I have a list of strings like
[ABC].[XXX].sdfnwoaenwaf
[ABC].[XXX].sdfnwoaenwaf
[ABC].[XX1].sdfnwoaenwaf
[ABC].[XX1].sdfnwoaenwaf
[AB1].[XX3].sdfnwoaenwaf
[AB2].[XX1].sdfnwoaenwaf
How can I get everything before the second dot? e.g. [ABC].[XXX] for the first one.
(.*)\. is the regex you need. You may test on http://regexhero.net/tester/
You could try a regex or use the LastIndexOf method of the String class or the Split method of the String class.
Regex
var toMatch = "[ABC].[XXX].sdfnwoaenwaf";
var pattern = new Regex("(.*?\\..*?)(:?\\.)");
var beforeSecondDot = pattern.Match(toMatch);
var stringBeforeSecondDot = beforeSecondDot.Groups[1].Value;
String.LastIndexOf
var toMatch = "[ABC].[XXX].sdfnwoaenwaf";
var indexOfLastDot = toMatch.LastIndexOf('.');
var beforeSecondDot = toMatch.Substring(0, indexOfLastDot);
String.Split
var toMatch = "[ABC].[XXX].sdfnwoaenwaf";
var parts = toMatch.Split('.');
var beforeSecondDot = String.Join(".", parts.Take(2));
string x = "[AB2].[XX1].sdfnwoaenwaf";
Regex regex = new Regex("([^.]+\\.[^.]+)\\.");
Match match = regex.Match(x);
if (match.Success)
{
Console.WriteLine(match.Groups[1].Value);
}
Output:
[AB2].[XX1]
List<string> finalStrings = new List<string>();
List<string> strings = new List<string>();
strings.Add("[ABC].[XXX].sdfnwoaenwaf");
strings.Add("[ABC].[XXX].sdfnwoaenwaf");
strings.Add("[ABC].[XX1].sdfnwoaenwaf");
strings.Add("[ABC].[XX1].sdfnwoaenwaf");
strings.Add("[ABC].[XX3].sdfnwoaenwaf");
strings.Add("[ABC].[XX1].sdfnwoaenwaf");
foreach (var item in strings)
{
Regex rex = new Regex("(.*)\\.");
string[] y = rex.Split(item);
finalStrings.Add(y[1]);
}
Related
I have a string looking something like this:
/Gender=&Age=&Query=&Orgrimmar+l%C3%A4n=01&Stormwind+l%C3%A4n=07&Undercity+l%C3%A4n=09&Pag
I want a list of string with "Orgrimmar", "Stormwind" and "Undercity". How is this possible so that it splits AFTER Query and between & and + in order so that we avoid getting a string like this "Orgrimmar+l%C3%A4n=01&Stormwind".
Let us assume that we don't know the name of the strings.. :)
Updated, i still don't seem to get it to work. I have added a list of counties that i can use to validate this. However i still find it hard in this case. countyList is used to validate that the counties/cities in the url matches a pre-existing Collection.
var countyQuery = Request.Url.Query;
var counties = this._locationService.GetAllCounties();
List<string> countyList = new List<string>();
List<string> selectedCountiesList = new List<string>();
foreach (var i in counties)
{
countyList.Add(i.Name);
}
Regex r = new Regex(#"&(.+?)\+");
MatchCollection mc = r.Matches(countyQuery);
foreach (Match curMatch in mc)
{
if (countyList.Contains(curMatch.Groups[1].Value))
{
selectedCountiesList.Add(curMatch.Groups[1].Value);
}
}
return selectedCountiesList;
Changed url to be/?Gender=&Age=&Query=&county=13&county=08&county=01&Page=1
where 13, 08, 01 and so on is Id of the counties
The final solution was:
var selectedCountyQuery = Request.QueryString
//CountySearch = "county"
[QueryStringParameters.CountySearch];
List countyList = new List();
List<string> selectedCounties = new List<string>();
if (!string.IsNullOrEmpty(selectedCountyQuery))
{
var selectedCountiesArray = selectedCountyQuery.Split(new[]{ ',' });
foreach (var selectedCounty in selectedCountiesArray)
{
selectedCounties.Add(selectedCounty);
}
}
return selectedCounties;
You can get all parameter and value with Substring() and Split() method.
