I need convert a phrase words in uppercase and lowercase continuous (alternating).
Example.
Input:
the girl is pretty.
Output:
tHe GiRl Is PrEtTy
I have tried the code below but it only convert the first letter:
char[] array = texto.ToCharArray();
if (array.Length >= 1)
{
if (char.IsLower(array[0]))
{
array[0] = char.ToUpper(array[0]);
}
}
for (int i = 1; i < array.Length; i++)
{
if (array[i - 1] == ' ')
{
if (char.IsLower(array[i]))
{
array[i] = char.ToUpper(array[i]);
}
}
}
return new string(array);
Thanks
Fancy solution using LINQ:
string someString = "the girl is pretty";
string newString = string.Concat(
someString.ToLower().AsEnumerable().Select((c, i) => i % 2 == 0 ? c : char.ToUpper(c)));
This basically does the following:
Convert the string to lowercase.
Iterate over each character.
Convert every second character to upper case.
Join the characters into a single string.
A more “classical” solution could look like this:
string someString = "the girl is pretty";
StringBuilder sb = new StringBuilder();
bool uppercase = false;
foreach (char c in someString)
{
if (uppercase)
sb.Append(char.ToUpper(c));
else
sb.Append(char.ToLower(c));
uppercase = !uppercase;
}
string newString = sb.ToString();
Answer by poke was right, however it includes the spaces on alternating the case. I do some tweak to the previous answer, it ignores the spaces of the string.
string someString = "the girl is pretty";
string space = " ";
char[] str = someString.ToCharArray();
char[] str2 = space.ToCharArray();
bool uppercase = false;
StringBuilder sb = new StringBuilder();
foreach (char c in str)
{
if (c != str2[0])
{
if (uppercase)
sb.Append(char.ToUpper(c));
else
{
sb.Append(char.ToLower(c));
}
uppercase = !uppercase;
}
else
{
sb.Append(c);
}
}
string newString = sb.ToString();
How can I remove (or recognize) non-alphanumeric characters such as '-', '*', '‡', '€', '⁋', '™' from a string without removing non-Latin alphanumeric characters such as 'Ж', 'ק', 'ओ', 'を'?
The removing part is easy, my issue is differentiating the non-Latin alphabets from the non-Latin symbols.
* All existing Q&A I found filtered out non-Latin alphabets.
A simple solution (that works only for basic BMP characters) is:
string str = "-*‡€⁋™Жקओを";
var sb = new StringBuilder();
foreach (char ch in str)
{
bool isLetter = char.IsLetterOrDigit(ch);
if (isLetter)
{
sb.Append(ch);
}
}
string str2 = sb.ToString();
The Char.IsLetterOrDigit is described as:
Indicates whether the specified Unicode character is categorized as a letter or a decimal digit.
if you want to support surrogate pairs it becomes more complex:
// \U0001F000 is MAHJONG TILE EAST WIND
// \U0001D49E is MATHEMATICAL SCRIPT CAPITAL C
string str = "-*‡€⁋™Жקओを\U0001F000\U0001D49E";
var sb = new StringBuilder();
for (int i = 0; i < str.Length; i++)
{
bool isLetter = char.IsLetterOrDigit(str, i);
bool isHighSurrogate = char.IsHighSurrogate(str[i]);
if (isLetter)
{
sb.Append(str, i, isHighSurrogate ? 2 : 1);
}
if (isHighSurrogate && i + 1 < str.Length && char.IsLowSurrogate(str[i + 1]))
{
i++;
}
}
string str2 = sb.ToString();
Rather than describing what I want (it's difficult to explain), Let me provide an example of what I need to accomplish in C# using a regular expression:
"HelloWorld" should be transformed to "Hello World"
"HelloWORld" should be transformed to "Hello WO Rld" //Two consecutive letters in capital should be treatead as one word
"helloworld" should be transformed to "helloworld"
EDIT:
"HellOWORLd" should be transformed to "Hell OW OR Ld"
Every 2-consecutive capital letters should be considered one word.
