Using a baseclass method return value? - c#

I have a method in my baseclass that returns a bool and I want that bool to determine what happens to the same overridden method in my derived class.
Base:
public bool Debt(double bal)
{
double deb = 0;
bool worked;
if (deb > bal)
{
Console.WriteLine("Debit amount exceeds the account balance – withdraw cancelled");
worked = false;
}
else
bal = bal - deb;
worked = true;
return worked;
}
Derived
public override void Debt(double bal)
{
// if worked is true do something
}
Note that bal comes from a constructor I made earlier

You can call the base class method using the base keyword:
public override void Debt(double bal)
{
if(base.Debt(bal))
DoSomething();
}
As indicated in the comments above, you either need to make sure that there is a virtual method with the same signature (return type and parameters) in the base class or remove the override keyword from the deriving class.

if(base.Debt(bal)){
// do A
}else{
// do B
}
base refers to the base class. So base.X refers to X in the base class.

Call the base method:
public override void Debt(double bal)
{
var worked = base.Debt(bal);
//Do your stuff
}

As several others have mentioned you can use base.Debt(bal) to call into your base class method. I also noticed that your base class method was not declared as virtual. C# methods are NOT virtual by default so you will not be override it in a derived class unless you have specified it as virtual in the base class.
//Base Class
class Foo
{
public virtual bool DoSomething()
{
return true;
}
}
// Derived Class
class Bar : Foo
{
public override bool DoSomething()
{
if (base.DoSomething())
{
// base.DoSomething() returned true
}
else
{
// base.DoSomething() returned false
}
}
}
Here's what msdn has to say about virtual methods

Related

Calling a super base class method from a derived class C# [duplicate]

