Is there any way to declare a top-level window as a content template in xaml and recreate it at load time? Essentially I'm trying to do something equivalent to data templating:
<DataTemplate DataType="{x:Type my:MyType}" >
<Window>
...etc...
</Window>
</DataTemplate>
This works fine at run-time but it generates an error at compile time due to the fact that you're not supposed to use a top-level window to a data template or style etc, so basically I need to replace DataTemplate with a custom class to get around this. I don't actually need support for DataType...data templates set the resource key implicitly to DataType but a bug in WPF means you can't use the relevant attribute on your own types. I can easily get around that by doing things in reverse i.e. specifying the type as the key:
<MyClass x:Key="{x:Type my:MyType}" >
<Window>
...etc...
</Window>
</MyClass>
What I need to know though is how to declare MyClass so that the XAML content generates a template that I can create instances from rather than an actual instance of the Window itself.
Related
I have a grid that I am trying to hook up a visibility converter to. I have a class set up in the HelperObjects namespace, but for some reason the xaml is not picking up the reference. The error message is "The resource BoolToVisConverter could not be resolved" Why won't the xaml pull in this resource? I am sure I am doing something ridiculous here...
Here is the xaml:
xmlns:HelperObjects="clr-namespace:foo.HelperObjects"
...
<Grid Visibility="{Binding isZoneTwoVisible, Converter={StaticResource BoolToVisConverter}}">
The error message is indicating that the resource identified by the key BoolToVisConverter, to which you're trying to bind, cannot be found.
The most likely explanation is that you haven't declared that resource within a scope that can be accessed by your xaml. You'll want to create a StaticResource with a key matching the name you're referencing, within a Resources section of your xaml, the exact location may vary depending on your needs/structure.
Assuming you're doing this within a Window, you could do something like:
<Window>
<Window.Resources>
<BooleanToVisibilityConverter x:Key="BoolToVis"/>
</Window.Resources>
<Grid Visibility="{Binding isZoneTwoVisible, Converter={StaticResource BoolToVis}}">
<--...Content...-->
</Grid>
</Window>
Note: I haven't included your namespace in front of the BooleanToVisibilityConverter because this is a class which already exists within the framework.
It may be the case you require slightly different behaviour, or don't have access to that class, in which case you may need to add your namespace when defining the resource, e.g. <HelperObjects:BooleanToVisibilityConverter x:Key="BoolToVis"/>
Potentially useful further info about static resources: https://learn.microsoft.com/en-us/dotnet/framework/wpf/advanced/staticresource-markup-extension
Try to specify the converter in UserControlResources or even parent level Grid Resources. Assuming you are using a UserControl.
And your code is unclear as of where you are defining the StaticResource BoolToVisConverter. But generally heres the process.
Look at this sample code below to define your StaticResorce in the UserControl Resources section. Make sure you set the DataContext where isZoneTwoVisible is residing. I am hoping you implemented ImplementINotifyPropertyChanged and said PropertyChanged on your isZoneTwoVisible or isZoneTwoVisible is a DependencyProperty. Note: BooleanToVisibilityConverter is a class that implements an IValueConverter or if your property is a bool you don't even need that class.
<UserControl.Resources>
<BooleanToVisibilityConverter
x:Key="boolToVisibility"></BooleanToVisibilityConverter>
</UserControl.Resources>
You did all the things said above and it still dosen't work, sometimes I specify the relative Source hoping its residing in a UserControl.
Visibility="{Binding isZoneTwoVisible,Converter={StaticResource boolToVisibility},RelativeSource={RelativeSource Mode=FindAncestor,AncestorType=UserControl}}">
I have a listbox in WPF that will contain a list of ResultsViewModel items, however the actual runtime type of these objects could be
CalculateResultsViewModel,
ScenarioResultsViewModel,
GraphResultsviewModel etc etc,
all of which extend the base abstract class ResultsViewModel.
Each of these view models should be rendered differently in the ListBox so needs a different DataTemplate. I can do that just with XAML easy enough. The difficulty is that when the viewmodels are either "processing" or when they have failed", I need them to display a DataTemplate for "processing" or "errored" which I can only so far do with Triggers. That however then means I can't use the DataTemplateSelector or a basic XAML style.
The only solution I can think of (not clean I know) is to set the DataTemplate programmatically in the SetResult() method of each viewmodel class, which is what gets called when the processing completes either successfully or with an error. In that DependencyProperty I can look at the return code and then programatically set the DataTemplate depending on the sucess/failure result. The only problem is I cannot figure out how to
Obtain a DataTemplate resource from a ResourceDictionary just using c# code - bearing in mind Im calling all of this from the viewmodel class, not the window code-behind .xaml.cs file so it doesn't have access to the properties of Window
having only a handle to the viewmodel class, somehow obtain a reference to the ListBoxItem that contains it and then programmatically set the DataTemplate on this container.
