i am trying to write a code to encrypt text using public key and decrypt using private key and passphrase.
I am not very good with programming language because i'm not a programming student. But for my mini-project, i need to write some program about encryption.
For the below code uses a text file from my c drive to encode using the public key.
But i want to use openfiledialog to choose the file instead of directing it manually(not really practical)
Really appreciate if anyone can help me edit the codes.
P.S. i don't really know how to apply openfiledialog to my code. i keep getting errors when i use informations from youtubes and google.
using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Windows.Forms;
using System.IO;
using DidiSoft.Pgp;
namespace TEST2
{
public partial class Form1 : Form
{
PGPLib pgp = new PGPLib();
public Form1()
{
InitializeComponent();
}
private void encryptButton_Click(object sender, EventArgs e)
{
string testingstring = pgp.EncryptString(testTextBox.Text, new FileInfo(#"c:\TCkeyPublic.txt"));
encryptedtextTextBox.Text = testingstring;
}
private void decryptButton_Click(object sender, EventArgs e)
{
try
{
String plainString = pgp.DecryptString(encryptedtextTextBox.Text,
new FileInfo(#"c:\TCkeyPrivate.txt"), passphraseTextBox.Text);
decryptedtextTextBox.Text = plainString;
encryptedtextTextBox.Text = "";
passphraseTextBox.Text = "";
}
catch
{
MessageBox.Show("ERROR! Please check passphrase and do not attempt to edit cipher text");
}
}
private void passphraseTextBox_TextChanged(object sender, EventArgs e)
{
}
private void Form1_Load(object sender, EventArgs e)
{
}
}
}
Assuming you're using WinForms.
Just create an instance of OpenFileDialog, call ShowDialog and if user didn't cancel the operation then read FileName property: it'll contain the full path of selected file. In code:
var dlg = new OpenFileDialog();
if (dlg.ShowDialog() != DialogResult.OK)
return;
new FileInfo(dlg.FileName, passphraseTextBox.Text);
Of course you may need to let user quickly filter files to display, you can use Filter property for that:
var dlg = new OpenFileDialog();
dlg.Filter = "Text Files (*.txt)|*.txt|All Files (*.*)|*.*";
You can even allow multiple selection, set Multiselect to true and you'll get all selected files in the FileNames property:
var dlg = new OpenFileDialog();
dlg.Filter = "Text Files (*.txt)|*.txt|All Files (*.*)|*.*";
dlg.Multiselect = true;
if (dlg.ShowDialog() != DialogResult.OK)
return;
foreach (var path in dlg.FileNames)
{
new FileInfo(path, passphraseTextBox.Text);
// ...
}
private void decryptButton_Click(object sender, EventArgs e)
{
OpenFileDialog openFileDialog1 = new OpenFileDialog();
openFileDialog1.InitialDirectory = "c:\\" ;
openFileDialog1.Filter = "txt files (*.txt)|*.txt|All files (*.*)|*.*" ;
openFileDialog1.FilterIndex = 2 ;
openFileDialog1.RestoreDirectory = true ;
if(openFileDialog1.ShowDialog() == DialogResult.OK)
{
try
{
String plainString = pgp.DecryptString(encryptedtextTextBox.Text,new FileInfo(openFileDialog1.FileName), passphraseTextBox.Text);
decryptedtextTextBox.Text = plainString;
encryptedtextTextBox.Text = "";
passphraseTextBox.Text = "";
}
catch
{
MessageBox.Show("ERROR! Please check passphrase and do not attempt to edit cipher text");
}
}
}
Related
I am trying to build a small .pdf -> .txt / searchable .pdf converter, but I am having trouble to assign the first var result to the other buttons
Made myself a "solution" but the code seems too messed and exagerated.
