I'm serializing a class like below
XmlSerializerNamespaces namespaces = new XmlSerializerNamespaces();
namespaces.Add(string.Empty, string.Empty);
StringWriter sw = new StringWriter();
XmlSerializer serializer1 = new XmlSerializer(typeof(List<student>), new XmlRootAttribute("Response"));
XmlTextWriter xmlWriter = new XmlTextWriter(sw);
serializer1.Serialize(xmlWriter, ls, namespaces);
sw.ToString()
The result string below
<?xml version="1.0" encoding="utf-16"?>
<Response><student><name>xxx</name></student></Response>
but, How can i add an attribute to the root element(Response)?
like below one
<?xml version="1.0" encoding="utf-16"?>
<Response status="1"><student><name>xxx</name></student></Response>
You just need to mark that property of the class with XmlAttribute, i.e.
class MyClass{
[XmlAttribute("status")]
public string ErrorStatus { get; set; }
}
Edit:
Just realised you are serializing the list directly. Put your list inside a parent class, Response, and add the above attribute to this Response class, then serialise the Response object.
Hope this helps.
You can create another object that contains the list, and then create a property to add the attribute to the root node.
The trick is to preface the list in this new class with an explicit type assignment to the Student type to avoid having your list nested within another parent node.
[XmlType(TypeName = "Response")]
public class ResponseObject
{
[XmlAttribute("status")]
public string file { get; set; }
[XmlElement("Student", Type = typeof(Student))]
public List<Student> studentList { get; set; }
}
Your code would then look like the following
XmlSerializerNamespaces namespaces = new XmlSerializerNamespaces();
namespaces.Add(string.Empty, string.Empty);
StringWriter sw = new StringWriter();
XmlSerializer serializer1 = new XmlSerializer(typeof(ResponseObject));
XmlTextWriter xmlWriter = new XmlTextWriter(sw);
//Creating new object and assign the existing list and status
ResponseObject resp = new ResponseObject();
resp.studentList = ls;
resp.status = 1;
//Serialize with the new object
serializer1.Serialize(xmlWriter, resp, namespaces);
sw.ToString()
Related
I am serializing List of objects List<TestObject>
, and XmlSerializer generates <ArrayOfTestObject> attribute, I want rename it or remove it.
Can it be done with creating new class that encapsulated List as field?
[XmlRoot("Container")]
public class TestObject
{
public TestObject() { }
public string Str { get; set; }
}
List<TestObject> tmpList = new List<TestObject>();
TestObject TestObj = new TestObject();
TestObj.Str = "Test";
TestObject TestObj2 = new TestObject();
TestObj2.Str = "xcvxc";
tmpList.Add(TestObj);
tmpList.Add(TestObj2);
XmlWriterSettings settings = new XmlWriterSettings();
settings.OmitXmlDeclaration = true;
settings.Indent = true;
XmlSerializer serializer = new XmlSerializer(typeof(List<TestObject>));
using (XmlWriter writer = XmlWriter.Create(#"C:\test.xml", settings))
{
XmlSerializerNamespaces namespaces = new XmlSerializerNamespaces();
namespaces.Add(string.Empty, string.Empty);
serializer.Serialize(writer, tmpList, namespaces);
}
<ArrayOfTestObject>
<TestObject>
<Str>Test</Str>
</TestObject>
<TestObject>
<Str>xcvxc</Str>
</TestObject>
</ArrayOfTestObject>
The most reliable way is to declare an outermost DTO class:
[XmlRoot("myOuterElement")]
public class MyOuterMessage {
[XmlElement("item")]
public List<TestObject> Items {get;set;}
}
and serialize that (i.e. put your list into another object).
You can avoid a wrapper class, but I wouldn't:
class Program
{
static void Main()
{
XmlSerializer ser = new XmlSerializer(typeof(List<Foo>),
new XmlRootAttribute("Flibble"));
List<Foo> foos = new List<Foo> {
new Foo {Bar = "abc"},
new Foo {Bar = "def"}
};
ser.Serialize(Console.Out, foos);
}
}
public class Foo
{
public string Bar { get; set; }
}
The problem with this is that when you use custom attributes you need to be very careful to store and re-use the serializer, otherwise you get lots of dynamic assemblies loaded into memory. This is avoided if you just use the XmlSerializer(Type) constructor, as it caches this internally automatically.
Change the following line from:
XmlSerializer serializer = new XmlSerializer(typeof(List<TestObject>));
To:
XmlRootAttribute root = new XmlRootAttribute("TestObjects");
XmlSerializer serializer = new XmlSerializer(typeof(List<TestObject>), root);
It should work.
You can add an additional parameter to the XmlSerializer constructor to essentially name the root element.
