I have a feeling that Im am missing something obvious but:
I have a single row of pictures in a form, in theory the pictures could go on forever. I need a scroll bar so that the user can look at all of the pictures in the row. I know I need to enable auto scroll but I have no idea how to enable it. Can someone tell me how to enable it or something that I am missing?
If it helps this is the code i am using to generate the pictures:
private void imagePalletToolStripMenuItem_Click(object sender, EventArgs e)
{
MyPalletGui.Show();
Dictionary<string,Bitmap> MyPallet = MyImageCollection.ToDictionary();
int xcor = -50;
int ycor = 0;
foreach (Bitmap curtImage in MyPallet.Values){
PictureBox myPicBox = new PictureBox();
xcor += 50;
myPicBox.Location = new Point(xcor, ycor);
myPicBox.Width = 50;
myPicBox.Height = 50;
myPicBox.Visible = true;
myPicBox.Image = new Bitmap(curtImage);
this.MyPalletGui.Controls.Add(myPicBox);
This code will do exactly what you want, it uses the Form as the ViewPort with AutoScroll:
public Form1()
{
InitializeComponent();
PopulatePictures();
}
private void PopulatePictures()
{
this.AutoScroll = true;
string[] list = Directory.GetFiles(#"C:\\Users\\Public\\Pictures\\Sample Pictures", "*.jpg");
PictureBox[] picturebox= new PictureBox[list.Length];
int y = 100;
for (int index = 0; index < picturebox.Length; index++)
{
picturebox[index] = new PictureBox();
this.Controls.Add(picturebox[index]);
picturebox[index].Location=new Point(index * 120, y);
if(x%12 == 0)
y = y + 150;
picturebox[index].Size = new Size(100,120);
picturebox[index].Image = Image.FromFile(list[index]);
}
}
Related
I am absolutely new with C#, so I hope my question is not completely off.
As you can see in the picture above, I have a form, in which there is a table (image) and a button. In the resources of the project, I have another image (black_rectangle.png), which is a black rectangle, exactly at the same size of each the table's cell. This is what I'm trying to achieve:
Each time the 'Again' button is clicked, I want the six black rectangles to cover two of the tree cells in each column, in a random manner. For example, after the first try, the table could look like this:
I'm basically stuck at the beginning:
public partial class Form1 : Form
{
public Form1()
{
InitializeComponent();
}
private void button1_Click(object sender, EventArgs e)
{
Random rand = new Random();
List<PictureBox> items = new List<PictureBox>();
PictureBox newPic= new PictureBox();
newPic.Height = 50;
newPic.Width = 50;
newPic.BackColor = Color.Maroon;
int x = rand.Next(10, this.ClientSize.Width - newPic.Width);
int y = rand.Next(10, this.ClientSize.Height - newPic.Height);
newPic.Location = new Point(x, y);
}
}
Assuming the table (image) is in "pictureBox1", you could try something like:
private Random rnd = new Random();
private List<int> positions = new List<int> { 0, 1, 2 };
private List<PictureBox> prevBoxes = new List<PictureBox>();
private void button1_Click(object sender, EventArgs e)
{
prevBoxes.ForEach(pb => pb.Dispose()); // remove previous boxes
for(int col=0; col<3; col++)
{
positions = positions.OrderBy(i => rnd.Next()).ToList(); // shuffle positions
for(int i=0; i<2; i++)
{
PictureBox newPic = new PictureBox();
newPic.Height = 50;
newPic.Width = 50;
newPic.BackColor = Color.Maroon;
newPic.Location = new Point(pictureBox1.Left + (col * 50), pictureBox1.Top + (positions[i] * 50));
this.Controls.Add(newPic);
newPic.BringToFront();
prevBoxes.Add(newPic);
}
}
}
Output:
I have a panel in Visual Studio/windows form app.But I coulnd't add pictureBox on it with code.It is working if I work without panel however I need it.MyCodes:
PictureBox[] pipe = new PictureBox[3];
private void Form1_Load(object sender, EventArgs e)
{
CreatePipes(1);}
private void CreatetopPipes(int Number)
{
for (int i = 0; i <= Number; i++)
{
PictureBox temp = new PictureBox();
this.Controls.Add(temp);
temp.Width = 50;
temp.Height = 350;
temp.BorderStyle = BorderStyle.FixedSingle;
temp.BackColor = Color.Red;
temp.Top = 30;
temp.Left = 300;
topPipe[i] = temp;
topPipe[i].Visible = true;
}
}
You can use panelName.Controls.Add(temp), and i advise you to change a top of PictureBox in for loop to view all PictureBox, like this :
private void CreatetopPipes(int Number)
{
for (int i = 0; i <= Number; i++)
{
PictureBox temp = new PictureBox();
panelName.Controls.Add(temp);
temp.Width = 50;
temp.Height = 350;
temp.BorderStyle = BorderStyle.FixedSingle;
temp.BackColor = Color.Red;
temp.Top = temp.Height * panelName.Controls.Count;
temp.Left = 300;
topPipe[i] = temp;
topPipe[i].Visible = true;
}
}
I am trying to make a simple five in a row (gomoku) game for two players using windows forms and c#. I put a picturebox with a picture and stretched it out on the form. Now I want to put labels at all the intersections on the picture board so a user can click them and change their background color to black or white.
