The XML I am getting is provided by an outside source so I don't have the ability to easily reformat it. I would like to use xml attributes on my entities instead of having to write a linq query that knows how the XML and entity is formatted. Here is an example:
<?xml version="1.0"?>
<TERMS>
<TERM>
<ID>2013-2</ID>
<DESC>Spring 2013</DESC>
</TERM>
<TERM>
<ID>2013-3</ID>
<DESC>Summer 2013 Jun&Jul</DESC>
</TERM>
</TERMS>
I know the the XMLSerializer expects ArrayOfTerm instead of TERMS for example, but that I can tweak my entity to use a different element name with the xml attributes such as this:
public class TermData
{
[XmlArray("TERMS")]
[XmlArrayItem("TERM")]
public List<Term> terms;
}
public class Term
{
[XmlElement("ID")]
public string id;
[XmlElement("DESC")]
public string desc;
}
and I am deserializing the data like so:
TermData data;
XmlSerializer serializer = new XmlSerializer(typeof(TermData));
using (StringReader reader = new StringReader(xml))
{
data = (TermData)serializer.Deserialize(reader);
}
return View(data.terms);
The problem I am facing is that TERMS is the root and the array itself. If the XML were to have a root element that was not the array, I could edit my TermData class like so and it would deserialize correctly (already tested).
[XmlRoot("ROOT")]
public class TermData
{
[XmlArray("TERMS")]
[XmlArrayItem("TERM")]
public List<Term> terms;
}
Note that using TERMS as the XMLRoot does not work. Right now, my code is throwing
InvalidOperationException: There is an error in XML document (2,2).
InnerException: "<TERMS xmlns=" was not expected.
This would lead me to believe that the XML is not formatted correctly, but from my understanding the example I gave is perfectly valid XML.
This would all be trivial if I could edit the source xml, but there could be tons of other responses like this and I need to be able to flex for whatever I might get. What I'm trying to confirm is whether or not the XMLSerializer can support this type of XML structure. I've tested just about everything and can't get it deserialize without editing the XML. It would also be convenient if I didn't have to define a wrapper class (TermData) to hold the list, but this seems to only work if the xml follows the naming conventions for the serializer (ArrayOfTerm, etc).
Maybe you can try :
[XmlRoot("TERMS")]
public class TermData
{
public TermData()
{
terms = new List<Term>();
}
[XmlElement("TERM")]
public List<Term> terms{get;set;}
}
public class Term
{
[XmlElement("ID")]
public string id{get;set;}
[XmlElement("DESC")]
public string desc{get;set;}
}
Hope this will help,
Related
I want to serialize a list to xml (from a web-api method).
public class Result
{
public List<string> Users { get; set; }
}
So I get for example:
<result>
<user>Paul</user>
<user>David</user>
<user>Joan</user>
</result>
So far, I get:
<result>
<users>
<user>Paul</user>
<user>David</user>
<user>Joan</user>
</users>
</result>
How do I tell the serialization not to wrap the user list in a "users" tag?
Thanks.
You could either derive from XmlObjectSerializer and implement your own XML Serializer (see here FMI) or else manipulate your type so it works with the default formatter. Which isn't a great solution, but may work for a simple example, like so:
public class Result : List<User>
{
//Any user added to Result will be nested directly within Result in the XML
}
Further reading:
MSDN: XmlObjectSerializer Class:
"Extend the XmlObjectSerializer to create your own serializer to serialize and deserialize objects."
Insights on WCF: CustomXmlObjectSerializer: Real-world example with source code.
You need to replace default DataContractSerializer with XmlSerializer in Application_Start method.
For whole project:
var xml = GlobalConfiguration.Configuration.Formatters.XmlFormatter;
xml.UseXmlSerializer = true;
For specific type:
var xml = GlobalConfiguration.Configuration.Formatters.XmlFormatter;
xml.SetSerializer<Result>(new XmlSerializer(typeof(Result)));
After this you can use attributes to format your xml output:
public class Result
{
[XmlElement("user")]
public List<string> Users { get; set; }
}
I am trying to read XML document.
My XML:
<?xml version="1.0" encoding="utf-8"?>
<SplashScreen xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<Path>SplashScreen/Image-King</Path>
</SplashScreen>
My code which is reading XML:
XmlGameScreen = new XmlManager<GameScreen>();
XmlGameScreen.Type = currentscreen.Type;
currentscreen = XmlGameScreen.Load("LoadXML/SplashScreen.xml");
And
public Type Type;
public T Load(string path)
{
T instance;
using (TextReader textreader = new StreamReader(path))
{
XmlSerializer xml = new XmlSerializer(Type);
instance = (T)xml.Deserialize(textreader);
}
return instance;
}
I am getting error on instance = (T)xml.Deserialize(textreader); Is my XML document wrong? I am trying to read <Path>.