Example :
var URL = "controller/method?var1=&var2=&var3=dsgdf";
var ParameterPart = URL.Split("?")[1];
var ParametersArray = ParameterPart.Split("&");
//output : ["var1=","var2=","var3=dsgdf"];
foreach(var Parameter in ParametersArray)
{
var ParameterName= Parameter.Split("=")[0];
var ParameterValue= Parameter.Split("=")[1];
}
You can use a regex and extract the matches:
Regex r = new Regex(#"&(.+?)\+");
MatchCollection mc = r.Matches(s);
Then you can itterate your desired strings (in this case wow cities) like:
foreach(Match curMatch in mc)
{
Console.WriteLine(curMatch.Groups[1].Value);
}
string[] numbers ={ "/Gender=&Age=&Query=&Orgrimmar+l%C3%A4n=01&Stormwind+l%C3%A4n=07&Undercity+l%C3%A4n=09&Pag"};
string sPattern = #"(?<=&Orgrimmar)+";
foreach (string s in numbers){
if (System.Text.RegularExpressions.Regex.IsMatch(s, sPattern)){
System.Console.WriteLine(" - valid");}
else{System.Console.WriteLine(" - invalid");}
Output: valid
string[] numbers ={ "/Gender=&Age=&Query=Orgrimmar+l%C3%A4n=01&Stormwind+l%C3%A4n=07&Undercity+l%C3%A4n=09&Pag"};
Output: invalid
Further to check two parameters:
string[] numbers ={ "/Gender=&Age=&Query=&Orgrimmar+l%C3%A4n=01&Stormwind+l%C3%A4n=07&Undercity+l%C3%A4n=09&Pag"};
string sPattern = #"(?<=&Orgrimmar)+";
string sPattern2 = #"(?<=&Stormwind)+";
foreach (string s in numbers){
if (System.Text.RegularExpressions.Regex.IsMatch(s, sPattern) && System.Text.RegularExpressions.Regex.IsMatch(s, sPattern2))
...
I am trying to extract the digits from 10:131186; and get 10131186 without the : and ;.
What is the Regex pattern I need to create?
var input = "10:131186;";
string pattern = ":(.*);";
Match m = Regex.Match(input, pattern);
Console.WriteLine(m.Value);
With the above code, I am getting :131186; instead of 10121186.
Why you need to use Regex. It's slower than using string.Replace method
string input = "10:131186;";
input = input.Replace(":", "");
input = input.Replace(";", "");
Console.WriteLine(input);
You can try using Regex.Replace:
var input = "10:131186;";
string pattern = #"(\d+):(\d+);";
string res = Regex.Replace(input, pattern, "$1$2");
Console.WriteLine(res);
and you can also use Split with Join:
var input = "10:131186;";
Console.WriteLine(string.Join("", input.Split (new char[] { ':', ';' }, StringSplitOptions.RemoveEmptyEntries)));
Please try this..
string input = "10:131186;";
input = input.Replace(":", String.Empty).Replace(";", string.Empty);
Just print the group index 1.
var input = "10:131186;";
string pattern = ":(.*);";
Match m = Regex.Match(input, pattern);
Console.WriteLine(m.Value[1]);
or use assertions.
var input = "10:131186;";
string pattern = "(?<=:).*?(?=;)";
Match m = Regex.Match(input, pattern);
Console.WriteLine(m.Value);
You could use the pattern \\d+ to match digits in the string and concatenate them into a single string.
using System;
using System.Text;
using System.Text.RegularExpressions;
public class Program
{
public static void Main()
{
string input = "10:131186;";
MatchCollection mCol = Regex.Matches(input, "\\d+");
StringBuilder sb = new StringBuilder();
foreach (Match m in mCol)
{
sb.Append(m.Value);
}
Console.WriteLine(sb);
}
}
Results:
10131186
Demo
I have following code that works if the search text and the items in the list are of same case (lower case / upper case). If there is a mixed casing it is not working,. How can we make it case insensitive search.
var text = "c";
var myStrings = new List<string>() { "Aa", "ACB", "cc" };
var regEx = new System.Text.RegularExpressions.Regex(text);
var results = myStrings
.Where<string>(item => regEx.IsMatch(item))
.ToList<string>();
EDIT :
I need to pass that string with Case Insensitive to the method how can i do that ...
