Here's the part 1 of my question, if you wanna check the background of this question :
Detecting brackets in input string
Forgive me if the title doesn't match, since I also confused how to name it appropriately to picture my problem. If anyone knows a more appropriate title, feel free to edit.
So, given below code (my own code) :
private const int PARTICLE_EACH_CHAR = 4;
/*ProcessBarLines : string s only contains numbers, b, [, and ]*/
private int ProcessBarLines(Canvas canvas, string s, int lastLineAboveNotation)
{
List<int> bracket = new List<int>();
List<int> other = new List<int>();
int currentCloseNumber = 0;
int currentOpenNumber = 0;
for (int i = 0; i < s.Length; i++)
{
if (s[i] == '[')
{
bracket.Add(i);
currentOpenNumber++;
if (i - 1 > 0 && s[i - 1] != '[')
{
currentOpenNumber = 1;
}
}
else if (s[i] == ']')
{
bracket.Add(i);
currentCloseNumber++;
if (i + 1 >= s.Length || s[i + 1] != ']' || currentOpenNumber == currentCloseNumber)
{
int min = bracket.Count - (currentCloseNumber * 2);
int max = bracket[bracket.Count - 1];
List<int> proc = new List<int>();
int firstIndex = -1;
int lastIndex = -1;
for (int ii = 0; ii < other.Count; ii++)
{
if (other[ii] > min && other[ii] < max)
{
proc.Add(other[ii]);
if (firstIndex == -1)
{
firstIndex = ii;
lastIndex = ii;
}
else
{
lastIndex = ii;
}
}
}
double leftPixel = firstIndex * widthEachChar;
double rightPixel = (lastIndex * widthEachChar) + widthEachChar;
DrawLine(canvas, currentCloseNumber, leftPixel,
rightPixel, lastLineAboveNotation * heightEachChar / PARTICLE_EACH_CHAR);
lastLineAboveNotation += currentCloseNumber - 1;
currentOpenNumber -= currentCloseNumber;
currentCloseNumber = 0;
}
}
else
{
other.Add(i);
}
}
return lastLineAboveNotation + 1;
}
Here's the test cases :
Picture 1 & 2 is the correct answer, and picture 3 is the wrong answer. Picture 3 should have a line, just like inverted from number 2, but, apparently, (if you look closely) the line is drawn on the right, but it should be on the left to be correct (above 0).
I figured, the problem is, I'm quite sure on the "min". Since it doesn't give the correct starting value.
Any idea on this? Feel free to clarify anything. It's used for writing numeric musical scores.
Btw, DrawLine() just meant to draw the line above the numbers, it's not the problem.
Finally! I found it!
private int ProcessBarLines(Canvas canvas, string s, int lastLineAboveNotation)
{
List<int> bracket = new List<int>();
List<int> other = new List<int>();
int currentCloseNumber = 0;
int currentOpenNumber = 0;
int space = 0;
for (int i = 0; i < s.Length; i++)
{
if (s[i] == '[')
{
bracket.Add(i);
currentOpenNumber++;
if (i - 1 > 0 && s[i - 1] != '[')
{
currentOpenNumber = 1;
}
}
else if (s[i] == ']')
{
bracket.Add(i);
currentCloseNumber++;
if (i + 1 >= s.Length || s[i + 1] != ']' || currentOpenNumber == currentCloseNumber)
{
int min = bracket[Math.Max(bracket.Count - ((currentCloseNumber * 2) + space), 0)];
int max = bracket[bracket.Count - 1];
space = max - min - 1;
List<int> proc = new List<int>();
int firstIndex = -1;
int lastIndex = -1;
for (int ii = 0; ii < other.Count; ii++)
{
if (other[ii] > min && other[ii] < max)
{
proc.Add(other[ii]);
other[ii] = -1;
if (firstIndex == -1)
{
firstIndex = ii;
lastIndex = ii;
}
else
{
lastIndex = ii;
}
}
}
double leftPixel = firstIndex * widthEachChar;
double rightPixel = (lastIndex * widthEachChar) + widthEachChar;
DrawLine(canvas, currentCloseNumber, leftPixel,
rightPixel, lastLineAboveNotation * heightEachChar / PARTICLE_EACH_CHAR);
lastLineAboveNotation += 1;
currentOpenNumber -= currentCloseNumber;
currentCloseNumber = 0;
}
}
else
{
other.Add(i);
}
}
return lastLineAboveNotation + 1;
}
If someone got a more efficient code, please let us know!
