I'm sorry if this has been answered before but I couldn't find the answer which fit my needs
I have a richTextBox in c# and I want to get a continuous string of text of the contents
The problem is .Text will get something like:
First line \n Second Line \n Third Line
and what I need is:
First line Second Line Third Line
I don't want to directly parse the \n as it might be relevant to the text I'm retrieving but I don't want it added based on the lines of the richTextBox
Any ideas? Any help is gratefully appreciated.
If I understand correctly, would this work for you?
string text = richTextBox.Text.Replace(Environment.NewLine, " ");
The alternative could be to use the regex from this answer.
string text = Regex.Replace(richTextBox.Text, #"\r\n?|\n", " ");
Related
I can't find how to split a Console.WriteLine text without creating a new line in the program. I mean, my code line is too long and it's uncomforable to scroll horizontally in order to check it
Console.WriteLine("BlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBla")
the result is only a line of text in the console (Might be split because of its length, but keeps being the same line)
into the same, but in different lines in the code, giving the same result. I've tried just splitting them with a new code of line as if it was common code like this:
Console.WriteLine("BlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBla
BlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBla
BlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBla
BlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBla")
and the result keeps being a line of text in the console
But looks like it's not the right way.
Sorry if it's stupid. Thanks
There's not a way to split a string literal in C# without embedding the line breaks in the string. The typical way to split a line like that is:
Console.WriteLine("BlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBla" +
"BlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBla" +
"BlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBla" +
"BlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBla");
If your string has line breaks, then you can use the literal string identifier #:
Console.WriteLine(#"This is one line followed by a carriage return
this is the second line of the string
and this is the third line");
You can use Console.Write instead and call it multiple times. Call WriteLine once at the end either as a part of the all or with an empty string to ensure you start on a new line when you are done with that string.
Console.Write("BlaBlaBlaBlaBlaBlaBlaBla");
Console.Write("BlaBlaBlaBlaBlaBlaBlaBla");
Console.Write("BlaBlaBlaBlaBlaBlaBlaBla");
Console.Write("BlaBlaBlaBlaBlaBlaBlaBla");
Console.WriteLine("BlaBlaBlaBlaBlaBlaBlaBla");
Console.WriteLine("BlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBla" +
"BlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBla" +
"BlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBla" +
"BlaBla");
If you have Resharper installed hitting enter inside of a string will automatically format the new line and add the + for you.
The best you can do is split long string into substrings and concat them before output:
Console.WriteLine("BlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBla"
+ "BlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBlaBla"
+ "BlaBlaBlaBlaBlaBlaBlaBlaBla")
If you only are going to write Bla then do
for(int i = 0; i < /*Amount of Bla's here*/; i++){
Console.Write("Bla");
}
Short question: I have a string in my resources: "This is my test string {0}\n\nTest"
I'm trying to display this string in my Messagebox:
MessageBox.Show(String.Format(Properties.Resources.About,
Constants.VERSION),
Properties.Resources.About_Title, MessageBoxButton.OK,
MessageBoxImage.Information);
However I don't get new lines. The \n still show up as characters, not as new lines.
I also tried to use a workaround like mystring.Replace("\n", Environment.NewLine) but this also doesn't change anything.
What am I doing wrong?
Edit: Funny thing to mention: Replace("\n", "somethingelse") doesn't change anything.
Edit2: Shift+Enter in my Resource-File instead of \n seems to work... Strange behaviour anyway
Put a place holder where you want to put new line and in the code where you use that resource string, just replace it with new line: string resource: "This is first line.{0}This is second line.{0}This is third line." You will use this resource string like this: MessageBox.Show(string.Format(MyStringResourceClass.MyStringPropertyName, Environment.NewLine));
OR
Unconventional Method
But i just now got it working by coping newline from word directly (or anyother place) & pasting it inside the resource string file.
It was simple..
OR
\r\n characters will be converted to new line when you display it by using message box or assign it to text box or whenever you use it in interface.
In C# (like most C derived languages), escape characters are used to denote special characters such as return and tab, and + is used in place of & for string concatenation.
To make your code work under C# you’ve got two options... the first is to simply replace the NewLine with the return escape character \n ala:
MessageBox.Show("this is first line" + "\n" + "this is second line");
The other method, and more correct is to replace it instead with Environment.NewLine which theoretically could change depending on the system you are using (however unlikely).
MessageBox.Show("this is first line" + Environment.NewLine + "this is second line");
In the resource editor seperate your string content by using shift+enter. Or else, edit your ResX file in xml editor and using enter key create a new line for your resource string.
Refer this link for detail info: Carriage Return/Line in ResX file.
Try this:
String outputMessage = string.Format("Line 1{0}Line 2{0}Line 3", Environment.NewLine);
MessageBox.Show(outputMessage);
A further example with another variable:
String anotherValue = "Line 4";
String outputMessage = string.Format("Line 1{0}Line 2{0}Line 3{0}{1}", Environment.NewLine, anotherValue);
MessageBox.Show(outputMessage);
Try this
removing the MessageBoxButtons.OK and MessageBoxImage. Information.
MessageBox.Show(String.Format(Properties.Resources.About,
Constants.VERSION),
Properties.Resources.About_Title);
I know this is kind of easy question but i cant seem to find it anywhere. Is there someone out there who knows how to create a soft return inside a set of text using C#.net?
