://example.com/media";
int newsCounter = 0;
List<News> _newsList = new List<News>();
HtmlWeb web = new HtmlWeb();
HtmlDocument doc = web.Load(_url);
HtmlNode ulNode = doc.DocumentNode.SelectSingleNode("//ul[#class='content articles']");
HtmlNodeCollection liNode = ulNode.SelectNodes(".//li");
foreach (HtmlNode node in ulNode.SelectNodes(".//div[#class='article_box']"))
{
var news = new News();
news.Imgsrc = node.FirstChild.SelectSingleNode("//img").Attributes["src"].Value;
var nodes = doc.DocumentNode.FirstChild.SelectNodes("//img[#src]");
foreach (HtmlNode childNode in node.SelectNodes(".//div[#class='box_info']"))
{
// string src = node.SelectSingleNode("//img").Attributes["src"].Value;
foreach(HtmlNode _node in childNode.SelectNodes(".//h3"))
{
news.Link = "";
news.Title = _node.FirstChild.InnerText;
news.Date = _node.NextSibling.NextSibling.InnerText;
news.Text = _node.NextSibling.NextSibling.NextSibling.NextSibling.InnerText;
}
}
_newsList.Add(news);
newsCounter++;
}
and also the News class :
public class News
{
public string Imgsrc { get; set; }
public string Title { get; set; }
public string Link { get; set; }
public string Date { get; set; }
public string Text { get; set; }
}
these are all the parameters i have to read from the list.I am able to read them and return all of the news in my list , but what next , how to transform my list into xml format? Any suggestions are welcomed.

There are many way of creating xml. There are not a lot of items in your case so just using Xml linq is very simple. Putting it into a class may produce cleaner code or you can just use the code directly like Sledge suggested.
public class News
{
public string Imgsrc { get; set; }
public string Title { get; set; }
public string Link { get; set; }
public string Date { get; set; }
public string Text { get; set; }
public XElement ToXml()
{
return new XElement("news", new object[] {
new XElement("Imgscr", Imgsrc),
new XElement("Title", Title),
new XElement("Link", Link),
new XElement("Date", Date),
new XElement("Text", Text),
});
}
}

Thanks to everyone guys. I marked 'News' class as Serializable and with a few lines of code managed to generate the xml file. Here is the code, really simple :
XmlSerializer serializer = new XmlSerializer(typeof(List<News>));
using (TextWriter writer = new StreamWriter(#"D:\News.xml"))
{
serializer.Serialize(writer, _newsList);
}

Deserializing xml with inner array

I'm trying to deserialize simple xml file:
<thesaurus xmlns="http://marklogic.com/xdmp/thesaurus">
<metadata>
</metadata>
<entry>
<term>a</term>
<synonym>
<term>as</term>
</synonym>
</entry>
<entry>
<term>b</term>
<synonym>
<term>bs</term>
</synonym>
<synonym>
<term>bss</term>
</synonym>
</entry>
</thesaurus>
I'm using XmlSerializer like this:
var xmlSerializer = new XmlSerializer(typeof(Thesaurus));
var thesaurus = xmlSerializer.Deserialize(stream);
My model looks like this:
[Serializable]
[XmlRoot("thesaurus", Namespace = "http://marklogic.com/xdmp/thesaurus")]
public class Thesaurus
{
[XmlElement("metadata")]
public Metadata Metadata { get; set; }
[XmlElement("entry")]
public List<Entry> Entries { get; set; }
}
public class Metadata
{
}
public class Entry
{
[XmlElement("term")]
public string Term { get; set; }
[XmlElement("synonym")]
public String[] Synonym { get; set; }
}
So when I'm running this code, I get deserialized thesaurus object with parsed metadata and 1 entry with filled term and synonym fields. I can't get all of the entries here.
BUT
when I comment out Synonym field it starts giving me 2 entries in thesaurus object. I can't wrap entries in <entries> tag because it's some internal format of an application I'm feeding with this xml file.
Anyone has any ideas how to parse this xml file correctly? I tried searching for a solution, but this xml looks quite different than ones in examples.

Ok, so if you need to keep inside synonim field array of terms fields you need to change your Entry class to something like this:
public class Entry
{
[XmlElement("term")]
public string Term { get; set; }
[XmlElement("synonim")]
public Term[] Synonym { get; set; }
}
also you'll need to add additional one:
public class Term
{
[XmlElement("term")]
public string Value { get; set; }
}
This way you'll have what you need.
So, additional hierarchy level was added by additional class.
Please find below code for your test:
var xmlSerializer = new XmlSerializer(typeof(Thesaurus));
var r = new Thesaurus();
r.Entries = new List<Entry>();
r.Metadata = new Metadata();
r.Entries.Add(new Entry()
{
Synonym = new Term[] { new Term(){Value = "1"}, new Term() {Value = "2"}, },
Term = "Term1"
});
r.Entries.Add(new Entry()
{
Synonym = new Term[] { new Term() { Value = "3" }, new Term() { Value = "4" }, },
Term = "Term2"
});
using (TextWriter writer = new StreamWriter(#"c:\111.xml"))
{
xmlSerializer.Serialize(writer, r);
writer.Close();
}
using (TextReader reader = new StreamReader(#"c:\111.xml"))
{
Thesaurus tt = xmlSerializer.Deserialize(reader) as Thesaurus;
Console.Write(tt.Entries.Count);
reader.Close();
}