Related
I need make symmetric letter “W” in string Array
get_w() Is method that should return string array that contains letter "W"
get_w(5) # should return:
public string[] GetW(int h)
{
if (h < 2) return new string[h];
int row = 0;
int stars_number = h * 4 - 3;
int times = 0;
StringBuilder[] c = new StringBuilder[h];
for(int a = 0; a < h; a++)
{
c[a] = new StringBuilder();
c[a].Length = stars_number;
}
for (int i = 0; i < stars_number; i++)
{
if (i == h - 1) times = 1;
if (i == stars_number-2 * h + 1) times = 2;
if (i == stars_number - h) times = 3;
c[row][i] = '*';
if (row < h - 1 && (times == 0 || times == 2))
{
row += 1;
}
else
{
row -= 1;
}
}
string []str = new string[h];
for(int i = 0; i < h; i ++)
{
str[i] = c[i].ToString();
}
return str;
}
if I compile it in a VS i get no errors.Here is an example of the result
This task is taken from the Codewars
but if I try to test on Codewars with the code I described above, I get this error
Edited:I changed returning array with "h" length to empty array and had got this
i found the task solution by replacing charters that equal '\0' with character ' '
here is working code
public string[] GetW(int h)
{
if (h < 2) return new string[]{};
int row = 0;
int stars_number = h * 4 - 3;
int times = 0;
StringBuilder[] c = new StringBuilder[h];
for(int a = 0; a < h; a++)
{
c[a] = new StringBuilder();
c[a].Length = stars_number;
}
for (int i = 0; i < stars_number; i++)
{
if (i == h - 1) times = 1;
if (i == stars_number-2 * h + 1) times = 2;
if (i == stars_number - h) times = 3;
c[row][i] = '*';
if (row < h - 1 && (times == 0 || times == 2))
{
row += 1;
}
else
{
row -= 1;
}
}
string []str = new string[h];
for(int i = 0; i < h; i ++)
{
c[i].Replace('\0', ' ');
str[i] = c[i].ToString();
}
return str;
}
And here is result of test
Hi I have a task to convert exponential code into linear, but I have no idea how to do it. Could you give me any tips or point me in the right direction?
Here's the code:
int F (int m, int n)
{
if(n == 0)
{
return m;
}
else if(m == 0 && n > 0)
{
return n;
}
else
{
int[] array = { 1 + F(m - 1, n), 1 + F(m, n - 1), D(m, n) + F(m - 1, n - 1) };
return array.Min();
}
}
int D(int i, int f)
{
if(x[i] == y[f])
{
return 1;
}
else
{
return 0;
}
}
Update:
Am I going in the right direction? So far it works only with m=0,1,2 and n=0,1,2. How do I fill all the values if let's say, I give m = 10 and n = 20?
int Fdp(int m, int n)
{
fdin[m, 0] = m;
for(int i = 0; i <= n; i++)
{
fdin[0, i] = n;
}
if (n == 0)
{
return m;
}
else if (m == 0 && n > 0)
{
return n;
}
else
{
int[] temp = { 1 + fdin[m-1, n], 1+ fdin[m,n-1], D(m,n) + fdin[m-1,n-1] };
fdin[m, n] = temp.Min();
return temp.Min();
}
}
Solved it.
static int Fdp(int m, int n)
{
for (int i = 0; i <= m; i++)
{
fdin[i, 0] = i;
for (int j = 1; j <= n; j++)
{
if(i == 0)
{
fdin[i, j] = j;
}
else
{
int[] temp = new int[] { 1 + fdin[i - 1, j], 1 + fdin[i, j - 1], D(i, j) + fdin[i - 1, j - 1] };
fdin[i, j] = temp.Min();
}
}
}
return fdin[m,n];
}
I want to develop method that will return the length of largest substring composed of identical characters form string that is passed as argument, but without using any of .NET libraries.