Is this possible?
This is fully working C# code, not just the regex:
Console.WriteLine(
Regex.Replace(
"HelloWORld",
"(?<!^)(?<wordstart>[A-Z]{1,2})",
" ${wordstart}", RegexOptions.Compiled));
And it prints:
Hello WO Rld
Update
To make this more UNICODE/international aware, consider replacing [A-Z] by \p{Lt} (meaning a UNICODE code point that represents a Letter in uppercase). The result for the current input would the same. So here is a slightly more compelling example:
Console.WriteLine(Regex.Replace(
#"ÉclaireürfØÑJßå",
#"(?<!^)(?<wordstart>\p{Lu}{1,2})",
#" ${wordstart}",
RegexOptions.Compiled));
The regular expression engine is not a transformative thing by nature, but rather a pattern matching (and replacing) engine. People often mistake the replace part of Regex, thinking that it can do more than it's designed to.
Back to your question, though... Regex cannot do what you want, instead, you should write your own parser to do this. With C#, if you're familiar with the language, this task is somewhat trivial.
It's a case of "You're using the wrong tool for the job".
Here are regular expressions that detect what you are looking for:
([A-Z]\w*?)[A-Z]
this matches any uppercase letter from A to Z once followed by aphanumerics up to the next uppercase.
([A-Z]{2}\w*?)[A-Z]
this matches any uppercase letter from A to Z exactly 2 times.
Regex is a matching engine, you can parse the input string and use regex.isMatch to find candidate matches to then insert spaces into the output string
string f(string input)
{
//'lowerUPPER' -> 'lower UPPER'
var x = Regex.Replace(input, "([a-z])([A-Z])","$1 $2");
//'UPPER' -> 'UP PE R'
return Regex.Replace(x, "([A-Z]{2})","$1 ");
}
class Program
{
static void Main(string[] args)
{
Print(Parse("HelloWorld"));
Print(Parse("HelloWORld"));
Print(Parse("helloworld"));
Print(Parse("HellOWORLd"));
Console.ReadLine();
}
static void Print(IEnumerable<string> input)
{
foreach (var s in input)
{
Console.Write(s);
Console.Write(' ');
}
Console.WriteLine();
}
static IEnumerable<string> Parse(string input)
{
var sb = new StringBuilder();
for (int i = 0; i < input.Length; i++)
{
if (!char.IsUpper(input[i]))
{
sb.Append(input[i]);
continue;
}
if (sb.Length > 0)
{
yield return sb.ToString();
sb.Clear();
}
sb.Append(input[i]);
if (char.IsUpper(input[i + 1]))
{
sb.Append(input[++i]);
yield return sb.ToString();
sb.Clear();
}
}
if (sb.Length > 0)
{
yield return sb.ToString();
}
}
}
I think does not need regular expression in this case.
Try this:
static void Main(string[] args)
{
var input = "HellOWORLd";
var i = 0;
var x = 4;
var len = input.Length;
var output = new List<string>();
while (x <= len)
{
output.Add(SubStr(input, i, x));
i = x;
x += 2;
}
var ret = output.ToArray(); //["Hell","OW", "OR", "Ld"]
Console.ReadLine();
}
static string SubStr(string str, int start, int end)
{
var len = str.Length;
if (start >= 0 && end <= len)
{
var ret = new StringBuilder();
for (int i = 0; i < len; i++)
{
if (i == start)
{
do
{
ret.Append(str[i]);
i++;
} while (i != end);
}
}
return ret.ToString();
}
return null;
}
I have the following method (written in C#/.NET). Input text consist only of letters (no digits). Returned value is another text in which groups of more than two consecutive characters are replaced with one the character preceded with a count of repetitions.
