I have a small application that needs to save to contents of a rich text box as a text file upon a button click. What I currently have is
//save button logic
private void saveBtn1_Click(object sender, EventArgs e)
{
//set up new SaveFileDialog
SaveFileDialog saveFileDialog1 = new SaveFileDialog();
saveFileDialog1.Filter = "Text Files (*.txt)|*.txt";
saveFileDialog1.Title = "Save a text File";
//prompt the user
DialogResult result = saveFileDialog1.ShowDialog();
//if they select save write the contents of the RTB to a text file
if (result == DialogResult.OK)
{
System.IO.File.WriteAllText(saveFileDialog1.FileName, richTextBox1.Text);
}
}
It seems like a pretty straight forward piece of code, but I can't figure out why the dialog opens twice.
Just expanding Servy's comment into an answer because I suspect his diagnosis is correct. I'm going to give some simple suggestions for diagnosing/finding the problem. Firstly, you can put a break point in the event handler, if you're taken into that event handler twice then that's obviously the problem. The other solution (without even running) is simply to right click on the method name and select "find all references" this will give you list of all the references to the this method within your code. I'm guessing you will find 3; the method itself, the place where you expect to be registering it, and the place you were you don't. Remove the one and your problem will go away.
Shortest answer: you called the save dialog() twice in your code. Remove the second one and your issue will clear up.
Because you are used twice.
Thisa is simple excample for you
SaveFileDialog save = new SaveFileDialog();
save.DefaultExt = "zip";
save.Filter = "zip faylı (*.zip)|*.7z|Hamısı(*.*)|*.*";
save.ShowDialog(); // this is first using
if (save.ShowDialog() == DialogResult.OK) // and second using save.ShowDialog()
{
// yours code here
}
Related
I have been searching for DAYS for material explaining how to do this...
I have a code in WPF (C#) that loops through a collection of FrameworkElements. The objective is to save each of the FrameworkElements as separate images (gif files). The code is working currently and does in fact save all of the images I need.
However, the user has to manually click the "Save" button in the SaveFileDialog box for EACH element. There are over 100 elements. I want the code to Open the SaveFileDialog box and automatically "click" the "Save" button for the user throughout the loop (ie - for each element).
Here is the code currently...
foreach(FrameworkElement x in y)
{
SaveFileDialog dlg = new SaveFileDialog();
dlg.Filter = " ...blah...";
dlg.DefaultExt = "...blah..";
Nullable<bool> result = dlg.ShowDialog(); // (A)
string path = dlg.FileName;
int selectedFilterIndex = dlg.FilterIndex;
if(result == true) // (B)
{ ... then do all the rendering, cropping, etc.. .. }
}
I know that I can write some line in between the line containing "(A)" and "(B)" that will activate the "Save" button. I cannot find any examples online that eliminate the "if" statement.
I don't want my code to "wonder if this result will be true". I want the code to actually set the result to true regardless of anything else.
Any help is greatly appreciated.
I'm trying to make this program in C# using WPF in Visual Studio. This is basically what it has to do.
When a button called "Browse" is clicked on the main form, it will open up a new form/window that let's the user browse to any directory that he chooses. After he selects the folder and clicks "Open" (or some other button on that form), the path of that directory, for example, "C:\temp" will be stored in a string variable so it can used later.
My first problem is, what do I write in the even handler of the "Browse" button that will open up a window that let's the user browse and select a folder? Is there a default window I can use or do I have to create a new form for it? Please note, the user has to select a folder, not a file like the default "Open" window.
Secondly, how do I reference a string variable so that it stores the path of the directory that the user selected?
The type you are looking for is the OpenFileDialog
http://msdn.microsoft.com/en-us/library/system.windows.forms.openfiledialog.aspx
The basic usage is the following
using (FileDialog fileDialog = new OpenFileDialog()) {
if (DialogResult.Ok == fileDialog.ShowDialog()) {
string fileName = fileDialog.FileName;
...
}
}
EDIT
Comments clarified OP is looking to open a directory vs. a file. For this you need the FolderBrowseDialog
var dialog = new System.Windows.Forms.FolderBrowserDialog();
System.Windows.Forms.DialogResult result = dialog.ShowDialog();
For choosing directory you should use FolderBrowserDialog. It's a control from WinForms. WPF doesn't have it's own.
For example:
var dialog = new FolderBrowserDialog();
var result = dialog.ShowDialog();
if (result == DialogResult.OK)
// ...
Don't forget to add reference to the System.Windows.Forms.
Simply do this on Button Click
FileDialog fileDialog = new OpenFileDialog();
fileDialog.ShowDialog();
folderpathTB.Text = fileDialog.FileName;
(folderpathTB is name of TextBox where I wana put the file path, OR u can assign it to a string variable too)
This small program shows how to open a txt file on the hard drive, is there a way I can have a procedure that when I click a button a txt file pops up, may someone help me with it or how I can go about it....
