How can I hide a window having his handler on c# - c#

I need to hide a window that is generated using Process class.
I made this procedure
_process = new Process()
{
EnableRaisingEvents = true
};
_process.StartInfo.UseShellExecute = false;
_process.StartInfo.RedirectStandardOutput = true;
_process.StartInfo.CreateNoWindow = true;
_process.StartInfo.WindowStyle = ProcessWindowStyle.Hidden;
_process.StartInfo.FileName = "app.exe";
_process.Start();
I need to hide a window that is generated for this process. Probably a child window of it.
I need a way to hide all child windows that a process call can generate.

Related

C# Running exe through process, how to hide window

Im running an exe through process in my c# program, i want the process to be completely invisible without the console of it popping up.
This is my code
Process process2 = new Process();
process2.StartInfo.FileName = "cmd.exe";
process2.StartInfo.UseShellExecute = false;
process2.StartInfo.CreateNoWindow = true;
process2.StartInfo.RedirectStandardOutput = true;
process2.StartInfo.RedirectStandardError = true;
process2.StartInfo.WindowStyle = ProcessWindowStyle.Hidden;
process2 = Process.Start(path3);
even with this code the console window still opens and shows, any help will be appreciated :)
Using
UseShellExecute = false; CreateNoWindow = true;
Should hide the process although it depends on the path in which you are opening, if the process has a force show
Try the following:
private void RunCmd(string exePath, string arguments = null)
{
//create new instance
ProcessStartInfo startInfo = new ProcessStartInfo(exePath, arguments);
startInfo.Arguments = arguments; //arguments
startInfo.CreateNoWindow = true; //don't create a window
startInfo.RedirectStandardError = true; //redirect standard error
startInfo.RedirectStandardOutput = true; //redirect standard output
startInfo.RedirectStandardInput = false;
startInfo.UseShellExecute = false; //if true, uses 'ShellExecute'; if false, uses 'CreateProcess'
startInfo.WindowStyle = ProcessWindowStyle.Hidden;
startInfo.ErrorDialog = false;
//create new instance
using (Process p = new Process { StartInfo = startInfo, EnableRaisingEvents = true })
{
//subscribe to event and add event handler code
p.ErrorDataReceived += (sender, e) =>
{
if (!String.IsNullOrEmpty(e.Data))
{
//ToDo: add desired code
Debug.WriteLine("Error: " + e.Data);
}
};
//subscribe to event and add event handler code
p.OutputDataReceived += (sender, e) =>
{
if (!String.IsNullOrEmpty(e.Data))
{
//ToDo: add desired code
Debug.WriteLine("Output: " + e.Data);
}
};
p.Start(); //start
p.BeginErrorReadLine(); //begin async reading for standard error
p.BeginOutputReadLine(); //begin async reading for standard output
//waits until the process is finished before continuing
p.WaitForExit();
}
}
See also this post.
I fixed it by renaming the window instead ty for all your help

CommonOpenFileDialog allows usage of parent window

Hello my application uses some OpenFileDialogs for file picking. Furthermore, I need a folder picker for which I used the CommonOpenFileDialog with the option IsFolderPicker = true.
Now when I open an OpenFileDialog in the app the parent window is locked and can't be used anymore, exactly the behavior I want.
But when I use the CommonOpenFileDialog I can still access the parent window and open even more CommonOpenFileDialogs.
The OpenFileDialog is intialized like this:
//init dialog
OpenFileDialog openFileDialog = new OpenFileDialog();
openFileDialog.InitialDirectory = Path.GetFullPath(SecondQPcrFilePath);
openFileDialog.CheckFileExists = true;
openFileDialog.CheckPathExists = true;
openFileDialog.Multiselect = false;
openFileDialog.ReadOnlyChecked = false;
openFileDialog.ShowReadOnly = false;
//show dialog
bool? dialogResult = openFileDialog.ShowDialog();
The CommonOpenFileDialog like this:
//is this mvvm conform?
Button senderButton = (Button)sender;
string clickedButton = senderButton.Name;
//init dialog
CommonOpenFileDialog openPathDialog = new CommonOpenFileDialog();
openPathDialog.IsFolderPicker = true;
openPathDialog.EnsurePathExists= true;
openPathDialog.Multiselect = false;
openPathDialog.EnsureFileExists = false;
openPathDialog.AllowNonFileSystemItems = true;
if(clickedButton == "limsOpenButton")
{
openPathDialog.InitialDirectory = Path.GetFullPath(LimsPath);
}
else if(clickedButton == "qpcrOpenButton")
{
openPathDialog.InitialDirectory = Path.GetFullPath(QpcrPath);
}
//show dialog
CommonFileDialogResult dialogResult = openPathDialog.ShowDialog();
Is there a way to prevent that behavior? The common dialog does not have a property like Owner or similiar.
The common file dialog exposes an overload for the ShowDialog method.
public CommonFileDialogResult ShowDialog(Window window);
Pass the parent window to this method and the dialog will be modal.
var window = // Get the parent window here.
var dialogResult = openPathDialog.ShowDialog(window);
It looks like you use code-behind, so this would be the window. Alternatively you could use MainWindow or the Windows collection in Application.Current to find the window.