For example if we pass aaacccccdefffgg as parameter the biggest substring is ccccc and method should return 5.
Here is my working solution :
public static int GetMaxSubstringLenght(char[] myArray)
{
int max = 0;
for (int i = 0; i < myArray.Length-1; i++)
{
if (myArray.Length == 0)
{
return 0;
}
else
{
int j = i + 1;
int currentMax = 1; // string has some value, so we start with 1
while (myArray[i] == myArray[j])
{
currentMax++;
if (max < currentMax)
{
max = currentMax;
}
j++;
}
}
}
return max;
}
The code above will return expected result, but there will be some unnecessary iteration in for loop that I want to avoid. In first iteration when i=0it will compare it until j=2 and then will get out of while loop and start second iteration in for loop comparing the one at [1] index with [2], which we already did in previous iteration.So basically, when first iteration is completed, next one should start from the last value of j. How can I achieve that ?
Thank You in advance.
Since you want "Largest substring..." let's take String as argument and return String
public static String GetMaxSubstring(String value) {
if (String.IsNullOrEmpty(value))
return "";
int bestCount = 0;
char bestChar = '\0';
int currentCount = 0;
char current = '\0';
for (int i = 0; i < value.Length; ++i) {
if ((i == 0) || (value[i] != current))
currentCount = 0;
currentCount += 1;
current = value[i];
if (currentCount > bestCount) {
bestCount = currentCount;
bestChar = current;
}
}
return new String(bestChar, bestCount);
}
....
// "ccccc"
String result = GetMaxSubstring("aaacccccdefffgg");
// 5
int length = result.Length;
Another approach:
public static int MaxSubstringLength(string s)
{
if (string.IsNullOrEmpty(s))
return 0;
int max = 0, cur = 1;
for (int i = 1; i < s.Length; ++i, ++cur)
{
if (s[i] != s[i-1])
{
max = cur > max ? cur : max;
cur = 0;
}
}
return cur > max ? cur : max;
}
[EDIT] Simplified the code.
[EDIT2] Simplified the code further.
you also can do it with one loop:
public static int GetMaxSubstringLenght(char[] myArray)
{
int max = 0;
char currentchar = myArray[0];
int count = 1;
for each(char c in myArray)
{
if(currentchar != c)
{
count = 1;
currentchar = c;
}
if(count > max)
{
max = count;
}
count++;
}
return max;
}
I changed the code... now this code does not use math.max and I think I eleminated the mistake... I've no IDE at the moment to test it
public static int GetMaxSubstringLenght(char[] myArray)
{
if (myArray.Length == 0)
return 0;
if (myArray.Length == 1)
return 1;
int max = 1;
int localMax = 1;
for (int i = 0; i < myArray.Length - max; i++ )
{
if (myArray[i] == myArray[i + 1])
{
localMax++;
}
else
{
max = Math.Max(max, localMax);
localMax = 1;
}
}
return Math.Max(max, localMax);
}
static int LongestCharSequence(string s)
{
if (string.IsNullOrEmpty(s)) return 0;
var prevChar = '\0';
int cmax = 0;
int max = 1;
foreach (char c in s)
{
if (c != prevChar)
{
cmax = 1;
prevChar = c;
}
else
{
if (++cmax > max) max = cmax;
}
}
return max;
}
recursion!
static int LongestCharSequence(string s)
{
int i = (s?.Length ?? 0) == 0 ? 0 : 1;
for (; i < s?.Length; i++)
if (s[i] != s[i - 1]) return Math.Max(i, LongestCharSequence(s.Substring(i)));
return i;
}
Another solution using my favorite nested loop technique:
public static int MaxSubstringLength(string s)
{
int maxLength = 0;
for (int length = s != null ? s.Length : 0, pos = 0; pos < length;)
{
int start = pos;
while (++pos < length && s[pos] == s[start]) { }
maxLength = Math.Max(maxLength, pos - start);
}
return maxLength;
}
I have two words,
britanicaeng and
britanicahin
I need to find out the longest common word between these i.e, britanica.