This is the procedure below
private void button1_Click(object sender, EventArgs e)
{
OpenFileDialog of = new OpenFileDialog();
of.ShowDialog();
textBox1.Text = of.FileName;
}
May somebody tell me what I can do or give some material to read kind of new in C#
Assuming that you like opening notepad with the text file showing on it, you could use:
System.Diagnostics.Process.Start(of.FileName);
This will open the file using the default text editor of the computer.
EDIT
According to your comment, you should the do it like this:
private void button1_Click(object sender, EventArgs e)
{
System.Diagnostics.Process.Start(#"C:\dir1\dir2\yourfile.txt");
}
Obviusly, you should replace that with the path for your specific file.
Try
MessageBox.Show(File.ReadAllText(of.FileName));
After it, try to learn each component of the statement, what it does.
BTW,
You also need:
if (of.ShowDialog() == DialogResult.OK)
before that, to avoid displaying message in case user clicks Cancel.
Based on the clarification, this is pretty straightforward. Just create a new form class that contains a textbox (and probably a Close button). You'll want a property on the form that will set the textbox. You can launch the this form from your button event handler (the one you have in your example) like this:
using(var myForm = new TextBoxForm()) {
myForm.TextFileContents = <file contents>
myForm.ShowDialog();
}
As for reading in the file contents, you'll want to use File.ReadAllText() as described in Daniel's answer. See the MSDN documentation for more on that. I'll leave the remaining details as an exercise to the reader.
I'm using Microsoft.Win32.SaveFileDialog class to save my files. When I saved file, and minimize my app, I can't restore it back. It happens only after when used Microsoft.Win32.SaveFileDialog. Here is code:
Microsoft.Win32.SaveFileDialog dlg = new Microsoft.Win32.SaveFileDialog();
dlg.FileName = String.Format("{0} {1} {2}", ev["b"], ev["a"], ev["c"]);
dlg.DefaultExt = ".csv";
dlg.Filter = "Supported format (.csv)|*.csv";
Nullable<bool> result = dlg.ShowDialog();
if (result == true)
{
string s = dlg.FileName;
//other code
}
File saves successfully, but I don't know how to solve problem with minimizing. Does anybody knows what it could be?
WPF has all kinds of weird modality issues when you show dialogs without parent windows. I haven't seen this directly with the SaveFileDialog, but I have seen similar behavior with other dialogs. Try using the overload of .ShowDialog() where you pass in the parent window.
I encountered also a strange modality problem with WPF and the Win32 SaveFileDialog / OpenFileDialog.
What happens:
The modal state is violated / gets lost completely and the main window can be clicked while the OpenFileDialog is opened with ShowDialog()
When does it happen:
There was a task running before the OpenFileDialog opens
The debugger breaks into a breakpoint before running the task
Just create a simple WPF Application with a button click event:
private void Button_Click(object sender, RoutedEventArgs e)
{ // <-- Breakpoint sits here
Task.Run(() => {}).Wait();
new Microsoft.Win32.OpenFileDialog().ShowDialog();
}
Using the overloaded ShowDialog(Window owner) function solves this problem.
If the dialog click Make new folder, just start editing the name just create a folder and click OK, OK dialogrezalt returns, but in the property SelectedPath he will name the folder New folder, then there is the name of the default
This happens because when we create, just edit and click OK, this property is not updated and the method ShowDialog () returns.
How fix this problem?
Thank you!
I had the same problem - if you created a new Folder with the FolderBrowseDialog, the .SelectedPath showed "xxx\NewFolder" not whatever new name the user had given.
The problem went away once I explicitly gave the command, prior to displaying the dialog,
MyFolderBrowser.ShowNewFolderButton = True
I failed to simulate the problem you are describing, I have tested it:
Create a new Form Form1 add button1 to it and in the button1.Click handler copy this code:
private void button1_Click(object sender, EventArgs e)
{
using (FolderBrowserDialog dialog = new FolderBrowserDialog())
{
dialog.ShowNewFolderButton = true;
if (dialog.ShowDialog(this) == System.Windows.Forms.DialogResult.OK)
{
string path = dialog.SelectedPath;
Console.WriteLine(path);//will not print new folder if the file renamed.
}
}
}
It worked as expected either by creating a new folder and press enter two times. or by creating a new folder and click ok.
Are you using a third party UI Controls, theams...
Edit: You stated:
Yes, if this sample run at windows application, it work correct. But
my application is Excel add-in. And FolderBrowserDialog work that I
write at started post
So you are using a third party "Excel add-in", When using a third party with FolderBrowserDialog or OpenFileDialog.. you may notice a strange behavior depending on the third party..
The solution for the problem you described is either by disabling ShowNewFolderButton or implement your own custom OpenFileDialog.