I'm trying to get messages from Gmail in C#
but the message body comes like this "\r\n\r\nBODY\r\n\r\n"
How can I get the "BODY" out of the string ?
I tried to loop through it but I found out that when looping the "\r" becomes a " "
You can use String.Trim() to remove all leading and trailing whitespace form a given string. Something like this:
var body = inputString.Trim();
This would cover /r/n characters, as well as any other whitespace.
try this:
string after = text.Replace(Environment.NewLine, "");
body = body.Replace("\r\n", string.Empty);
When a user writes some text in a file, the Editor automatically appends CR|LF after each line.
CR or Carriage Return is denoted as \r
LF or Line Feed is denoted as \n
These are normally invisible to us, but while reading a text file using some code process it also captures these escape sequences.
To avoid these character you can easily replace them using builtin C# function Replace method
You can use following code to get rid from \r and \n
str = str.Replace("\r\n","");
This will first find out all combined \r\n characters and then replaces this string with "" (Blank string).
This works for me:
string result= rawString.Replace(#"\r\n", " ").Trim().Replace(Environment.NewLine, " ").Replace("\n", " ");
Related
Considering I have a string like this:
var myStr = #"\r\n test";
What is the best way to remove the characters like \r and \n (carriage feed characters) and empty characters
One way I can think of is
var trimmedString = myStr.Replace("\r\n", "").Trim();
What is the most elegant way to do this ?
It's hard to tell if you want the carriage return and line feed characters removed or if you want the literal string: "\r\n" removed.
The code you have posted:
new string (#"\r\n test")
Is not even valid syntax. If you want a string literal the syntax is:
var someString = #"\r\n some value";
The # Means that you are literally including the string: "\r\n" in the output, this means it will not output the escape characters \r\n which is carriage return and line feed.
If you want to remove the specific string "\r\n" you can use String.Replace like you were doing, I have cleaned up your code a bit and removed some redundancies:
var trimmedString = #"\r\n test".Replace(#"\r\n", "");
If you actually want to remove the escape characters from the beginning of the string you need to remove the # symbol so its no longer a string literal, then you can use the TrimStart() method of a string:
var trimmedString = "\r\n test".TrimStart();
TrimStart() accepts a char[] parameter that details the specific characters you want to remove. However if you do not pass any parameter to TrimStart() it will automatically remove whitespace characters from the beginning of the string.
Fiddle here
Assuming that you wish to remove "raw" escape sequences from your string, you can generalize regex-based approach as follows:
var trimmed = Regex.Replace(original, #"^(\\[rntv]|\s)*", "");
This removes verbatim \n, \r, \t, and \v sequences with optional whitespaces at the beginning of the string. Note that \ at the beginning is doubled inside a verbatim #"..." string literal, meaning that the regex is going to match an escape sequence, not the character it represents.
Demo.
Your best answer would be to use a regular expression.
new Regex(#"(^\s+").Replace("\r\n BLah blah blah ","")
How can I replace \r's with \r\n when the \r isn't followed by a \n using Regex ?
The problem
I'm having problems with a text editor on Windows I'm creating in that line breaks are being added as \r. As a result they are not being read as line breaks when I open the file in Notepad.
What I tried
I've tried looking everywhere (google, stackoverflow, etc) for this, but have been unable to find something that is specifically for what I'm after.
Everything I've tried so far does what I'm after the first time but it then keeps unnecessarily replacing \r's even if they're followed by a \n.
For reference, this is the expression:
"\r(?!^\n)", "\r\n"
You need to use
\r(?!\n)
That is, remove the ^ start of string/line modifier from your \r(?!^\n) expression. The \r will match a carriage return and the (?!\n) will fail the match if there is an LF immediately to the right of it.
A C# demo:
var s = "Line1\rLine2\r\nLine3";
var res = Regex.Replace(s, "\r(?!\n)", "\r\n");
Console.WriteLine(res.Replace("\r","CR").Replace("\n","LF\n"));
// => Line1CRLF
// Line2CRLF
// Line3
My question already states my problem.. So how do I properly remove all extra white space in a string?