How can I make the labels created clickable on the form?
public partial class Form1 : Form
{
int labelCount = 0;
int iteration = 0;
public Form1()
{
InitializeComponent();
Label[] board = new Label[361];
for (int i = 0; i < 361; i++)
{
board[i] = new Label
{
Name = "label" + i,
Height = 55,
Width = 55,
MinimumSize = new Size(55, 55),
Text = "label " + i
};
}
int x = 0;
int y = 0;
foreach (var Label in board)
{
if (x >= 580)
{
x = 0;
y = y + Label.Height + 55;
}
Label.Location = new Point(x, y);
this.Controls.Add(Label);
x += Label.Width;
}
}
}
Should I make a one-dimensional [361] or two-dimensional array[{A,1}, {A,2}....{D,1}] to easily check for a winner? How can I connect it to the created labels so the array data corresponds to the objects on the board?
Well Sorry If don`t understand your question. For the Q.1 to add 361 labels you can try the code below. I hope it will help you.
public int x = 0;
public int y = 0;
private Label[] moku = new Label[361];
private void Form1_Load(object sender, EventArgs e)
{
try
{
for (int i = 0; i < 361; i++)
{
moku[i] = new Label();
moku[i].Parent = pictureBox1;//make the picturebox parent
moku[i].Location = new Point(x, y);
moku[i].Text = "O";
moku[i].Name = "moku" + i;
moku[i].BackColor = Color.Transparent;
pictureBox1.Controls.Add(moku[i]);
y += 55;
if (y >= 361) { x += 55; y = 0; x+=55; }
}
}catch(Exception er)
{
MessageBox.Show(er.ToString());
}
}
I prefer using a 2D array because it's easier if you want to check the surrounding boxes.
Form design:
Full source:
using System;
using System.Drawing;
using System.Windows.Forms;
namespace WindowsFormsApplication6
{
public enum Player
{
Empty = 0,
White,
Black
}
public partial class Form1 : Form
{
// initialize board of 5x5
private Player[,] board = new Player[5, 5];
public Form1()
{
InitializeComponent();
}
private void Form1_Load(object sender, EventArgs e)
{
DrawBoard();
}
private void DrawBoard()
{
for (var i = 0; i <= board.GetUpperBound(0); i++)
{
for (var j = 0; j <= board.GetUpperBound(1); j++)
{
// for name and text
var name = string.Format("{0}, {1}", i, j);
var label = new Label()
{
Name = name, // name of label
Size = new Size(55, 55),
BorderStyle = BorderStyle.FixedSingle,
Location = new Point(i * 55, j * 55), // location depends on iteration
Text = name
};
label.Click += ClickLabel; // subscribe the Click event handler
pictureBox1.Controls.Add(label); // add label to a container
}
}
}
// this event handler will handle all the labels click event
private void ClickLabel(object sender, EventArgs e)
{
var label = (Label)sender; // this is the label that you click
var x = Convert.ToInt32(label.Name.Split(',')[0]);
var y = Convert.ToInt32(label.Name.Split(',')[1]);
// change the color
if (radPlayerBlack.Checked)
{
// Player Black
label.ForeColor = Color.White;
label.BackColor = Color.Black;
board[x, y] = Player.Black;
}
else
{
// Player White
label.ForeColor = Color.Black;
label.BackColor = Color.White;
board[x, y] = Player.White;
}
}
}
}
You can check the value of the 2D array for black or white. Here's the value when I QuickWatch it in Visual Studio.
I'm using Teechart for .net V3.
When trying to rotate the X-labels to 45° some of the labels are not displayed, but if the angle is set to 90° it is OK.
Please see the following images:
This is 45° rotation:
This is 90° rotation:
Is it possible to show all the labels with 45° angle?
