I have a (login) form that use it as modal like this (parent form code):
using (var login = new Login())
{
login.ShowDialog();
}
I do some checks on opened modal dialog and I want that it not close on pressing OK button if user name and password was wrong.
My login:
private void goSignIn_Click(object sender, EventArgs e)
{
var loggedInCustomer =LoginController.signIn(usernameBox.Text, passwordBox.Text);
if (loggedInCustomer == null)
{
MessageBox.Show("Wrong username or password! :( ", "Wrong!");
}
else
Close();
}
Check the button (goSignIn) DialogResult property. If it's set, it automatically close the form.
If the DialogResult for this property is set to anything other than None, and if the parent form was displayed through the ShowDialog method, clicking the button closes the parent form without your having to hook up any events. The form's DialogResult property is then set to the DialogResult of the button when the button is clicked.
MSDN Button.DialogResult Property
I guess you've set the DialogResult of goSignIn button to some value(probably DialogResult.OK), remove that line, everything should work fine as expected.
Don't call close then
private void goSignIn_Click(object sender, EventArgs e)
{
var loggedInCustomer =LoginController.signIn(usernameBox.Text, passwordBox.Text);
if (loggedInCustomer == null)
{
MessageBox.Show("Wrong username or password! :( ", "Wrong!");
}
else
{
Close();
}
}
Related
I am creating a password window using Windows Form Designer, except the context is a little different. There are several input fields, and one of them is password protected. There is a "Change" button that spawns a new password window on top of the home window. The user enters a password attempt and presses "OK". I need a way to have the OK button check the password and then send a DialogResult.OK back to the home window, or display an "incorrect password" if the attempt is incorrect. This means I can't set the DialogResult to DialogResult.OK initially, so I'm not sure how to do this.
Currently I set the DialogResult to DialogResult.OK in the click event function, but obviously this sets it for the next click, not the current one, so the user has to press the OK button twice.
private void buttonOK_Click(object sender, EventArgs e)
{
string passwordAttempt = textBoxPassword.Text;
if( passwordAttempt.CompareTo("pass") == 0 )
{
this.buttonOK.DialogResult = System.Windows.Forms.DialogResult.OK;
}
}
One possible solution is to trigger a second event through the code (not sure how to do this). Or alternatively, is there a better way to do password windows I'm not thinking of in this situation?
Set the AcceptButton of the dialog to buttonOK (the OK button). You can do this either in code or designer.
Set the DialogResult of the dialog form, not the button.
Code:
this.AcceptButton = buttonOK;
...
private void buttonOK_Click(object sender, EventArgs e)
{
string passwordAttempt = textBoxPassword.Text;
if (passwordAttempt.CompareTo("pass") == 0)
{
this.DialogResult = System.Windows.Forms.DialogResult.OK;
Close();
}
}
I'm writing a WinForm desktop application. In the main form, the user clicks on a button which calls another form for the user to submit data to. At the end of this submission process, the user clicks on a "Save" menu item to close the subform.
This is the code for the subform calling:
private void btnSubmit_Click(object sender, EventArgs e)
{
// code for setting myFormArgs
myForm form = new myForm(myFormArgs);
form.ShowDialog();
// the user clicked "Yes" on a "Confirm" MessageBox
if (form.DialogResult == DialogResult.Yes)
{
// code for saving data
form.Dispose();
}
}
and this is the code for the "Save" menu item in the subform:
private void menuSave_Click(object sender, EventArgs e)
{
string message, title;
MessageBoxIcon icon;
MessageBoxButtons buttons;
if(DataSubmitted)
{
if(ValidData)
{
message = "Confirm?";
title = "Select an action";
icon = MessageBoxIcon.Information;
buttons = MessageBoxButtons.YesNo;
}
else
{
message = "Incomplete data";
title = "Error";
icon = MessageBoxIcon.Error;
buttons = MessageBoxButtons.OK;
}
}
else
{
message = "No data submitted";
title = "Error";
icon = MessageBoxIcon.Error;
buttons = MessageBoxButtons.OK;
}
this.DialogResult = MessageBox.Show(message, title, buttons, icon);
if (this.DialogResult == DialogResult.Yes) this.Close();
else this.OnFormClosing(new FormClosingEventArgs(CloseReason.None, true));
}
The problem is that the code will always get back to the calling method, thus closing (maybe just hiding?) the sub-form, even if the this.Close() method isn't called.
Thanks in advance.
you should not make a new event instance, those are things you would want to avoid
instead try:
DialogResult dialogResult = MessageBox.Show("Sure", "Some Title",
MessageBoxButtons.YesNo);
if(dialogResult == DialogResult.Yes)
{
Close();
}
Events are supposed to occur automatically, so 'OnFormClosing' will raise when the form will close.
also i recommend to use this.Close instead of Dispose
Form.Close() sends the proper Windows messages to shut down the win32 window. During that process, if the form was not shown modally, Dispose is called on the form. Disposing the form frees up the unmanaged resources that the form is holding onto.
for more organized code,
try making an instance of the form from the main form
and handle the dialog result like this:
using (SubForm form = new SubForm())
{
DialogResult dr = form.ShowDialog();
if(dr == DialogResult.Yes)
{
string studdToSave= form.StuffToSave;
SaveToFile(studdToSave);
}
}
I find it strange that you want to close the form when the user just wants to save the data. :)
Save should not close your form.
