I'm trying to write the largest int64 value to the command line. I tried using 0x1111111111111111 which is 16 ones, and visual studio says that is int64. I would have assumed that would be int16. What am missing here?
0x is the prefix for hexadecimal and not binary literals. This means that the binary representation of your number is 0001000100010001000100010001000100010001000100010001000100010001
There are unfortunately no binary literals in C#, so you either have to do the calculation yourself (0x7FFFFFFFFFFFFFFF) or use the Convert class, for example:
short s = Convert.ToInt16("1111111111111111", 2); // "2" for binary
In order to just get the largest Int64 number, you don't need to perform any calculations of your own, as it is already available for you in this field:
Int64.MaxValue
The literal 0x1111111111111111 is a hexadecimal number. Each hexadecimal digit can be represented using four bits so with 16 hexadecimal digits you need 4*16 = 64 bits. You probably intended to write the binary number 1111111111111111. You can convert from a binary literal string to an integer using the following code:
Convert.ToInt16("1111111111111111", 2)
This will return the desired number (-1).
To get the largest Int64 you can use Int64.MaxValue (0x7FFFFFFFFFFFFFFF) or if you really want the unsigned value you can use UInt64.MaxValue (0xFFFFFFFFFFFFFFFF).
The largest Int64 value is Int64.MaxValue. To print this in hex, try:
Console.WriteLine(Int64.MaxValue.ToString("X"));
Related
I am wondering how you take a number (for example 9), convert it to a 32 int (00000000000000000000000000001001), then invert or flip every bit (11111111111111111111111111110110) so that the zeroes become ones and the ones become zeroes.
I know how to do that by replacing the numbers in a string, but I need to know how to do that with binary operators on a binary number.
I think you have to use this operator, "~", but it just gives me a negative number when I use it on a value.
That is doing the correct functionality. The int data type within C# uses signed integers, so 11111111111111111111111111110110 is in fact a negative number.
As Marc pointed out, if you want to use unsigned values declare your number as a uint.
If you look at the decimal version of your number then its a negative number.
If you declare it as a unsigned int then its a positive one.
But this doesnt matter, binary it will always be 11111111111111111111111111110110.
Try this:
int number = 9;
Console.WriteLine(Convert.ToString(number, 2)); //Gives you 1001
number = ~number; //Invert all bits
Console.WriteLine(Convert.ToString(number, 2));
//Gives you your wanted result: 11111111111111111111111111110110
I want to display a three bytes (signed) in C#.
The code (fragment) I made is:
case 3:
HexadecimalValueRange = SignedValueChecked ?
string.Format("{0:X6}..{1:X6}", (Int32) minValue, (Int32) maxValue)
: string.Format("{0:X6}..{1:X6}", (UInt32)minValue, (UInt32)maxValue);
But it displays an example negative value as 0xFFC00000 where I would like to see 0xC000000, so with 6 'significant' digits (thus without the leading FF).
The leading bits of negative number are significant, so you can't cut the off with String.Format (there is no specifier that let you ignore significant digits, width specify only minimum size and left/right justification).
You can convert the values to 3-byte uint to print them the way you want:
string.Format("{0,-6:X}",(uint)(int.MaxValue & 0xFFFFFF))
Trying to convert the following value:
9.40551020088303E+21
to
9405510200883031584406
I am a but lost on how to do this? Math.Round, (int)Value.
Edit: Ok i may be wrong here, but i am trying to convert this to 9405510200883031584406 in anyway possible, it can be a string, or different type.
The final result is a tracking number and what i am starting with is what the shipping company provides me with.
the closest thing I can think of is using BigInteger
double d = 9.40551020088303E+21;
BigInteger bi = new BigInteger(d);
Console.WriteLine(bi.ToString());
Output would be:
9405510200883030261760
What you're describing isn't possible. An int (Int32) data type has a maximum value of 2147483647.
the long (Int64) data type, can only go up to 9,223,372,036,854,775,807
an unsigned long (UInt64) can go to 18,446,744,073,709,551,615
The number is simply too large for any of those data types.
9,405,510,200,883,031,584,406 (Your value)
9,223,372,036,854,775,807 (Int64.MaxValue)
18,446,744,073,709,551,615 (UInt64.MaxValue)
If you just want to convert this to a string as in your question it can be a string, or different type. Than this should suffice.
decimal value = 9405510200883031584406m;
string str = value.ToString("F0");
However, this assumes you know the actual full number. You can't convert 9.40551020088303E+21 to a more precise value, if you don't know the trailing digits.
You can see how to format in Standard Numeric Format Strings
The fixed-point ("F) format specifier converts a number to a string of
the form "-ddd.ddd…" where each "d" indicates a digit (0-9). The
string starts with a minus sign if the number is negative. The
precision specifier indicates the desired number of decimal places. If
the precision specifier is omitted, the current
NumberFormatInfo.NumberDecimalDigits property supplies the numeric
precision.
problem is to convert a string of binary digits into its decimal representation. Easy eh?
well, it needs to be able to handle input of over 64 bits in length and convert it without using any external libraries or data types like big integer.
How can I do this?
so far i have a string called input which handles the binary
I then access each digit using input[0] etc to get a char representing that digit.
Now I manipulate it and multiply by the corresponding power of 2 that its index represents, and move through the array storing the total as i go.
I use a big integer to store the total as for large numbers the primative types dont work.
My first solution works perfectly, how can I do this without using anything to store the total, i.e only using strings to store answers.
Any Ideas?
Thanks
You will need an array of digits to hold the result. An array of int's would be easier but you can also use the final string. You can calculate it's length from the length of the inputstring, you may have to remove leading zero's in the end.
Calculate your result as before but do the adding (including the carrying) in the result array.
I think this is a (homework) assignment that wants you to implement a version of the "pen & paper" addition method.
In C language octal number can be written by placing 0 before number e.g.
int i = 012; // Equals 10 in decimal.
I found the equivalent of hexadecimal in C# by placing 0x before number e.g.
int i = 0xA; // Equals 10 in decimal.
Now my question is:
Is there any equivalent of octal number in C# to represent any value as octal?
No, there are no octal number literals in C#.
For strings: Convert.ToInt32("12", 8) returns 10.
No there isn't, the language specification (ECMA-334) is quite specific.
4th edition, page 72
9.4.4.2 Integer literals
Integer literals are used to write values of types int, uint, long,
and ulong. Integer literals have two possible forms: decimal and
hexadecimal.
No octal form.
No, there are no octal literals in C#.
If necessary, you could pass a string and a base to Convert.ToInt32, but it's obviously nowhere near as nice as a literal:
int i = Convert.ToInt32("12", 8);
No, there are no octal numbers in C#.
Use public static int ToInt32(string value, int fromBase);
fromBase
Type: System.Int32
The base of the number in value, which must be 2, 8, 10, or 16.
MSDN
You can't use literals, but you can parse an octal number: Convert.ToInt32("12", 8).