I am new to C# and I am trying to read xml from URL.
xml looks like this
<posts>
<post>
<title>title1</title>
<des>des1</des>
</post>
<post>
<title>title2</title>
<des>des2</des>
</post>
.....
</posts>
And this is what I am using to parse it.
String uri = "url";
XDocument books = XDocument.Load(uri);
When the debug hits XDocument line it throws an exception and skips it.
How can I avoid this?
I think URI for your XML is lacking the extension of the file which is causing the problem. Please try using:
String uri = PATH + "url.xml";
XDocument books = new XDocument();
books.Load(uri);
To parse XML obtained from URL u can use:
string strURL = "http://<some-server>/<some-uri-path>";
string xmlStr;
WebClient wc = new WebClient();
xmlStr = wc.DownloadString(strURL);
XmlDocument xmlDoc = new XmlDocument();
xmlDoc.LoadXml(xmlStr);
Related
I am trying to get my xml response in the correct format using HttpUtility.Decode. Upon doing and loading it in Xml Document, it is throwing the following exception : Unexpected XML declaration. The XML declaration must be the first node in the document, and no white space characters are allowed to appear before it. Line 1, position 313. I'm not sure why because the xml declaration does appear as the first node if I'm not mistaken. Im fairly new to XML so any help will be appreciated. How do I fix this? Thanks.
XML decode response:
<?xml version="1.0" encoding="utf-8"?><soap:Envelope xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"><soap:Body><Query_With_StringResponse xmlns="http://www.syspro.com/ns/query/"><Query_With_StringResult><?xml version="1.0" encoding="Windows-1252"?>
<ARListOfCustomers Language='05' Language2='EN' CssStyle='' DecFormat='1' DateFormat='01' Role='01' Version='7.0.005' OperatorPrimaryRole=' ' >
<QueryOptions>
<ReportSequence>CU</ReportSequence>
<PriceCode/>
<PriceProductmatrix>N</PriceProductmatrix>
<ExtraFields>N</ExtraFields>
<InterestExemptionStatusSelection>A</InterestExemptionStatusSelection>
<TaxExemptionSelection>A</TaxExemptionSelection>
<CustomerSelectionFilterType>A</CustomerSelectionFilterType>
<CustomerSelectionFilterValue/>
<CustomerClassSelectionFilterType>A</CustomerClassSelectionFilterType>
<CustomerClassSelectionFilterValue/>
<GeographicAreaSelectionFilterType>A</GeographicAreaSelectionFilterType>
<GeographicAreaSelectionFilterValue/>
<BranchSelectionFilterType>A</BranchSelectionFilterType>
<BranchSelectionFilterValue/>
<SalespersonSelectionFilterType>A</SalespersonSelectionFilterType>
<SalespersonSelectionFilterValue/>
<LineDiscountCodeSelectionFilterType>A</LineDiscountCodeSelectionFilterType>
<LineDiscountCodeSelectionFilterValue/>
<TermsSelectionFilterType>A</TermsSelectionFilterType>
<TermsSelectionFilterValue/>
<ProductCategorySelectionFilterType>A</ProductCategorySelectionFilterType>
<ProductCategorySelectionFilterValue/>
<InvoiceDiscountCodeSelectionFilterType>A</InvoiceDiscountCodeSelectionFilterType>
<InvoiceDiscountCodeSelectionFilterValue/>
<CurrencySelectionFilterType>A</CurrencySelectionFilterType>
<CurrencySelectionFilterValue/>
<CreditLimitSelectionFilterType>A</CreditLimitSelectionFilterType>
<CreditLimitSelectionFilterValue/>
</QueryOptions>
<Customer>
<CustomerListHeader>
<Customer>TSAR</Customer>
<CustomerName>TSAR BUSINESS SOLUTION</CustomerName>
<CustomerShortName>TSAR BUSINESS SOLUTI</CustomerShortName>
<Branch>TSAR</Branch>
<BranchDescription>HEAD OFFICE TSAR</BranchDescription>
<Geography>031</Geography>
