C# DateTime to be copied without format getting changed - c#

I have a date and time which should be copied to DateTime object without changing its format.
Is there a way to resolve it?
Pls see the code below
string dateTime = "07/20/11 14:40:28";
DateTime copyDateTime = Convert.ToDateTime(dateTime);
string dateTime2 = copyDateTime.ToString();
Output:
{7/20/2011 2:40:28 PM}
If you notice the output, it got changed to PM. I want it as it is. How to get it?
EDIT:
I want dateTime2 to have the value exactly as it was for dateTime.

Format is not intrinsically associated with the DateTime. Format is simply a display property.
If you need to display it in your preferred format than simply call:
Console.WriteLine(copyDateTime.ToString("G"));
See MSDN for a complete list of standard format strings.

Before outputting, you need to convert the DateTime back into a string. By default, it simply calls "ToString" which uses the default DateTime format configured for the current user/locale.
Use ToString and specify a format to convert the datetime back into a String, then you can control the format.

Related

DateTime.TryParse() not working with formatted date dd/MM/yyyy

This code returns (min time 1/1/0001 12:00:00 AM) not Date.Time.Now . Try Parse works for MM/dd/yyyy but not dd/MM/yyyy . Any suggestions
Here is code
DateTime start, end;
DateTime.TryParse(EPSDate12.Text, out start);
string TNow = DateTime.Now.ToString("dd/MM/yyyy HH:mm:ss"); // Works
// string TNow = DateTime.Now.ToString();// works but gives MM/dd/yyyy as expected
DateTime.TryParse(TNow, out end); // No. gives min time (1/1/0001 12:00:00 AM)
Use TryParseExact and supply the format string.
Also examine the return value from TryParseExact to know if it failed or not (it returns a bool)
I see "EPSDate12.Text" which i suspect may be a TextBox: If you're doing this in a UI, make life easy and use a DateTimePicker - you can set the format, the user can type into them just like a textbox, but they don't accept invalid inputs, and all you have to do is get the .Value property which gives you a DateTime
As to why your attempts to parse the string you made don't work, I think it most likely that the date format Parse is using (which is based on the culture settings of the executing thread) is not the same format as the string you prepared using your forced format. Either make sure your forced format is matched to the current culture, or use a culture that matches your forced format, or use [Try]ParseExact to force the format for parsing like you did when creating the string
See https://learn.microsoft.com/en-us/dotnet/api/system.datetime.parse?view=net-5.0#Culture for more info
The datetime value is internally the same. But, ToString() return value, depends on
the local machine culture setup.
Reference article
The default DateTime.ToString() method returns the string
representation of a date and time value using the current culture's
short date and long time pattern. The following example uses the
default DateTime.ToString() method.
For en-US culture(MM/dd/yyyy hh:mm:ss) , it will be in
7/28/2021 11:37:40 AM
If you want to see in en-GB(dd/MM/yyyy hh:mm:ss), you can apply conversion as given below:
var culture = new CultureInfo("en-GB");
MessageBox.Show($"{DateTime.Now.ToString(culture)}");
28/07/2021 11:45:09 AM
you can also specify exact custom format, in which you want to display.
MessageBox.Show($"{DateTime.Now.ToString("dd/MM/yyyy HH:mm:ss tt")}");
28/07/2021 11:45:09 AM
Thanks for suggestions . Yes DateTime.TryParse is not working and it could be format issue
This line of code.
string TNow = DateTime.Now.ToString("dd/MM/yyyy HH:mm:ss");
generates
29/07/2021 14:49:03
which looks OK but fails TryParse

Date Time Format is not Formatting

I need have this format :
aaaa-mm-jjThh:mm:sszzzzzz
And put it in a XML property "DateTime" type.
So, I did it :
var xmlObj= new xmlObj.tHeader();
xmlObj.prop = DateTime.ParseExact(DateTime.Now.ToString("yyyy'-'MM'-'dd'T'HH':'mm':'ss'Z'"), "yyyy'-'MM'-'dd'T'HH':'mm':'ss'Z'", CultureInfo.InvariantCulture);
Console.WriteLine(xmlObj.prop);
The Console.WriteLine instruction return : 03/05/2016 15:43:10
I don't understand why the property remove the format.
In the XSD, this property is waiting a datetime format.
Any ideas?
EDIT :
Ok, on the command result, I see a default format but If convert my XML object to File, the format is correct :
Very strange... but it's ok now. Many thanks to all of you
You are calling DateTime.ParseExact, which parses a string into a DateTime object. Just drop that part and assign the result of ToString directly to xmlObj.prop, or assign the DateTime object directly (if that's what it's looking for).
Edit:
To address your edit, your XML file is generated correctly. However, when you output the DateTime prop to the console, it uses the default string format for a date. You can format that with ToString() if you want to.
You try this:
Console.WriteLine(DateTime.UtcNow.ToString("s") + "Z");
Your format is wrong in parse, if you want yyyy-MM-ddTHH:mm:ssz format then you have to convert it as string otherwise, it will represent standard datetime, try this
xmlObj.prop = DateTime.ParseExact(DateTime.Now.ToString("yyyy-MM-ddTHH:mm:ssZ"), "yyyy-MM-ddTHH:mm:ssZ", CultureInfo.InvariantCulture);
Console.WriteLine(xmlObj.prop.ToString("yyyy-MM-ddTHH:mm:ssz"));

