Trying to work with XmlSerializer to nicely deserialize stuff I get from webservice.
Here is my class declaration:
[Serializable]
public class CarrierLookupResponse
{
[XmlElement(ElementName = "ResponseDO")]
public ResponseDo ResponseDo { get; set; }
}
Here is how XML looks:
<?xml version="1.0" encoding="utf-8" ?>
<CarrierService.CarrierLookup>
<ResponseDO>
<status>APPROVED</status>
<action>OK</action>
<code>SFW00389</code>
<displayMsg></displayMsg>
<techMsg></techMsg>
</ResponseDO>
Here is code I use to deserialize:
var serializer = new XmlSerializer(typeof(CarrierLookupResponse));
var carrierLookupResponse = serializer.Deserialize(new StringReader(response.Key)) as CarrierLookupResponse;
Problem is simple. Service returns "CarrierService.CarrierLookup" and I need to force it to deserialize into "CarrierLookupResponse"
I can't put XmlElement attribute on class itself, so I have no idea how to map this name properly.
Have you tried with XmlRoot attribute?
[Serializable]
[XmlRoot("CarrierService.CarrierLookup")]
public class CarrierLookupResponse
{
...
Related
I am trying to serialize a class instance of the following class into a XML string.
[Serializable]
[XmlRoot]
public class Orders
{
[XmlElement("Order")]
public Order order { get; set; }
}
The serializations works fine, but I want to remove the two defaults attributes from the Orders element. Although I need another encoding (ISO-8859-1) and I have to add other attributes to the Orders element.
I wanted to solve the latter by adding a [XmlAttribute] to the Orders class, but it results in the same output.
<?xml version="1.0" encoding="utf-16"?>
<Orders xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<Order>
...
<Order>
</Orders>
Does anybody know, how I could achieve that? I highly appreciate any kind of help, cheers! (:
My current root class, which should have a root attribute
public class AGTOSV
{
private string _attribute = "Hello World";
[XmlAttribute]
public string xmlns
{
get { return _attribute; }
set { _attribute = value; }
}
// ....
If I understood you correctly, you just want to export plain xml.
Then you need to set XmlWriterSettings as below and tell the serializer to use a empty namespace.
var emptyNamespaces = new XmlSerializerNamespaces(new[] { XmlQualifiedName.Empty });
var settings = new XmlWriterSettings()
{
OmitXmlDeclaration = true,
};
using (var stream = new StringWriter())
using (var writer = XmlWriter.Create(stream, settings))
{
var serializer = new XmlSerializer(orders.GetType());
serializer.Serialize(writer, orders, emptyNamespaces);
string xml = stream.ToString();
}
Also see How can I make the xmlserializer only serialize plain xml?.
I am attempting to serialize a class as XML and to have the properties be serialized as attributes of the class, rather than a nested node. I am using WebApi to automatically handle the serialization of the XML.
This is my class:
[DataContract (Namespace="", Name="AttributeTest")]
[Serializable]
public class AttributeTestClass
{
[XmlAttribute("Property")]
[DataMember]
public int Property1 { get; set; }
}
Here is the output I am receiving (note that Property1 is not an attribute in spite of it being decorated with [XmlAttribute]):
<AttributeTest xmlns:i="http://www.w3.org/2001/XMLSchema-instance">
<Property1>123</Property1>
</AttributeTest>
This is the output I want to receive:
<AttributeTest Property1="123" xmlns:i="http://www.w3.org/2001/XMLSchema-instance">
</AttributeTest>
What am I missing?
I'm not familiar with WebApi but the output you receive looks like it's serialized using DataContractSerializer, not XmlSerializer which you would need. Check if adding the following to Application_Start in Global.asax helps:
GlobalConfiguration.Configuration.Formatters.Clear();
GlobalConfiguration.Configuration.Formatters.Add(
new System.Net.Http.Formatting.XmlMediaTypeFormatter());
GlobalConfiguration.Configuration.Formatters.XmlFormatter.UseXmlSerializer = true;
(From http://serena-yeoh.blogspot.de/2013/02/xml-serialization-in-aspnet-web-api.html)
I have a class defined as below:
[XmlRoot("ClassName")]
public class ClassName_0
{
//stuff...
}
I then create a list of ClassName_0 like such:
var myListInstance= new List<ClassName_0>();
This is the code I use to serialize:
var ser = new XmlSerializer(typeof(List<ClassName_0>));
ser.Serialize(aWriterStream, myListInstance);
This is the code I use to deserialize:
var ser = new XmlSerializer(typeof(List<ClassName_0>));
var wrapper = ser.Deserialize(new StringReader(xml));
If I serialize it to xml, the resulting xml looks like below:
<?xml version="1.0" encoding="utf-8"?>
<ArrayOfClassName_0 xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<ClassName_0>
<stuff></stuff>
</ClassName_0>
<ClassName_0>
<stuff></stuff>
</ClassName_0>
</ArrayOfClassName_0>
Is there a way to serialize and be able to deserialize the below from/to a list of ClassName_0?