<GeographyDescription>DURBAN</GeographyDescription>
<Class/>
<ClassDescription>** Not on file **</ClassDescription>
<BalanceType>Op-item</BalanceType>
<Sales>IVAN</Sales>
<CreditLimit> 0</CreditLimit>
<Currency>R</Currency>
<CurrencyDescription>Rand</CurrencyDescription>
<Telephone/>
<InvoiceTermsCode>CO</InvoiceTermsCode>
<TermsCodeDescription>CASH ON DELIVERY</TermsCodeDescription>
</CustomerListHeader>
<CustomerListDetails>
<Contact/>
<TaxNo>Tax No:</TaxNo>
<SpecialInstructions/>
<SoldToAddress1/>
<SoldToAddress2/>
<SoldToAddress3/>
<SoldToAddress3Loc/>
<SoldToAddress4/>
<SoldToAddress5/>
<SoldToAddress6/>
<SoldToGpsLat> 0.000000</SoldToGpsLat>
<SoldToGpsLong> 0.000000</SoldToGpsLong>
<ShipToAddress1>STRAUSS DALY</ShipToAddress1>
<ShipToAddress2>41 RICHFONT CRICLE</ShipToAddress2>
<ShipToAddress3>DURBAN</ShipToAddress3>
<ShipToAddress3Loc/>
<ShipToAddress4>KZB</ShipToAddress4>
<ShipToAddress5>SOUTH AFRICA</ShipToAddress5>
<ShipToAddress6>4000</ShipToAddress6>
<ShipToGpsLat> 0.000000</ShipToGpsLat>
<ShipToGpsLong> 0.000000</ShipToGpsLong>
<GSTNumber/>
<LineDiscCode/>
<InvDiscCode/>
<DefaultPriceCode/>
<CompanyTaxNumber/>
<ExemptFinChg>No finance charges</ExemptFinChg>
</CustomerListDetails>
</Customer>
<ReportSummary>
<NoOfCustomersListed> 1</NoOfCustomersListed>
</ReportSummary>
</ARListOfCustomers>
</Query_With_StringResult></Query_With_StringResponse></soap:Body></soap:Envelope>
My code: Code breaks on "doc.LoadXml(decodedXml);"
public async Task<string> CreateSoapEnvelop()
{
string soapString = #"<?xml version=""1.0"" encoding=""utf-8""?>
<soap:Envelope xmlns:xsi=""http://www.w3.org/2001/XMLSchema-instance"" xmlns:xsd=""http://www.w3.org/2001/XMLSchema"" xmlns:soap=""http://schemas.xmlsoap.org/soap/envelope/"">
<soap:Body>
<Query_With_String xmlns=""http://www.syspro.com/ns/query/"">
<UserId>" + Settings.GUID + #"</UserId>
<BusinessObject></BusinessObject>
<XMLIn></XMLIn>
</Query_With_String>
</soap:Body>
</soap:Envelope>";
try
{
HttpResponseMessage response = await PostXmlRequest("http://sysprowebservices/query.asmx", soapString);
var soapResponse = await response.Content.ReadAsStringAsync();
var decodedXml = HttpUtility.HtmlDecode(soapResponse);
XmlDocument doc = new XmlDocument();
doc.LoadXml(decodedXml);
XmlNamespaceManager nsmgr = new XmlNamespaceManager(doc.NameTable);
nsmgr.AddNamespace("soap", "http://schemas.xmlsoap.org/soap/envelope/");
nsmgr.AddNamespace("ab", "http://www.syspro.com/ns/query/");
nsmgr.AddNamespace("bg", " https://bixg.choicepoint.com/webservices/3.0");
nsmgr.AddNamespace("xsd", "http://www.w3.org/2001/XMLSchema");
nsmgr.AddNamespace("xsi", "http://www.w3.org/2001/XMLSchema-instance");
XmlNode xmlnode = doc.DocumentElement.SelectSingleNode("/soap:Envelope/soap:Body/ab:Query_With_StringResponse/ab:Query_With_StringResult", nsmgr);
string customer = xmlnode.SelectSingleNode("CustomerName").InnerText;
}
catch (Exception ex)
{
string msg = ex.Message;
}
return "";
}
public static async Task<HttpResponseMessage> PostXmlRequest(string baseUrl, string xmlString)
{
using (var httpClient = new HttpClient())
{
var httpContent = new StringContent(xmlString, Encoding.UTF8, "text/xml");
httpContent.Headers.Add("SOAPAction", "http://www.syspro.com/ns/query/Query_With_String");
return await httpClient.PostAsync(baseUrl, httpContent);
}
}
UPDATE
{
HttpResponseMessage response = await PostXmlRequest("http://196.37.159.30/sysprowebservices/query.asmx", soapString);