// Cannot change source code
class Base
{
public virtual void Say()
{
Console.WriteLine("Called from Base.");
}
}
// Cannot change source code
class Derived : Base
{
public override void Say()
{
Console.WriteLine("Called from Derived.");
base.Say();
}
}
class SpecialDerived : Derived
{
public override void Say()
{
Console.WriteLine("Called from Special Derived.");
base.Say();
}
}
class Program
{
static void Main(string[] args)
{
SpecialDerived sd = new SpecialDerived();
sd.Say();
}
}
The result is:
Called from Special Derived.
Called from Derived. /* this is not expected */
Called from Base.
How can I rewrite SpecialDerived class so that middle class "Derived"'s method is not called?
UPDATE:
The reason why I want to inherit from Derived instead of Base is Derived class contains a lot of other implementations. Since I can't do base.base.method() here, I guess the best way is to do the following?
// Cannot change source code
class Derived : Base
{
public override void Say()
{
CustomSay();
base.Say();
}
protected virtual void CustomSay()
{
Console.WriteLine("Called from Derived.");
}
}
class SpecialDerived : Derived
{
/*
public override void Say()
{
Console.WriteLine("Called from Special Derived.");
base.Say();
}
*/
protected override void CustomSay()
{
Console.WriteLine("Called from Special Derived.");
}
}
Just want to add this here, since people still return to this question even after many time. Of course it's bad practice, but it's still possible (in principle) to do what author wants with:
class SpecialDerived : Derived
{
public override void Say()
{
Console.WriteLine("Called from Special Derived.");
var ptr = typeof(Base).GetMethod("Say").MethodHandle.GetFunctionPointer();
var baseSay = (Action)Activator.CreateInstance(typeof(Action), this, ptr);
baseSay();
}
}
This is a bad programming practice, and not allowed in C#. It's a bad programming practice because
The details of the grandbase are implementation details of the base; you shouldn't be relying on them. The base class is providing an abstraction overtop of the grandbase; you should be using that abstraction, not building a bypass to avoid it.
To illustrate a specific example of the previous point: if allowed, this pattern would be yet another way of making code susceptible to brittle-base-class failures. Suppose C derives from B which derives from A. Code in C uses base.base to call a method of A. Then the author of B realizes that they have put too much gear in class B, and a better approach is to make intermediate class B2 that derives from A, and B derives from B2. After that change, code in C is calling a method in B2, not in A, because C's author made an assumption that the implementation details of B, namely, that its direct base class is A, would never change. Many design decisions in C# are to mitigate the likelihood of various kinds of brittle base failures; the decision to make base.base illegal entirely prevents this particular flavour of that failure pattern.
You derived from your base because you like what it does and want to reuse and extend it. If you don't like what it does and want to work around it rather than work with it, then why did you derive from it in the first place? Derive from the grandbase yourself if that's the functionality you want to use and extend.
The base might require certain invariants for security or semantic consistency purposes that are maintained by the details of how the base uses the methods of the grandbase. Allowing a derived class of the base to skip the code that maintains those invariants could put the base into an inconsistent, corrupted state.
You can't from C#. From IL, this is actually supported. You can do a non-virt call to any of your parent classes... but please don't. :)
The answer (which I know is not what you're looking for) is:
class SpecialDerived : Base
{
public override void Say()
{
Console.WriteLine("Called from Special Derived.");
base.Say();
}
}
The truth is, you only have direct interaction with the class you inherit from. Think of that class as a layer - providing as much or as little of it or its parent's functionality as it desires to its derived classes.
EDIT:
Your edit works, but I think I would use something like this:
class Derived : Base
{
protected bool _useBaseSay = false;
public override void Say()
{
if(this._useBaseSay)
base.Say();
else
Console.WriteLine("Called from Derived");
}
}
Of course, in a real implementation, you might do something more like this for extensibility and maintainability:
class Derived : Base
{
protected enum Mode
{
Standard,
BaseFunctionality,
Verbose
//etc
}
protected Mode Mode
{
get; set;
}
public override void Say()
{
if(this.Mode == Mode.BaseFunctionality)
base.Say();
else
Console.WriteLine("Called from Derived");
}
}
Then, derived classes can control their parents' state appropriately.
Why not simply cast the child class to a specific parent class and invoke the specific implementation then? This is a special case situation and a special case solution should be used. You will have to use the new keyword in the children methods though.
public class SuperBase
{
public string Speak() { return "Blah in SuperBase"; }
}
public class Base : SuperBase
{
public new string Speak() { return "Blah in Base"; }
}
public class Child : Base
{
public new string Speak() { return "Blah in Child"; }
}
public partial class MainWindow : Window
{
public MainWindow()
{
InitializeComponent();
Child childObj = new Child();
Console.WriteLine(childObj.Speak());
// casting the child to parent first and then calling Speak()
Console.WriteLine((childObj as Base).Speak());
Console.WriteLine((childObj as SuperBase).Speak());
}
}
public class A
{
public int i = 0;
internal virtual void test()
{
Console.WriteLine("A test");
}
}
public class B : A
{
public new int i = 1;
public new void test()
{
Console.WriteLine("B test");
}
}
public class C : B
{
public new int i = 2;
public new void test()
{
Console.WriteLine("C test - ");
(this as A).test();
}
}
You can also make a simple function in first level derived class, to call grand base function