Can't convert DateTime format from MM/dd/yyyy to yyyy-MM-dd

I know this is a recurrent question but I cannot seem to be able to get this to work even after a lot of research! I want to convert a string to a DateTime.
public DateTime ConvertToDateTime(string thisDate)
{
return DateTime.ParseExact(thisDate, "yyyy-MM-dd", CultureInfo.InvariantCulture);
}
(EDITED)
I give "2012-03-07" as a parameter and I get a DateTime that is 03/07/2012 12:00AM. When I wanted it to return: 2012-03-07 00:00:00
Your code is correct; your expectations are wrong.
When a method returns a DateTime, it has no format. Well, more accurately, it has a binary in-memory format that has no relation to its string format.
The debugger formats the DateTime to show it to you, but that has no bearing on the DateTime value itself. The format it uses is presumably determined by your locale settings.
When you want to display the DateTime to a user, or pass it as a string to some other function, you can format it as you like using one of the ToString overloads.
It may be that you are displaying or passing the return value of the function you've given; if so, the error is in the code displaying or passing the DateTime, not in the function you've given. If that's the case, edit your answer to include that code, and perhaps we can help you fix it.
Try this
public String ConvertToDateTime(string thisDate)
{
return DateTime.ParseExact(thisDate, "yyyy-MM-dd",
CultureInfo.InvariantCulture).toString("yyyy-MM-dd");
}

Retrieve format of date from date value

I am receiving some data into a variable of type object. In certain cases this data are date values. For that data, I would like to convert this to a string and return it in the same format as it was passed. In some cases, the object could be a datetime, in others a date only or time only values.
As soon as I convert the object to a date or a string, it is obviously given a time of midnight which in my scenario may be a valid time (so I cannot test to see if the time is midnight in which case I could deduce that it would have been a date only date value, nor can I use regex on it as there will always be a time element).
Intellisense shows me it correctly, ie in the format I am wishing to return the value.
Is there an easy way to achieve this (hopefully without using reflection)
Many thx
Simon
Your question is a little unclear but I think you're looking for something like this:
DateTime result;
if (DateTime.TryParse(value, out result))
{
// use result here
}
In the above code value is a string that represents the data coming in. The code will only enter the if block if the string is a valid DateTime. At which point you can do the processing you need on it.
Im not sure i understand the question but i would recommend you to take a look at this conversion example on MSDN, and see the Documentation of the DateTime Structur it contains a lot of Conversion/Formatting Methods i hope it helps.
There are many way to do formatting on the datetime and one of the simple way is fetch the data from the required table in the desired format. Like here you need to display the date and if you your format is dd/MM/yyyy then try this
select Convert(varchar(10),StartDate,103) as StartDateformat from table where filtername=#filtername
use this link to find other format Cast and Convert
From local variable to DateTime Conversion
DateTime todateformat = Convert.ToDateTime(txttodate.Text.Trim());
From DateTime to local variable Conversion in specific format
string startdate = todateformat.ToString("dd/MM/yyyy hh:mm:ss");

.NET DateTime to BizTalk DateTime

I have date in this format "1999-05-31T13:20:00.000-05:00" I want to add some hours or days to it . BizTalk expects same datetime format how can i pass it as Datetime in that format ? No string . Date time with same format as source date.
You should be able to do something like this to get it into a DateTimeOffset object. After that you can call whatever methods you want on it.
DateTimeOffset dateTime = DateTimeOffset.Parse( "1999-05-31T13:20:00.000-05:00" );
To get the value back just use a formatting string.
dateTime.ToString( "O" ); //this should be the same format as you started with
Here are some other options http://msdn.microsoft.com/en-us/library/az4se3k1.aspx
Here is a link to the DateTimeOffset structure
http://msdn.microsoft.com/en-us/library/bb351654.aspx
I hope this helps.
The DateTime object is format-independent (for the most part). So whether or not it starts in the format you list or not doesn't matter. You can always get it back into that format (using the ToString("o") function). But that's as a string (when format matters).
After a quick search, it looks like you must be talking about string format, even though you said no string. So the other answer or the ToString("o"); part of mine is relevant.

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