i can't find anywhere how can i get selected file's path in asp.net mvc (i am using c#)?
I need to send file to server, so i just need to get it's path and then i use
Image image = Image.FromFile(path);
but only way to get path i found was:
var fileName = Path.GetFileName(file.FileName);
var path = Path.Combine(Server.MapPath("~/App_Data/uploads"), fileName);
file.SaveAs(path);
but i dont want to save my file. If i use
Path.GetFullPath
i get path in II Express folder and i can not use this path.
So, is there any way to get selected file's path?
How select file:
<form id="Form1" method="post" enctype="multipart/form-data" runat="server">
<input type=file id=File1 name=file value="Browse" runat="server" dir="rtl" aria-selected="false" />
<br>
<input type="submit" id="Submit1" value="Upload" runat="server" aria-haspopup="False" dir="rtl" />
It seems like you're trying to get the file's path on the client, and "read" it to an image object - that's impossible, because the server doesn't have access to the client's filesystem.
Normally, a file upload will look like this:
<form id="form1" runat="server" method="post" enctype="multipart/form-data">
<div>
<input id="File1" type="file" runat="server" />
<input type="submit" value="submit" runat="server" onserverclick="Btn1_ServerClick" />
</div>
</form>
and the server side is:
protected void Btn1_ServerClick(object sender, EventArgs e)
{
var file = File1.PostedFile;
var image = System.Drawing.Image.FromStream(file.InputStream);
}
This is in classic ASP.NET, but if you're using MVC.NET and accessing a controller action it's pretty similar (the controller will receive some sort of HttpPostedFileBase as a parameter from the form)
It is proper behavior of the server and framework that you receive path to location on server.
Normally when we mean one way communication from client to server, as it occurs with http requests (e.g. get or post), the server has not access to clients' file system (hard disk etc). Normally uploading data to server (file) by choosing file on client's file system is sending the data (copy of the file), not path to the file. Server does not initiate getting the file form client by using client's path to it.
Related
Following is the HTML form code, for uploading text value and a JPEG file.
<html>
<head></head>
<body>
<form action="https://mywebsiteforexample.com/" method="post" enctype="multipart/form-data">
<input type="text" name="id" value="01"/>
<input type="file" name="image">
<input type="submit" value="send">
</form>
</body>
</html>
Problem is whenever I have to upload the file on server, I need to manually browse the file to upload it. I want to write the same code in C# so when I run the code it itself select the file by path given, and upload the file so I don't need to browse and select the file manually. Is it possible.
You don't need to write code that fills input elements (if you want, use Selenium with C# driver). Just simulate POST action from simple console application using for e.g. HttpClient.
There are plenty of questions on SO how to do it, e.g. C# HttpClient 4.5 multipart/form-data upload
I am trying to login into fogbugz using my c# application.I am using FogBugz XML API.
The code that I am currently using is:
<form method="post" action="https://xxxxx.fogbugz.com/api.asp?cmd=logon">
Email:
<input type="text" value="email" name="email">
<br />
Password:
<input type="password" value="password" name="password">
<br />
<input type="submit">
<br />
</form>
When I do this I do get logged into FogBugz.I get an XML file as output where I have my token under tags.
Is there any way to make the user see an aspx file and not the XML file but I could use the XML file and cache the token value?
I am new to FogBugz please help!
Thank you.
I would recommend checking out FogLampz.
It allows you to write code such as:
FogBugzClient.LogOn("https://myproject.fogbugz.com/api.asp",
"email#mydomain.com", "password");
var projects = FogBugzClient.GetProjects();
var areas = FogBugzClient.GetAreas();
Use this in your code-behind for your aspx page. (you wont need your form action pointing to fogbugz)
You can then display/modify/do-anything-to the results as you wish.
Alternatively there is the Fogbugz Csharp API Wrapper which allows very similar coding style to pull out FogBugz data.
I'm modifying an existing ASP.NET project. The original author erroneously tried to create a styled asp:FileUpload by setting its visibility to hidden and just creating two custom styled browse and save buttons.
For security reason, IE does not permit this. My strategy is to instead try to use input tags with type="file", like this example. So if I set up the input like <input type="file" ID="inputFile" /> how do I access/save the file in my code behind, inputFile.SaveAs("someFile.txt");? Also (in code behind) can I do something like inputFile.HasFile or is there some other analog of this?
