I want to know what is the best way to assign a value to textbox 2 instantly as the user write this value in textbox 1 ie. Directly showing what the user is entering in textbox1 also in textbox2 at the same. I'm using MVC5 aspx pages..
Any help is highly appreciated. Thanks in advance
Add a onkeyup event listener to your first element(Whenever a key is pressed, the value in first textbox is also entered in second.). Then call the function like
function enterAmt(ev) {
document.getElementById('amt2').value = ev.value;
}
You have to use javascript or jquery for it, suppose you have two textboxes.
HTML:
<input type="text" id="txtBox1"/>
<input type="text" id="txtBox2"/>
You have to write keyup event for the textbox and copy its value in second.
JQUERY:
$("#txtBox1").on('keyup', function () {
$("#txtBox2").val($(this).val())
})
Here you can find the solution to the absolutely same question: Textbox onchange in ASP.NET
Related
I have an input tag having some text in it. Now I would like that onclick of a button the text will be changed.
For some reason it is not being changed.
This is the input tag:
<input id="network_table" type="text" value="oldValue" runat="server"/>
the following is the way I am trying to change the value of the input tag:
network_table.Value = "newValue";
network_table.Text = "newValue";
Bind the "onclick" event and apply this these methods:
In jQuery :
$('#network_table').val("your val");
http://docs.jquery.com/Val
Javascript
document.getElementById('network_table').value = "your val";
you can do it serverside with "OnClick" event on button, assuming your controls are defined with runat="server" attribute
http://msdn.microsoft.com/fr-fr/library/system.web.ui.webcontrols.button.onclick(v=VS.80).aspx
You could try and assign some meaningless class to the input and use that as a reference point to get in hold of the input field.
<input id="network_table" type="text" value="oldValue" runat="server" class="myInputField"/>
$('.myInputField').val('newValue');
Using the id will not work because you are using the 'runat=server' and it makes the id unavailable on client side and you would need to get the unique id first to be able to get in hold of it. This is a lot cleaner way but you need to make sure not to use the class elsewhere to avoid ambiguous results.
Here is a jsfiddle example which does what you want but on load.
http://jsfiddle.net/yX5ze/
I am using masterpage in my solution. In that masterpage there is a imagebutton named "Save" using as the saving option for all my pages, which is set as Defaultbutton in masterpage. The problem is that, in one of my page i have a textchanged event which i want to work when pressing "Enter" key. But when i press "Enter" key "Save" function works after the textchanged event. I dont want to happen "Save" function on "Enter" key press. I don't want there to be any default button on my page
You can set the button's UseSubmitBehavior = "false"
similar question is here Canceling the default submit button in ASP.NET
I think you have to prevent enter key while you are work in text-box
just put this function in ur page.
just add onkeydown event to ur text-box
<input type='text' onkeydown="return (event.keyCode!=13);" />
another one
this function need jquery
$('input').keypress(function(event) {
if (event.keyCode == 13) {
event.preventDefault();
}
});
I have written one JavaScript to Calculate the TotalWeight based on two TextBox integer values. I multiplied these two values and displayed in the 3rd TextBox Using JavaScript. But the problem is, I have one radiobuttonlist, in its selectedindexchanged event, the value I got in the 3rd TextBox gets disappeared. How to solve this?
My JavaScript is
<script type="text/javascript">
function TotalWeight()
{
var D1 = document.getElementById('<%=txtD1.ClientID%>');
var SectionWgt = document.getElementById('<%=txtSectionWeight.ClientID%>');
var TotalWgt = 0*1;
TotalWgt = parseFloat(D1.value) * parseFloat(SectionWgt.value);
if(isNaN(TotalWgt))
document.getElementById('<%=txtTotalWgt.ClientID%>').innerText = "0.000";
else
document.getElementById('<%=txtTotalWgt.ClientID%>').innerText = TotalWgt.toFixed(3);
}
</script>
<asp:TextBox ID="txtD1" runat="server" Width="136px" onkeyup="return TotalWeight();"></asp:TextBox>
After you calculate and assign the value to your Total Textbox, then put that value in a hidden field as well, and then on postback reassign that value to the textbox from the hidden Field.
Read the value of the textbox in when the radio button event fires and posts back - and then write it back to the textbox afterwards.
I would imagine that when the event fires and the page posts back, the third text box reverts to its original value - capture the new value and write it back to the box during the event.
use hidden field to store values. just use
[intput type="hidden" id="someid">]
after that you can use the value using $("#someid").val()
Try, this helped me.
I want to develop an application in asp.net with C#.
In that application there are one text box and one label.
I want the following functionality:
When I press any key in textbox then I should get this value on .cs page i.e; code behind. And from .cs page I want to add this value to the label.
The problem is that there is no keypress event for an asp textbox and if I take a html text box then I don't get its value on .cs page
How can I come out with this problem?
Because a keypress on a textbox is a client side event but you want to perform server-side processing you will need to use AJAX requests.
You may find the following useful:
AJAX Toolit
Using Jquery to call asp.net page methods
In asp.net the TextBox will have TextChanged event but you will need to enable post back for the button and the event will fire when you tab out of the TextBox.
For the task you want either use javascript or add a button and when this button is do what you want.
I don't think this is a good aproach in web app., In this way you will end with a lot of post-backs.
However, if you still want this functionality. Texbox has TextChanges event, and if you also change the textboxs's AutoPostBack property to true you will get something close, but you will still have to move a currsor.
But it is still a terible solution. Why don't you simply use a button that fires click event instead?
Alternative solution is to use Ajax or javaScript,..
You can simply create a JavaScript-Method for this.
Your Textbox:
<asp:TextBox ID="textBox" runat="server" onkeydown="onFilterTextChanged()">
</asp:TextBox>
Your JavaScript, do a TimeOut to not do this every 0,0001 secs.
function onFilterTextChanged() {
if (timeoutID)
window.clearTimeout(timeoutID);
timeoutID = window.setTimeout(updateFilterText, 600);
}
Send the Values to the CodeBehind, textis your TextBox-Text.
function updateFilterText() {
var text = document.getElementById("<%=textBox.ClientID %>").value;
__doPostBack("<%=textBox.ClientID%>", "CommandArg" + text);
}
You won't need to do as many PostBacks as with the native TextChanged-Event and you can simply use this e.g. for Auto-Extender-Plugins. Pack the TextBox into an UpdatePanel and you're good to go!
Unless of course you do not NEED to go back to the server, in which case just set the labeltext in updateFilterText.
I've got an ASP WebForm with 2 Textboxes and 3 Buttons and I want a specific button_click event to be fired whenever I press return whilst in a TextBox - how would I achieve this?
I tried using the TabIndex-Property, unfortunately that actually only seems to work for tabbing, not for pressing return in a TextBox.
Thanks!
Hey everyone, thanks for your answers - I just found the solution, for an aspx-page within a MasterPage I need to set
Form.DefaultButton = myButton.UniqueID;
instead of
Form.DefaultButton = myButton.ID;
which throws an error.
Thanks everyone!
Set the form's AcceptButton to the button you want pressed:
form1.AcceptButton = btnOK;
You can set which button is to be used as the default directly in mark-up of controls, by settings the defaultbutton property value to the ID of the desired button control, try this:
<form id="form1" runat="server" defaultbutton="DefaultButtonId">
<!-- content -->
</form>