I've seen similar examples, but can't find something exactly like my problem.
I need to run a command like this from C#:
C:\FOLDER\folder with spaces\OTHER_FOLDER\executable.exe p1=hardCodedv1 p2=v2
I'm setting v2 at runtime, so I need to be able to modify the string in C# before calling Process.Start. Does anyone know how to handle this, since I have spaces between my parameters?
Even when you use the ProcessStartInfo Class, if you have to add spaces for arguments, then the above answers won't solve the problem. There's a simple solution. Just add quotes around arguments. That's all.
string fileName = #"D:\Company Accounts\Auditing Sep-2014 Reports.xlsx";
System.Diagnostics.ProcessStartInfo startInfo = new System.Diagnostics.ProcessStartInfo();
startInfo.FileName = "Excel.exe";
startInfo.Arguments = "\"" + fileName + "\"";
System.Diagnostics.Process.Start(startInfo);
Here I've added escaped quotes around filename, and it works.
You can use the ProcessStartInfo class to separate your arguments, FileName, WorkingDirectory and arguments without worry for spaces
string fullPath = #"C:\FOLDER\folder with spaces\OTHER_FOLDER\executable.exe"
ProcessStartInfo psi = new ProcessStartInfo();
psi.FileName = Path.GetFileName(fullPath);
psi.WorkingDirectory = Path.GetDirectoryName(fullPath);
psi.Arguments = "p1=hardCodedv1 p2=" + MakeParameter();
Process.Start(psi);
where MakeParameter is a function that returns the string to be used for the p2 parameter
Try this
ProcessStartInfo startInfo = new ProcessStartInfo();
startInfo.CreateNoWindow = false;
startInfo.UseShellExecute = false;
startInfo.FileName = "\"C:\\FOLDER\\folder with spaces\\OTHER_FOLDER\\executable.exe\"";
startInfo.Arguments = "p1=hardCodedv1 p2=v2";
Process.Start(startInfo);
After looking at the other solutions provided I ran into the issue where all my various arguments were bundled into one argument.
i.e. "-setting0=arg0 --subsetting0=arg1"
So I would propose the following:
ProcessStartInfo psi = new ProcessStartInfo();
psi.FileName = "\"" + Prefs.CaptureLocation.FullName + "\"";
psi.Arguments = String.Format("-setting0={0} --subsetting0={1}", "\"" + arg0 + "\"", "\"" + arg1+ "\"");
Process.Start(psi);
With the quotes around each argument, instead of around the entire set of arguments. And as pointed out by Red_Shadow this can all be done with the single line
Process.Start("\"" + filename + "\"", arguments here)
Very subtle caveat:
If I use ArgumentList, it only works when using it strictly trimmed (without leading or trailing spaces) and each string in it's own array place.
var psi = new ProcessStartInfo("cmd") {
ArgumentList = {
"--somepath",
"/root/subpath",
"--someid",
"12345",
}
};
If I try for example
"--somepath /root/subpath",
it doesn't work and I get errors from the cmd application.
Even
"--somepath ",
breaks the parser of the receiving program.
If the process you want to start is cmd /C
and the argument contains multiple spaces like C:\Program Files (x86)\Adobe\Acrobat Reader DC\Reader\AcroRd32.exe /N /T C:\users\someuser\AppData\Local\Temp\temp file with spaces.tmp Printer Name with Spaces maybe this answer will help you:
https://stackoverflow.com/a/6378038/20704455
In short: double quote
string arguments ="/C \"\"C:\\Program Files (x86)\\Adobe\\Acrobat Reader DC\\Reader\\AcroRd32.exe\" /N /T \"C:\\users\\someuser\\AppData\\Local\\Temp\\temp file with spaces.tmp\" \"Printer Name with Spaces\"\"";
ProcessStartInfo procStartInfo = new ProcessStartInfo("C:\\Windows\\sysnative\\cmd.exe",arguments);
Related
The issue lies with the space between Test & Program. How do I get around this so Process.Start(Info); works as intended. I could change Test Program.exe to TestProgram.exe and this would work perfectly. Ive looked at similar questions but non seem to answer my question. Most mention String Replace or altering the string. I dont want to alter the string but regognise there is a space and process as normal.
Apoligies if this has been asked before but I cant seem to find it so please post the link if this has. Thanks
My code
private string program_name = "Test Program.exe";
ProcessStartInfo Info = new ProcessStartInfo();
Info.Arguments = "/C choice /C Y /N /D Y /T 0 & start " + program_name;
Info.WindowStyle = ProcessWindowStyle.Hidden;
Info.CreateNoWindow = true;
Info.FileName = "cmd.exe";
Process.Start(Info);
In your specific example - which seems a little odd, if you don't mind me saying - the program you are executing is part of the argument list and needs to be wrapped in double quotes like so:
Info.Arguments = "/C choice /C Y /N /D Y /T 0 & start \"" + program_name + "\"";
Or, just in case program_name is already quoted:
var quoted_name = $"\"{program_name.Trim('"')}\"";
Info.Arguments = "/C choice /C Y /N /D Y /T 0 & start " + quoted_name;
If that's really what you're using rather than a contrived example (which is perfectly fine as an example) then it would be simpler to just run the program directly rather than passing it as a commandline to cmd.exe, in which case you don't need the quotes at all:
ProcessStartInfo Info = new ProcessStartInfo();
Info.WindowStyle = ProcessWindowStyle.Hidden;
Info.CreateNoWindow = true;
Info.FileName = program_name; // or program_name.Trim('"')
Process.Start(Info);
Since you're hiding the console window anyway there doesn't seem much point explicitly invoking cmd.exe and having it wait around for the program to complete.