Can anyone point me in the right direction?
you can take the magic with implicit datatemplates
<ListBox ItemSource={Binding YourResults}>
<ListBox.Resources>
<DataTemplate DataType={x:Type CalculateResultsViewModel}>
<Grid></Grid>
</DataTemplate>
<DataTemplate DataType={x:Type ScenarioResultsViewModel}>
<Grid></Grid>
</DataTemplate>
<DataTemplate DataType={x:Type GraphResultsviewModel }>
<Grid></Grid>
</DataTemplate>
</ListBox.Resources>
</ListBox>
for "processing" or "errored" viewmodels you can specify a adorner overlay in all yout datatemplates (ok but you must use the triggers)
hope this helps
In MainWindow we have:
<HeaderedContentControl
Content="{Binding Path=Workspaces}"
ContentTemplate="{StaticResource WorkspacesTemplate}"
Header="Workspaces"
Style="{StaticResource MainHCCStyle}"
/>
In the resources:
<DataTemplate x:Key="WorkspacesTemplate">
<TabControl
IsSynchronizedWithCurrentItem="True"
ItemsSource="{Binding}"
ItemTemplate="{StaticResource ClosableTabItemTemplate}"
Margin="4"
/>
</DataTemplate>
And in the article says:
A typed DataTemplate does not have an x:Key value assigned to it, but
it does have its DataType property set to an instance of the Type
class. If WPF tries to render one of your ViewModel objects, it will
check to see if the resource system has a typed DataTemplate in scope
whose DataType is the same as (or a base class of) the type of your
ViewModel object. If it finds one, it uses that template to render the
ViewModel object referenced by the tab item's Content property.
My question is:
How does the template know that the type is a collection of workspaces (WorkspaceViewModel)?
It doesn't need to, in the code you've posted. In your sample, you have given a strict value to your content template: you've explicitly used {StaticResource WorkspacesTemplate}, and so a resource with the key of "WorkspacesTemplate is looked up.
Because you've explicitly set the template, it doesn't matter what the intended type is: it'll try to display any object in your Content using the template you've set - with varying degrees of success if you use a type that doesn't match!
In the alternate method you mention - with a "typed DataTemplate", you would declare your datatemplate with <DataTemplate DataType="{x:Type l:WorkSpace}" />. Note that there is no x:Key (and also that I've assumed you have a namespace l mapped to your local code). What happens here is that WPF automatically sets the key of your resource to the DataType (important to note: a resource key doesn't have to be a string!).
Then, when you declare your HeaderedContentControl, you can leave out setting the ContentTemplate. At runtime, when the control is rendered, WPF will check the type of the Content object and find that it is WorkSpace, and it'll then look up a resource with x:Key="{x:Type l:WorkSpace}" - which will match your typed template.
This is a useful way of making consistent representations of data throughout your application, since a typed DataTemplate will be used automatically by any content-presenting control throughout your application.
WPF doesn't really care about the concrete type, it's just need to be some IEnumerable of something, WPF uses the type descriptor to know what the ui binding with.
I am trying the following in my WPF application:
Structure of XAML elements.
DataTemplate[Data Type 'A']
Grid
Broder
TextBlock
I want to bind the text block's text property to a "string" which is derived from my "Users" class which is referenced in the resource dictionary of the XAML.
So in the above structure since the DataTemplate gets the feed from data type 'A'.
I want to assign the datacontext(Users) to the grid and bind the string to the textblock.
Is there a way i can achieve this ,since all my trials which include assigning the datacontext to the Grid or Border or TextBlock doesn't work.
Can any one suggest me or correct me if my approach is wrong here ?
This markup should suffice:
<DataTemplate DataType="{x:Type local:A}">
<Grid DataContext="{Binding Path=Users}">
<Border>
<TextBlock Text="{Binding Path=PropertyOnUsers}"/>
</Border>
</Grid>
</DataTemplate>
Make sure you have the namespace declared at the top of your Xaml. For whatever reason, WPF doesn't always automatically infer the template from the type if you don't use {x:Type ...}.
From there it should be straight forward.
If Users is a collection, you will have to drill into the collection to get a specific instance of User.
By the way, if you are using Visual Studio, you can use the Output window to debug binding issues.
I'm building a custom WPF control that derives from TabControl. In the ControlTemplate, I'm using a ItemsControl to display a list that is being bound from the template (an observable collection of type FileMenuItem). During program execution, I'm getting the following error in the output window:
ItemTemplate and ItemTemplateSelector
are ignored for items already of the
ItemsControl's container type;
Type='FileMenuItem'
The type FileMenuItem is derived from MenuItem. If I change the base class to DependencyObject, the code actually runs and the template is applied (so that's an option). I googled the error and couldn't find anything about it, has anyone run into this while developing custom controls? Even though I have a workaround, I'd like to understand what's happening, and I think using the MenuItem as a base class is a cleaner implementation.
I can post more code if it would help. Thanks!
The purpose of a DataTemplate (like ItemTemplate) is to provide a visualization for a data object. Specifically, it defines a set of elements to add to the visual tree in place of the data given to an ContentPresenter or ItemsPresenter. In your case your source list is a collection of objects that are already able to be added directly to the visual tree for display in the UI.
You can see this in the following simplified example where only "Three" shows up in Red because the first two items are defined in a form that can be displayed directly by ComboBox.
<ComboBox>
<ComboBox.ItemTemplate>
<DataTemplate>
<TextBlock Text="{Binding}" Foreground="Red"/>
</DataTemplate>
</ComboBox.ItemTemplate>
<ComboBoxItem>One</ComboBoxItem>
<ComboBoxItem>Two</ComboBoxItem>
<sys:String>Three</sys:String>
</ComboBox>