XmlSerializer xsSubmit = new XmlSerializer(typeof(List<DropDownOption>), new XmlRootAttribute("DropDownOptions"));
This would result in the following structure:
<DropDownOptions xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<DropDownOption>
<ID>1</ID>
<Description>foo</Description>
</DropDownOption>
<DropDownOption>
<ID>2</ID>
<Description>bar</Description>
</DropDownOption>
</DropDownOptions>
Create another class like :
[XmlRoot("TestObjects")]
public class TestObjects: List<TestObject>
{
}
Then apply below code while sealizing :
XmlSerializer serializer = new XmlSerializer(typeof(TestObjects));
MemoryStream memStream = new MemoryStream();
serializer.Serialize(memStream, tmpList);
I need to remove all of the xmlns attributes from every element. I am using the XmlSerializer class in c#.
Here is a sample of the XML I am getting from serializing an object returned by a webservice.
Code for serialization
public static string ToXML<T>(object obj,string nameSpace)
{
XmlSerializerNamespaces ns = new XmlSerializerNamespaces();
ns.Add("", "");
var xml = "";
using (var stringwriter = new StringWriter())
{
var serializer = new XmlSerializer(typeof(T));
serializer.Serialize(stringwriter, obj,ns);
xml = xml + stringwriter;
}
return xml;
}
Calling Code
var unitInfo = RC.GetUnitInfo(txtUnitNum.Text);
var x = XML.DocumentExtensions.ToXML<Vehicles>(unitInfo, "");
Result
<Vehicles>
<Unit xmlns="http://Entities/2006/09">430160</Unit>
<VinNumber xmlns="http://Entities/2006/09">1FUJGP9337</VinNumber>
<CustName xmlns="http://Entities/2006/09">Ryder : N/A</CustName>
<CustCode xmlns="http://Entities/2006/09">4199</CustCode>
<NationalAccountFVM xmlns="http://Entities/2006/09">0</NationalAccountFVM>
<VehMake xmlns="http://Entities/2006/09">FREIGHTLINER/MERCEDES</VehMake>
<VehModel xmlns="http://Entities/2006/09">PX12564ST CASCADIA</VehModel>
<VehYear xmlns="http://Entities/2006/09">2012</VehYear>
<VehDescrip xmlns="http://Entities/2006/09">TRACTOR</VehDescrip>
<InService xmlns="http://Entities/2006/09">10/28/2011 12:00:00 AM</InService>
<EngMake xmlns="http://Entities/2006/09">CUMMINS ENGINE CO.</EngMake>
<EngModel xmlns="http://Entities/2006/09">ISX'10 14.9 450/1800</EngModel>
<EngSize xmlns="http://Entities/2006/09">450</EngSize>
<EngSerial xmlns="http://Entities/2006/09">79502</EngSerial>
<TransMake xmlns="http://Entities/2006/09">FULLER TRANS., DIV. EATON</TransMake>
</Vehicles
I need to serialize the object without getting the xmlns attributes.
Vehicle Object
[System.CodeDom.Compiler.GeneratedCodeAttribute("System.Xml", "4.0.30319.34234")]
[System.SerializableAttribute()]
[System.Diagnostics.DebuggerStepThroughAttribute()]
[System.ComponentModel.DesignerCategoryAttribute("code")]
[System.Xml.Serialization.XmlTypeAttribute(Namespace="http://Entities/2006/09")]
public partial class Vehicles {
private string unitField;
private string vinNumberField;
/// <remarks/>
public string Unit {
get {
return this.unitField;
}
set {
this.unitField = value;
}
}
/// <remarks/>
public string VinNumber {
get {
return this.vinNumberField;
}
set {
this.vinNumberField = value;
}
}
}
I modified your ToXML() method below to always correctly exclude a namespace.
The main difference is how the XmlSerializerNamespaces is instantiated.
Generating an empty namespace disables the inserting of namespaces by the XmlWriter into the output XML.
I also change how you build the output XML since string concatenation is more resource intensive than utilizing a StringBuilder in conjuction with a StringWriter.
public static string ToXML<T>(object obj)
{
StringBuilder outputXml = new StringBuilder();
using (var stringwriter = new StringWriter(outputXml))
{
// Define a blank/empty Namespace that will allow the generated
// XML to contain no Namespace declarations.