Try this:
Info.Arguments = "/C choice /C Y /N /D Y /T 0 & start \"" + program_name + "\"";
Tearing my hair out over something that should be ridiculously simple! I have cd'd to C:\Program Files\ImageMagick-6.9.0-Q16 on my shell and used the following the command string which works on my machine; it creates the expected output image, no problem:
convert "C:\Users\someguy\Debug\test_in.jpg" -resize 75x75 -colorspace
RGB "C:\Users\someguy\Debug\test_out.jpg"
I am trying to automate this with a simple test application in C#:
var proc = new Process
{
StartInfo = new ProcessStartInfo()
{
//WorkingDirectory = #"C:\Program Files\ImageMagick-6.9.0-Q16\",
Arguments = //_arguments,
"convert \"" + InputPath + "\" -resize 75x75 \"" + OutputPath + "\""
,
UseShellExecute = _useShellExecute,
RedirectStandardError = _redirectStandardError,
//RedirectStandardOutput = _redirectStandardOutput,
//CreateNoWindow = _createNoWindow,
//Verb = _verb,
FileName = #"C:\Program Files\ImageMagick-6.9.0-Q16\" + "convert.exe"
}
};
var test = proc.StartInfo.Arguments.ToString();
proc.Start();
string error = proc.StandardError.ReadToEnd();
proc.WaitForExit();
I have tried several permutations of this, using convert.exe, mogrify.exe, with verb as "runas", with the working directory set on, or off... (see commented out stuff - I've tried setting it) I have referred to how to use imageMagick with C# but I continue to get the same error:
mogrify.exe: unable to open image convert': No such file or directory
# error/blob.c/OpenBlob/2709. mogrify.exe: no decode delegate for this
image format' # error/constitute.c/ReadImage/501. mogrify.exe:
unable to open image `C:\Users\someguy\Debug\test_out.jpg': No such
file or directory # error/blob.c/OpenBlob/2709.
I feel like I'm just missing something really basic here, but I don't have a clue at this point. Could someone please offer a suggestion?
var proc = new Process
{
StartInfo = new ProcessStartInfo(_imageMagickFile)
{
//WorkingDirectory = #"C:\Program Files\ImageMagick-6.9.0-Q16\",
Arguments = //_arguments,
"" + InputPath + " -resize 75x75 " + OutputPath + ""
,
UseShellExecute = _useShellExecute,
RedirectStandardError = _redirectStandardError,
RedirectStandardOutput = _redirectStandardOutput,
CreateNoWindow = _createNoWindow,
Verb = _verb,
FileName = _imageMagickFile
}
};
var test = proc.StartInfo.Arguments.ToString();
proc.Start();
string error = proc.StandardError.ReadToEnd();
proc.WaitForExit();
I'm not actually sure why this works instead of the original question, but it does. Using convert.exe is indeed correct, not mogrify.exe. As an FYI, the other parameters are ShellExecute = false, Redirect std err/out are set to true, verb is runas.
I'm new to c# as well as this website so I'll probably make some mistakes but hopefully I'll learn as well.
I'm trying to develop an app to extract from a .7z a file, read it and delete it before moving to the next (there is about 12k files in there, which take up a lot of space).
Now, I'm using .NET 2.0 and I haven't found easy solutions to extract single files from an archive. I came across a post explaining that you could use 7za.exe to do so from the command line, and so I did. Now, the problem is that if I try to do the same in my app 7za throws the "cannot use absolute pathnames" error. However, as I said, the same parameters work at the command prompt.
My idea is to get a list of all the files in the compressed folder and put it in a textfile. From there it is as easy as get the name of the first one, unzip it, read it, delete it and move to next. This is what I got to get the list:
System.Diagnostics.Process process = new System.Diagnostics.Process();
System.Diagnostics.ProcessStartInfo startInfo = new System.Diagnostics.ProcessStartInfo();
startInfo.FileName = #"C:\Users\yadayada\Desktop\7za.exe"; //just testing
string parameters= "-y l " + path_file7z + " > " + path_file_destination + #"\file.txt";
//needeless to say, path_file7z and path_file_destination are strings with the correct path like "C:\Users\yadayada\Desktop"
startInfo.Arguments = parameters
process.StartInfo = startInfo;
process.StartInfo.UseShellExecute = false;
process.Start();
process.WaitForExit();
As I said, as the process ends I can see a console opening and closing. I took a screenshot to check what it said and the error I got was the one I said at the begining of the question.