How can I do this in C# ?
Try this method:
public static string FindLongestCommonSubstring(string s1, string s2)
{
int[,] a = new int[s1.Length + 1, s2.Length + 1];
int row = 0; // s1 index
int col = 0; // s2 index
for (var i = 0; i < s1.Length; i++)
for (var j = 0; j < s2.Length; j++)
if (s1[i] == s2[j])
{
int len = a[i + 1, j + 1] = a[i, j] + 1;
if (len > a[row, col])
{
row = i + 1;
col = j + 1;
}
}
return s1.Substring(row - a[row, col], a[row, col]);
}
Usage example:
Console.WriteLine(FindLongestCommonSubstring("britanicaeng", "britanicahin"));
I refactored the C++ code from Ashutosh Singh at https://iq.opengenus.org/longest-common-substring-using-rolling-hash/ to create a rolling hash approach in C# - this will find the substring in O(N * log(N)^2) time and O(N) space
using System;
using System.Collections.Generic;
public class RollingHash
{
private class RollingHashPowers
{
// _mod = prime modulus of polynomial hashing
// any prime number over a billion should suffice
internal const int _mod = (int)1e9 + 123;
// _hashBase = base (point of hashing)
// this should be a prime number larger than the number of characters used
// in my use case I am only interested in ASCII (256) characters
// for strings in languages using non-latin characters, this should be much larger
internal const long _hashBase = 257;
// _pow1 = powers of base modulo mod
internal readonly List<int> _pow1 = new List<int> { 1 };
// _pow2 = powers of base modulo 2^64
internal readonly List<long> _pow2 = new List<long> { 1L };
internal void EnsureLength(int length)
{
if (_pow1.Capacity < length)
{
_pow1.Capacity = _pow2.Capacity = length;
}
for (int currentIndx = _pow1.Count - 1; currentIndx < length; ++currentIndx)
{
_pow1.Add((int)(_pow1[currentIndx] * _hashBase % _mod));
_pow2.Add(_pow2[currentIndx] * _hashBase);
}
}
}
private class RollingHashedString
{
readonly RollingHashPowers _pows;
readonly int[] _pref1; // Hash on prefix modulo mod
readonly long[] _pref2; // Hash on prefix modulo 2^64
// Constructor from string:
internal RollingHashedString(RollingHashPowers pows, string s, bool caseInsensitive = false)
{
_pows = pows;
_pref1 = new int[s.Length + 1];
_pref2 = new long[s.Length + 1];
const long capAVal = 'A';
const long capZVal = 'Z';
const long aADif = 'a' - 'A';
unsafe
{
fixed (char* c = s)
{
// Fill arrays with polynomial hashes on prefix
for (int i = 0; i < s.Length; ++i)
{
long v = c[i];
if (caseInsensitive && capAVal <= v && v <= capZVal)
{
v += aADif;
}
_pref1[i + 1] = (int)((_pref1[i] + v * _pows._pow1[i]) % RollingHashPowers._mod);
_pref2[i + 1] = _pref2[i] + v * _pows._pow2[i];
}
}
}
}
// Rollingnomial hash of subsequence [pos, pos+len)
// If mxPow != 0, value automatically multiply on base in needed power.