XmlSerializerNamespaces emptyNS = new XmlSerializerNamespaces(new[] { new XmlQualifiedName("", "") });
var serializer = new XmlSerializer(typeof(T));
serializer.Serialize(stringwriter, obj, emptyNS);
}
return outputXml.ToString();
}
Passing in a sample object, I get the output XML of
<?xml version="1.0" encoding="utf-16"?>
<Vehicles>
<Unit>430160</Unit>
<VinNumber>1FUJGP9337</VinNumber>
<CustName>Ryder : N/A</CustName>
<CustCode>4199</CustCode>
<NationalAccountFVM>0</NationalAccountFVM>
<VehMake>FREIGHTLINER/MERCEDES</VehMake>
<VehModel>PX12564ST CASCADIA</VehModel>
<VehYear>2012</VehYear>
<VehDescrip>TRACTOR</VehDescrip>
<InService>2011-10-28T00:00:00</InService>
<EngMake>CUMMINS ENGINE CO.</EngMake>
<EngModel>ISX'10 14.9 450/1800</EngModel>
<EngSize>450</EngSize>
<EngSerial>79502</EngSerial>
<TransMake>FULLER TRANS., DIV. EATON</TransMake>
</Vehicles>
I want to create a serialisable class to represent an xml envelope that can contain arbitrary message content. Example xml (simplified) below:
<?xml version="1.0" encoding="utf-8"?>
<Envelope>
<MessageA>
<Url></Url>
</MessageA>
</Envelope>
<?xml version="1.0" encoding="utf-8"?>
<Envelope>
<MessageB>
<Value></Value>
</MessageB>
</Envelope>
My idea is to use a generic envelope class to handle this:
[Serializable]
[XmlRoot(ElementName="Envelope")]
public class Envelope<TContent> where TContent : new()
{
public Envelope()
{
Content = new TContent();
}
public TContent Content { get; set; }
}
[Serializable]
public class MessageA
{
public string Url { get; set; }
}
[Serializable]
public class MessageB
{
public string Value { get; set; }
}
These could be serialised so:
var envelope = new Envelope<MessageA>();
envelope.Content.Url = "http://www.contoso.com";
string xml = envelope.ToXml();
However, instead of the xml message that I want (per examples above), I get the following. How can I change the classes or the serialisation process to rename the Content element to the name of the Message itself?
<?xml version="1.0" encoding="utf-8"?>
<Envelope>
<Content>
<Url>http://www.contoso.com</Url>
</Content>
</Envelope>
Found that the XmlAttributeOverrides class has a solution for this problem. Adding the following method to the Envelope class causes the ToXml() extension method to serialise the object as required.
public string ToXml()
{
return ToXml(typeof(TContent).Name);
}
public string ToXml(string contentElementName)
{
XmlElementAttribute element = new XmlElementAttribute(contentElementName, typeof(TContent));
XmlAttributes attributes = new XmlAttributes();
attributes.XmlElements.Add(element);
XmlAttributeOverrides overrides = new XmlAttributeOverrides();
overrides.Add(typeof(Envelope<TContent>), "Content", attributes);
return ToXml(this, overrides);
}
public string ToXml(Envelope<TContent> value, XmlAttributeOverrides overrides)
{
using (var sw = new Utf8StringWriter())
{
var settings = new XmlWriterSettings
{
OmitXmlDeclaration = omitXmlDeclaration,
Indent = true
};
XmlSerializer xs = new XmlSerializer(typeof(Envelope<TContent>), overrides);
using (XmlWriter writer = XmlWriter.Create(sw, settings))
{
xs.Serialize(writer, value);
}
return sw.ToString();
}
}
here is my xml :
<connections total="2" >
<person>
<id>ohKiUAZWz2</id>
<first-name>ミ★нιяαℓ</first-name>
<last-name>§|-|ä|-|»♥«</last-name>
<headline>--</headline>
</person>
<person>
<id>LmgYe-Nl2a</id>
<first-name>kunal</first-name>
<last-name>b</last-name>
<headline>Student at MscIT,Surat</headline>
</person>
</connection>
from code behind :
List<LinkWall> LinkWallList = new List<LinkWall>();
XmlNodeList xmlnode = doc.GetElementsByTagName("person");
foreach (XmlElement ele in xmlnode)
{
XmlRootAttribute xr = new XmlRootAttribute("person");
XmlSerializer mySerializer = new XmlSerializer(typeof(LinkWall),xr);
StringReader re = new StringReader(ele.InnerXml);
LinkWallList.Add((LinkWall)mySerializer.Deserialize(re));
}
here is my class definition :
[XmlRoot("person")]
public class LinkWall
{
public LinkWall()
{ }
[XmlElement(ElementName = "id")]
public string id { get; set; }
[XmlElement(ElementName = "first-name")]
public string firstName { get; set; }
[XmlElement(ElementName = "last-name")]
public string lastName { get; set; }
[XmlElement(ElementName = "headline", IsNullable=true)]
public string headline { get; set; }
}
but when i try to deserialize. it show me error like : {"There are multiple root elements."}
is there any solution or alternative for specifying XmlRootAttribute ?