Ex.: aAAbbbcccc -> aAA3b4c
public static string Pack(string text)
{
if (string.IsNullOrEmpty(text)) return text;
StringBuilder sb = new StringBuilder(text.Length);
char prevChar = text[0];
int prevCharCount = 1;
for (int i = 1; i < text.Length; i++)
{
char c = text[i];
if (c == prevChar) prevCharCount++;
else
{
if (prevCharCount > 2) sb.Append(prevCharCount);
else if (prevCharCount == 2) sb.Append(prevChar);
sb.Append(prevChar);
prevChar = c;
prevCharCount = 1;
}
}
if (prevCharCount > 2) sb.Append(prevCharCount);
else if (prevCharCount == 2) sb.Append(prevChar);
sb.Append(prevChar);
return sb.ToString();
}
The method is not too long. But does any one has an idea how to do that in a more concise way using regex? Or LINQ?
How about:
static readonly Regex re = new Regex(#"(\w)(\1){2,}", RegexOptions.Compiled);
static void Main() {
string result = re.Replace("aAAbbbcccc",
match => match.Length.ToString() + match.Value[0]);
}
The regex is a word char, followed by the same (back-ref) at least twice; the lamba takes the length of the match (match.Length) and appends the first character (match.Value[0])
I would like to split a string with delimiters but keep the delimiters in the result.
How would I do this in C#?
If the split chars were ,, ., and ;, I'd try:
using System.Text.RegularExpressions;
...
string[] parts = Regex.Split(originalString, #"(?<=[.,;])")
(?<=PATTERN) is positive look-behind for PATTERN. It should match at any place where the preceding text fits PATTERN so there should be a match (and a split) after each occurrence of any of the characters.
If you want the delimiter to be its "own split", you can use Regex.Split e.g.:
string input = "plum-pear";
string pattern = "(-)";
string[] substrings = Regex.Split(input, pattern); // Split on hyphens
foreach (string match in substrings)
{
Console.WriteLine("'{0}'", match);
}
// The method writes the following to the console:
// 'plum'
// '-'
// 'pear'
So if you are looking for splitting a mathematical formula, you can use the following Regex
#"([*()\^\/]|(?<!E)[\+\-])"
This will ensure you can also use constants like 1E-02 and avoid having them split into 1E, - and 02
So:
Regex.Split("10E-02*x+sin(x)^2", #"([*()\^\/]|(?<!E)[\+\-])")
Yields:
10E-02
*
x
+
sin
(
x
)
^
2
Building off from BFree's answer, I had the same goal, but I wanted to split on an array of characters similar to the original Split method, and I also have multiple splits per string:
public static IEnumerable<string> SplitAndKeep(this string s, char[] delims)
{
int start = 0, index;
while ((index = s.IndexOfAny(delims, start)) != -1)
{
if(index-start > 0)
yield return s.Substring(start, index - start);
yield return s.Substring(index, 1);
start = index + 1;
}
if (start < s.Length)
{
yield return s.Substring(start);
}
}
Just in case anyone wants this answer aswell...
Instead of string[] parts = Regex.Split(originalString, #"(?<=[.,;])") you could use string[] parts = Regex.Split(originalString, #"(?=yourmatch)") where yourmatch is whatever your separator is.
Supposing the original string was
777- cat
777 - dog
777 - mouse
777 - rat
777 - wolf
Regex.Split(originalString, #"(?=777)") would return
777 - cat
777 - dog
and so on
This version does not use LINQ or Regex and so it's probably relatively efficient. I think it might be easier to use than the Regex because you don't have to worry about escaping special delimiters. It returns an IList<string> which is more efficient than always converting to an array. It's an extension method, which is convenient. You can pass in the delimiters as either an array or as multiple parameters.