I need to print soft return to a text file/xml file. this text file will be generated using c#.net. you could verify if the answer is correct if you use NOTEPAD++ then enable the option to “View>Show Symbol > Show End of Line” then you will see a symbol like this:
Thanks in advance :)
Not sure what you mean by a soft return. A quick Google search says it's a non-stored line break typically due to word wrapping in which case you wouldn't actually put this in a string, it would only be relevant when the string was rendered for display.
To put a carriage return and/or line feed in the string you would use:
string s = "line one\r\nline two";
And for further reference, here are the other escape codes that you can use.
Link (MSDN Blogs)
In response to your edit
The LF that you see can be represented with \n in a string. Obviously you have a specific line ending sequence that you need to represent. If you were to use Environment.NewLine that is going to give you different results on different platforms.
var message = $"Tom{Convert.ToChar(10)}Harry";
Results in:
Tom
Harry
With just a line feed between.
Lke already mentioned you can use Enviroment.NewLine but I am not sure if that i what you want or if you are actually trying to append a ASCII 141 to your string as mentioned in the comments.
You can add ASCII chr sequences to your string like this.
var myString = new StringBuilder("Foo");
myString.Append((char)141);
So I have a textbox where I want an address to be stored, but as a single line. To get the address in there I will always do a copy and paste, and the issue is that where I copy it from, it is multiline, so when I paste it, it only shows the first line. I know I can change it into a multiline textbox and then use backspace to make it one line, but I'm just wondering if there is a way I can just make it single line with code.
textBox1.Text = Clipboard.GetText().Replace(Environment.NewLine, " ");
Try,
textBox1.Text = textBox2.Text.Replace("\r\n", " ");
EDIT:
String singleLine=multiLine.Replace("\r\n"," ");
You can remove '\n' characters from the input and '\r' as well.
I have a program that generates a plain text file. The structure (layout) is always the same. Example:
Text File:
LinkLabel
"Hello, this text will appear in a LinkLabel once it has been
added to the form. This text may not always cover more than one line. But will always be surrounded by quotation marks."
240, 780
So, to explain what is going on in that file:
Control
Text
Location
And when a button on the Form is clicked, and the user opens one of these files from the OpenFileDialog dialog, I need to be able to Read each line. Starting from the top, I want to check to see what control it is, then starting on the second line I need to be able to get all text inside the quotation marks (regardless of whether is is one line of text or more), and on the next line (after the closing quotation mark), I need to extract the location (240, 780)... I have thought of a few ways of going about this but when I go to write it down and put it to practice, it doesn't make much sense and end up figuring out ways that it won't work.
Has anybody ever done this before? Would anybody be able to provide any help, suggestions or advice on how I'd go about doing this?
I have looked up CSV files but that seems too complicated for something that seems so simple.
Thanks
jase
You could use a regular expression to get the lines from the text:
MatchCollection lines = Regex.Matches(File.ReadAllText(fileName), #"(.+?)\r\n""([^""]+)""\r\n(\d+), (\d+)\r\n");
foreach (Match match in lines) {
string control = match.Groups[1].Value;
string text = match.Groups[2].Value;
int x = Int32.Parse(match.Groups[3].Value);
int y = Int32.Parse(match.Groups[4].Value);
Console.WriteLine("{0}, \"{1}\", {2}, {3}", control, text, x, y);
}
I'll try and write down the algorithm, the way I solve these problems (in comments):
// while not at end of file
// read control
// read line of text
// while last char in line is not "
// read line of text
// read location
Try and write code that does what each comment says and you should be able to figure it out.
HTH.
You are trying to implement a parser and the best strategy for that is to divide the problem into smaller pieces. And you need a TextReader class that enables you to read lines.
You should separate your ReadControl method into three methods: ReadControlType, ReadText, ReadLocation. Each method is responsible for reading only the item it should read and leave the TextReader in a position where the next method can pick up. Something like this.
public Control ReadControl(TextReader reader)
{
string controlType = ReadControlType(reader);
string text = ReadText(reader);
Point location = ReadLocation(reader);
... return the control ...
}
Of course, ReadText is the most interesting one, since it spans multiple lines. In fact it's a loop that calls TextReader.ReadLine until the line ends with a quotation mark:
private string ReadText(TextReader reader)
{
string text;
string line = reader.ReadLine();
text = line.Substring(1); // Strip first quotation mark.
while (!text.EndsWith("\"")) {
line = reader.ReadLine();
text += line;
}
return text.Substring(0, text.Length - 1); // Strip last quotation mark.
}
This kind of stuff gets irritating, it's conceptually simple, but you can end up with gnarly code. You've got a comparatively simple case:one record per file, it gets much harder if you have lots of records, and you want to deal nicely with badly formed records (consider writing a parser for a language such as C#.
For large scale problems one might use a grammar driven parser such as this: link text
Much of your complexity comes from the lack of regularity in the file. The first field is terminated by nwline, the second by delimited by quotes, the third terminated by comma ...
My first recomendation would be to adjust the format of the file so that it's really easy to parse. You write the file so you're in control. For example, just don't have new lines in the text, and each item is on its own line. Then you can just read four lines, job done.