I have an XML file on a given location and I want to have the content of the XML in a string variable. However, when I print it out, the encoding changes. This is how I am doing it.
XmlDocument xmlFile = new XmlDocument();
xmlFile.Load(xmlFileLocation);
using (StringWriter stringWriter = new StringWriter(new StringBuilder()))
{
using (XmlTextWriter xmlTextWriter = new XmlTextWriter(stringWriter) { Formatting = Formatting.Indented })
{
xmlFile.Save(xmlTextWriter);
}
return stringWriter.ToString();
}
When I try to initialize the XmlTextWriter (new XmlTextWriter(stringWriter, Encoding.UTF8)) with a given encoding, then I have issues with the StringWriter but I don't know how to sort it out. Any idea?
The issue is: Cannot convert from StringWriter into Stream
Encoding using StringWriter always will be UTF-16 and cannot be changed. When you want to use a StringWriter with different encoding it is possible to subclass StringWriter. Please refer to this answer on how to do so.
Using your code this would then change to
using (EncodingStringWriter eStringWriter = new EncodingStringWriter (new StringBuilder(), Encoding.UTF8))
{
using (XmlTextWriter xmlTextWriter = new XmlTextWriter(stringWriter) { Formatting = Formatting.Indented })
{
xmlFile.Save(xmlTextWriter);
}
return eStringWriter.ToString();
}
I have TextBlock with name XML_View, also I know .xml file location string filename = dlg.FileName;
So I want to show xml n that TextBlock, I found a possible solution here (Display XML in a WPF textbox), it gives as a function, like this:
protected string FormatXml(string xmlString)
{
XmlDocument doc = new XmlDocument();
doc.LoadXml(xmlString);
StringBuilder sb = new StringBuilder();
System.IO.TextWriter tr = new System.IO.StringWriter(sb);
XmlTextWriter wr = new XmlTextWriter(tr);
wr.Formatting = Formatting.Indented;
doc.Save(wr);
wr.Close();
return sb.ToString();
}
If I get required string, I might just simply write XML_View.Text = String_xml; or something like this. But I don't know how to get string if I have .xml file and I don't know how to use such a function.
I've modified your function to take as parameter the filename to read your xml from. Make sure the file exists in your bin directory (or you use an absolute path like #"C:\temp\myfile.xml" to resolve).
protected string FormatXml(string xmlFile)
{
XmlDocument doc = new XmlDocument();
FileStream fs = new FileStream(xmlFile, FileMode.Open, FileAccess.Read);
doc.Load(fs);
StringBuilder sb = new StringBuilder();
System.IO.TextWriter tr = new System.IO.StringWriter(sb);
XmlTextWriter wr = new XmlTextWriter(tr);
wr.Formatting = Formatting.Indented;
doc.Save(wr);
wr.Close();
return sb.ToString();
}
You can replace
doc.LoadXml(xmlString);
with
doc.Load(xmlFilePath);
I used this as reference.
I am trying to create an XML file using string data. (Which is itself in XML format.) But the main problem is that the XML that I have created is not properly formatted. I have used XmlWriterSettings to format the XML, but it does not seem to be working. Can anyone tell me what is wrong with this code.
string unformattedXml = #"<datas><data1>sampledata1</data1><datas>";
XmlWriterSettings xmlSettingsWithIndentation = new XmlWriterSettings { Indent = true};
using (XmlWriter writer = XmlWriter.Create(Console.Out, xmlSettingsWithIndentation))
{
writer.WriteRaw(unformattedXml);
}
Actually when I load this string in an XmlDocument and then saves it as a file, it was formatted. I just wanted to know why it was not working with XmlWriter.
You help would be much appreciated.
Thanks,
Alex
To ignore white space, try this:
private static string FormatXml(string unformattedXml)
{
//First read the xml, ignoring whitespace.
var readeroptions = new XmlReaderSettings { IgnoreWhitespace = true };
var reader = XmlReader.Create(new StringReader(unformattedXml), readeroptions);
//Then write it out with indentation.
var sb = new StringBuilder();
var xmlSettingsWithIndentation = new XmlWriterSettings { Indent = true };
using (var writer = XmlWriter.Create(sb, xmlSettingsWithIndentation))
writer.WriteNode(reader, true);
return sb.ToString();
}
It should work if you use a XmlReader instead of a raw string.
