I want to make my click event change an ApplicationBarIconButton. My ApplicationBarIconButton looks like this:
<shell:ApplicationBarIconButton x:Name="driveAction" Click="drive_click" IconUri="/img/car.png" Text="kör" />
I want the IconUri to change from /img/car.png to ex. /img/car-stop.png and the text value from kör to passagera. I tried the function below, but it only causes my app to shut down.
private void drive_click(object sender, EventArgs e)
{
this.driveAction.Text = "passagera";
this.driveAction.Source = "/img/car-stop.png";
}
What is wrong? Why doesn't this work?
The default ApplicationBar requires you to access the buttons through the ApplicationBar object. To accomplish this you must know the index of the button that you want to change
private const int DriveButtonIndex = 0;
private void drive_click(object sender, EventArgs e)
{
var button = (ApplicationBarIconButton)ApplicationBar.Buttons[DriveButtonIndex];
button.IconUri = new Uri("/img/car-stop.png", UriKind.Relative);
button.Text = "passagera";
}
There are a few custom ApplicationBars that allow you to name your buttons. But I've found that the above solution always works for me.
Get it directly from the application bar list -
ApplicationBar.Buttons[0].Text = "passagera";
ApplicationBar.Buttons[0].Source = "/img/car-stop.png";
You could also query the list of buttons for a specific icon as a more tenable long-term solution, but if you only have one button and that's not going to change, this works.
Because the ApplicationBarIconButton is actually a native control and not a true XAML object you cannot refer to it by name.
You can refer to it by index if create in XAML. Alternatively you could create it in code and then you can maintain a named reference you can use.
Related
I have a main page which has a play, options and exit button, both the play and exit button work as I followed a tutorial on it however for the options button I do not know how to navigate it. What I am planning to do is to create another class called optionsMenu.cs and have like a credits screen or a how to play guide on it.
These are the codes that I have for my options button.
var optionsGameButton = new Button(buttonTexture, buttonFont)
{
Position = new Vector2(300, 250),
Text = "Options",
};
optionsGameButton.Click += OptionsGameButton_Click;
_components = new List<Component>()
{
titleGameButton,
playGameButton,
optionsGameButton,
exitGameButton,
};
Finally I know I have to write a code in this area to be able to get the options button working but I don't know which kind of code to put.
private void OptionsGameButton_Click(object sender, EventArgs e)
{
Console.WriteLine("Credits");
}
If you're set on using click events, then you'll need to create a new instance of your options page and set it as the content of your control object within OptionsGameButton_Click. On the options page you'll need to set the xmlns to your optionsMenu.cs file.
I think you could also set the content of your control object by passing it as a parameter within the method itself, but I've only done this using the ICommand interface.
I wanted to show my search and clear(cross mark) icon into textbox that i had designed to search my treeview. When user enter into textbox and writes some text into it i want my cross icon to be visible and when nothing is written inside of it i wanted to show search icon.
What i have done so far is something like this.
but i wanted it to be like this when nothing entered.
and when text is entered i wanted to be like this ->
also when user clicks cross mark i wanted textbox to get empty.
Thankyou!
If you can live with the icon sitting above the text you can do this:
Add a Panel IconPanel and nest it in the TextBox textBox1:
Panel IconPanel = new Panel();
IconPanel.Parent = textBox1;
IconPanel.Size = new Size(32, textBox1.ClientSize.Height); // use your numbers!
IconPanel.Location = new Point(textBox1.Width - IconPanel.Width, 0);
IconPanel.BackgroundImageLayout = ImageLayout.Stretch;
Add your icons to the project resources and code the TextChanged event like this:
private void textBox1_TextChanged(object sender, EventArgs e)
{
IconPanel.BackgroundImage = textBox1.Text.Length == 0 ?
global::yourProjectName.Properties.Resources.searchIcon :
global::yourProjectName.Properties.Resources.clearIcon;
}
Initialize the IconPanel.BackgroundImage depending on your intial Textbox content!
