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c# WPF MVVM TabControl with Multiple ViewModels and changing tabs

So I currently have a Window with a TabControl. The MainWindow has its own ViewModel and all the TabItems have their own ViewModels also.
I can easily change tabs from the MainWindow ViewModel through a bound SelectedIndex property. What I would like to do is change to another tab from code that runs within ANOTHER tab viewmodel. Since the Tabs are not part of the MainWindowViewModel, I am looking for a clean way to change the Tab without resorting to code behind to do it.
There are also cases, where I might need to change the tab from something such as a message prompt. I thinking my only way is to create and event and subscribe to that from MainWindowViewModel.

So I solved this with an EventAggregator.
public static class IntAggregator
{
public static void Transmit(int data)
{
if (OnDataTransmitted != null)
{
OnDataTransmitted(data);
}
}
public static Action<int> OnDataTransmitted;
}
First ViewModel sends data.
public class ModifyUsersViewModel : INotifyPropertyChanged
{
private void change_tab(int data)
{
IntAggregator.Transmit(data);
}
}
Second ViewModel receives data and then does something with it.
public class MainWindowViewModel : INotifyPropertyChanged
{
private int _Tab_SelectedIndex = 0;
public int Tab_SelectedIndex
{
get
{
return _Tab_SelectedIndex;
}
set
{
_Tab_SelectedIndex = value;
OnPropertyChanged(new PropertyChangedEventArgs("Tab_SelectedIndex"));
}
}
public MainWindowViewModel()
{
IntAggregator.OnDataTransmitted += OnDataReceived;
}
private void OnDataReceived(int data)
{
Tab_SelectedIndex = data;
}
}

Rather than trying to bind to SelectedIndex, if the TabItems have their own view models, then you can create a property for each of those view models: IsSelected and then bind the TabItem.IsSelected property to that:
<TabItem IsSelected="{Binding IsSelected}">
This prevents the view models from needing to know the index of their corresponding TabItem, something I would argue is a detail that should be specific to the view and something the view model should not concern itself with. What if you add another TabItem or want to change the order? Now you've got changes to make in the view models for something that could be just simple change to the view.

How to change UserControl in background?

I am stuck with a problem where I want to change user control on different events in background. I am new in MVVM but I am bound to use MVVM only to achive this task. Code structure is little complex to me but still I figured that New Employee form is getting shown on button click but in new window but I want that form to be opened in current window's content. Code is given here which I need to modify to open usercontrol.
public Task<bool?> InitModification(CoreViewModel vm)
{
var tcs = new TaskCompletionSource<bool?>();
_dispatcherService.CurrentDispatcher.BeginInvoke(new Action(() =>
{
bool? result = null;
Window activeWindow = null;
for (var i = 0; i < Application.Current.Windows.Count; i++)
{
var win = Application.Current.Windows[i];
if ((win != null) && (win.IsActive))
{
activeWindow = win;
break;
}
}
if (activeWindow != null)
{
var win = new NewEmp(vm) { Owner = activeWindow };
result = win.ShowDialog();
}
tcs.SetResult(result);
}));
return tcs.Task;
}

My answer will not use your code since I don't find it useful to what you want to achieve. My answer will suffice with a suggestion on how you can achieve changing content control with MVVM
The way I go about it is with every MVVM-project I have a "application-shell" that acts as a wrapper for all my other content and through that you can easily change content. This application is a View and a ViewModel like such.
ShellView
<xmlns:ViewModel="clr-namespace:WhereOurViewModelIs.ViewModel">
<!--More XAML code-->
<Window.Resources>
<DataTemplate DataType="{x:Type ViewModel:MyViewModel}">
<Views:MyView/>
</DataTemplate>
<DataTemplate DataType="{x:Type ViewModel:AnotherViewModel}">
<Views:AnotherView/>
</DataTemplate>
</Window.Resources>
<ContentControl Content="{Binding CurrentPage}"/>
ShellViewModel
public class ShellViewModel
{
private BaseViewModel _currentPage{get;set;}
Public BaseViewModel CurrentPage{
get{return _currentPage;}
set{_currentPage = value; OnPropertyChanged();}
}
public ShellViewModel
{
CurrentPage = new MyViewModel();
}
}
Since we don't know how many different pages there is (in theory) we will tell them that need to be a of a type (inherited or an object) of BaseViewModel. This way we don't need to check for every single page and remove redundant code.
Then you set the Datacontext = new ShellViewModel(); in behind code of ShellView.xaml
BaseViewModel
public class BaseViewModel
{
/*This class can contains whatever you want your other ViewModels to be able to do*/
}
Now you need to set up 2 ViewModels with 2 Views just like we did with our shell.
MyViewModel
public class MyViewModel:BaseViewModel
{
/*Contains Properties,methods,private fields. What you want to show on view*/
}
AnotherViewModel
public class AnotherViewModel:BaseViewModel
{
/*Contains Properties,methods,private fields. What you want to show on view*/
}
Now you can set event to your ShellViewModel to change content whenever something happens. Hopefully this can atleast give you some idea how to work with MVVM. Of course you need to set up our ViewModels with properties changed event and other to get everything working, but this is a start for you.
If you find this answer helpful please chose it as an answer since it take some time to make an example like this.