(I expect it is a typo when your last XML element is not closed property, and that by formatting you refer to correct indentation):
class Program
{
static void Main(string[] args)
{
string unformattedXml = #"<datas><data1>sampledata1</data1></datas>";
var rdr = XmlReader.Create(new StringReader(unformattedXml));
var sb = new StringBuilder();
var xmlSettingsWithIndentation = new XmlWriterSettings
{
Indent = true
};
using (var writer = XmlWriter.Create(sb, xmlSettingsWithIndentation))
writer.WriteNode(rdr, true);
Console.WriteLine(sb);
Console.ReadKey();
}
}
It outputs:
<?xml version="1.0" encoding="utf-16"?>
<datas>
<data1>sampledata1</data1>
</datas>
Please cf. similar questions:
XmlWriter.WriteRaw indentation
XML indenting when injecting an XML string into an XmlWriter
i have the following code:
var doc = new XmlDocument();
XmlDeclaration xmlDeclaration = doc.CreateXmlDeclaration("1.0", "UTF-8", null);
doc.AppendChild(xmlDeclaration);
XmlElement root = doc.CreateElement("myRoot");
doc.AppendChild(root);
root.InnerText = "myInnerText";
StringWriter sw = new StringWriter();
doc.Save(sw);
Console.WriteLine(sw.ToString());
Console.WriteLine();
MemoryStream ms = new MemoryStream();
doc.Save(ms);
Console.WriteLine(Encoding.ASCII.GetString(ms.ToArray()));
And here is the output:
<?xml version="1.0" encoding="utf-16"?>
<myRoot>myInnerText</myRoot>
???<?xml version="1.0" encoding="UTF-8"?>
<myRoot>myInnerText</myRoot>
Basically what it does is make an xml file, and set the encoding to utf8, but when it saves it to stringwriter it ignores my encoding and uses utf16. However, when using a memory stream, it uses utf8 (with the extra BOM chars)
Why is this? Why isn't it honouring my explicit encoding setting of utf-8?
Thanks a lot
Because all you are doing is setting an XML element that says it's UTF-8, you aren't actually saving it as UTF-8. You need to set the output stream to use UTF-8, like this:
var doc = new XmlDocument();
XmlElement root = doc.CreateElement("myRoot");
doc.AppendChild(root);
root.InnerText = "myInnerText";
using(TextWriter sw = new StreamWriter("C:\\output.txt", false, Encoding.UTF8)) //Set encoding
{
doc.Save(sw);
}
Once you do that, you don't even have to add the XML declaration. It figures it out on its own. If you want to save it to a MemoryStream, use a StreamWriter that wraps the MemoryStream.
I use the following method, it writes it out pretty and as UTF-8
public static string Beautify(XmlDocument doc)
{
string xmlString = null;
using (MemoryStream ms = new MemoryStream()) {
XmlWriterSettings settings = new XmlWriterSettings {
Encoding = new UTF8Encoding(false),
Indent = true,
IndentChars = " ",
NewLineChars = "\r\n",
NewLineHandling = NewLineHandling.Replace
};
using (XmlWriter writer = XmlWriter.Create(ms, settings)) {
doc.Save(writer);
}
xmlString = Encoding.UTF8.GetString(ms.ToArray());
}
return xmlString;
}
Call it like:
File.WriteAllText(fileName, Utilities.Beautify(xmlDocument));
From the MSDN we can see...
The encoding on the TextWriter determines the encoding that is written out (The encoding of the XmlDeclaration node is replaced by the encoding of the TextWriter). If there was no encoding specified on the TextWriter, the XmlDocument is saved without an encoding attribute.
If you want to use the encoding from the XmlDeclaration you'll need to use a stream to save the document.