thanks in advance, Milan Mendpara
I think your issue is with this line:
StringReader re = new StringReader(ele.InnerXml);
Change it to:
StringReader re = new StringReader(ele.OuterXml);
The reason is the InnerXml property will return all of the child nodes but not the parent node. OuterXml will include your parent person node too.
i.e. InnerXml has no root element (well, it has many!):
<id>ohKiUAZWz2</id>
<first-name>?????al</first-name>
<last-name>§|-|ä|-|»?«</last-name>
<headline>--</headline>
OuterXml is as expected:
<person>
<id>ohKiUAZWz2</id>
<first-name>?????al</first-name>
<last-name>§|-|ä|-|»?«</last-name>
<headline>--</headline>
</person>
There is also no real need to use the XmlSerializer constructor you are using. Try:
XmlSerializer mySerializer = new XmlSerializer(typeof(LinkWall));
Instead.
Try OuterXml instead of InnerXML
StringReader re = new StringReader(ele.OuterXml);
I believe you should make a class structured like your xml file and deserialize your xml file into an instance of this class.
MyClass myObject = new MyClass;
XmlSerializer ser = new XmlSerializer(myObject.GetType());
using (FileStream fs = new FileStream(FilePath, FileMode.Open))
{
XmlTextReader reader = new XmlTextReader(fs);
myObject = (MyClass)ser.Deserialize(reader);
}
This code runs faster and then you will be able to do wathever you want with the data inside your object.
I am serializing List of objects List<TestObject>
, and XmlSerializer generates <ArrayOfTestObject> attribute, I want rename it or remove it.
Can it be done with creating new class that encapsulated List as field?
[XmlRoot("Container")]
public class TestObject
{
public TestObject() { }
public string Str { get; set; }
}
List<TestObject> tmpList = new List<TestObject>();
TestObject TestObj = new TestObject();
TestObj.Str = "Test";
TestObject TestObj2 = new TestObject();
TestObj2.Str = "xcvxc";
tmpList.Add(TestObj);
tmpList.Add(TestObj2);
XmlWriterSettings settings = new XmlWriterSettings();
settings.OmitXmlDeclaration = true;
settings.Indent = true;
XmlSerializer serializer = new XmlSerializer(typeof(List<TestObject>));
using (XmlWriter writer = XmlWriter.Create(#"C:\test.xml", settings))
{
XmlSerializerNamespaces namespaces = new XmlSerializerNamespaces();
namespaces.Add(string.Empty, string.Empty);
serializer.Serialize(writer, tmpList, namespaces);
}
<ArrayOfTestObject>
<TestObject>
<Str>Test</Str>
</TestObject>
<TestObject>
<Str>xcvxc</Str>
</TestObject>
</ArrayOfTestObject>
The most reliable way is to declare an outermost DTO class:
[XmlRoot("myOuterElement")]
public class MyOuterMessage {
[XmlElement("item")]
public List<TestObject> Items {get;set;}
}
and serialize that (i.e. put your list into another object).
You can avoid a wrapper class, but I wouldn't:
class Program
{
static void Main()
{
XmlSerializer ser = new XmlSerializer(typeof(List<Foo>),
new XmlRootAttribute("Flibble"));
List<Foo> foos = new List<Foo> {
new Foo {Bar = "abc"},
new Foo {Bar = "def"}
};
ser.Serialize(Console.Out, foos);
}
}
public class Foo
{
public string Bar { get; set; }
}
The problem with this is that when you use custom attributes you need to be very careful to store and re-use the serializer, otherwise you get lots of dynamic assemblies loaded into memory. This is avoided if you just use the XmlSerializer(Type) constructor, as it caches this internally automatically.
Change the following line from:
XmlSerializer serializer = new XmlSerializer(typeof(List<TestObject>));
To:
XmlRootAttribute root = new XmlRootAttribute("TestObjects");
XmlSerializer serializer = new XmlSerializer(typeof(List<TestObject>), root);
It should work.
You can add an additional parameter to the XmlSerializer constructor to essentially name the root element.
XmlSerializer xsSubmit = new XmlSerializer(typeof(List<DropDownOption>), new XmlRootAttribute("DropDownOptions"));
This would result in the following structure:
<DropDownOptions xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<DropDownOption>
<ID>1</ID>
<Description>foo</Description>
</DropDownOption>
<DropDownOption>
<ID>2</ID>
<Description>bar</Description>
</DropDownOption>
</DropDownOptions>
Create another class like :
[XmlRoot("TestObjects")]
public class TestObjects: List<TestObject>
{
}
Then apply below code while sealizing :
XmlSerializer serializer = new XmlSerializer(typeof(TestObjects));
MemoryStream memStream = new MemoryStream();
serializer.Serialize(memStream, tmpList);