var soapResponse = await response.Content.ReadAsStringAsync();
XmlDocument doc = new XmlDocument();
doc.LoadXml(soapResponse);
XmlNamespaceManager nsmgr = new XmlNamespaceManager(doc.NameTable);
nsmgr.AddNamespace("soap", "http://schemas.xmlsoap.org/soap/envelope/");
nsmgr.AddNamespace("ab", "http://www.syspro.com/ns/query/");
nsmgr.AddNamespace("bg", " https://bixg.choicepoint.com/webservices/3.0");
nsmgr.AddNamespace("xsd", "http://www.w3.org/2001/XMLSchema");
nsmgr.AddNamespace("xsi", "http://www.w3.org/2001/XMLSchema-instance");
XmlNode xmlnode = doc.DocumentElement.SelectSingleNode("/soap:Envelope/soap:Body/ab:Query_With_StringResponse/ab:Query_With_StringResult", nsmgr);
var xmlDecoded = HttpUtility.HtmlDecode(xmlnode.ToString());
}
Update Response from XmlDecode: "System.Xml.XmlElement"
First of all, don't roll your own SOAP client unless you know very well what you're doing. Can't you use WCF instead?
But you have a SOAP call that returns ... XML. You can't just decode the entire response as if it were HTML, because then the encoding of the inner XML will be lost, resulting in an invalid XML document.
You need to read the repsonse first, then obtain the inner XML string and then decode that:
XmlDocument doc = new XmlDocument();
doc.LoadXml(soapResponse);
XmlNamespaceManager nsmgr = new XmlNamespaceManager(doc.NameTable);
nsmgr.AddNamespace("soap", "http://schemas.xmlsoap.org/soap/envelope/");
nsmgr.AddNamespace("ab", "http://www.syspro.com/ns/query/");
nsmgr.AddNamespace("bg", " https://bixg.choicepoint.com/webservices/3.0");
nsmgr.AddNamespace("xsd", "http://www.w3.org/2001/XMLSchema");
nsmgr.AddNamespace("xsi", "http://www.w3.org/2001/XMLSchema-instance");
XmlNode xmlnode = doc.DocumentElement.SelectSingleNode("/soap:Envelope/soap:Body/ab:Query_With_StringResponse/ab:Query_With_StringResult", nsmgr);
Now xmlnode holds the encoded XML. Decode that and do whatever you want with it:
var decodedXml = HttpUtility.HtmlDecode(xmlnode.InnerXml);
I'm trying to load rss feed by XDocument.
The url is:
http://www.ft.com/rss/home/uk
XDocument doc = XDocument.Load(url);
But I'm getting an error:
Cannot open 'http://www.ft.com/rss/home/uk'. The Uri parameter must be a file system relative or absolute path.
XDocument.Load does not take URL's, only files as stated in the documentation.
Try something like the following code which I totally did not test:
using(var httpclient = new HttpClient())
{
var response = await httpclient.GetAsync("http://www.ft.com/rss/home/uk");
var xDoc = XDocument.Load(await response.Content.ReadAsStreamAsync());
}
I need information from imdb unoffical api "omdbapi".I am sending link in correct but when I get response the document is null.I am using htmlagiltypack.what am I doing wrong?
here is direct link:http://www.omdbapi.com/?i=tt2231253&plot=short&r=xml
string url = "http://www.omdbapi.com/?i=" + ImdbID + "&plot=short&r=xml";
HtmlWeb source = new HtmlWeb();
HtmlDocument document = source.Load(url);
Its no Html but a XML document you expect. Try this instead:
string url = "http://www.omdbapi.com/?i=tt2231253&plot=short&r=xml";
WebClient wc = new WebClient();
XDocument doc = XDocument.Parse(wc.DownloadString(url));
Console.WriteLine(doc);
I trying to convert JSON output into XML. Unfortunately I get this error:
JSON root object has multiple properties. The root object must have a single property in order to create a valid XML document. Consider specifing a DeserializeRootElementName.