I think you can use custom labels to achieve all labels appear when you use an angle of 45º. You can do something as next code:
private Steema.TeeChart.TChart tChart1;
public Form1()
{
InitializeComponent();
tChart1 = new Steema.TeeChart.TChart();
this.Controls.Add(tChart1);
tChart1.Left = 100;
tChart1.Top = 50;
tChart1.Width = 500;
tChart1.Height = 350;
tChart1.Dock = DockStyle.Fill;
InitialzieChart();
}
private void InitialzieChart()
{
Steema.TeeChart.Styles.Bar bar1 = new Steema.TeeChart.Styles.Bar(tChart1.Chart);
DateTime dt = DateTime.Today;
Random rnd = new Random();
bar1.XValues.DateTime = true;
//bar1.date
for (int i = 0; i < 20; i++)
{
bar1.Add(dt, rnd.Next(100));
dt = dt.AddDays(5);
}
tChart1.Axes.Bottom.Labels.Angle = 45;
tChart1.Panel.MarginLeft = 10;
tChart1.Legend.Alignment = Steema.TeeChart.LegendAlignments.Bottom;
AddCustomLabels();
}
private void AddCustomLabels()
{
tChart1.Axes.Bottom.Labels.Items.Clear();
for (int i = 0; i < tChart1[0].Count; i++)
{
tChart1.Axes.Bottom.Labels.Items.Add(tChart1[0].XValues[i], DateTime.FromOADate(tChart1[0].XValues[i]).ToLongDateString());
}
}
Could you tell us if previous code works in your end?
Thanks,
I'm very new to visual C# I want to display an array of images in a picture box
Here's my code:
string[] list = Directory.GetFiles(#"C:\\pictures", "*.jpg");
Image[] images = new Image[5];
for (int index = 0; index < 5; index++)
{
//HERE IS WHERE IM STUCKED WITH
picturebox[index] = Image.FromFile(list[index]);
}
Edit-1 : This answer has a scope limited to Win-Forms C#.
You need certain assemblies added in your application before using this code.
using System.IO;
using System.Windows.Forms;
Edit ended;
Original Answer
You have to draw all image to one image for displaying them in single picturebox
That is bit complex you can use mutiple pictureboxes
In following code they are created dynamically according to need:
// For confirm visibility of all images set
this.AutoScroll = true;
string[] list = Directory.GetFiles(#"C:\pictures", "*.jpg");
PictureBox[] picturebox= new PictureBox[list.Length];
int y = 0;
for (int index = 0; index < picturebox.Length; index++)
{
this.Controls.Add(picturebox[index]);
// Following three lines set the images(picture boxes) locations
if(index % 3 == 0)
y = y + 150; // 3 images per rows, first image will be at (20,150)
picturebox[index].Location=new Point(index * 120 + 20, y);
picturebox[index ].Size = new Size(100,120);
picturebox[index].Image = Image.FromFile(list[index]);
}
The answer provided throws an object reference exception. Otherwise thanks for the example!
for (int index = 0; index < picturebox.Length; index++)
{
this.Controls.Add(picturebox[index]);
// Following three lines set the images(picture boxes) locations
should be
for (int index = 0; index < picturebox.Length; index++)
{
picturebox[index] = new PictureBox();
this.Controls.Add(picturebox[index]);
// Following three lines set the images(picture boxes) locations
Use picturebox[index].Image = Image.FromFile(list[index]);
//this code help you to work with picturebox in arraye
public partial class Form_Begin : Form
{
PictureBox[] pictureBoxs = new PictureBox[50];
public Form_Begin()
{
InitializeComponent();
pictureBoxs[0] = pictureBox1;
pictureBoxs[1] = pictureBox2;
pictureBoxs[2] = pictureBox3;
pictureBoxs[3] = pictureBox4;}
List<PictureBox> pictureBoxes = new List<PictureBox>();
private void buttonX1_Click(object sender, EventArgs e)
{
for (int i = 0; i <2; i++)
{
pictureBoxs[i].Image =your_name_project.Properties.Resources.Image_1; // Load Image_1 from Resources on property of picturebox
}
for (int i = 2; i < 4; i++)
{
pictureBoxs[i].Image =your_name_project.Properties.Resources.Image_2; // Load Image_12 from Resources on property of picturebox
}
private void picbutton_Click(object sender, EventArgs e)
{
OpenFileDialog open = new OpenFileDialog();
PictureBox[] picture = new PictureBox[5];
int x = 0;
int y = 15;
for (int index = length; index < picture.Length; index++)
{
picture[index] = new PictureBox();
picture[index].Size = new Size(100, 50);
open.Title = "OPen Image";
open.Filter = "JPG Files (*.jpg)|*.jpg|JPEG Files (*.jpeg)|*.jpeg|PNG Files (*.png)|*.png|GIF Files (*.gif)|*.gif";
DialogResult result = open.ShowDialog();
if (result == DialogResult.OK)
{
picture[index].BackgroundImage = new Bitmap(open.FileName);
picture[index].SizeMode = PictureBoxSizeMode.AutoSize;
listBox1.Controls.Add(picture[index]);
if ((x % 3 == 0) && (index != 0))
{
y = y + 150; // 3 images per rows, first image will be at (20,150)
x = 0;
}
picture[index].Location = new Point(x * 210 + 20, y);
picture[index].Size = new Size(200, 150);
x++;
}
}
}