using IronOcr;
using System;
using System.IO;
namespace ocr
{
public partial class Form1 : Form
{
public Form1()
{
InitializeComponent();
}
private void button1_Click(object sender, EventArgs e)
{
OpenFileDialog ofd = new OpenFileDialog();
ofd.Filter = "pdf files (*.pdf)|*.pdf|All Files (*.*)|*.*";
if (ofd.ShowDialog() == DialogResult.OK)
{
textBox1.Text = ofd.FileName;
var Ocr = new IronTesseract(); // nothing to configure
IronOcr.License.LicenseKey = "SOMELICENSEKEY";
using (var Input = new OcrInput())
{
Input.AddPdf(ofd.FileName, "password");
var Result = Ocr.Read(Input);
Console.WriteLine(Result.Text);
richTextBox1.Text = Result.Text;
}
}
}
private void button2_Click(object sender, EventArgs e)
{
OpenFileDialog ofd = new OpenFileDialog();
ofd.Filter = "pdf files (*.pdf)|*.pdf|All Files (*.*)|*.*";
if (ofd.ShowDialog() == DialogResult.OK)
{
textBox1.Text = ofd.FileName;
var Ocr = new IronTesseract(); // nothing to configure
IronOcr.License.LicenseKey = "SOMELICENSEKEY";
using (var Input = new OcrInput())
{
Input.AddPdf(ofd.FileName, "password");
var Result = Ocr.Read(Input);
Console.WriteLine(Result.Text);
Result.SaveAsTextFile("pdf.txt");
}
}
}
private void button3_Click(object sender, EventArgs e)
{
OpenFileDialog ofd = new OpenFileDialog();
ofd.Filter = "pdf files (*.pdf)|*.pdf|All Files (*.*)|*.*";
if (ofd.ShowDialog() == DialogResult.OK)
{
textBox1.Text = ofd.FileName;
var Ocr = new IronTesseract(); // nothing to configure
IronOcr.License.LicenseKey = "SOMELICENSEKEY";
using (var Input = new OcrInput())
{
Input.AddPdf(ofd.FileName, "password");
var Result = Ocr.Read(Input);
Console.WriteLine(Result.Text);
Result.SaveAsSearchablePdf("pdfpesquisavel.pdf");
}
}
}
}
}
Tried to assign and use the variable "Result" in the others buttons fuctions (button 2 and button 3)
But it didn't worked.
I already got most of the help I needed in order to create a working button to save my scraped proxies to a .txt file, but I still run into one issue. This is the code that I have gotten so far, it works perfectly fine:
using System;
using System.Text;
using System.Text.RegularExpressions;
using System.Net;
using System.Windows.Forms;
using System.IO;
namespace CyberScraper
{
public partial class Base_Scraper : Form
{
WebClient _WC = new WebClient();
Defaults _DF = new Defaults();
public Base_Scraper()
{
CheckForIllegalCrossThreadCalls = false;
InitializeComponent();
}
private void Base_Scraper_Load(object sender, EventArgs e)
{
MessageBox.Show("twitch.tv/CyberLost same YT Name");
}
private void ScrapeTheProxies()
{
try
{
foreach (string Source in ScrapeSources.Lines)
{
string UnparsedWebSource = _WC.DownloadString(Source);
MatchCollection _MC = _DF.REGEX.Matches(UnparsedWebSource);
foreach (Match Proxy in _MC)
{
GatheredProxies.Items.Add(Proxy);
}
}
}
catch (Exception)
{
}
}
private void SaveProxyResults_Click(object sender, System.EventArgs e)
{
Stream myStream;
SaveFileDialog dlg = new SaveFileDialog();
dlg.Title = "";
dlg.InitialDirectory = #"C:\Users\username\Desktop";
dlg.Filter = "txt files (*.txt)|*.txt";
dlg.FilterIndex = 1;
if (dlg.ShowDialog() == DialogResult.OK)
{
if ((myStream = dlg.OpenFile()) != null)
{
myStream.Close();
StreamWriter writer = new StreamWriter(dlg.FileName);
for (int i = 0; i < GatheredProxies.Items.Count; i++)
{
writer.WriteLine((string)GatheredProxies.Items[i]);
}
writer.Close();
}
}
dlg.Dispose();
}
private void BackgroundWorker_DoWork(object sender, System.ComponentModel.DoWorkEventArgs e)
{
ScrapeTheProxies();
}
private void ScrapeButton_Click(object sender, EventArgs e)
{
BackgroundWorker.RunWorkerAsync();
}
}
}
When I click on "Save Results" it works before I scraped the proxies, if I do it after finishing scraping the proxies it outputs this error and saves it on the desktop as an empty .txt file instead of a .txt file containing the scraped proxies:
System.InvalidCastException: 'Unable to cast object of type 'System.Text.RegularExpressions.Match' to type 'System.String'.'