My 2c for this is to implement the functionality you require to be called in a toolkit class and call that from wherever you need:
// Util.cs
static class Util
{
static void DoSomething( FooBase foo ) {}
}
// FooBase.cs
class FooBase
{
virtual void Do() { Util.DoSomething( this ); }
}
// FooDerived.cs
class FooDerived : FooBase
{
override void Do() { ... }
}
// FooDerived2.cs
class FooDerived2 : FooDerived
{
override void Do() { Util.DoSomething( this ); }
}
This does require some thought as to access privilege, you may need to add some internal accessor methods to facilitate the functionality.
In cases where you do not have access to the derived class source, but need all the source of the derived class besides the current method, then I would recommended you should also do a derived class and call the implementation of the derived class.
Here is an example:
//No access to the source of the following classes
public class Base
{
public virtual void method1(){ Console.WriteLine("In Base");}
}
public class Derived : Base
{
public override void method1(){ Console.WriteLine("In Derived");}
public void method2(){ Console.WriteLine("Some important method in Derived");}
}
//Here should go your classes
//First do your own derived class
public class MyDerived : Base
{
}
//Then derive from the derived class
//and call the bass class implementation via your derived class
public class specialDerived : Derived
{
public override void method1()
{
MyDerived md = new MyDerived();
//This is actually the base.base class implementation
MyDerived.method1();
}
}
As can be seen from previous posts, one can argue that if class functionality needs to be circumvented then something is wrong in the class architecture. That might be true, but one cannot always restructure or refactor the class structure on a large mature project. The various levels of change management might be one problem, but to keep existing functionality operating the same after refactoring is not always a trivial task, especially if time constraints apply. On a mature project it can be quite an undertaking to keep various regression tests from passing after a code restructure; there are often obscure "oddities" that show up.
We had a similar problem in some cases inherited functionality should not execute (or should perform something else). The approach we followed below, was to put the base code that need to be excluded in a separate virtual function. This function can then be overridden in the derived class and the functionality excluded or altered. In this example "Text 2" can be prevented from output in the derived class.
public class Base
{
public virtual void Foo()
{
Console.WriteLine("Hello from Base");
}
}
public class Derived : Base
{
public override void Foo()
{
base.Foo();
Console.WriteLine("Text 1");
WriteText2Func();
Console.WriteLine("Text 3");
}
protected virtual void WriteText2Func()
{
Console.WriteLine("Text 2");
}
}
public class Special : Derived
{
public override void WriteText2Func()
{
//WriteText2Func will write nothing when
//method Foo is called from class Special.
//Also it can be modified to do something else.
}
}
There seems to be a lot of these questions surrounding inheriting a member method from a Grandparent Class, overriding it in a second Class, then calling its method again from a Grandchild Class. Why not just inherit the grandparent's members down to the grandchildren?
class A
{
private string mystring = "A";
public string Method1()
{
return mystring;
}
}
class B : A
{
// this inherits Method1() naturally
}
class C : B
{
// this inherits Method1() naturally
}
string newstring = "";
A a = new A();
B b = new B();
C c = new C();
newstring = a.Method1();// returns "A"
newstring = b.Method1();// returns "A"
newstring = c.Method1();// returns "A"
Seems simple....the grandchild inherits the grandparents method here. Think about it.....that's how "Object" and its members like ToString() are inherited down to all classes in C#. I'm thinking Microsoft has not done a good job of explaining basic inheritance. There is too much focus on polymorphism and implementation. When I dig through their documentation there are no examples of this very basic idea. :(
I had the same problem as the OP, where I only wanted to override a single method in the middle Class, leaving all other methods alone. My scenario was:
Class A - base class, DB access, uneditable.
Class B : A - "record type" specific functionality (editable, but only if backward compatible).
Class C : B - one particular field for one particular client.
I did very similar to the second part of the OP posting, except I put the base call into it's own method, which I called from from Say() method.
class Derived : Base
{
public override void Say()
{
Console.WriteLine("Called from Derived.");
BaseSay();
}
protected virtual void BaseSay()
{
base.Say();
}
}
class SpecialDerived : Derived
{
public override void Say()
{
Console.WriteLine("Called from Special Derived.");
base.BaseSay();
}
}
You could repeat this ad infinitum, giving, for example SpecialDerived a BaseBaseSay() method if you needed an ExtraSpecialDerived override to the SpecialDerived.
The best part of this is that if the Derived changes its inheritance from Base to Base2, all other overrides follow suit without needing changes.
If you want to access to base class data you must use "this" keyword or you use this keyword as reference for class.
namespace thiskeyword
{
class Program
{
static void Main(string[] args)
{
I i = new I();
int res = i.m1();
Console.WriteLine(res);
Console.ReadLine();
}
}
public class E
{
new public int x = 3;
}
public class F:E
{
new public int x = 5;
}
public class G:F
{
new public int x = 50;
}
public class H:G
{
new public int x = 20;
}
public class I:H
{
new public int x = 30;
public int m1()
{
// (this as <classname >) will use for accessing data to base class
int z = (this as I).x + base.x + (this as G).x + (this as F).x + (this as E).x; // base.x refer to H
return z;
}
}
}