New process out of order?

I wasn't able to find the answer I'm looking for already here, but if it is please link it and I'll close this duplicate post.
As part of a program I'm working on, I want three simple things to happen in this order:
1.) Show a marquee progress bar
2.) Run some commands in through CMD and move the output to an accessible string
3.) Stop/hide the progress bar
The problem I'm seeing is that my code is not executing in order and I'm super confused as to why. It seems to go step 2-1-3 which shouldn't be possible.
To make things even weirder, if I un-comment a message box between Step 1 and Step 2, things execute in order.
Is there something with the new CMD process throwing this out of wack?
Here's my code for this method:
//STEP 1 - Updates label and starts progress bar
lblSelectDiagnostic.Text = "Diagnostic Running";
progressBarDiag.Visible = true;
progressBarDiag.MarqueeAnimationSpeed = 100;
//MessageBox.Show("Status Updated");
//STEP 2 - Runs "Test Internet Connection"
//Gets selected diagnostic name
string strSelectedDiag = listBoxDiagnostics.SelectedItem.ToString();
var name = strSelectedDiag.Substring(strSelectedDiag.LastIndexOf(':') + 1);
strSelectedDiag = name.Trim();
if (strSelectedDiag.Contains("Test Internet Connection"))
{
//Pings Google
ProcessStartInfo info = new ProcessStartInfo();
info.RedirectStandardError = true;
info.RedirectStandardInput = true;
info.RedirectStandardOutput = true;
info.UseShellExecute = false;
info.FileName = "cmd.exe";
info.CreateNoWindow = true;
//Creates new process
Process proc = new Process();
proc.StartInfo = info;
proc.Start();
//Writes commands
using (StreamWriter writer = proc.StandardInput)
{
if (writer.BaseStream.CanWrite)
{
writer.WriteLine("ping www.google.com");
writer.WriteLine("exit");
}
writer.Close();
}
string PingGoogle = proc.StandardOutput.ReadToEnd();
proc.Close();
}
//STEP 3 - Resets label and stops progress bar
progressBarDiag.MarqueeAnimationSpeed = 0;
progressBarDiag.Visible = false;
lblSelectDiagnostic.Text = "Select Diagnostic to Run:";
-Thanks!
The progress bar will not be shown because you are painting it in the same thread where your logic is. You will have to do this in another thread. Simplest way would be to use a backgroundworker
This will help you: http://msdn.microsoft.com/en-us/library/cc221403(v=vs.95).aspx

Hiding cmd.exe window when starting from c# code

I am running a cmd.exe process from within a winforms application. However I can't seem to get the console window to run in the background (ie not show on screen)
here is my code
ProcessStartInfo si = new ProcessStartInfo("cmd.exe");
si.RedirectStandardInput = true;
si.RedirectStandardOutput = true;
si.UseShellExecute = false;
si.Arguments = "/c";
si.WindowStyle = ProcessWindowStyle.Hidden;
Process p = Process.Start(si);
Set CreateNoWindow to true.
si.CreateNoWindow = true;
si.CreateNoWindow = true;
si.WindowStyle = ProcessWindowStyle.Hidden;