// Finally base ^ mxPow
internal Tuple<int, long> Apply(int pos, int len, int mxPow = 0)
{
int hash1 = _pref1[pos + len] - _pref1[pos];
long hash2 = _pref2[pos + len] - _pref2[pos];
if (hash1 < 0)
{
hash1 += RollingHashPowers._mod;
}
if (mxPow != 0)
{
hash1 = (int)((long)hash1 * _pows._pow1[mxPow - (pos + len - 1)] % RollingHashPowers._mod);
hash2 *= _pows._pow2[mxPow - (pos + len - 1)];
}
return Tuple.Create(hash1, hash2);
}
}
private readonly RollingHashPowers _rhp;
public RollingHash(int longestLength = 0)
{
_rhp = new RollingHashPowers();
if (longestLength > 0)
{
_rhp.EnsureLength(longestLength);
}
}
public string FindCommonSubstring(string a, string b, bool caseInsensitive = false)
{
// Calculate max neede power of base:
int mxPow = Math.Max(a.Length, b.Length);
_rhp.EnsureLength(mxPow);
// Create hashing objects from strings:
RollingHashedString hash_a = new RollingHashedString(_rhp, a, caseInsensitive);
RollingHashedString hash_b = new RollingHashedString(_rhp, b, caseInsensitive);
// Binary search by length of same subsequence:
int pos = -1;
int low = 0;
int minLen = Math.Min(a.Length, b.Length);
int high = minLen + 1;
var tupleCompare = Comparer<Tuple<int, long>>.Default;
while (high - low > 1)
{
int mid = (low + high) / 2;
List<Tuple<int, long>> hashes = new List<Tuple<int, long>>(a.Length - mid + 1);
for (int i = 0; i + mid <= a.Length; ++i)
{
hashes.Add(hash_a.Apply(i, mid, mxPow));
}
hashes.Sort(tupleCompare);
int p = -1;
for (int i = 0; i + mid <= b.Length; ++i)
{
if (hashes.BinarySearch(hash_b.Apply(i, mid, mxPow), tupleCompare) >= 0)
{
p = i;
break;
}
}
if (p >= 0)
{
low = mid;
pos = p;
}
else
{
high = mid;
}
}
// Output answer:
return pos >= 0
? b.Substring(pos, low)
: string.Empty;
}
}
Just got done with the latest Codility, passed it, but didnt get 100% on it
Here is the spec
A prefix of a string S is any leading contiguous part of S. For example, "c" and "cod" are prefixes of the string "codility". For simplicity, we require prefixes to be non-empty.
The product of prefix P of string S is the number of occurrences of P multiplied by the length of P. More precisely, if prefix P consists of K characters and P occurs exactly T times in S, then the product equals K * T.
For example, S = "abababa" has the following prefixes:
"a", whose product equals 1 * 4 = 4,
"ab", whose product equals 2 * 3 = 6,
"aba", whose product equals 3 * 3 = 9,
"abab", whose product equals 4 * 2 = 8,
"ababa", whose product equals 5 * 2 = 10,
"ababab", whose product equals 6 * 1 = 6,
"abababa", whose product equals 7 * 1 = 7.
The longest prefix is identical to the original string. The goal is to choose such a prefix as maximizes the value of the product. In above example the maximal product is 10.
In this problem we consider only strings that consist of lower-case English letters (a−z).
So basically, it is a string traverse problem. I was able to pass all the validation parts, but I lost on the time. Here is what I wrote
int Solution(string S)
{
int finalCount = 0;
for (int i = 0; i <= S.Length - 1; i++)
{
string prefix = S.Substring(0, i + 1);
int count = 0;
for (int j = 0; j <= S.Length - 1; j++)
{
if (prefix.Length + j <= S.Length)
{
string newStr = S.Substring(j, prefix.Length);
if (newStr == prefix)
{
count++;
}
}
if (j == S.Length - 1)
{
int product = count * prefix.Length;
if (product > finalCount)
{
finalCount = product;
}
}
}
}
return finalCount;
}
I know that the nested loop is killing me, but I cannot think of a way to traverse the "sections" of the string without adding the other loop.