public ActionResult GetItems(string text)
{
ContextObject contextObject = new ContextObject();
TransactionHistory transactionhistory = new TransactionHistory();
System.Text.RegularExpressions.Regex regEx = new System.Text.RegularExpressions.Regex(text, RegexOptions.IgnoreCase);
var items = transactionhistory.GetItems(contextObject, text);
return Json(items, JsonRequestBehavior.AllowGet);
}
Try to declare your regex like this
Regex regEx = new Regex(text, RegexOptions.IgnoreCase);
you need to use the overload which takes RegexOptions.IgnoreCase
Example
RegexOptions options = RegexOptions.IgnoreCase | RegexOptions.Compiled;
System.Text.RegularExpressions.Regex regEx = new System.Text.RegularExpressions.Regex(text, options);
EDIT:
RegexOptions options = RegexOptions.IgnoreCase | RegexOptions.Compiled;
var text = "c";
var myStrings = new List<string>() { "Aa", "ACB", "cc" };
var regEx = new System.Text.RegularExpressions.Regex(text, options);
var results = myStrings
.Where<string>(item => regEx.IsMatch(item))
.ToList<string>();
//you will have 2 items in results
foreach(string s in results)
{
GetItems(s);
}
Based in your code, why using a regex? I would use a regex only with complex text patterns. In this case is way easier to use string.IndexOf() like in
var text = "c";
var myStrings = new List<string>() { "Aa", "ACB", "cc" };
var results = myStrings
.Where(item => item.IndexOf(text, StringComparison.CurrentCultureIgnoreCase) >= 0)
.ToList();
I have al removed the explicit use of string in where and toList as it is applied by default.
How do I split the following string
string s = "username=bill&password=mypassword";
Dictionary<string,string> stringd = SplitTheString(s);
such that I could capture it as follows:
string username = stringd.First().Key;
string password = stringd.First().Values;
Please let me know. Thanks
You can populate the dictionary list like so:
Dictionary<string, string> dictionary = new Dictionary<string, string>();
string s = "username=bill&password=mypassword";
foreach (string x in s.Split('&'))
{
string[] values = x.Split('=');
dictionary.Add(values[0], values[1]);
}
this would allow you to access them like so:
string username = dictionary["username"];
string password = dictionary["password"];
NOTE: keep in mind there is no validation in this function, it assumes your input string is correctly formatted
It looks like you are trying to parse a query string - this is already built in, you can use HttpUtility.ParseQueryString() for this:
string input = "username=bill&password=mypassword";
var col = HttpUtility.ParseQueryString(input);
string username = col["username"];
string password = col["password"];
I think something similar to this should work
public Dictionary<string, string> SplitTheStrings(s) {
var d = new Dictionary<string, string>();
var a = s.Split('&');
foreach(string x in a) {
var b = x.Split('=');
d.Add(b[0], b[1]);
}
return d;
}
var splitString = "username=bill&password=pass";
var splits = new char[2];
splits[0] = '=';
splits[1] = '&';
var items = splitString.Split(splits);
var list = new Dictionary<string, string> {{items[1], items[3]}};
var username = list.First().Key;
var password = list.First().Value;
this my also work
If Keys will not repeat
var dict = s.Split('&').Select( i=>
{
var t = i.Split('=');
return new {Key=t[0], Value=t[1]};}
).ToDictionary(i=>i.Key, i=>i.Value);
If Keys can repeat
string s = "username=bill&password=mypassword";
var dict = s.Split('&').Select( i=>
{
var t = i.Split('=');
return new {Key=t[0], Value=t[1]};}
).ToLookup(i=>i.Key, i=>i.Value);
The other answers are better, easier to read, simpler, less prone to bugs, etc, but an alternate solution is to use a regular expression like this to extract all the keys and values:
MatchCollection mc = Regex.Matches("username=bill&password=mypassword&","(.*?)=(.*?)&");
Each match in the match collection will have two groups, a group for the key text and a group for the value text.
I am not too good at regular expressions so I don't know how to get it to match without adding the trailing '&' to the input string...
Is there (.NET 3.5 and above) already a method to split a string like this:
string str = "{MyValue} something else {MyOtherValue}"
result: MyValue , MyOtherValue
Do like:
string regularExpressionPattern = #"\{(.*?)\}";
Regex re = new Regex(regularExpressionPattern);
foreach (Match m in re.Matches(inputText))
{
Console.WriteLine(m.Value);
}
System.Console.ReadLine();
dont forget to add new namespace: System.Text.RegularExpressions;
You can use regular expressions to do it. This fragment prints MyValue and MyOtherValue.
var r = new Regex("{([^}]*)}");
var str = "{MyValue} something else {MyOtherValue}";
foreach (Match g in r.Matches(str)) {
var s = g.Groups[1].ToString();
Console.WriteLine(s);
}
MatchCollection match = Regex.Matches(str, #"\{([A-Za-z0-9\-]+)\}", RegexOptions.IgnoreCase);
Console.WriteLine(match[0] + "," + match[1]);
Something like this:
string []result = "{MyValue} something else {MyOtherValue}".
Split(new char[]{'{','}'}, StringSplitOptions.RemoveEmptyEntries)
string myValue = result[0];
string myOtherValue = result[2];