As per recommendations I'm trying something like the following:
<td>
Enabled: <asp:CheckBox ID="CheckBox2" runat="server" />
<div id="testFileUploader">>
<input type="file" id="browserHidden" runat="server" />
<div id="browserVisible"><input type="text" id="fileField" /></div>
</div>
</td>
So, you can generate a random file name for the a future upload, based on the GUID at the CodeBehind of ASPX page:
HttpPostedFile filePosted = Request.Files["uploadFieldNameFromHTML"];
if (filePosted != null && filePosted.ContentLength > 0)
{
string fileNameApplication = System.IO.Path.GetFileName(filePosted.FileName);
string fileExtensionApplication = System.IO.Path.GetExtension(fileNameApplication);
// generating a random guid for a new file at server for the uploaded file
string newFile = Guid.NewGuid().ToString() + fileExtensionApplication;
// getting a valid server path to save
string filePath = System.IO.Path.Combine(Server.MapPath("uploads"), newFile);
if (fileNameApplication != String.Empty)
{
filePosted.SaveAs(filePath);
}
}
For Request.Files["uploadFieldNameFromHTML"] set the ID in HTML code here:
<input type='file' id='...' />
Also, don't forget to define runat="server" at the main form in ASPX page, it's better to set it at the main form and don't forget about enctype="multipart/form-data" parameter of the <form>:
<body>
<form enctype="multipart/form-data" id="form1" runat="server">
<input type='file' id='uploadFieldNameFromHTML' />
...
Add a runat="server" to the object. This way it will work on the CodeBehid just like any asp:FileUpload control.
As commented you can add the runat="server" to you input file tag.
By another hand, there is already a similar post about what you're asking for. Check this out:
Uploading Files in ASP.net without using the FileUpload server control
Hope this help
Cheers!
if(fileUrunResim.HasFile)
fileUrunResim.SaveAs(MapPath("~/Images/" + fileUrunResim.FileName));
**if you unique filename,**
string extension = Path.GetExtension(fileUrunResim.FileName);
string fileName = Guid.NewGuid().ToString().Substring(0, 25) + extension ;
if(fileUrunResim.HasFile)
fileUrunResim.SaveAs(MapPath("~/Images/" + filename ));
I've developed a web app using asp.net c#. There is a FileUpload Control that must upload personnel photos. But as I published the website, it is not working properly! While on the local version no problem seen. I've been trying the following:
Check HttpRuntime in the web.config => executionTime="60", maxRequestLength="4097151"
Searching on the web and nothing came out
Here is my code:
fupImage.SaveAs(Server.MapPath(#"\UploadedImages\" + fupImage.FileName));
fupImage.SaveAs(Server.MapPath(#"\UploadedImages\" + fupImage.FileName));
What might be wrong with that?
Make sure you have set form enctype="multipart/form-data" and path where you are saving does exist and you have permission. you can check it by debugging..
Here is complete code
<form id="Form1" method="post" action="/home/save" enctype="multipart/form-data">
<input type="file" name="file" />
<input type="submit" value="OK" />
</form>
[HttpPost]
public ActionResult Save(HttpPostedFileBase file)
{
// Verify that the user selected a file
if (file != null && file.ContentLength > 0)
{
// extract only the fielname
var fileName = Path.GetFileName(file.FileName);
// store the file inside ~/App_Data/uploads folder
var path = Path.Combine(Server.MapPath("~/UploadedImages"), fileName);
file.SaveAs(path);
}
// redirect back to the index action to show the form once again
return RedirectToAction("Index");
}
How can identify input (type="file") id of fileupload while file uploading to server.
Let me explain in detail:
I have multiple file upload control on my page and different control save file on different folders like "Fileupload1" will save file on "Folder1" and so on.
You can't. The id of an HTML element is never sent to the server when posting a form. As far as the name attribute is concerned you may loop through the Request.Files collection. In ASP.NET MVC it more common to use action parameters. Example:
<form action="" method="post" enctype="multipart/form-data">
<input type="file" name="files" id="file1" />
<input type="file" name="files" id="file2" />
<input type="file" name="files" id="file3" />
<input type="submit" value="Upload files" />
</form>
and your controller action:
[HttpPost]
public ActionResult Index(IEnumerable<HttpPostedFileBase> files)
{
foreach (var file in files)
{
if (file.ContentLength > 0)
{
var fileName = Path.GetFileName(file.FileName);
var path = Path.Combine(Server.MapPath("~/App_Data"), fileName);
file.SaveAs(path);
}
}
return RedirectToAction("Index");
}
It's as simple as that.
As Darian points out, the ID isn't sent. But the name attribute is, so your file upload should be something like:
<input type="file" name="contactsFile" />
Which will let you use a method such as
public ActionResult UploadFile(HttpPostedFileBase contactsFile)
in your controller.
You won't have access to any DOM element since ASP.NET MVC uses the FileCollectionModelBinder to create a collection of files. So what you receive in your controller won't have anything to do with the DOM. But the good thing is since it's a collection you can access the index of the file.
<input type="file" name="files[0]" id="file1" />
<input type="file" name="files[1]" id="file2" />
<input type="file" name="files[2]" id="file3" />
Then if you need to upload files[0] to folder Y and files[1] to folder Z you can access the files collection index.
switch (index)
{
case 0:
// Upload to Y
case 1:
// Upload to Z
default:
}