<?xml version="1.0" encoding="utf-8"?>
<ArrayOfClassName xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<ClassName>
<stuff></stuff>
</ClassName>
<ClassName>
<stuff></stuff>
</ClassName>
</ArrayOfClassName>
Thanks!
In your example ClassName isn't the real root.
The real root is your list. So you have to mark the list as the root element.
Your class is just an XmlElement.
try this :
XmlType(TypeName="ClassName")]
public class ClassName_0
{
//stuff...
}
Worked it out, finally, with the help of Jan Peter. XmlRoot was the wrong attribute to put on the class. It was supposed to be XmlType. With XmlType the desired effect is achieved.
You make a root of document tree and this root will contain list of any object.
[XmlRootAttribute("myDocument")]
public class myDocument
{
[XmlArrayAttribute]
publict ClassName[] ArrayOfClassName {get;set;}
}
[XmlType(TypeName="ClassName")]
public class ClassName
{
public string stuff {get;set;}
}
I have the following xml:
<?xml version="1.0" encoding="UTF-8"?>
<connection_state>conn_state</connection_state>
Following the msdn, I must describe it as a type for correct deserialization using XmlSerializer. So the class name points the first tag, and its fields subtags.
For example:
public class connection_state
{
public string state;
}
Will be transformed into the following xml:
<?xml version="1.0" encoding="UTF-8"?>
<connection_state>
<state>conn_state</state>
</connection_state>
But the xml I receive has only one tag. And we cannot create a field with the name of its class like:
public class connection_state
{
public string connection_state;
}
Or can?
Is there any solution for this issue?
Proper Xml has a root element with no content except other elements. If you are stuck with that tiny one-tag psuedo-XML, is there a reason you need to use XmlSerializer? Why not just create a class with a constructor that takes the literal "Xml" string:
using System.Xml.Linq;
public class connection_state {
public string state { get; set; }
public connection_state(string xml) {
this.state = XDocument.Parse(xml).Element("connection_state").Value;
}
}
Edit:
In response to OP's comment: You don't have to us an XmlSerializer; you can just read the ResponseStream directly and pass that to your connection_state constructor:
String xmlString = (new StreamReader(webResponse.GetResponseStream())).ReadToEnd();
connection_state c= new connection_state(xmlString);
Replace
public class connection_state
{
public string state;
}
to
public class connection_state
{
public string state {set; get;}
}
If I have a class MovieClass as
[XmlRoot("MovieClass")]
public class Movie
{
[XmlElement("Novie")]
public string Title;
[XmlElement("Rating")]
public int rating;
}
How can I've an attribute "x:uid" in my "Movie" element, so that the output when XmlSerializer XmlSerializer s = new XmlSerializer(typeof(MovieClass)) was used
is like this:
<?xml version="1.0" encoding="utf-16"?>
<MovieClass>
<Movie x:uid="123">Armagedon</Movie>
</MovieClass>
and not like this
<?xml version="1.0" encoding="utf-16"?>
<MovieClass xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<Movie x:uid="123" Title="Armagedon"/>
</MovieClass>
Note: I want the xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" removed, if possible.
I answered this in your original post, but I think this one is worded better so I will post it here as well, if it gets closed as duplicate you can modify your original post to mirror this question.
I don't think this is possible without having Title be a custom type or explicitly implementing serialization methods.
You could do a custom class like so..
class MovieTitle
{
[XmlText]
public string Title { get; set; }
[XmlAttribute(Namespace="http://www.myxmlnamespace.com")]
public string uid { get; set; }
public override ToString() { return Title; }
}
[XmlRoot("MovieClass")]
public class Movie
{
[XmlElement("Movie")]
public MovieTitle Title;
}
which will produce:
<MovieClass xmlns:x="http://www.myxmlnamespace.com">
<Movie x:uid="movie_001">Armagedon</Movie>
</MovieClass>
Although the serializer will compensate for unknown namespaces with a result you probably won't expect.
You can avoid the wierd behavior by declaring your namespaces and providing the object to the serializer..
XmlSerializerNamespaces ns = new XmlSerializerNamespaces();
ns.Add("x", "http://www.myxmlnamespace.com");
It's not valid XML if you don't have x declared as a namespace prefix. Quintin's response tells you how to get valid XML.