When you close the form, you should verify if there are unsaved changes.
If there are, ask the user the question if he wants to save his changes before closing and offer him the options Yes, No and Cancel, where Cancel means 'cancel closing the form'.
Depending on wether the user clicked Yes or No, you should or shouldn't save the changes.
If the user clicked cancel, you should cancel closing the form by having an event for the FormClosing event. This event allows you to cancel closing the form.
private void btnClose_Click(object sender, EventArgs e)
{
if (unsavedChanges)
{
var result = MessageBox.Show("Save changes?", "unsaved changes", MessageBoxButtons.YesNoCancel);
if (result == DialogResult.Yes)
{
SaveChanges();
}
if (result == DialogResult.Cancel)
{
cancelClose = true;
}
this.Close();
}
}
private void Form2_FormClosing(object sender, FormClosingEventArgs e)
{
e.Cancel = cancelClose;
cancelClose = false;
}
The code above is usefull when 'Form2' is not a modal form.
If you want Form2 to be shown modal, the code above will work as well. However, you can also use the DialogResult proprety of the Form in that case:
private void btnClose_Click(object sender, EventArgs e)
{
if (unsavedChanges)
{
var result = MessageBox.Show("Save changes?", "unsaved changes", MessageBoxButtons.YesNoCancel);
if (result == DialogResult.Yes)
{
SaveChanges();
}
if (result == DialogResult.Cancel)
{
result = DialogResult.None;
}
this.DialogResult = result;
}
}
I have a WinForms application that checks for pending changes whenever the user hits the cancel button. If there are pending changes, I prompt the user to see if they are sure they wish to cancel. If they do, I close the form. If not, I just return. However, the form is closing anyways. After some debugging, I realized it was because this particular button is set to the form's CancelButton, so clicking it caused the form to close. To verify, I removed the CancelButton property, but the behavior persisted.
How can I prevent this automatic closing? Here is my event handler code:
private void closeButton_Click(object sender, EventArgs e)
{
DialogResult dr = DialogResult.Yes;
if (changesMade)
{
dr = MessageBoxEx.Show(this, "Are you sure you wish to disregard the changes made?", "Changes Made", MessageBoxButtons.YesNo);
}
if (dr == DialogResult.Yes)
{
Close();
}
else
{
//TODO:
}
}
In the above code, the form should only close if there are no changes made, or if the user chose to disregard them. I made changes, and clicked 'No' to the DialogBox, but the form still closed. With and without the button set as the form's CancelButton.
Just set the property DialogResult of the form to the enum DialogResult.None
....
if (dr == DialogResult.Yes)
{
Close();
}
else
{
this.DialogResult = DialogResult.None;
}
or simply:
if (dr != DialogResult.Yes)
this.DialogResult = DialogResult.None;
The form closes automatically because the property DialogResult of the button is not set to DialogResult.None in the Forms Designer. In this scenario, the WinForms engine takes that value and assign it to the DialogResult property of the whole form causing it to automatically close. This is usually used in the calling code of the form to distinguish between a Confirm and a Cancel button
In the example below suppose that on the frmCustomers there are two buttons, one with the DialogResult property set to DialogResult.OK and another set to DialogResult.Cancel. Now if the user hits the OK button you know, in the calling code what to do with the inputs for your new customer
using(frmCustomers f = new frmCustomers())
{
if(f.ShowDialog() == DialogResult.OK)
{
// Execute code to save a customer
}
}
Following up on my comment, this is what I do for an internal tool I wrote recently:
private void Form_FormClosing(object sender, FormClosingEventArgs e)
{
e.Cancel = !PromptUnsavedChanges();
}
private bool PromptUnsavedChanges()
{
if (HasFormChanged()) //checks if form is different from the DB
{
DialogResult dr = MessageBox.Show("You have unsaved changes. Would you like to save them?", "Unsaved Changes", MessageBoxButtons.YesNoCancel, MessageBoxIcon.Question);
if (dr == System.Windows.Forms.DialogResult.Yes)
tsmiSave_Click(null, null); // Saves the data
else if (dr == System.Windows.Forms.DialogResult.Cancel)
return false; // Cancel the closure of the form, but don't save either
}
return true; // Close the form
}
The logic could probably cleaned up from a readability point of view, now that I'm looking at it months later. But it certainly works.
With this you simply just call this.Close(); in your button click event. Then that event is what handles the prompting and decides if it should actually close or not.