Override method from instance of the class

I have a merly simple question, but seems cant find an answer for it, I want to know if its possible to override a method from a instance class structore would look like this:
public class A : baseA
{
public virtual void methodA()
{
}
}
public class B : baseB
{
public void method B()
{
var ClassA = new A();
}
/* Now Is there some sort of overide like */
public override methodA()
{
//Do stuff
}
}
And those classes do not inherit from each other, to make it more difficult.
Now if this sort of construction is possible in c#?
No. You cannot override a class's behavior if you don't inherit from it.
The override modifier is required to extend or modify the abstract or virtual implementation of an inherited method, property, indexer, or event.
Class B must inherit from class A in order to do so.
public class A
{
public virtual void methodA()
{
}
}
public class B : A
{
public void methodB()
{
var ClassA = new A();
}
public override void methodA()
{
//Do stuff
}
}
Check MSDN for more details:
An override method provides a new implementation of a member that is inherited from a base class. The method that is overridden by an override declaration is known as the overridden base method. The overridden base method must have the same signature as the override method

Is it possible to override a base method with a more specific (by return type) method?

I have classes like this.
public class Base{
public virtual Base Clone(){ ...... }
}
public class Derived:Base{
public Derived Clone(){ ...... }
private override Base Clone(){ return Clone(); }
}
This code, of course, gives me some compile errors, one saying there are two Clone() methods in Derived class and the other saying that overriding method must be in the same accessibility level as the overridden one.
Now, since the Derived.Clone() method which overrides Base.Clone() is never needed directly, I'd like to hide it with the more specific Derived.Clone() method which returns a Derived object. I know this can be done in C# with interfaces, but is it possible to do the same with classes?
Not in the way you show. A common approach is to introduce an extra method for the implementation:
public class Base
{
public Base Clone() { return CloneImpl(); }
protected virtual Base CloneImpl() { ... }
}
public class Derived : Base
{
public new Derived Clone() { ... }
protected override Base CloneImpl() { return Clone(); }
}
This then satisfies all expectations of polymorphism, substitution, etc.
To go a little further on the answer of Marc which is in basis what you need, I would change the signature of the internal method:
public class Base
{
public Base Clone()
{
Base b = new Base();
CloneImpl(b);
return b;
}
protected virtual void CloneImpl(Base b) { ... }
}
public class Derived : Base
{
public new Derived Clone()
{
Derived d = new Derived();
this.CloneImpl(d);
return d;
}
protected override void CloneImpl(Base b)
{
Derived d = b as Derived;
...
base.CloneImpl(d);
}
}
In this way the internal method can do the work for the type itself and let the base class do the part they have in common.