in:
writer.WriteLine((string)GatheredProxies.Items[i]);
I am creating a text editor and i am stuck on the SaveFileDialog window opening
and asking to overwrite the current file open.
I have seen all the similar questions asked like this on SO but none have been able to help me. I have even tried the code from this question: "Saving file without dialog" Saving file without dialog
I got stuck on my program having a problem with FileName.
Here is the code i have currently
namespace Text_Editor
{
public partial class Form1 : Form
{
public Form1()
{
InitializeComponent();
}
private void newToolStripMenuItem_Click(object sender, EventArgs e)
{
richTextBox1.Clear();
}
private void openToolStripMenuItem_Click(object sender, EventArgs e)
{
OpenFileDialog open = new OpenFileDialog();
open.Filter = "Text Files (.txt)|*.txt|All Files (*.*)|*.*";
open.Title = "Open File";
open.FileName = "";
if (open.ShowDialog() == DialogResult.OK)
{
this.Text = string.Format("{0}", Path.GetFileNameWithoutExtension(open.FileName));
StreamReader reader = new StreamReader(open.FileName);
richTextBox1.Text = reader.ReadToEnd();
reader.Close();
}
}
private void exitToolStripMenuItem_Click(object sender, EventArgs e)
{
Application.Exit();
}
private void saveToolStripMenuItem_Click(object sender, EventArgs e)
{
SaveFileDialog save = new SaveFileDialog();
save.Filter = "Text Files (.txt)|*.txt|All Files (*.*)|*.*";
save.Title = "Save File";
save.InitialDirectory = Environment.GetFolderPath(Environment.SpecialFolder.MyDocuments);
if (save.ShowDialog() == DialogResult.OK)
{
StreamWriter writer = new StreamWriter(save.FileName);
writer.Write(richTextBox1.Text);
writer.Close();
}
}
private void saveAsToolStripMenuItem_Click(object sender, EventArgs e)
{
SaveFileDialog saving = new SaveFileDialog();
saving.InitialDirectory = Environment.GetFolderPath(Environment.SpecialFolder.MyDocuments);
saving.Filter = "Text Files (.txt)|*.txt|All Files (*.*)|*.*";
saving.Title = "Save As";
saving.FileName = "Untitled";
if (saving.ShowDialog() == DialogResult.OK)
{
StreamWriter writing = new StreamWriter(saving.FileName);
writing.Write(richTextBox1.Text);
writing.Close();
}
}
}
}
So my question is how can i modify my code so that i can save a file currently open without having the SaveFileDialog box opening everytime?
I do understand that it has something to do with the fact that i'm calling .ShowDialog but i don't know how to modify it.
When opening the file, save the FileName in a form-level variable or property.
Now while saving the file, you can use this FileName instead of getting it from a FileOpenDialog.
