Sounds simple and it probably is.
I have this variable:
byte[,,] data = new byte[360,288]
And I want 4 for them.
I do not want this though:
byte[,,,] data = new byte[360,288,4]
I prefer this:
byte[,,][] data = new byte[360,288][4]
Is it possible?
Yes this is a special case of jagged arrays, one where one of the jagged dimension is multidimensional.
You should write something like this:
// Initialise 4 arrays of two dimensional arrays
byte[][,] data = new byte[4][,];
// Initialise the arrays
for (var i = data.GetLowerBound(0); i <= data.GetLowerBound(0); ++i)
data[i] = new byte[360, 258];
Of course you can invert the dimensions if you need it.
// Initialise 4 arrays of two dimensional arrays
byte[,][] data2 = new byte[360,258][];
// Initialise the arrays
for (var i = data2.GetLowerBound(0); i <= data2.GetLowerBound(0); ++i)
for (var j = data2.GetLowerBound(1); j <= data2.GetLowerBound(1); ++j)
data2[i,j] = new byte[4];
Related
I would like to get the output of this to be [1,2,3,4,...,200]. Any suggestions for how to go about this?
var Laser_data = 0;
var i = 0;
var j = 1;
int[] LaserData_200 = new int[200];
for (i = 0; i < LaserData_200.Length; i++)
{
Laser_data += j;
LaserData_200[i] = Laser_data;
Console.WriteLine(" " + LaserData_200[i]);
}
Current output:
1
2
3
4
ect.
Your array initialization and element assignment can be simplified massively. Your array is just the numbers 1 through 200 (inclusive). Enumerable.Range can generate that for you, then save it as an array.
int[] myArray = Enumerable.Range(1, 200).ToArray();
To print it all, string.Join it using a comma as a seperator.
Console.WriteLine($"[{string.Join(',', myArray)}]");
// [1,2,3,4,5,6,7,8,9,10,11,12,13, .... 200]
I see the title has nothing to do with the posted code.
So I am answering the question in the title.
Say you have two arrays a and b and you want to create a third array that combines the two arrays, then you write code like
int[] c = Enumerable.Concat(a, b).ToArray();
or you have and array a and you want to keep adding values to it in loop. When arrays are fixed size (a.IsFixedSize = true always) so you can do this efficiently.
The best solution is to use List<T> instead of an array
List<int> a = new List<int>()
for(int i=0; i<200; i++)
{
a.Add( i+1 );
}
and if you want an array in the end, you just do
int[] c= a.ToArray();
I have a 8x8x3 array with some values. What I want to do is make a list of just the 1D arrays.
What I've got so far:
int[] packIt(int[,,] data, int factor) {
List<int[]> toReturn = new List<int[]>();
int[] test = data[0, 0];
So unless I'm missing something, I make a list of one dimensional arrays and try to fit in the one dimensional array at data[0, 0] (the test is just a placeholder so far). The error I'm getting is "Wrong number of indices", however if I follow the data[0,0,0] (which gives no error) I'll just get the 1 value at the location. I could do it manually, but am just wondering if there is an implementation for the functionality that I'm trying to do, as I will be using it a lot. Thanks a bunch.
You don't need to do anything specific to turn a 3D array into a 1D one; you can just enumerate it:
foreach(var x in multiDim)
...
This will print 1 to 8:
var x = new int[2,2,2];
x[0,0,0] = 1;
x[0,0,1] = 2;
x[0,1,0] = 3;
x[0,1,1] = 4;
x[1,0,0] = 5;
x[1,0,1] = 6;
x[1,1,0] = 7;
x[1,1,1] = 8;
foreach(int i in x)
Console.WriteLine(i);
To this end you can just straight enumerate your array in chunks of whatever:
var out = new List<int[]>();
var arr = new int[chunkSize];
out.Add(arr);
var idx = 0;
foreach(var x in miltiDimArray){
if(idx == chunkSize){
out.Add(arr = new int[chunkSize]);
idx = 0;
}
arr[idx++] = i;
}
Note that I don't try to make the ticks array smaller if the chunk size doesn't divide into the number of elements. idx will have a residual value you can use to work out what to resize the last array by if that is important
I have an somewhat basic question regarding multidimensional arrays in C#.