Overriding class method via a wrapper class

I'm trying to come up with a very neat way to alter an existing class. I'll try to explain what I came up with using this example;
abstract class AbstractX
{
public abstract string X();
protected internal abstract int Y();
}
// Execute all methods on another instance of AbstractX
// This is why the method(s) are 'protected *internal*'
class WrappedX : AbstractX
{
AbstractX _orig;
public WrappedX(AbstractX orig)
{
_orig = orig;
}
public override string X()
{
return _orig.X();
}
protected internal override int Y()
{
return _orig.Y();
}
}
// The AbstractX implementation I start with
class DefaultX : AbstractX
{
public override string X()
{
// do stuff
// call Y, note that this would never call Y in WrappedX
var y = Y();
return y.ToString();
}
protected internal override int Y()
{
return 1;
}
}
// The AbstractX implementation that should be able to alter *any* other AbstractX class
class AlteredX : WrappedX
{
public AlteredX(AbstractX orig)
:base(orig)
{
}
protected internal override int Y()
{
Console.WriteLine("Sweet, this can be added to any AbstractX instance!");
return base.Y();
}
}
Right, so the way I intend to use this is;
AbstractX x = new DefaultX();
x = new AlteredX(x);
Console.WriteLine(x.X()); // Should output 2 lines
Or to step away from the abstract example for a second and make it more concrete (should be self-explanatory);
FileWriterAbstract writer = new FileWriterDefault("path/to/file.ext");
writer = new FileWriterSplit(writer, "100MB");
writer = new FileWriterLogged(writer, "path/to/log.log");
writer.Write("Hello");
But (back to the abstract example) this isn't going to work. The moment AlteredX.X() is called (which isn't overridden) it goes to WrappedX.X(), which of course runs DefaultX.X() which uses it's own Y() method, and not the one I defined in AlteredX. It doesn't even know it exists.
I'm hoping it's obvious why I want this to work, but I'll explain further to make sure;
If I don't use WrappedX to created AlteredX, AlteredX will not be 'applyable' to any AbstractX instance,
thus making something like the FileWriter above impossible. Instead of;
FileWriterAbstract
FileWriterDefault : FileWriterAbstract
FileWriterWrap : FileWriterAbstract
FileWriterSplit : FileWriterWrap
FileWriterLogged : FileWriterWrap
It would become;
FileWriterAbstract
FileWriterDefault : FileWriterAbstract
FileWriterSplit : FileWriterDefault
// Implement Logged twice because we may want to use it with or without Split
FileWriterLogged : FileWriterDefault
FileWriterLoggedSplit : FileWriterSplit
And if I then created a new one, I'd have to implement it 4 times because I'd want it usable with;
Default
Split
Logged
Split+Logged
And so on...
So with that in mind, what's the best way to achieve this? The best I could come up with (untested) is;
class DefaultX : AbstractX
{
protected internal override Func<string> xf { get; set; }
protected internal override Func<int> yf { get; set; }
public DefaultX()
{
xf = XDefault;
yf = YDefault;
}
public override string X()
{
return xf();
}
protected override int Y()
{
return yf();
}
string XDefault()
{
var y = Y();
return y.ToString();
}
int YDefault()
{
return 1;
}
}
class AlteredX : WrappedX
{
Func<int> _yfOrig { get; set; }
public AlteredX()
{
// I'm assuming this class member doesn't get overwritten when I set
// base.yf in the line below.
_yfOrig = base.yf;
base.yf = YAltered;
}
private int YAltered()
{
Console.WriteLine("Sweet, this can be added to any AbstractX instance!");
return yfOrig();
}
}
Even if this does work, it seems really messy... does anyone have any suggestions?
One way to handle this would be to defer all of the internal operations to a separate, perhaps, internal utility class and provide a way for the wrapping classes to replace the implementation of the utility class. Note: this example requires any concrete, non-wrapping class to implement the utility class. A wrapper class may or may not choose to wrap the utility class. The key here is that the getter/setter for the utilities class in the base (abstract) class doesn't allow it to be overridden, thus every inheriting class uses the utility class as defined by it's constructor. If it chooses not to create it's own utilities, it defaults to that of the class it's wrapping - eventually making it all the way back to the concrete, non-wrapped composition root class if need be.
NOTE: this is very complex and I would avoid doing it. If possible use the standard decorator and only rely on public interface methods of the wrapped class. Also, the utility classes need not be inner classes. They could be injected via the constructor which might make it a bit cleaner. Then you would explicitly use the Decorator pattern on the utilities as well.
public interface IFoo
{
string X();
}
public abstract class AbstractFoo : IFoo
{
public abstract string X();
protected internal Footilities Utilities { get; set; }
protected internal abstract class Footilities
{
public abstract int Y();
}
}
public class DefaultFoo : AbstractFoo
{
public DefaultFoo()
{
Utilities = new DefaultFootilities();
}
public override string X()
{
var y = Utilities.Y();
return y.ToString();
}
protected internal class DefaultFootilities : Footilities
{
public override int Y()
{
return 1;
}
}
}
public abstract class AbstractWrappedFoo : AbstractFoo
{
protected readonly AbstractFoo Foo;
public AbstractWrappedFoo(AbstractFoo foo)
{
Foo = foo;
}
public override string X()
{
return Foo.X();
}
}
public class LoggedFoo : AbstractWrappedFoo
{
public LoggedFoo(AbstractFoo foo)
: base(foo)
{
Foo.Utilities = new LoggedUtilities(Foo.Utilities);
}
public override string X()
{
return Foo.X();
}
protected internal class LoggedUtilities : Footilities
{
private readonly Footilities _utilities;
public LoggedUtilities(Footilities utilities)
{
_utilities = utilities;
}
public override int Y()
{
Console.WriteLine("Sweet");
return _utilities.Y();
}
}
}
Now, this program
class Program
{
static void Main(string[] args)
{
AbstractFoo foo = new LoggedFoo(new DefaultFoo());
Console.WriteLine(foo.X());
}
}
Produces
Sweet!
1
I think you mixed up composition with inheritance.
When you call x.X() on an AlteredX object, the object calls X method of it's base object (WrappedX). The base object itself calls an object of type DefaultX which it has already wrapped. Now the Y method is called on an an object of DefaultX (_orig). You expect _orig knows there is something overriden in the caller of the caller! But how?
In this chain of call I don't see any point where overriding the method Y is involved.