First declare a variable to hold filename at form level
// declare at form level
private string FileName = string.Empty;
When opening a file, save the FileName in this variable
private void openToolStripMenuItem_Click(object sender, EventArgs e)
{
OpenFileDialog open = new OpenFileDialog();
open.Filter = "Text Files (.txt)|*.txt|All Files (*.*)|*.*";
open.Title = "Open File";
open.FileName = "";
if (open.ShowDialog() == DialogResult.OK)
{
// save the opened FileName in our variable
this.FileName = open.FileName;
this.Text = string.Format("{0}", Path.GetFileNameWithoutExtension(open.FileName));
StreamReader reader = new StreamReader(open.FileName);
richTextBox1.Text = reader.ReadToEnd();
reader.Close();
}
}
And when doing SaveAs operation, update this variable
private void saveAsToolStripMenuItem_Click(object sender, EventArgs e)
{
SaveFileDialog saving = new SaveFileDialog();
saving.InitialDirectory = Environment.GetFolderPath(Environment.SpecialFolder.MyDocuments);
saving.Filter = "Text Files (.txt)|*.txt|All Files (*.*)|*.*";
saving.Title = "Save As";
saving.FileName = "Untitled";
if (saving.ShowDialog() == DialogResult.OK)
{
// save the new FileName in our variable
this.FileName = saving.FileName;
StreamWriter writing = new StreamWriter(saving.FileName);
writing.Write(richTextBox1.Text);
writing.Close();
}
}
The save function can then be modified like this:
private void saveToolStripMenuItem_Click(object sender, EventArgs e)
{
if (string.IsNullOrEmpty(this.FileName))
{
// call SaveAs
saveAsToolStripMenuItem_Click(sender, e);
} else {
// we already have the filename. we overwrite that file.
StreamWriter writer = new StreamWriter(this.FileName);
writer.Write(richTextBox1.Text);
writer.Close();
}
}
In the New (and Close) function, you should clear this variable
private void newToolStripMenuItem_Click(object sender, EventArgs e)
{
// clear the FileName
this.FileName = string.Empty;
richTextBox1.Clear();
}
Create a new string variable in your class for example
string filename = string.empty
and then
private void saveToolStripMenuItem_Click(object sender, EventArgs e)
{
if(string.IsNullOrEmpty(filename)) {
//Show Save filedialog
SaveFileDialog save = new SaveFileDialog();
save.Filter = "Text Files (.txt)|*.txt|All Files (*.*)|*.*";
save.Title = "Save File";
save.InitialDirectory = Environment.GetFolderPath(Environment.SpecialFolder.MyDocuments);
if (save.ShowDialog() == DialogResult.OK)
{
filename = save.FileName;
}
}
StreamWriter writer = new StreamWriter(filename);
writer.Write(richTextBox1.Text);
writer.Close();
}
The SaveFileDialog now only opens if fileName is null or empty
You will have to store the fact that you have already saved the file, e.g. by storing the file name in a member variable of the Form class you have. Then use an if to check whether you have already saved your file or not, and then either display the SaveFileDialog using ShowDialog() (in case you haven't) or don't and continue to save to the already defined file name (stored in your member variable).
Give it a try, do the following:
Define a string member variable, call it _fileName (private string _fileName; in your class)
In your saveToolStripMenuItem_Click method, check if it's null (if (null == _fileName))
If it is null, continue as before (show dialog), and after getting the file name, store it in your member variable
Refactor your file writing code so that you either get the file name from the file dialog (like before), or from your member variable _fileName
Have fun, C# is a great language to program in.
First, extract method from saveAsToolStripMenuItem_Click: what if you want add up a popup menu, speed button? Then just implement
public partial class Form1: Form {
// File name to save text to
private String m_FileName = "";
private Boolean SaveText(Boolean showDialog) {
// If file name is not assigned or dialog explictly required
if (String.IsNullOrEmpty(m_FileName) || showDialog) {
// Wrap IDisposable into using
using (SaveFileDialog dlg = new SaveFileDialog()) {
dlg.Filter = "Text Files (.txt)|*.txt|All Files (*.*)|*.*";
dlg.Title = "Save File";
dlg.FileName = m_FileName;
if (dlg.ShowDialog() != DialogResult.OK)
return false;
m_FileName = dlg.FileName;
}
}
File.WriteAllText(m_FileName, richTextBox1.Text);
this.Text = Path.GetFileNameWithoutExtension(m_FileName);
return true;
}
private void saveAsToolStripMenuItem_Click(object sender, EventArgs e) {
// SaveAs: always show the dialog
SaveText(true);
}
private void saveToolStripMenuItem_Click(object sender, EventArgs e) {
// Save: show the dialog when required only
SaveText(false);
}
...