/// <summary>
/// Splits the given string into a list of substrings, while outputting the splitting
/// delimiters (each in its own string) as well. It's just like String.Split() except
/// the delimiters are preserved. No empty strings are output.</summary>
/// <param name="s">String to parse. Can be null or empty.</param>
/// <param name="delimiters">The delimiting characters. Can be an empty array.</param>
/// <returns></returns>
public static IList<string> SplitAndKeepDelimiters(this string s, params char[] delimiters)
{
var parts = new List<string>();
if (!string.IsNullOrEmpty(s))
{
int iFirst = 0;
do
{
int iLast = s.IndexOfAny(delimiters, iFirst);
if (iLast >= 0)
{
if (iLast > iFirst)
parts.Add(s.Substring(iFirst, iLast - iFirst)); //part before the delimiter
parts.Add(new string(s[iLast], 1));//the delimiter
iFirst = iLast + 1;
continue;
}
//No delimiters were found, but at least one character remains. Add the rest and stop.
parts.Add(s.Substring(iFirst, s.Length - iFirst));
break;
} while (iFirst < s.Length);
}
return parts;
}
Some unit tests:
text = "[a link|http://www.google.com]";
result = text.SplitAndKeepDelimiters('[', '|', ']');
Assert.IsTrue(result.Count == 5);
Assert.AreEqual(result[0], "[");
Assert.AreEqual(result[1], "a link");
Assert.AreEqual(result[2], "|");
Assert.AreEqual(result[3], "http://www.google.com");
Assert.AreEqual(result[4], "]");
A lot of answers to this! One I knocked up to split by various strings (the original answer caters for just characters i.e. length of 1). This hasn't been fully tested.
public static IEnumerable<string> SplitAndKeep(string s, params string[] delims)
{
var rows = new List<string>() { s };
foreach (string delim in delims)//delimiter counter
{
for (int i = 0; i < rows.Count; i++)//row counter
{
int index = rows[i].IndexOf(delim);
if (index > -1
&& rows[i].Length > index + 1)
{
string leftPart = rows[i].Substring(0, index + delim.Length);
string rightPart = rows[i].Substring(index + delim.Length);
rows[i] = leftPart;
rows.Insert(i + 1, rightPart);
}
}
}
return rows;
}
This seems to work, but its not been tested much.
public static string[] SplitAndKeepSeparators(string value, char[] separators, StringSplitOptions splitOptions)
{
List<string> splitValues = new List<string>();
int itemStart = 0;
for (int pos = 0; pos < value.Length; pos++)
{
for (int sepIndex = 0; sepIndex < separators.Length; sepIndex++)
{
if (separators[sepIndex] == value[pos])
{
// add the section of string before the separator
// (unless its empty and we are discarding empty sections)
if (itemStart != pos || splitOptions == StringSplitOptions.None)
{
splitValues.Add(value.Substring(itemStart, pos - itemStart));
}
itemStart = pos + 1;
// add the separator
splitValues.Add(separators[sepIndex].ToString());
break;
}
}
}
// add anything after the final separator
// (unless its empty and we are discarding empty sections)
if (itemStart != value.Length || splitOptions == StringSplitOptions.None)
{
splitValues.Add(value.Substring(itemStart, value.Length - itemStart));
}
return splitValues.ToArray();
}
Recently I wrote an extension method do to this:
public static class StringExtensions
{
public static IEnumerable<string> SplitAndKeep(this string s, string seperator)
{
string[] obj = s.Split(new string[] { seperator }, StringSplitOptions.None);
for (int i = 0; i < obj.Length; i++)
{
string result = i == obj.Length - 1 ? obj[i] : obj[i] + seperator;
yield return result;
}
}
}
I'd say the easiest way to accomplish this (except for the argument Hans Kesting brought up) is to split the string the regular way, then iterate over the array and add the delimiter to every element but the last.
To avoid adding character to new line try this :
string[] substrings = Regex.Split(input,#"(?<=[-])");
result = originalString.Split(separator);
for(int i = 0; i < result.Length - 1; i++)
result[i] += separator;
(EDIT - this is a bad answer - I misread his question and didn't see that he was splitting by multiple characters.)