Why do we use virtual and override?

Why do we use override and virtual if it gives the same effect when we dont use override and virtual?
example 1:
class BaseClass
{
public virtual string call()
{
return "A";
}
}
class DerivedClass : BaseClass
{
public override string call()
{
return "B";
}
}
output : B
Example 2:
class BaseClass
{
public string call()
{
return "A";
}
}
class DerivedClass : BaseClass
{
public string call()
{
return "B";
}
}
and the output is still the same:
output : B
to run the test:
class Program
{
static void Main(string[] args)
{
DerivedClass dc = new DerivedClass();
Console.WriteLine(dc.call());
Console.ReadKey();
}
}
Does the compiler add virtual and override automatically at compile time?
I would be pleased if someone would explain to me the reason for using virtual and override.
(note, I'm quietly ignoring the compile errors)
Now do:
BaseClass obj = new DerivedClass();
Console.WriteLine(obj.call());
Without virtual, this will print A, when actually a DerivedClass should be writing B. This is because it has simply called the BaseClass implementation (since obj is typed as BaseClass, and no polymorphism is defined).
Virtual and override are a base mechanism of inheritance in object oriented programming.
This is perhaps the most important thing to understand when you use classes in a language like C# or Java.
http://en.wikipedia.org/wiki/Inheritance_(object-oriented_programming)
Inheritance allow you to reuse code adding new fields, properties and methods or replacing methods and properties of previously defined classes.
Virtual and Override allow you to replace the content of a method, and when i say replace, i say replace.
I would propose you a nice example.
public class MyClassEnglish
{
public virtual string SomethingToSay()
{
return "Hello!";
}
public void WriteToConsole()
{
Console.WriteLine(this.SomethingToSay());
}
}
public class MyClassItalian :
MyClassEnglish
{
public override string SomethingToSay()
{
return "Ciao!";
}
}
int main()
{
MyClassItalian it = new MyClassItalian();
it.WriteToConsole();
}
If you omit virtual and override, MyClassItalian will print out "Hello!" and not "Ciao!".
In your example you show a Shadowing technique, but the compiler should give you a warning.
You shoul add the "new" keyword if you want to hide a method in a base class.
Hiding a method is not overriding! Is just hiding.
One possible use that comes into my mind is that it can be used when you need some kind of optimization for example.
public abstract class MySpecialListBase
{
public int Count()
{
return this.GetCount();
}
protected abstract int GetCount();
}
public sealed class MySpecialArrayList : MySpecialListBase
{
int count;
public new int Count()
{
return this.count;
}
protected override int GetCount()
{
return this.count;
}
}
Now...
You can use MySpecialListBase in all your code, and when you call the Count() it will call the virtual method GetCount().
But if you use just MySpecialArrayList it will call the optimized Count() that is not virtual and that just return a field, increasing performances.
// This works with all kind of lists, but since it is a more general purpose method it will call the virtual method.
public void MyMethod(MySpecialListBase list)
{
Console.WriteLine(list.Count());
}
// This works only with MySpecialArrayList, and will use the optimized method.
public void MyMethod(MySpecialArrayList list)
{
Console.WriteLine(list.Count());
}
Best example I can think of where this is useful is when you create your own object(class) and you have to add a list of that object to a combobox.
When you add your object to the combobox you want to be able to control what text is displayed for each item. Object.toString is a virtual method. http://msdn.microsoft.com/en-us/library/system.object.tostring.aspx and because of this you can override that method and set .toString to display the correct information about your object by overriding it.