I have an XML string as such:
<?xml version='1.0'?><response><error code='1'> Success</error></response>
There are no lines between one element and another, and thus is very difficult to read. I want a function that formats the above string:
<?xml version='1.0'?>
<response>
<error code='1'> Success</error>
</response>
Without resorting to manually write the format function myself, is there any .Net library or code snippet that I can use offhand?
You will have to parse the content somehow ... I find using LINQ the most easy way to do it. Again, it all depends on your exact scenario. Here's a working example using LINQ to format an input XML string.
string FormatXml(string xml)
{
try
{
XDocument doc = XDocument.Parse(xml);
return doc.ToString();
}
catch (Exception)
{
// Handle and throw if fatal exception here; don't just ignore them
return xml;
}
}
[using statements are ommitted for brevity]
Use XmlTextWriter...
public static string PrintXML(string xml)
{
string result = "";
MemoryStream mStream = new MemoryStream();
XmlTextWriter writer = new XmlTextWriter(mStream, Encoding.Unicode);
XmlDocument document = new XmlDocument();
try
{
// Load the XmlDocument with the XML.
document.LoadXml(xml);
writer.Formatting = Formatting.Indented;
// Write the XML into a formatting XmlTextWriter
document.WriteContentTo(writer);
writer.Flush();
mStream.Flush();
// Have to rewind the MemoryStream in order to read
// its contents.
mStream.Position = 0;
// Read MemoryStream contents into a StreamReader.
StreamReader sReader = new StreamReader(mStream);
// Extract the text from the StreamReader.
string formattedXml = sReader.ReadToEnd();
result = formattedXml;
}
catch (XmlException)
{
// Handle the exception
}
mStream.Close();
writer.Close();
return result;
}
This one, from kristopherjohnson is heaps better:
It doesn't require an XML document header either.
Has clearer exceptions
Adds extra behaviour options: OmitXmlDeclaration = true, NewLineOnAttributes = true
Less lines of code
static string PrettyXml(string xml)
{
var stringBuilder = new StringBuilder();
var element = XElement.Parse(xml);
var settings = new XmlWriterSettings();
settings.OmitXmlDeclaration = true;
settings.Indent = true;
settings.NewLineOnAttributes = true;
using (var xmlWriter = XmlWriter.Create(stringBuilder, settings))
{
element.Save(xmlWriter);
}
return stringBuilder.ToString();
}
The simple solution that is working for me:
XmlDocument xmlDoc = new XmlDocument();
StringWriter sw = new StringWriter();
xmlDoc.LoadXml(rawStringXML);
xmlDoc.Save(sw);
String formattedXml = sw.ToString();
Check the following link: How to pretty-print XML (Unfortunately, the link now returns 404 :()
The method in the link takes an XML string as an argument and returns a well-formed (indented) XML string.
I just copied the sample code from the link to make this answer more comprehensive and convenient.
public static String PrettyPrint(String XML)
{
String Result = "";
MemoryStream MS = new MemoryStream();
XmlTextWriter W = new XmlTextWriter(MS, Encoding.Unicode);
XmlDocument D = new XmlDocument();
try
{
// Load the XmlDocument with the XML.
D.LoadXml(XML);
W.Formatting = Formatting.Indented;
// Write the XML into a formatting XmlTextWriter
D.WriteContentTo(W);
W.Flush();
MS.Flush();
// Have to rewind the MemoryStream in order to read
// its contents.
MS.Position = 0;
// Read MemoryStream contents into a StreamReader.
StreamReader SR = new StreamReader(MS);
// Extract the text from the StreamReader.
String FormattedXML = SR.ReadToEnd();
Result = FormattedXML;
}
catch (XmlException)
{
}
MS.Close();
W.Close();
return Result;
}
I tried:
internal static void IndentedNewWSDLString(string filePath)
{
var xml = File.ReadAllText(filePath);
XDocument doc = XDocument.Parse(xml);
File.WriteAllText(filePath, doc.ToString());
}
it is working fine as expected.