(EDIT - a correct LINQ version is awkward, since the separator shouldn't get concatenated onto the final string in the split array.)
Iterate through the string character by character (which is what regex does anyway.
When you find a splitter, then spin off a substring.
pseudo code
int hold, counter;
List<String> afterSplit;
string toSplit
for(hold = 0, counter = 0; counter < toSplit.Length; counter++)
{
if(toSplit[counter] = /*split charaters*/)
{
afterSplit.Add(toSplit.Substring(hold, counter));
hold = counter;
}
}
That's sort of C# but not really. Obviously, choose the appropriate function names.
Also, I think there might be an off-by-1 error in there.
But that will do what you're asking.
veggerby's answer modified to
have no string items in the list
have fixed string as delimiter like "ab" instead of single character
var delimiter = "ab";
var text = "ab33ab9ab"
var parts = Regex.Split(text, $#"({Regex.Escape(delimiter)})")
.Where(p => p != string.Empty)
.ToList();
// parts = "ab", "33", "ab", "9", "ab"
The Regex.Escape() is there just in case your delimiter contains characters which regex interprets as special pattern commands (like *, () and thus have to be escaped.
using System.Collections.Generic;
using System.Text.RegularExpressions;
namespace ConsoleApplication9
{
class Program
{
static void Main(string[] args)
{
string input = #"This;is:a.test";
char sep0 = ';', sep1 = ':', sep2 = '.';
string pattern = string.Format("[{0}{1}{2}]|[^{0}{1}{2}]+", sep0, sep1, sep2);
Regex regex = new Regex(pattern);
MatchCollection matches = regex.Matches(input);
List<string> parts=new List<string>();
foreach (Match match in matches)
{
parts.Add(match.ToString());
}
}
}
}
I wanted to do a multiline string like this but needed to keep the line breaks so I did this
string x =
#"line 1 {0}
line 2 {1}
";
foreach(var line in string.Format(x, "one", "two")
.Split("\n")
.Select(x => x.Contains('\r') ? x + '\n' : x)
.AsEnumerable()
) {
Console.Write(line);
}
yields
line 1 one
line 2 two
I came across same problem but with multiple delimiters. Here's my solution:
public static string[] SplitLeft(this string #this, char[] delimiters, int count)
{
var splits = new List<string>();
int next = -1;
while (splits.Count + 1 < count && (next = #this.IndexOfAny(delimiters, next + 1)) >= 0)
{
splits.Add(#this.Substring(0, next));
#this = new string(#this.Skip(next).ToArray());
}
splits.Add(#this);
return splits.ToArray();
}
Sample with separating CamelCase variable names:
var variableSplit = variableName.SplitLeft(
Enumerable.Range('A', 26).Select(i => (char)i).ToArray());
I wrote this code to split and keep delimiters:
private static string[] SplitKeepDelimiters(string toSplit, char[] delimiters, StringSplitOptions splitOptions = StringSplitOptions.None)
{
var tokens = new List<string>();
int idx = 0;
for (int i = 0; i < toSplit.Length; ++i)
{
if (delimiters.Contains(toSplit[i]))
{
tokens.Add(toSplit.Substring(idx, i - idx)); // token found
tokens.Add(toSplit[i].ToString()); // delimiter
idx = i + 1; // start idx for the next token
}
}
// last token
tokens.Add(toSplit.Substring(idx));
if (splitOptions == StringSplitOptions.RemoveEmptyEntries)
{
tokens = tokens.Where(token => token.Length > 0).ToList();
}
return tokens.ToArray();
}
Usage example:
string toSplit = "AAA,BBB,CCC;DD;,EE,";
char[] delimiters = new char[] {',', ';'};
string[] tokens = SplitKeepDelimiters(toSplit, delimiters, StringSplitOptions.RemoveEmptyEntries);
foreach (var token in tokens)
{
Console.WriteLine(token);
}