public MyClass()
{
private int ID;
public override string ToString()
{
return "My Item:" + ID;
}
}
Method Overriding:
Where you define or implement a virtual method in a parent class and then replace it in a descendant class.
When you decide to declare a method as virtual, you are giving permission to derived classes to extend and override the method with their own implementation. You can have the extended method call the parent method's code too.
In most OO languages you can also choose to hide a parent method. When you introduce a new implementation of the same named method with the same signature without overriding, you are hiding the parent method.
C# Overriding
In C#, you specify a virtual method with the virtual keyword in a parent class and extend (or replace) it in a descendant class using the override keyword.
Use the base keyword in the descendant method to execute the code in the parent method, i.e. base.SomeMethod().
Syntax Example:
class Robot
{
public virtual void Speak()
{
}
}
class Cyborg:Robot
{
public override void Speak()
{
}
}
Override Details
You cannot override a regular non-virtual method, nor a static method.
The first version of the parent method must be virtual or abstract.
You can override any parent method marked virtual, abstract, or override (already overridden).
The methods must have the same signature.
The methods must have the same visibility (the same access level).
Use the base keyword to refer to the parent class as in base.SomeMethod().
C# Override Example
The following code snippet demonstrates using virtual and override to override a parent method in a descendant class.
using System;
class Dog
{
public virtual void Bark()
{
Console.WriteLine("RUFF!");
}
}
class GermanShepard:Dog
{
public override void Bark()
{
Console.WriteLine("Rrrrooouuff!!");
}
}
class Chiuaua:Dog
{
public override void Bark()
{
Console.WriteLine("ruff");
}
}
class InclusionExample
{
public static void Main()
{
Dog MyDog=new Dog();
MyDog=new GermanShepard();
MyDog.Bark(); // prints Rrrrooouuff!!
MyDog=new Chiuaua();
MyDog.Bark(); // prints ruff;
}
}
Hiding a Method with New
Use the new keyword to introduce a new implementation of a parent method (this hides the parent method). You can hide a method without using new but you will get a compiler warning. Using new will suppress the warning.
The new and override modifiers have different meanings. The new modifier creates a new member with the same name, signature, and visibility and hides the original member. The override modifier extends the implementation for an inherited member and allows you to implement inheritance-based polymorphism.
Avoid Introducing New Members: Sometimes there are clear reasons to introduce a new method with the same name, signature, and visibility of a parent method. In those clear cases, introducing a new member is a powerful feature. However, if you do not have a clear reason, then avoid introducing a new version of a method by naming the new method something unique and appropriate.
class Robot : System.Object
{
public void Speak()
{
MessageBox.Show("Robot says hi");
}
}
class Cyborg : Robot
{
new public void Speak()
{
MessageBox.Show("hi");
}
}
Calling the Base Class Version
A common task In OO is to extend a method by first executing the parent method code and then adding code. Use the base keyword to refer to the parent class as in base.SomeMethod().
class Robot : System.Object
{
public virtual void Speak()
{
MessageBox.Show("Robot says hi");
}
}
class Cyborg : Robot
{
public override void Speak()
{
base.Speak();
MessageBox.Show("hi");
}
}

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