Develop Reference

Multiview controls

I wrote the following code for multiview where I am using gridview and datalist:
<ContentPlaceHolderID="ContentPlaceHolder1">
<div class="alert alert-success" >
<div class="divbtn" style="text-align:right">
<asp:LinkButton ID="gridbtn" runat="server" CssClass="glyphicon glyphicon-th" OnClick="gridbtn_Click"></asp:LinkButton>
<asp:LinkButton ID="listbtn" runat="server" CssClass="glyphicon glyphicon-th-list" OnClick="listbtn_Click"></asp:LinkButton>
</div>
</div>
<asp:MultiView runat="server" ID="multiview" ActiveViewIndex="0">
<asp:View runat="server" ID="gridview">
<uc1:GridControl runat="server" ID="GridControl"/>
</asp:View>
<asp:View runat="server" ID="listview">
<uc1:Listing runat="server" ID="Listing" />
</asp:View>
</asp:MultiView>
</asp:Content>
I am using two link buttons to call their respective views by firing two separate events as follows.
protected void listbtn_Click(object sender, EventArgs e)
{
multiview.ActiveViewIndex = 1;
}
protected void gridbtn_Click(object sender, EventArgs e)
{
multiview.ActiveViewIndex = 0;
}
Suppose, my datalist (Index=1) is active on my page and if there is a post back it should still be showing the datalist but on postback it automatically switches back to grid view (Index=0). I really need help with this!

You can save the index to a session variable and then read it back on post back like this:
To save:
Session["index"] = index.ToString();
Read it on page load like this:
Index = Session["index"];
You will need the session variable to maintain state per user session. If you want to maintain state for the application then you have to use the application variable.

Hi add the following code in your page_load event.
if(!Page.IsPostBack)
{
multiview.ActiveViewIndex=0;
}

i think you are setting the multiview's active index to zero on every post back like follows
protected void Page_Load(object sender, EventArgs e)
{
multiview.ActiveViewIndex=0;
}
this will cause the multiview to set active index as 0 on every post back.To avoid this you have to set it as follows
protected void Page_Load(object sender, EventArgs e)
{
if(!Page.IsPostBack)
{
multiview.ActiveViewIndex=0;
}
}

How to pass variable from textbox to code behind back to same page

I have a webs form page and I have a text box which once clicked passes a variable to the code behind and then back into another element of that page and I cannot get it to work.
This is the closest I have got.
<asp:Panel ID="Search" runat="server" Visible="true">
<tr>
<td>
<asp:Label ID="lblSearch" runat="server" Text="Search"></asp:Label>
</td>
<td>
<asp:TextBox ID="search" runat="server" />
</td>
<td>
<asp:RequiredFieldValidator ID="valSearch" runat="server"
ControlToValidate="movieSearch" Text="Please enter text" />
</td>
<td>
<asp:Button ID="btnSubmit" runat="server" Text="Save"
OnClick="btnSubmit_Click" />
</td>
</tr>
</table>
</asp:Panel>
<asp:Panel ID="pnlSearchResult" runat="server" Visible="false">
<script>
var search = '<%=Server.UrlDecode(Request.QueryString["Data"]) %>';
</script>
</asp:Panel>
And the code behind:
protected void btnSubmit_Click(object sender, EventArgs e)
{
if (IsValid)
{
pnlSearch.Visible = false;
pnlSearchResult.Visible = true;
Response.Redirect("search.aspx?Data=" + Server.UrlEncode(search.Text));
}
}
Also this does not change the visibility of the two panels for some reason.
I would appreciate any guidance I am very new to asp and c#.