Update :
My Internal Exception:
Cannot serialize member 'MyRPGgame.SplashScreen._image' of type 'Microsoft.Xna.Framework.Graphics.Texture2D'
In my case it appears one of the Visual Studio 2017 version 15.5 updates caused this error when trying to open SSRS projects. The solution is to delete the *.rptproj.rsuser file from the project folder and try again.
My experience from it would be that in the 2nd line in the 2nd chararacter, there is an error.
have a look if your class names are different from the XML tags. are you maybe changing the "XML Root name" to a different one.
Have a look at the XML structure and which class are you serializing to which node.
Also, read the
MSDN Documentation about the XmlRootAttribute Class.
That usually means you have whitespace at the start of the file; check for a line-break before the <?xml.... Even better: please show the first few bytes (preferably as far as <SplashScreen) of the file as viewed in a binary editor.
It could also mean you have an invisible unicode or control character somewhere before the <SplashScreen
Just wanted to share what worked for me. I had a similar error
System.InvalidOperationException: There is an error in XML document (1, 40).
---> System.InvalidOperationException: <tsResponse xmlns='http://xxxyyyzzzz.com/api'> was not expected.
I was trying to deserialize a string to an object of type tsResponse.
After adding the following attribute [Serializable, XmlRoot(ElementName = "tsResponse", Namespace = "http://xxxyyyzzzz.com/api")] to the class tsResponse i was able to resolve my issue.
[Serializable, XmlRoot(ElementName = "tsResponse", Namespace = "http://xxxyyyzzzz.com/api")]
public class tsResponse
{
[XmlElement]
public CredentialsXml credentials { get; set; }
}
I.e had to add Namespace attribute (System.Xml.Serialization).
Try this: When you are deserializing XML to List just add an extra
line to the start i.e ArrayOfAddressDirectory as follows and don't put any space at start and end of file.
<?xml version="1.0"?>
<ArrayOfAddressDirectory xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<AddressDirectory>
<Owner>MS. Dhoni</Owner>
<Age>48</Age>
<Company>India</Company>
</AddressDirectory>
</ArrayOfAddressDirectory>
Here is the C# code:
namespace XmlReadProgram
{
public class AddressDirectory
{
public string Owner { get; set; }
public string Age { get; set; }
public string Company { get; set; }
}
public class Program
{
static void Main(string[] args)
{
List<AddressDirectory> adlist = new List<AddressDirectory>();
using (FileStream fileStream = File.OpenRead(#"E:\inputDirectory\address.xml"))
{
XmlSerializer serializer = new XmlSerializer(typeof(List<AddressDirectory>));
adlist = (List<AddressDirectory>)serializer.Deserialize(fileStream);
}
//You can use foreach to print all data
Console.WriteLine(adlist[0].Owner);
Console.WriteLine(adlist[0].Age);
Console.WriteLine(adlist[0].Company);
}
}
}
In my case, a property with [XmlArrayAttribute] had the getter accessing a field with [XmlIgnoreAttribute] that was left uninitialized.
The problem in your case it's definitely the confusion between Type and template T. You are trying to construct Serializer with Type --> new XmlSerializer(Type) and then deserialize with template T ----> (T)xml.Deserialize. So the solution is to replace Type in constructing with typeof(T), and this should eliminate the initial XML document problem of (2, 2).
this is my first question on stackoverflow, so this is going to be fun!
I've got the following structure that I want to convert to xml. I need to include all the sub elements from the inner object, without the inner object as a node.
class element1
{
element1.1
{
element1.1.1,
element1.1.2,
element1.1.3,
element1.1.4,
}
}
In other words, how can I serialize that to the following?
<element1>
<element1.1.1 />
<element1.1.2 />
<element1.1.3 />
<element1.1.4 />
</element1>
I'm trying different combinations with the xmlelement, XmlIgnore, etc. but non seem to work until now.
Any word of advice would be deeply appreciated!