Now, does anyone know why I get this error and how can I fix this?
SOLUTION
Ended un going for a not too elegant (being gentle) solution that works.
To list the names:
System.Diagnostics.Process process = new System.Diagnostics.Process();
System.Diagnostics.ProcessStartInfo startInfo = new System.Diagnostics.ProcessStartInfo();
startInfo.FileName = #"cmd.exe";
string parameters= "/k -y l " + path_file7z + " > " + path_file_destination + #"\file.txt";
//needeless to say, path_file7z and path_file_destination are strings with the correct path like "C:\Users\yadayada\..."
startInfo.Arguments = parameters
process.StartInfo = startInfo;
process.StartInfo.UseShellExecute = false;
process.Start();
Thread.Sleep(1000);
process.Kill();
Now, once this has been done the extract part is tanken care of by a method similar to the one provided by Igor's links:
public void ExtractFile(string source, string element, string destination)
{
System.Diagnostics.Process process = new System.Diagnostics.Process();
System.Diagnostics.ProcessStartInfo startInfo = new System.Diagnostics.ProcessStartInfo();
startInfo.WindowStyle = System.Diagnostics.ProcessWindowStyle.Hidden;
startInfo.FileName = /*7zG.exe's path*/;
startInfo.Arguments = #"-y x " + source + " -o" + destination + " " + element + " -r";
process.StartInfo = startInfo;
process.StartInfo.UseShellExecute = false;
process.Start();
process.WaitForExit();
}
I think it is working well now. If I have further issues I'll update this with the solutions I come up with with the help provided. Thanks again!
Use this tutorial for 7zip:
https://stick2basic.wordpress.com/2013/04/25/how-to-extract-7z-file-to-a-folder-c-net/
Use this library if rar and zip are allowed:
http://dotnetzip.codeplex.com/
private void MyExtract()
{
string zipToUnpack = "C1P3SML.zip";
string unpackDirectory = "Extracted Files";
using (ZipFile zip1 = ZipFile.Read(zipToUnpack))
{
// here, we extract every entry, but we could extract conditionally
// based on entry name, size, date, checkbox status, etc.
foreach (ZipEntry e in zip1)
{
e.Extract(unpackDirectory, ExtractExistingFileAction.OverwriteSilently);
}
}
}
EDIT
This can help you:
Unzip a file in c# using 7z.exe
Happy to help you!
First of all, i searched a lot to avoid asking a duplicate question. If there is one, i will delete this question immediately.
All the solutions on the web are suggesting to use Process.StartInfo like this one
How To: Execute command line in C#, get STD OUT results
I dont want to run a batch file, or an .exe.
I just want to run some commands on cmd like
msg /server:192.168.2.1 console "foo" or ping 192.168.2.1
and return the result if there is one.
How can i do that ?
Those commands are still exe files, you just need to know where they are. For example:
c:\windows\system32\msg.exe /server:192.168.2.1 console "foo"
c:\windows\system32\ping.exe 192.168.2.1
The only proper way to do this is to use Process.Start. This is demonstrated adequately in this question, which is itself a duplicate of two others.
However, as DavidG says, the commands are all exe files and you can run them as such.
Apparently, i found an answer
while (true)
{
Console.WriteLine("Komut giriniz.");
string komut = Console.ReadLine();
System.Diagnostics.Process process = new System.Diagnostics.Process();
System.Diagnostics.ProcessStartInfo startInfo = new System.Diagnostics.ProcessStartInfo();
//startInfo.WindowStyle = System.Diagnostics.ProcessWindowStyle.Hidden;
startInfo.FileName = "cmd.exe";
startInfo.Arguments = "/C" + komut;
startInfo.RedirectStandardOutput = true;
startInfo.UseShellExecute = false;
process.StartInfo = startInfo;
Console.WriteLine(process.Start());
string line = "";
while (!process.StandardOutput.EndOfStream)
{
line = line + System.Environment.NewLine + process.StandardOutput.ReadLine();
// do something with line
}
Console.WriteLine(line);
Console.ReadLine();
}
seems like if you can run cmd.exe with arguments including your command.
thanks for contributing.
At the beginning of this document, it says you can right-click on a file and print from there. Now my question is, how do I print using C#? I can call the executable and give it the print command and the file, and it prints. I can call the file directly, and it opens. But how do I call the file, and tell it to print?
Here is my current code, which requires knowing where the program is.
ProcessStartInfo psi = new ProcessStartInfo();
psi.FileName = PathToProgram;
psi.Arguments = "/P \"" + PathToFile + "\"";
psi.UseShellExecute = false;
Process.Start(psi).WaitForExit();
Ok, I got it. This is exactly what I was looking for. Notice the Verbs property. It lists the different options you have to work with for that program.
ProcessStartInfo psi = new ProcessStartInfo();
psi.FileName = Program.appdata.PathToBillItemsLabels;
//Break. psi.Verbs = { "Open", "Print" };
psi.Verb = "Print";
Process.Start(psi).WaitForExit();
psi.UseShellExecute = true;
You must change the property to TRUE to work properly.
Regards