}
Here is my code;
private void button1_Click(object sender, EventArgs e)
{
string newFile =textBox1.Text;
string temp = newFile.Replace("YNATEST.", "");
SaveFileDialog a1 = new SaveFileDialog();
a1.FileName = "";
a1.Filter = "Text Files(*txt)|*.txt";
a1.DefaultExt = "txt";
a1.ShowDialog();
StreamWriter yazmaislemi = new StreamWriter(a1.FileName);
yazmaislemi.WriteLine(temp);
yazmaislemi.Close();
}
it is saving the text on Desktop but i want to save it to the following path:
C:\Users\esra.ur\Desktop\projee1
use save file dialog, so you can save your text in your specific directory
using System;
using System.ComponentModel;
using System.IO;
using System.Windows.Forms;
namespace WindowsFormsApplication30
{
public partial class Form1 : Form
{
public Form1()
{
InitializeComponent();
}
private void button1_Click(object sender, EventArgs e)
{
// When user clicks button, show the dialog.
saveFileDialog1.ShowDialog();
}
private void saveFileDialog1_FileOk(object sender, CancelEventArgs e)
{
// Get file name.
string name = saveFileDialog1.FileName;
// Write to the file name selected.
// ... You can write the text from a TextBox instead of a string literal.
File.WriteAllText(name, "test");
}
}
}
this code snippets is from this link http://www.dotnetperls.com/savefiledialog
I hope it will help
1) Wrap your show dialog to check the result.
if(a1.ShowDialog() == DialogResult.OK)
2) The SaveFileDialog has a property for setting an initial path. This is for the directory which will be shown when the dialog is first open. For the desktop you want to use the Environment.GetFolderPath like so.
a1.InitialDirectory = Environment.GetFolderPath(Environment.SpecialFolder.Desktop);
3) Try to separate concerns:
private string OutputFile {get;set;}
private void button1_Click(object sender, EventArgs e)
{
if(string.IsNullOrEmpty(this.OutputPath))
{
SaveFileDialog a1 = new SaveFileDialog();
a1.FileName = textBox1.Text;
a1.Filter = "Text Files(*txt)|*.txt";
a1.DefaultExt = "txt";
a1.InitialDirectory = Environment.GetFolderPath(Environment.SpecialFolder.Desktop);
if(a1.ShowDialog() == DialogResult.OK)
{
this.OutputFile = ai.FileName
}
}
this.SaveFile(this.OutputFile);
}
private void SaveFile(string FileName)
{
string newFile = FileName;
string temp = newFile.Replace("YNATEST.", "");
using(StreamWriter yazmaislemi = new StreamWriter(temp))
{
yazmaislemi.WriteLine(temp);
yazmaislemi.Close();
}
}
The SaveFileDialog object has a property called InitialDirectory, which is a string you can specify, for example
SaveFileDialog a1 = new SaveFileDialog();
a1.InitialDirectory = #"C:\Users\esra.ur\Desktop\projee1";
If this directory doesn't exist, it will default back to documents. Be careful about writing a file even if the user tries to cancel. Hope this helps?
In response to your comment, it sounds like you want to hard code the destination file name. This is dangerous as you can get an exception if the directory doesn't exist, but you can use the following: (I'm not sure what you want to do with the file name)
'string newFile = textBox1.Text;
string temp = newFile.Replace("YNATEST.", "");
StreamWriter yazmaislemi = new StreamWriter(#"C:\Users\esra.ur\Desktop\projee1\" + temp + ".txt");
yazmaislemi.WriteLine(temp);
yazmaislemi.Close();
In this case you don't need the SaveFileDialog at all. I think this is what you're asking for, but it's dangerous to code in this way.