The code here would be :
[XmlElement("Element1")]
public class Element1
{
[XmlElement("Element11")]
public string Element11 {get;set;}
[XmlElement("Element12")]
public Element12 Element12 {get;set;}
}
public class Element12
{
[XmlElement("element121")]
public string element1{get;set;}
[XmlElement("element122")]
public string element2{get;set;}
[XmlElement("element123")]
public string element3{get;set;}
[XmlElement("element124")]
public string element4{get;set;}
}
You cannot do that. XmlSerializer makes the assumption that the model you want to serialize is shaped roughly like the xml you want. There are some minor tweaks you can do, but this is not one of them. If the problem is that your domain model has an extra layer, then the solution is simple: don't serialize your domain model. Introduce a new set of DTO classes that exist solely for the purpose of xml serialization, and transform your data into the DTO model prior to serialization.
I have an XML file that I need to deserialize into an object similar to this one:
public class TestObject
{
public string Name { get; set; }
public int Size { get; set; }
public TestObject()
{
Name = string.Empty;
Size = 0;
}
}
My deserialize method looks like this:
private TestObject DeserializeConfiguration(string xmlFileName)
{
XmlSerializer deserializer = new XmlSerializer(typeof(TestObject));
TextReader textReader = new StreamReader(xmlFileName);
TestObject testObj = (TestObject)deserializer.Deserialize(textReader);
textReader.Close();
return testObj;
}
This is working well enough for me but on occasion, I get an XML file that may contain an invalid data type (by "invalid", I mean with respect to the type of the object property that it should map to). For example, if my XML file looks like this:
<?xml version="1.0" encoding="utf-8"?>
<TestObject xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<Name>Orion</Name>
<Size>abc</Size>
</TestObject>
Obviously I can't convert "abc" into the integer Size property of my object. When I attempt to deserialize this, I see an InvalidOperationException and, not surprisingly, the InnerException is "Input string was not in a correct format". Is it possible to catch this error, use a default value for that property of my object and continue deserializing the remainder of the XML file? If not, can anyone tell me if there's a generally regarded "best practice" for handling invalid data during deserialization?
What you would need to do is to validate the incoming XML before deserializing. Basically you want to avoid having to process badly-formed XML. After validation the deserializer can at least be sure that all incoming XML will be deserializable.
You can create an XML Schema that contains the definition of valid XML in your case, and then validate the incoming XML with the XSD (XML Schema Definition) first (see also http://www.codeguru.com/csharp/csharp/cs_data/xml/article.php/c6737/Validation-of-XML-with-XSD.htm for more details).
Good luck!
I have a problem which I have been bashing my head against for the better part of three hours. I am almost certain that I've missed something blindingly obvious...
I have a simple XML file:
<?xml version="1.0" encoding="utf-8"?>
<WeightStore xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<Records>
<Record actual="150" date="2010-05-01T00:00:00" />
<Record actual="155" date="2010-05-02T00:00:00" />
</Records>
</WeightStore>
I have a simple class structure:
[Serializable]
public class Record
{
[XmlAttribute("actual")] public double weight { get; set; }
[XmlAttribute("date")] public DateTime date { get; set; }
[XmlIgnore] public double trend { get; set; }
}
[Serializable]
[XmlRoot("WeightStore")]
public class SimpleWeightStore
{
[XmlArrayAttribute("Records")]
private List<Record> records = new List<Record>();
public List<Record> Records { get { return records; } }
[OnDeserialized()]
public void OnDeserialized_Method(StreamingContext context)
{
// This code never gets called
Console.WriteLine("OnDeserialized");
}
}
I am using these in both calling code and in the class files:
using System.Xml.Serialization;
using System.Runtime.Serialization;
I have some calling code:
SimpleWeightStore weight_store_reload = new SimpleWeightStore();
TextReader reader = new StringReader(xml);
XmlSerializer deserializer = new XmlSerializer(weight_store.GetType());
weight_store_reload = (SimpleWeightStore)deserializer.Deserialize(reader);
The problem is that I am expecting OnDeserialized_Method to get called, and it isn't.
I suspect it might have something to do with the fact that it's XML deserialization rather than Runtime deserialization, and perhaps I am using the wrong attribute name, but I can't find out what it might be.
Any ideas, folks?
There's no equivalent of OnDeserialized for XML deserialization.
See this post for workarounds: How do you find out when you've been loaded via XML Serialization?
The only way you could do that in a graceful way is to manually implement IXmlSerializable, which is not fun. Simply; XmlSerializer doesn't support serialization callbacks.
Sometimes, though, you can switch to DataContractSerializer, which still offers xml capabilities but which does support serialization callbacks. Unfortunately the xml options are limited - it won't work for you xml structure, since that uses attributes (DataContractSerializer only supports elements).
You might also look at the comments on this answer, which discusses the points from this.