This is what I up to now created.
string url = string.Format("https://graph.facebook.com/{0}?fields=posts.fields(message)&access_token={1}", user_name, access_token);
HttpWebRequest request = WebRequest.Create(url) as HttpWebRequest;
using (HttpWebResponse response = request.GetResponse() as HttpWebResponse)
{
StreamReader reader = new StreamReader(response.GetResponseStream());
jsonOutput = reader.ReadToEnd();
Console.WriteLine("THIS IS JSON OUTPUT: " + jsonOutput);
}
XmlDocument doc = (XmlDocument)JsonConvert.DeserializeXmlNode(jsonOutput);
Console.WriteLine(doc);
And this is my JSON output:
{"id":"108013515952807","posts":{"data":[{"id":"108013515952807_470186843068804","created_time":"2013-05-14T20:43:28+0000"},{"message":"TEKST","id":"108013515952807_470178529736302","created_time":"2013-05-14T20:22:07+0000"}
How can I solve this problem?
Despite the fact your JSON provided in the question is not complete, you have multiple properties at the top level as indicated by the exception. You have to define the root for it to get valid XML:
var doc = JsonConvert.DeserializeXmlNode(jsonOutput, "root");
EDIT: In order to print out your XML with indentation you can use XDocument class from System.Xml.Linq namespace: XDocument.Parse(doc.InnerXml).
I thought it's worth linking to the Documentation for turning xml to json and the other way around.
The guys are right..
// To convert an XML node contained in string xml into a JSON string
XmlDocument doc = new XmlDocument();
doc.LoadXml(xml);
string jsonText = JsonConvert.SerializeXmlNode(doc);
// To convert JSON text contained in string json into an XML node
XmlDocument doc = (XmlDocument)JsonConvert.DeserializeXmlNode(json);
You can do JSON-to-XML also by using the .NET Framework (System.Runtime.Serialization.Json):
private static XDocument JsonToXml(string jsonString)
{
using (var stream = new MemoryStream(Encoding.ASCII.GetBytes(jsonString)))
{
var quotas = new XmlDictionaryReaderQuotas();
return XDocument.Load(JsonReaderWriterFactory.CreateJsonReader(stream, quotas));
}
}
DeserializeXmlNode returns XDcument.
If needed XNode use FirstNode.
//string jsonOutput="{"id":"108013515952807","posts":{"data":[{"id":"108013515952807_470186843068804","created_time":"2013-05-14T20:43:28+0000"},{"message":"TEKST","id":"108013515952807_470178529736302","created_time":"2013-05-14T20:22:07+0000"}";
var myelement= JsonConvert.DeserializeXmlNode(jsonOutput, "myelement").FirstNode;
Your shared JSON is invalid please go through http://jsonformatter.curiousconcept.com/ and validate your JSON first.
Yourt JSON should look like:
{
"id":"108013515952807",
"posts":{
"data":[
{
"id":"108013515952807_470186843068804",
"created_time":"2013-05-14T20:43:28+0000"
},
{
"message":"TEKST",
"id":"108013515952807_470178529736302",
"created_time":"2013-05-14T20:22:07+0000"
}
]
}
}
Adding on #jwaliszko's answer, converting json to XDocument:
XDocument xml = JsonConvert.DeserializeXNode(json);
Hi i have the xml document in my asp.net web application . I want to assign the xml document to a string and pass that string to a asp.net webservice. Can anyone able to help me to do this ?
Thank you
May be you need this:
XmlDocument xmlDoc = new XmlDocument();
StringWriter stringWriter = new StringWriter();
XmlTextWriter textWriter = new XmlTextWriter(stringWriter);
xmlDoc.WriteTo(textWriter);
string xmlText = stringWriter.ToString();
Try this code:
XmlDocument xml = new XmlDocument();
xml.Load("file1.xml");
string xmlString = xml.OuterXml;
and you can pass the xmlString.