The panel's visibility is not changing because you're forcing a new GET request to the page with this: -
Response.Redirect("search.aspx?Data=" + Server.UrlEncode(search.Text));
(I'm assuming your page is called 'search.aspx')
There's no need to do this. Remove this line.
Secondly, I see you want to force the textbox's Text value into a Javascript variable. Replace this
var search = '<%=Server.UrlDecode(Request.QueryString["Data"]) %>';
with this
var search = '<%= search.Text %>';

Write below code on page event.
Another more important point is you first panel Id is "Search" not "pnlSearch" on aspx page so please correct it
protected void Page_Load(object sender, EventArgs e)
{
if (Request.QueryString["Data"] != null)
{
Search.Visible = false;
pnlSearchResult.Visible = true;
}
}

I recommend solution without using Response.Redirect.
Code Behind Submit Button click:
protected void btnSubmit_Click(object sender, EventArgs e)
{
if (IsValid)
{
pnlSearch.Visible = false;
pnlSearchResult.Visible = true;
}
}
In Markup:
<asp:Panel ID="pnlSearchResult" runat="server" Visible="false">
<script>
var searchTxt = document.getElementById('search');
if(searchTxt.value != null && searchTxt.value != ''){
//do your stuff
}
</script>

Hide and Show Label and Button

I have 2 labels and 2 text boxes and 1 buttons displayed.
When the page loads the Name and Button (will be initially displayed). Later when i click on the Button i need to display the age label and textbox. How can i do this ?
<ol>
<li>
<asp:Label runat="server" AssociatedControlID="Name">
User name
</asp:Label>
<asp:TextBox runat="server" ID="Name" Width="167px" />
<asp:Button ID="Button1" runat="server" Text="Button" />
</li>
<li>
<asp:Label runat="server" AssociatedControlID="age">age</asp:Label>
<asp:TextBox runat="server" ID="age" TextMode="age" Width="240px" />
</li>
</ol>
code for button press
protected void Button1_Click(object sender, EventArgs e)
{
}

You could set the label/textbox Visible property to True in server side. Alternatively, you could use JavaScript to avoid post backs to the server.
Add OnClientClick to your button :
<asp:Button ID="Button1" runat="server" Text="Button" OnClientClick="ShowLabel();"/>
and declare the JavaScript function on page:
<script type="text/javascript">
function ShowLabel() {
// Note that the client ID might be different from the server side ID
document.getElementById('lblAge').style.display = 'inherit';
}
</script>
You need to set the Label Display style to none initially.
<asp:Label ID="lblAge" style="display: none;" runat="server" AssociatedControlID="age">age</asp:Label>

Try below code:
You need to set Visible property of controls to True or False according to your requirement. By default, all controls are visible on the screen whenever they are added on the page.You need to do following thing:
You need to remove TextMode="age" as there is not any supported textmode of type age.
Need to define id of control if you want to access a control server side in code behind. So define the ID of Label that you put corresponding to Age textbox.
By Default age label and textbox will not be visible by using below code:
<asp:Label ID="lblAge" runat="server" AssociatedControlID="age" Visible="false">age</asp:Label>
<asp:TextBox runat="server" ID="age" Width="240px" Visible="false"/>
Code behind:
After button click age label and the textbox will be visible by using below code:
protected void Button1_Click(object sender, EventArgs e)
{
lblAge.Visible = true;
age.Visible = true;
}

First add id to elements and set visible false
<asp:Label runat="server" AssociatedControlID="age" Visible="false" Id="lbl1">age</asp:Label>
<asp:TextBox runat="server" ID="age" TextMode="age" Width="240px" Visible="false" />
button click event set visible true
protected void Button1_Click(object sender, EventArgs e)
{
lbl1.Visible = True;
age.Visible = True;
}

this is the basic concept of asp.net. you can use visible property of the control.
your TextMode enumeration is wrong. there is no Age enumeration for Textbox.TextMode TextMode
<li>
<asp:Label runat="server" AssociatedControlID="age" id="lblAge">age</asp:Label>
<asp:TextBox runat="server" ID="age" TextMode="age" Width="240px" />
</li>
in code behind
protected void Button1_Click(object sender, EventArgs e)
{
lblAge.Visible=true;
age.Visible=true;
}

protected void Page_Load(object sender, EventArgs e)
{
NameLabel.Visible = false;
NameBox.Visible = false;
}
protected void Button1_Click(object sender, EventArgs e)
{
NameLabel.Visible = true;
NameBox.Visible = true;
}

Change div things in other page

I used the code below to make a change in div of the page of this code file:
HtmlGenericControl divTest = Page.FindControl("test") as HtmlGenericControl;
divTeste.InnerText = "tested";
But now, I want to change another page. Ex.: default.aspx code behind changes a div inner text in the test.aspx ...
The code above isn't appropriated. I want permanent changes. What code should be?
How can I do it?