I started out C# very recently and sorry if this question sounds dumb.
How do I add a Listbox in a Form that pops out from a Button click?
Note: The Form isn't the one that's added from the Solution Explorer whereby I can just drag a Listbox from the Toolbox to my Form.
So what I want is to create a ListBox in my file drawer1Form where I can add additional items. Thanks for the help in advance!:)
private void drawer1button_Click(object sender, EventArgs e) // Drawer 1 Button
{
drawer1Form df1 = new drawer1Form();
df1.StartPosition = FormStartPosition.CenterScreen;
df1.Show();
}
public partial class drawer1Form : Form // Creates drawer1Form
{
public drawer1Form()
{
Text = "Drawer 1 ";
}
}
Pretty much the same way as you'd do with any other object.
In the class of your form add a
private ListBox myAwesomeListBox;
Then in the button event handler add something like this:
myAwesomeListBox = new ListBox();
myAwesomeListBox.SuspendLayout();
// set all the properties that you want
myAwesomeListBox.Name = "myAwesomeListBox";
myAwesomeListBox.Location = new Point(...); // place it somewhere
myAwesomeListBox.Size = new Size(...); // give it a size
// etc...
df1.Controls.Add(myAwesomeListBox);
myAwesomeListBox.ResumeLayout();
This should be it.
I highly advise you to do it through the designer first though, and then take a look at the generated code in the form's .Designer.cs file, you'll have a very good understanding after reading through that.
I want to place a link inside the description field of my applications about box which will direct users to a wiki page for more help. I can't figure out how to make the address appear as a link.
I set the description through the assembly information properties.
There's a WinForms control you can use to achieve what you want: the LinkLabel.
Simply add one to your AboutBox layout and double click it. A handler to its LinkClicked event will be created, and there you can then use Process.Start to open your website's URL.
public AboutBox1()
{
InitializeComponent();
this.Text = String.Format("About {0}", AssemblyTitle);
this.labelProductName.Text = AssemblyProduct;
this.labelVersion.Text = String.Format("Version {0}", AssemblyVersion);
this.labelCopyright.Text = AssemblyCopyright;
this.labelCompanyName.Text = AssemblyCompany;
this.textBoxDescription.Text = AssemblyDescription;
this.Link.Text = "Visit our website!";
this.Link.Tag = WpfApplication2.Properties.Resources.website;
}
private void Link_LinkClicked(object sender, LinkLabelLinkClickedEventArgs e)
{
System.Diagnostics.Process.Start((sender as LinkLabel).Tag.ToString());
}
In my case, I've saved the URL as an application resource. And I've showed it separately from the Assembly Description.
If you want the link to appear inside the Assembly Description, it's quite a bit more complicated...
In the code behind of my page I want to attach a label in multiple places. To achieve this and avoid creating mutliple instances of the same label I've tried:
Label lblNone = new Label();
lblNone.Text = "<br/> None. <br/>";
Master.mainContent.Controls.Add(lblNone);
Master.mainContent.Controls.Add(lblNone);
Master.mainContent.Controls.Add(lblNone);
For some reason I only see 1 instance of the "None." on my page?
Why is this?
You have no option.. you need to create one instance of Label for each control you want to see in the screen.
This is because of the behavior of the ControlCollection class.
it will not allow multiple adds of the same "reference".
When you add a control to one ControlCollection it is automatically removed from the previous so, even if you were adding your label to different ControlCollections it wouldn't work.
PS: By ControlCollection I mean the type of the property Master.mainContent.Controls
You might find it easier to create a method for this as so: -
protected void Page_Load(object sender, EventArgs e)
{
this.Controls.Add(CreateLiteral("text"));
this.Controls.Add(CreateLiteral("text"));
this.Controls.Add(CreateLiteral("text"));
}
private Literal CreateLiteral(string Content)
{
Literal L = new Literal();
L.Text = Content;
return L;
}
Thanks,
Phil.