Any help would be appreciated.
Naive brute-force solution takes O(N ** 3) time. Choose length from 1 to N, get a prefix of its length and count occurences by brute-force searching. Сhoosing length takes O(N) time and brute force takes O(N ** 2) time, totally O(N ** 3).
If you use KMP or Z-algo, you can find occurences in O(N) time, so the whole solution will be O(N ** 2) time.
And you can precalc occurences, so it will take O(N) + O(N) = O(N) time solution.
vector<int> z_function(string &S); //z-function, z[0] = S.length()
vector<int> z = z_function(S);
//cnt[i] - count of i-length prefix occurrences of S
for (int i = 0; i < n; ++i)
++cnt[z[i]];
//if cnt[i] is in S, cnt[i - 1] will be in S
int previous = 0;
for (int i = n; i > 0; --i) {
cnt[i] += previous;
previous = cnt[i];
}
Here's the blog post, explaining all O(N ** 3), O(N ** 2), O(N) solutions.
my effort was as follows trying to eliminate unnecessary string compares, i read isaacs blog but it is in c how would this translate to c#, i even went as far as using arrays everywhere to avoid the string immutability factor but there was no improvement
int Rtn = 0;
int len = S.Length;
if (len > 1000000000)
return 1000000000;
for (int i = 1; i <= len; i++)
{
string tofind = S.Substring(0, i);
int tofindlen = tofind.Length;
int occurencies = 0;
for (int ii = 0; ii < len; ii++)
{
int found = FastIndexOf(S, tofind.ToCharArray(), ii);
if (found != -1)
{
if ((found == 0 && tofindlen != 1) || (found >= 0))
{
ii = found;
}
++occurencies ;
}
}
if (occurencies > 0)
{
int total = occurencies * tofindlen;
if (total > Rtn)
{
Rtn = total;
}
}
}
return Rtn;
}
static int FastIndexOf(string source, char[] pattern, int start)
{
if (pattern.Length == 0) return 0;
if (pattern.Length == 1) return source.IndexOf(pattern[0], start);
bool found;
int limit = source.Length - pattern.Length + 1 - start;
if (limit < 1) return -1;
char c0 = pattern[0];
char c1 = pattern[1];
// Find the first occurrence of the first character
int first = source.IndexOf(c0, start, limit);
while ((first != -1) && (first + pattern.Length <= source.Length))
{
if (source[first + 1] != c1)
{
first = source.IndexOf(c0, ++first);
continue;
}
found = true;
for (int j = 2; j < pattern.Length; j++)
if (source[first + j] != pattern[j])
{
found = false;
break;
}
if (found) return first;
first = source.IndexOf(c0, ++first);
}
return -1;
}
I only got a 43... I like my code though! Same script in javascript got 56 for what it's worth.
using System;
class Solution
{
public int solution(string S)
{
int highestCount = 0;
for (var i = S.Length; i > 0; i--)
{
int occurs = 0;
string prefix = S.Substring(0, i);
int tempIndex = S.IndexOf(prefix) + 1;
string tempString = S;
while (tempIndex > 0)
{
tempString = tempString.Substring(tempIndex);
tempIndex = tempString.IndexOf(prefix);
tempIndex++;
occurs++;
}
int product = occurs * prefix.Length;
if ((product) > highestCount)
{
if (highestCount > 1000000000)
return 1000000000;
highestCount = product;
}
}
return highestCount;
}
}
This works better
private int MaxiumValueOfProduct(string input)
{
var positions = new List<int>();
int max = 0;
for (int i = 1; i <= input.Length; i++)
{
var subString = input.Substring(0, i);
int position = 0;
while ((position < input.Length) &&
(position = input.IndexOf(subString, position, StringComparison.OrdinalIgnoreCase)) != -1)
{
positions.Add(position);
++position;
}
var currentMax = subString.Length * positions.Count;
if (currentMax > max) max = currentMax;
positions.Clear();
}
return max;
}