.NET 2.0 ignoring name resolving, and with proper resource-disposal, indentation, preserve-whitespace and custom encoding:
public static string Beautify(System.Xml.XmlDocument doc)
{
string strRetValue = null;
System.Text.Encoding enc = System.Text.Encoding.UTF8;
// enc = new System.Text.UTF8Encoding(false);
System.Xml.XmlWriterSettings xmlWriterSettings = new System.Xml.XmlWriterSettings();
xmlWriterSettings.Encoding = enc;
xmlWriterSettings.Indent = true;
xmlWriterSettings.IndentChars = " ";
xmlWriterSettings.NewLineChars = "\r\n";
xmlWriterSettings.NewLineHandling = System.Xml.NewLineHandling.Replace;
//xmlWriterSettings.OmitXmlDeclaration = true;
xmlWriterSettings.ConformanceLevel = System.Xml.ConformanceLevel.Document;
using (System.IO.MemoryStream ms = new System.IO.MemoryStream())
{
using (System.Xml.XmlWriter writer = System.Xml.XmlWriter.Create(ms, xmlWriterSettings))
{
doc.Save(writer);
writer.Flush();
ms.Flush();
writer.Close();
} // End Using writer
ms.Position = 0;
using (System.IO.StreamReader sr = new System.IO.StreamReader(ms, enc))
{
// Extract the text from the StreamReader.
strRetValue = sr.ReadToEnd();
sr.Close();
} // End Using sr
ms.Close();
} // End Using ms
/*
System.Text.StringBuilder sb = new System.Text.StringBuilder(); // Always yields UTF-16, no matter the set encoding
using (System.Xml.XmlWriter writer = System.Xml.XmlWriter.Create(sb, settings))
{
doc.Save(writer);
writer.Close();
} // End Using writer
strRetValue = sb.ToString();
sb.Length = 0;
sb = null;
*/
xmlWriterSettings = null;
return strRetValue;
} // End Function Beautify
Usage:
System.Xml.XmlDocument xmlDoc = new System.Xml.XmlDocument();
xmlDoc.XmlResolver = null;
xmlDoc.PreserveWhitespace = true;
xmlDoc.Load("C:\Test.svg");
string SVG = Beautify(xmlDoc);
Customizable Pretty XML output with UTF-8 XML declaration
The following class definition gives a simple method to convert an input XML string into formatted output XML with the xml declaration as UTF-8. It supports all the configuration options that the XmlWriterSettings class offers.
using System;
using System.Text;
using System.Xml;
using System.IO;
namespace CJBS.Demo
{
/// <summary>
/// Supports formatting for XML in a format that is easily human-readable.
/// </summary>
public static class PrettyXmlFormatter
{
/// <summary>
/// Generates formatted UTF-8 XML for the content in the <paramref name="doc"/>
/// </summary>
/// <param name="doc">XmlDocument for which content will be returned as a formatted string</param>
/// <returns>Formatted (indented) XML string</returns>
public static string GetPrettyXml(XmlDocument doc)
{
// Configure how XML is to be formatted
XmlWriterSettings settings = new XmlWriterSettings
{
Indent = true
, IndentChars = " "
, NewLineChars = System.Environment.NewLine
, NewLineHandling = NewLineHandling.Replace
//,NewLineOnAttributes = true
//,OmitXmlDeclaration = false
};
// Use wrapper class that supports UTF-8 encoding
StringWriterWithEncoding sw = new StringWriterWithEncoding(Encoding.UTF8);
// Output formatted XML to StringWriter
using (XmlWriter writer = XmlWriter.Create(sw, settings))
{
doc.Save(writer);
}
// Get formatted text from writer
return sw.ToString();
}
/// <summary>
/// Wrapper class around <see cref="StringWriter"/> that supports encoding.