I've just recently started with C# and as a project I decided I would try and make a image converter, but I can't seem to get the variable "open" accessible in my button1 context, I'm not looking for comments on how bad my code is, I am just starting.. I just want to get this done and add on to it, I will improve the code later on, thanks. So how can I make it accessible?
using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Windows.Forms;
using System.IO;
namespace WindowsFormsApplication9
{
public partial class Form1 : Form
{
public Form1()
{
InitializeComponent();
}
public void button2_Click(object sender, EventArgs e)
{
OpenFileDialog open = new OpenFileDialog();
// image filters
open.Filter = "Image Files(*.jpg; *.jpeg; *.gif; *.bmp)|*.jpg; *.jpeg; *.gif; *.bmp";
if (open.ShowDialog() == DialogResult.OK)
{
// image in picture box
pictureBox1.Image = new Bitmap(open.FileName);
pictureBox1.SizeMode = PictureBoxSizeMode.AutoSize;
// image file path
string path = Directory.GetCurrentDirectory();
textBox1.Text = Path.GetDirectoryName(open.FileName);
}
}
public void Form1_Load(object sender, EventArgs e)
{
this.AutoSize = true;
this.AutoSizeMode = AutoSizeMode.GrowAndShrink;
flowLayoutPanel1 = new FlowLayoutPanel();
flowLayoutPanel1.AutoSize = true;
flowLayoutPanel1.AutoSizeMode = AutoSizeMode.GrowAndShrink;
this.Controls.Add(flowLayoutPanel1);
}
public void button1_Click(object sender, EventArgs e)
{
int selectedIndex = comboBox1.SelectedIndex;
Object selectedItem = comboBox1.SelectedItem;
if ((string)comboBox1.SelectedItem == "*.jpg")
{
pictureBox1.Image.Save(#"" + textBox1.Text + open.FileName + "", System.Drawing.Imaging.ImageFormat.Jpeg);
}
}
}
}
You could move the variable out of the method and into the class, making it an instance field of the class. Then any method would be able to see it. However, there are a few things wrong with that approach:
The OpenFileDialog, like any modal dialog, should be disposed of when you are done with it. Storing the reference in an instance field extends its lifetime until the next time you create a new one or your form is closed, whichever comes first.
All you really need is the file name, not all the other data and resources that the OpenFileDialog carries around, so it's wasteful.
From a user experience point of view, it would be better to give the user a chance to save to a different file anyway. You would be better off presenting a SaveFileDialog to the user, initializing with the currently selected file name.
Sticking with your current UI design, the following is the right way to do what you want:
private string fileName;
public void button2_Click(object sender, EventArgs e)
{
using (OpenFileDialog open = new OpenFileDialog())
{
// image filters
open.Filter = "Image Files(*.jpg; *.jpeg; *.gif; *.bmp)|*.jpg; *.jpeg; *.gif; *.bmp";
if (open.ShowDialog() == DialogResult.OK)
{
// image in picture box
filename = open.FileName;
pictureBox1.Image = new Bitmap(open.FileName);
pictureBox1.SizeMode = PictureBoxSizeMode.AutoSize;
// image file path
string path = Directory.GetCurrentDirectory();
textBox1.Text = Path.GetDirectoryName(open.FileName);
}
}
}
public void button1_Click(object sender, EventArgs e)
{
if (string.IsNullOrEmpty(fileName))
{
return;
}
int selectedIndex = comboBox1.SelectedIndex;
Object selectedItem = comboBox1.SelectedItem;
if ((string)comboBox1.SelectedItem == "*.jpg")
{
pictureBox1.Image.Save(#"" + textBox1.Text + fileName + "", System.Drawing.Imaging.ImageFormat.Jpeg);
}
}
Note the use of using to ensure that the OpenFileDialog instance is disposed of properly when it's no longer needed.
C# don't have global variables, but you can have a workaround for that,
public class GlobalObjects
{
private static OpenFileDialog ofd;
public static OpenFileDialog OpenFileDlg
{
get
{
if (ofd == null)
ofd = new OpenFileDialog();
return ofd;
}
}
}
and call it like,
var fileDlg = GlobalObjects.OpenFileDlg;