Develop Reference

Refresh an open form from another open form

I want to refresh an already opened form (form1) from another opened form's (form2) button_click(). In form1 I display the data saved by form2 and when form1 is already opened I want it to refresh if new data is saved on form2 in order to display it.
The problem is that I've tried iterating through `Application.Openforms`, but it turns out that it is read-only and I cannot access the form once found and I don't know how to access *form1* from *form2*, since I can't simply find it.
How can I access *form1* from *form2*?
Edit:
Form1 is actually opened from Form2.
The problem with Application.Openforms is that , as I've stated, a read-only list of forms already opened and I cant actually access the forms through it. They simply don't have the methods for it, I sugest you try using Application.OpenForms and look it up if you don't know how it works.
Also it's pointless to show what I've already tried because it includes Application.OpenForms, but for the sake of information:
FormCollection of = Application.OpenForms;
foreach (var f in of)
{
if (f.GetType().ToString() == "Kontrl_Doc.Visualizar")
{
f.Refresh();
}
}
When I click the button (button_click()) in Form2 it checks if Form1 is open or not. If Form1 isn't open it opens one and if it is than I'd like it to refresh it. Simultaneously, it closes Form2 and opens Form2 again, in order to reset is fields.
What I wan to do is, if the form1 is already opened , it form2 should tell it to refresh the already opened window with the form 1.

"Form1 is actually opened from Form2" - If this is the case, then just call Refresh using the form variable that you have in Form2. If necessary, make that a private field in the Form2 class or store it in an array for later use.
For example:
(Somewhere in Form2)
Form1 form1 = new Form1();
form1.Show();
(Inside the button click in Form2)
form1.Refresh();

you can use events. In form2 you place this code
public event Action ReloadForm1;
//on the place where you will reload form1
ReloadForm1();
and in form1 if you have opening form2:
form2.ReloadForm1 += Reload;
//outside method
void Reload()
{
this.Reload();
}

Create a void method in form1 and add the components u want to refresh maybe you want to reload a dropdown from db
public void Refresh()
{
...
}
then open a dialog of form2
catch the dialog result

Pass a value to and from two different forms C#

I have 2 windows forms (Form1 and Form2). (C#)
In Form1 I have a Text and a LinkLabel. When I click the LinkLabel in Form1, Form2 shows.
In Form2, there is a TextBox and 2 buttons (Ok and Cancel).
What I am trying to do is have the string from the Text in Form1 show up in the TextBox in Form2. The user will then be able to edit the Text in the TextBox, and can Press the Ok button to confirm the changes or press the Cancel button to discard the changes. If the Ok button is pressed, Form2 will close and the Text in Form1 will be changed to whatever was entered into the TextBox from Form2.

Pass the string into Form2's cstor. Form1 has a reference to the Form2 object because it constructs Form2. Add a property to Form2. Set the property and read the property after Form2 closes in Form1. Conditionally use the value to set the textbox value in Form1 based on the DialogResult.

Might be useful from MSDN
http://msdn.microsoft.com/en-us/library/aa288422(v=vs.71).aspx
And for form to show:
Form2 frm = new Form2();
frm.Show();

Similar question to others... Here's some solutions I've offered in the past...
Option 1
Option 2

Calling MessageBox.Show from a separate form

I'm wondering today if there is any way to show a messagebox with a separate form as it's parent. As an example, say I have Form1 and Form2. From Form1, how do I call a messagebox to show with Form2 as the parent? In my case, Form2 is dynamically created, if that makes a difference.

You can pass a Form instance as the first parameter to MessageBox.Show().

Better way to Display forms one on top of another

I have a Main form.I want to launch another form from it and launch another from the launched form.I want to ensure that the Main form is not editable when sub forms are displayed so i use showdialog()
Mainform>(Showdialog)>form1>(showDialog+dispose)>form2(dispose)>Mainform
From Mainform i call form2.ShowDialog() then from form2 i use the following code to launch another form
this.visible=false;
form3.showdialog();
this.dispose();
But there are some problems in this.Is there a better way to achieve what im looking for?
edit:more description
I have a Main form,User clicks a Button on Mainform>Form1 is lauched>User clicks a Button in Form1>Form 2 is lauched(diposing/hiding form1) after form2 is closed Mainform should be brought to front and made editable,until then all other forms should be on top of Mainform and Mainform should be un-editable

The problem is that you have to specify the MainForm as the parent for (both) form2 and form3. When you use the overload of ShowDialog that has no parameters, WinForms uses the active form as the parent, so form3's parent becomes form2 automatically. You are then trying to close/dispose form2 causing form3 to become orphaned.
There are several options for getting the reference to MainForm, but the simplest is to use:
form2/3.ShowDialog(Application.OpenForms["MainForm"]);
Assuming that you have set the Name property on MainForm to "MainForm".

In your code, this.dispose() is executed only after form3 is closed. What i think you want is to close form2 after form3 was closed, so you can call this.Close() instead of this.Dispose().
this.visible=false;
form3.showdialog();
this.Close();
Or maybe, after form3 is shown up you dont need form2 any more. That meas:
this.visible=false;
//show instead of showdialog so it wont wait until form3 is closed
form3.show();
this.Close();

It looks like you are trying to implement something like a wizard. The best solution would be to launch all the child forms sequentially, in the main form.
If you need to pass data along the sequence, you should pass it from each dialog to the main form, which then passes it to the next dialog.

MainForm:
Form1 f = new Form1();
if (f.ShowDialog(this) == DialogResult.OK) {
Form2 f2 = new Form2();
f2.ShowDialog(this);
}
Form1 (button click which will open the form 2):
button1_click(object sender, EvengArgs e) {
this.DialogResult = DialogResult.OK;
Close();
}

c# gui - navigate between forms

I'm programming c# GUI and I have 2 forms.
Form1 is my main form, and it has a button to open form2.
When the button in form1 is being clicked, I hide form1, create a new object of form2 and show form2.
I have a back button in form2. I want the behavior of this button to close form2, and show again the hidden form1.
How can I do it?

Have your form1 subscribe to the VisibleChange event of form2 and act accordingly. It will have to "remember" whether form2 is visible or hidden (or query it directly).
The alternatives are:
Your form2 will need a reference to form1.
This can be done in a number of ways - passing it in a constructor parameter, adding a property and assigning form1 to it.
Either of these ways will tightly couple these forms to each other (bad thing).

Have you tried
Form1.Visible = true;
Form1.Activate();
And then in the Form1 VisibleChanged Event you simply write
Form2.Close();