I am learning about Forms and somehow can't figure out what's the problem with this code that when I want to press either button with Dialog.Result.Yes or button with Dialog.Result.No in Form2 to keep the Form2 open it anyway closes after clicking on one of them.
public partial class Form1 : Form
{
public Form1()
{
InitializeComponent();
}
private void button1_MouseClick(object sender, MouseEventArgs e)
{
Formular2 Form2 = new Formular2();
Form2.ShowDialog();
if (Form2.DialogResult == DialogResult.Yes)
{
this.DialogResult = DialogResult.None;
}
else if (Form2.DialogResult == DialogResult.No)
{
DialogResult = DialogResult.None;
}
}
}
Thanks for any advice
If you want to keep the Form2 open, you need to set the DialogResult property of Form2, not the DialogResult property of Form1.
You need to move this logic in the button on Form2 that close the Form2
So, suppose to have a button on Formular form class named buttonOK and its property DialogResult is set to DialogResult.OK.
Then in that class code you write the event handler for the button click event (not the MouseClick event)
private void buttonOK_Click(object sender, MouseEventArgs e)
{
// Perform some logic to validate the inputs and if something is wrong return false
if(SomeLogicToAcceptTheForm() == false)
{
// Inform the user of the error
MessageBox.Show("Your input is not valid");
// Stop the closing process of this Formular instance
this.DialogResult = DialogResult.None;
}
// If your logic accepts the input, then the code continue at this point
// This will cause the form to exit from the ShowDialog call
// and you can read the current form DialogResult value.
}
EDIT
To better understand this flow you should consider that, BEFORE calling the event handler for the button click event, the forms engine sets the Form's DialogResult property from the value present in the button's DialogResult property. So, if your validation turns out to be correct you don't need to do anything and the form closes returning DialogResult.OK (or whatever you have put in the Button's DialogResult property).
The act of setting a DialogResult will cause the Form to close returning that result to the Form that created the instance, that way it can check the result and take the appropriate action. In your case since you want to keep the second form open you either need to not assign the DialogResult.No to the button and do like Steve suggests or you can intercept the Form's FormClosing event, test for the DialogResult if DialogResult.No set to None and cancel the Closing of the Form.
Though I would suggest not using a DialogResult if you are wanting to keep the Form Open.
public Form2()
{
InitializeComponent();
}
private void button2_Click(object sender, EventArgs e)
{
DialogResult = DialogResult.No;
}
private void button1_Click(object sender, EventArgs e)
{
DialogResult = DialogResult.Yes;
}
private void Form2_FormClosing(object sender, FormClosingEventArgs e)
{
if (this.DialogResult == DialogResult.No)
{
DialogResult = DialogResult.None;
e.Cancel = true;
}
}
In the Form2 pick control for assigning respective dialog result.
Same DialogResult will be produced by the Form2 control if you click on it.
Example in Form2:
button1.DialogResult = DialogResult.Yes;
button2.DialogResult = DialogResult.No;
Now pressing any of these buttons should close the Form2.
If you want to restrict closing on button1 and button2. Following changes in the Click event are required:
private void button1_Click(object sender, EventArgs e)
{
this.DialogResult = DialogResult.None;
}
Form1:
In result you could see what is result, by looking into Form2.DialogResult. You can do this as you get results from Form2 dialog:
Formular2 Form2 = new Formular2();
Form2.ShowDialog();
if (Form2.DialogResult == DialogResult.Yes)
{
//
}
else if (Form2.DialogResult == DialogResult.No)
{
//
}
On any windows form displayed as modal (using ShowDialog()), the act of setting DialogResult will cause to hide the modal form and return control to calling code. Read Remarks from this page of MSDN
If you wish to show your form again, you can do the following:
private void button1_MouseClick(object sender, MouseEventArgs e)
{
Formular2 Form2 = new Formular2();
Form2.ShowDialog();
if (Form2.DialogResult == DialogResult.Yes)
{
Form2.DialogResult = DialogResult.None;
}
else if (Form2.DialogResult == DialogResult.No)
{
Form2.DialogResult = DialogResult.None;
}
Form2.Show(); // or Form2.ShowDialog()
}
I have some custom made dialog that have on it Set Button , I want when i exit from newBlockForm.ShowDialog(this); to get the dialog result if the user pressed on that button or not .
Like i would do in winforms dialog
if(MessageBox.Show("Exit?", "Close UP",
MessageBoxButtons.YesNo)== DialogResult.Yes)
Any idea how i do so ?
You can use the DialogResult Property of the Button on your Dialog form and set it to DialogResult Enumeration like:
//in your dialog form
button1.DialogResult = DialogResult.OK;
then in your main form :
//Create an instance of your dialog form
Form2 testDialog = new Form2();
// Show testDialog as a modal dialog and determine if DialogResult = OK.
if (testDialog.ShowDialog(this) == DialogResult.OK)
{
//do processing
}
else
{
//do processing
}
Map the AcceptButton property on the Form to Set button in the designer.
Or in the Set button click handler you could set some value.
private void HandleOnSetButtonClick(object sender, EventArgs e)
{
this.IsSetClicked = true;
this.Close();
//or
this.DialogResult = System.Windows.Forms.DialogResult.OK;
this.Close();
}
public Boolean IsSetClicked
{
get;
private set;
}
ShowDialog method returns a DialogResult by itself which you can set automatically by setting the DialogResult of the buttons in question in your form designer.