Realtime Console Output Redirection using Process

I am using VBOXMANAGE to "export" a guest machine. VBOXManage is a Console application that can control the guest machine's behavior from the host. Since the export command is a long process, it returns process updates like so:
0%...10%...20%...30%...100%
I am writing a C# application that will invoke VBOXManage using Process. Here's my code:
Process VBOXProc = new Process();
VBOXProc.StartInfo.FileName = VBOXMANAGE;
VBOXProc.StartInfo.Arguments = Arguments;
VBOXProc.StartInfo.UseShellExecute = false;
VBOXProc.StartInfo.CreateNoWindow = true;
VBOXProc.StartInfo.WindowStyle = ProcessWindowStyle.Hidden;
VBOXProc.StartInfo.RedirectStandardError = true;
VBOXProc.StartInfo.RedirectStandardOutput = true;
VBOXProc.OutputDataReceived += new DataReceivedEventHandler(VBOXProc_OutputDataReceived);
VBOXProc.ErrorDataReceived += new DataReceivedEventHandler(VBOXProc_ErrorDataReceived);
VBOXProc.EnableRaisingEvents = true;
VBOXProc.Start();
VBOXProc.BeginOutputReadLine();
VBOXProc.BeginErrorReadLine();
VBOXProc.WaitForExit();
This is fine, except that the output is being read per LINE. This means that the process updates "
0%...10%...20%...30%...100%" will only show AFTER the actual process is done.
Is there a way to capture the console output in realtime?
Thanks!
This worked for me:
process.StartInfo.CreateNoWindow = true;
process.StartInfo.ErrorDialog = false;
process.StartInfo.RedirectStandardError = true;
process.StartInfo.RedirectStandardOutput = true;
process.StartInfo.UseShellExecute = false;
process.ErrorDataReceived += (sendingProcess, errorLine) => error.AppendLine(errorLine.Data);
process.OutputDataReceived += (sendingProcess, dataLine) => SetMessage(dataLine.Data);
process.Start();
process.BeginErrorReadLine();
process.BeginOutputReadLine();
process.WaitForExit();
error.AppendLine() and SetMessage() are the methods I used.
You can read directly from the StanadardOutput/Error for the process using all the standard Stream methods, just be sure to set the StartInfo.Redirectxxx to true.
var p = new Process()
p.StartInfo.UseShellExecute = false; //not sure if this is absolutely required
p.StartInfo.RedirectStandardOuput = true;
....
do
{
Thread.Sleep(nnn);
Console.Out.Write(p.StandardOutput.ReadToEnd());
}
while (!p.HasExited);
//catch any leftovers in redirected stdout
Console.Out.Write(p.StandardOutput.ReadToEnd());
The above will echo the output of the child process to your applications Standard Out.
You can read Blocks of a particular size using p.StandardOutput.Read(char[], int, int) or asynchronous reads using p.StadardOutput.BaseStream.BeginRead(...).
All the same methods are available for StandardError.
Sleeping in the loop frees up the processor for other tasks and allows some data to accumulate in the bufffer. If the sleep period is too long and the buffer overflows some output from the executing process will be lost. If the sleep period is too short a lot of CPU cycles are spent reading and empty buffer.
Try to redirect standard input too and apply AutoFlush to StandardInput. Next read stream using StreamReader.
Process proces;
ProcessStartInfo psi = new ProcessStartInfo();
psi.FileName = "test.exe";
psi.UseShellExecute = false;
psi.CreateNoWindow = true;
psi.RedirectStandardOutput = true;
psi.RedirectStandardInput = true;
proces = Process.Start(psi);
proces.StandardInput.AutoFlush = true;
Sorry any mistake, I am Brazilian and to using Google Translate to write this text.
Coincidentally, I also'm doing a program that works with VBoxManage of Virtualbox. In my case I wanted, among other things, convert a virtual disk. Also it delays and the percentage with progress also
I managed to do just this by creating a process of will to run the program, and using a user classes 'Dean North` the other question that is similar to this. It is important to use a thread to run the VBoxManage, otherwise has no way to work the obtained text or view the progress.
O texto é muito grande pra eu adicionar quatro espaços antes de cada linha e repassar.
The classes replace the Process system class. Need not make any changes to your code, just add a arquivo.cs with the text passed by the user Dean North instead of Process p = new Process() use FixedProcess p = new FixedProcess ()
After that it was my code:
private void BotaoParaTestes_Click(object sender, EventArgs e)
{
string linha = #"clonehd " +
"\"Z:\\Máquinas Virtuais\\Teste.vdi\" " +
"\"C:\\Temp\\teste.vdi\" " +
"--format VDI --variant Standard";
Thread tarefa = new Thread(Executar);
tarefa.Start(linha);
}
private void Executar(object Linha)
{
FixedProcess fp = new FixedProcess ();
fp.StartInfo.FileName = ItensEstaticos.VBox;
fp.StartInfo.Arguments = Linha.ToString();
fp.StartInfo.CreateNoWindow = true;
fp.StartInfo.ErrorDialog = false;
fp.StartInfo.RedirectStandardError = true;
fp.StartInfo.RedirectStandardOutput = true;
fp.StartInfo.UseShellExecute = false;
fp.ErrorDataReceived += (sendingProcess, errorLine) => Escrita(errorLine.Data);
fp.OutputDataReceived += (sendingProcess, dataLine) => Escrita(dataLine.Data);
fp.Start();
fp.BeginErrorReadLine();
fp.BeginOutputReadLine();
fp.WaitForExit();
}
private void Escrita(string Texto)
{
if (!string.IsNullOrEmpty(Texto))
{
BeginInvoke(new MethodInvoker(delegate
{
this.Texto.Text += Texto;
}));
}
}
For me the event is only called when the text is changed, not only when the VBoxManage goes to a new line. Sometimes the text was null, then place a check structure as I did before using the text obtained for controls.

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