/// Attribution: http://stackoverflow.com/a/427737/3063884
/// </summary>
private sealed class StringWriterWithEncoding : StringWriter
{
private readonly Encoding encoding;
/// <summary>
/// Creates a new <see cref="PrettyXmlFormatter"/> with the specified encoding
/// </summary>
/// <param name="encoding"></param>
public StringWriterWithEncoding(Encoding encoding)
{
this.encoding = encoding;
}
/// <summary>
/// Encoding to use when dealing with text
/// </summary>
public override Encoding Encoding
{
get { return encoding; }
}
}
}
}
Possibilities for further improvement:-
An additional method GetPrettyXml(XmlDocument doc, XmlWriterSettings settings) could be created that allows the caller to customize the output.
An additional method GetPrettyXml(String rawXml) could be added that supports parsing raw text, rather than have the client use the XmlDocument. In my case, I needed to manipulate the XML using the XmlDocument, hence I didn't add this.
Usage:
String myFormattedXml = null;
XmlDocument doc = new XmlDocument();
try
{
doc.LoadXml(myRawXmlString);
myFormattedXml = PrettyXmlFormatter.GetPrettyXml(doc);
}
catch(XmlException ex)
{
// Failed to parse XML -- use original XML as formatted XML
myFormattedXml = myRawXmlString;
}
Check the following link: Format an XML file so it looks nice in C#
// Format the XML text.
StringWriter string_writer = new StringWriter();
XmlTextWriter xml_text_writer = new XmlTextWriter(string_writer);
xml_text_writer.Formatting = Formatting.Indented;
xml_document.WriteTo(xml_text_writer);
// Display the result.
txtResult.Text = string_writer.ToString();
It is possible to pretty-print an XML string via a streaming transformation with XmlWriter.WriteNode(XmlReader, true). This method
copies everything from the reader to the writer and moves the reader to the start of the next sibling.
Define the following extension methods:
public static class XmlExtensions
{
public static string FormatXml(this string xml, bool indent = true, bool newLineOnAttributes = false, string indentChars = " ", ConformanceLevel conformanceLevel = ConformanceLevel.Document) =>
xml.FormatXml( new XmlWriterSettings { Indent = indent, NewLineOnAttributes = newLineOnAttributes, IndentChars = indentChars, ConformanceLevel = conformanceLevel });
public static string FormatXml(this string xml, XmlWriterSettings settings)
{
using (var textReader = new StringReader(xml))
using (var xmlReader = XmlReader.Create(textReader, new XmlReaderSettings { ConformanceLevel = settings.ConformanceLevel } ))
using (var textWriter = new StringWriter())
{
using (var xmlWriter = XmlWriter.Create(textWriter, settings))
xmlWriter.WriteNode(xmlReader, true);
return textWriter.ToString();
}
}
}
And now you will be able to do:
var inXml = #"<?xml version='1.0'?><response><error code='1'> Success</error></response>";
var newXml = inXml.FormatXml(indentChars : "", newLineOnAttributes : false); // Or true, if you prefer
Console.WriteLine(newXml);
Which prints
<?xml version='1.0'?>
<response>
<error code="1"> Success</error>
</response>
Notes:
Other answers load the XML into some Document Object Model such as XmlDocument or XDocument/XElement, then re-serialize the DOM with indentation enabled.
This streaming solution completely avoids the added memory overhead of a DOM.
In your question you do not add any indentation for the nested <error code='1'> Success</error> node, so I set indentChars : "". Generally an indentation of two spaces per level of nesting is customary.
Attribute delimiters will be unconditionally transformed to double-quotes if currently single-quotes. (I believe this is true of other answers as well.)
Passing conformanceLevel : ConformanceLevel.Fragment allows strings containing sequences of XML fragments to be formatted.
Other than ConformanceLevel.Fragment, the input XML string must be well-formed. If it is not, XmlReader will throw an exception.
Demo fiddle here.
if you load up the XMLDoc I'm pretty sure the .ToString() function posses an overload for this.
But is this for debugging? The reason that it is sent like that is to take up less space (i.e stripping unneccessary whitespace from the XML).
Hi why don't you just try this:
XmlDocument xmlDoc = new XmlDocument();
xmlDoc.PreserveWhitespace = false;
....
....
xmlDoc.Save(fileName);
PreserveWhitespace = false; that option can be used xml beautifier as well.