You need to understand how ASP.NET works. Introduction to ASP.NET
If you are on Default.aspx and then wont to move to Test.aspx you can use values from Default.aspx in Test.aspx however you can't just change different pages from the page you are on. (Actually it is possible by writing data to a database and then later accessing that data on the page you want to change but for your example I don't believe you are looking for something like that)
The closest to your example I can think of is using a Query string.
Default.aspx Markup
<asp:Button ID="Button1" runat="server" Text="Button" OnClick="Button1_Click" />
Default.aspx Code behind
protected void Button1_Click(object sender, EventArgs e)
{
Response.Redirect("Test.aspx?DivMSG=Hello");
}
Test.aspx Markup
<div id="MyTestDiv" runat="server">
</div>
Test.aspx Code Behind
protected void Page_Load(object sender, EventArgs e)
{
if (!IsPostBack)
{
MyTestDiv.InnerText = Request.QueryString["DivMSG"];
}
}
Update:
One way to make it permanent is to write it to a database. A quick example but you need to do the database code
Default.aspx Markup
<asp:TextBox ID="TextBox1" runat="server"></asp:TextBox>
<asp:Button ID="Button1" runat="server" Text="Button" OnClick="Button1_Click" />
Default.aspx Code behind
protected void Button1_Click(object sender, EventArgs e)
{
string messageToWriteToTestDiv = TextBox1.Text;
// Code: to write messageToWriteToTestDiv to the database
}
Test.aspx Code Behind
protected void Page_Load(object sender, EventArgs e)
{
if (!IsPostBack)
{
string myMessage = "";
// Code: string myMessage = Get Message from Database to write to div
MyTestDiv.InnerText = myMessage;
}
}
Test.aspx Markup
<div id="MyTestDiv" runat="server">
</div>

FindControl can't find a control

I have a problem with FindControl function. The problem is as follow:
aspx:
<asp:Content ID="MainContent" ContentPlaceHolderID="MainContent" runat="server">
<ajaxToolkit:ToolkitScriptManager ID="ToolkitScriptManager1" runat="server">
</ajaxToolkit:ToolkitScriptManager>
<table class="inputTable">
<tr><td>
<asp:CheckBox ID="Extern" AutoPostBack="True" OnCheckedChanged="OnCheckedChangedMethod" runat="server" />
</td><td>Externes Unternehmen</td></tr>
<tr>
<td>
<asp:TextBox ID="Firmierung" runat="server"></asp:TextBox>
<asp:RequiredFieldValidator ID="RequiredFieldValidator1" runat="server"
ControlToValidate="Firmierung" Display="Dynamic"
ErrorMessage="RequiredFieldValidator"
Text="Bitte geben Sie die Firmierung ein."></asp:RequiredFieldValidator>
</td>
</tr>
</table>
aspx.cs:
protected void OnCheckedChangedMethod(object sender, EventArgs e)
{
if (Extern.Checked)
{
Control ctr = FindControl("RequiredFieldValidator1");
if (ctr != null)
{
ctr.Visible = false;
}
}
else
{
}
}
But FindControl didn't work, it couldn't find that control. Was I wrong at any point?
Thanks in advance.

ASP.NET creates a field for you, as it is located inside a Content: this.RequiredFieldValidator1 in your page.
The FindControl way would be like this (find it in the master page's content panel):
Control ctr = Master.FindControl("MainContent")
.FindControl("RequiredFieldValidator1");

Based on your limited source, you should be able to simplify your code behind method to:
protected void OnCheckedChangedMethod(object sender, EventArgs e)
{
this.RequiredFieldValidator1.Visible = this.Extern.Checked;
}
There should be no need for the use of FindControl().
When you type "this.", if you don't see RequiredFieldValidator1 appear in your intellisense, and assuming you are using ASP.NET 2.0 or greater, check your VS.NET warnings to see if your .aspx has a warning message with an associated "Generation of designer file failed". If so, you must correct the warning.