Currently I have the following array:
float[] matrix = new float[16];
I need to create instead a 2D array with each line containing the previously mentioned 16 float numbers. Also, the number of lines in the 2D array is not known at the start of the program (i.e. it will be based on a variable).
How can I create such an array using an efficient data structure?
You could do something like this:
const Int32 arraySize = 16;
var list = new List<float[]>();
Which gives you an empty list containing zero elements (arrays) to start. As you need to add new arrays you would write this:
var array = new float[arraySize];
// do stuff to the array
And then add it to the list:
list.Add(array);
To store 16 float numbers, you could use a 4x4 matrix (which is a 4x4 2-dimensional array). For more details, check out this documentation.
// init the array
float[,] matrix = new float[4,4];
// loop through the array
for(int col = 0; col < matrix.GetLength(0); col++)
for(int row = 0; row < matrix.GetLength(1); row++)
Console.WriteLine(matrix[col, row]);
You can use multidimentional array syntax
float[,] arr2D = new float[12,12];
Alternatively, you could use a loop
float[][] floats = new float[12][];
for(int i=0; i< 12; i++)
{
floats[i] = new float[12];
}
I have a function...
private double[,] AddToArray(double[,] array, double[] dataToAdd)
{
// Make a new row at the end of 'array' and copy values
// from 'dataToAdd' into the new row.
//
// Return the new, modified array.
}
However 'double[,]' isn't dynamic and I dont know what the final size of the array will be. I can create a List from it and add the new row to the list, but then I cant seem to convert it back to a double[,]. The List.ToArray() wants to output a jagged array (double[][]). This wont work. I'm interfacing with a program developed in LabVIEW and LV refuses to accept a jagged array. LV is happy with a fixed array ([,]).
Any help?
You could try this:
private double[,] AddToArray(double[,] array, double[] dataToAdd)
{
var dim0 = array.GetLength(0);
var dim1 = array.GetLength(1);
if (dim1 != dataToAdd.Length) throw new ArgumentException();
var na = new double[dim0 + 1, dim1];
Array.Copy(array, na, array.Length);
for (var i = 0; i < dim1; ++i) na[dim0, i] = dataToAdd[i];
return na;
}
It explicitly increments the high-order dimension by one, and also verifies that the length of the low-order dimension is equal to the dataToAdd array. I have not been able to any smarter copying from dataToAdd to the 2D array than by a for loop; it is not possible to apply Array.Copy for different ranked arrays.
You could always create the 2-dimensional array manually:
double[,] array = new double[list.Count, data.Length];
for(int i = 0;i < list.Count;++i)
for(int j = 0;j < data.Length;++j)
array[i, j] = list[i][j];
That is, of course, assuming that all of the 'dataToAdd' is of uniform length. Otherwise, what do you fill in the array for unused elements?
In C# how do i initialize
int[][] test;
I don't want to use int[,] instead. I am asking specifically how to initialize the above. The obvious = int[1][1] does not work. I tried a few different ways with no luck and [][] is not really google-able unfortunately (unless its possible!?)
It's called jagged arrays if you want to Google it.
Basically you can initialize the first dimension in the traditional way :
int[][] test = new int[23][];
And you manually initialize the others :
for (int i = 0; i < test.Length; ++i)
test[i] = new int[42];
You need a for-loop to initialize an array of array.
int[][] test = new int[N][];
for (int i = 0; i < test.Length; i ++)
test[i] = new int [M];
int[][] scores = new int[5][];
This is called a Jagged Array. So basically you have initialize the "first dimension" first and then each element:
int[][] foo = new int[3][];
foo[0] = new int[2];
...