Imagine the dashes are spaces.
my string = "[-----------na----me-----]"
output = "name-" (there is a space in the end of the string)
I used this code in a Leave event.
((Control)sender).Text = Regex.Replace(((Control)sender).Text, #"\s+", " ");
((Control)sender).Text.TrimEnd(' ');
I think you may be overthinking this.
Have you considered using the string Replace method.
For example:
string s = "[ na me ]";
var s2 = s.Replace(" ", "");
Console.WriteLine(s);
Console.WriteLine(s2);
It appears you have a typo. Your main problem seems to be in your call to Regex.Replace. Look at the line very carefully: " " means to replace sequences of spaces with one single space. Try changing " " to "".
Also, the ((Control)sender).Text.TrimEnd(' '); returns a new string and never updates ((Control)sender).Text. Perhaps you meant to assign the result to Text again? Remember that in C# strings are immutable. However, by changing " " to "", you should not need that line anymore.
Note: This answer is based off of the example code. However, the example string and output do not match the example code.
You may be running into whitespace which is the \r\n so use this pattern instead: [\s\r\n]+ to get all whitespace as well as any carriage return and line feeds. Also to be concise use string.empty instead of "" as the replacement text.
I wanted to replace any line feed (Lf) in a file with an empty string "". However, I don't want it to also replace the Lf in the CrLf one (end of line flag).
I was thinking something like this:
fileContent.Replace("\n","");
The line of code above will replace the Lf in CrLf to Cr, so I don't want that. Please give me some suggestion for a regular expression, which ignore the Lf in CrLf.
Thanks a lot.
PS: The logic changed. I used this:
fileContent = Regex.Replace(fileContent, #"\r\n(?=>)|(?<!\""\r)\n", "");
to replace all the CrLf that appear after > with empty string ("") and replace all the line feeds (Lf) that not followed by "Cr with empty string (""). Is that correct? Thanks
In addition to the other Regular Expression answer you can just use a Negative Look-Behind to avoid capturing the unnecessary data:
string result = Regex.Replace(fileContent, #"(?<!\r)\n+", "");
You could use a regular expression. The RegEx below matches \n characters that are either at the beginning of the input or are preceded with \r. It captures the character preceding the \n in a group so it can re-insert it into the string.
string result = Regex.Replace(fileContent, #"(^|[^\r])\n", "$1");
I am sent an XML string that I'm trying to parse via an XmlReader and I'm trying to strip out the \" characters.
I've tried
.Replace(#"\", "")
.Replace("\\''", "''")
.Replace("\\''", "\"")
plus several other ways.
Any ideas?
Were you trying it like this:
string text = GetTextFromSomewhere();
text.Replace("\\", "");
text.Replace("\"", "");
? If so, that's the problem - Replace doesn't change the original string, it returns a new string with the replacement performed... so you'd want:
string text = GetTextFromSomewhere();
text = text.Replace("\\", "").Replace("\"", "");
Note that this will replace each backslash and each double-quote character; if you only wanted to replace the pair "backslash followed by double-quote" you'd just use:
string text = GetTextFromSomewhere();
text = text.Replace("\\\"", "");
(As mentioned in the comments, this is because strings are immutable in .NET - once you've got a string object somehow, that string will always have the same contents. You can assign a reference to a different string to a variable of course, but that's not actually changing the contents of the existing string.)
In .NET Framework 4 and MVC this is the only representation that worked:
Replace(#"""","")
Using a backslash in whatever combination did not work...
Try it like this:
Replace("\\\"","");
This will replace occurrences of \" with empty string.
Ex:
string t = "\\\"the dog is my friend\\\"";
t = t.Replace("\\\"","");
This will result in:
the dog is my friend
\ => \\ and " => \"
so Replace("\\\"","")
Where do these characters occur? Do you see them if you examine the XML data in, say, notepad? Or do you see them when examining the XML data in the debugger. If it is the latter, they are only escape characters for the " characters, and so part of the actual XML data.
Replace(#"\""", "")
You have to use double-doublequotes to escape double-quotes within a verbatim string.