Advice on Views navigation using Caliburn.Micro MVVM WPF

I'm new on Caliburn Micro and want some advice on which path to take to devolop my app interface and navigation between views.
My idea is to have a MainWindow which will contain a menu of buttons, each one related with a specific view. Each view will be stored in a separated WPF UserControl. The mainWindow will also contain a TabControl bound to an ObservableCollection of tabs on viewmodel. Everytime a button on menu is clicked, I want to add a new tab with a ContentPresenter inside that will dynamically load a view and its corresponding viewmodel.
So my questions:
1) Should I use a Screen Collection here?
2) Should the UserControl implement Screen interface?
3) How do I tell MainWindow ViewModel which view to load on the new added tab maintaining viewmodels decoupled?
Thanks to everyone in advance.
UPDATE
After a lot of reading and some help of the community I managed to resolve this. This is the resultant AppViewModel:
class AppViewModel : Conductor<IScreen>.Collection.OneActive
{
public void OpenTab(Type TipoVista)
{
bool bFound = false;
Screen myScreen = (Screen)Activator.CreateInstance(TipoVista as Type);
myScreen.DisplayName = myScreen.ToString();
foreach(Screen miItem in Items)
{
if (miItem.ToString() == myScreen.ToString())
{
bFound = true;
ActivateItem(miItem);
}
}
if (!bFound) ActivateItem(myScreen);
}
public ObservableCollection<MenuItem> myMenu { get; set; }
public ObservableCollection<LinksItem> myDirectLinks { get; set; }
public ICommand OpenTabCommand
{
get
{
return new RelayCommand(param => this.OpenTab((Type) param), null);
}
}
public AppViewModel()
{
OpenTab(typeof(ClientsViewModel));
MenuModel menu = new MenuModel();
myMenu = menu.getMenu();
myDirectLinks = menu.getLinks();
}
public void CloseTab(Screen param)
{
DeactivateItem(param, true);
}
}
I have to keep the ICommand from OpenTabCommand because the name convention of Caliburn.micro doesn't seems to work inside DataTemplate. Hope it could help someone else. Thanks to all

I've done something very similar using Caliburn.Micro, and based it on the SimpleMDI example included with the examples, with a few tweaks to fit my needs.
Much like in the example, I had a main ShellViewModel:
public class ShellViewModel : Conductor<IScreen>.Collection.OneActive
{
}
with a corresponding ShellView containing a TabControl - <TabControl x:Name="Items">, binding it to the Items property of the the Conductor.
In this particular case, I also had a ContextMenu on my ShellView, bound (using the Caliburn.Micro conventions), to a series of commands which instantiated and Activated various other ViewModels (usually with a corresponding UserControl, using the ActivateItem method on the Conductor.
public class YourViewModel: Conductor<IScreen>.Collection.OneActive
{
// ...
public void OpenItemBrowser()
{
// Create your new ViewModel instance here, or obtain existing instance.
// ActivateItem(instance)
}
}
In that case, I didn't require the ViewModels to be created with any particular dependency, or from any other locations in the program.
At other times, when I've needed to trigger ViewModel from elsewhere in the application, I've used the Caliburn.Micro EventAggregator to publish custom events (e.g. OpenNewBrowser), which can be handled by classes implementing the corresponding interface (e.g. IHandle<OpenNewBrowser>), so your main ViewModel could have a simple Handle method responsible for opening the required View:
public class YourViewModel: Conductor<IScreen>.Collection.OneActive, IHandle<OpenNewBrowser>
{
// ...
public void Handle(OpenNewBrowser myEvent)
{
// Create your new ViewModel instance here, or obtain existing instance.
// ActivateItem(instance)
}
}
This section of the documentation will probably be useful, especially the Simple MDI section.
Additional code I mentioned in the comments:
I sometimes use a generic method along these lines ensure that if I have an existing instance of a screen of a particular type, switch to it, or create a new instance if not.
public void ActivateOrOpen<T>() where T : Screen
{
var currentItem = this.Items.FirstOrDefault(x => x.GetType() == typeof(T));
if (currentItem != null)
{
ActivateItem(currentItem);
}
else
{
ActivateItem(Activator.CreateInstance<T>());
}
}
Used like:
public void OpenBrowser()
{
this.ActivateOrOpen<BrowserViewModel>();
}

Correct approach to UserControl creation when using MVVM

This is more of a conceptual question rather than a practical one. I'm just starting to learn the MVVM concept for developing UI , and I've come across a dillema I'm not sure the answer to:
Say I have a main window and a little pop-up window (meaning it's a small window with some UI elements in it). The structure of the program will look something like this:
MainWindow
model <-- MainWindowViewModel.cs <-- MainWindowView.xaml (containing no code-behind)
PopUpWindow (A UserControl)
model <-- PopUpWindowViewModel.cs <-- PopUpWindowView.xaml (containing no code-behind)
*the model is just a bunch of BL classes that are irrelevant for this question.
Now , lets say I want to create a new PopUp window from inside the MainWindowViewModel (or even save an instance of it in a private data-member). What is the correct way of doing so?
The way I see it I can't do something like this :
PopUpWindow pop = new PopUpWindow()
Because it kind of defeats the purpose of abstracting the view from the view model(What if a year from now i'll want to create a better version of the PopUpWindow using the same PopUpWindowViewModel?).
On the other hand , I can't initialize a new instnace of the PopUpWindow using just it's view model (The viewModel as I understand is not supposed to know anything about the view that will use it).
Hope it all makes sense... so what would you do in that situation?
*Just to clarify it further , let's say for argument's sake that the situation I'm describing is a button on the MainWindowView that upon clicking will open a PopUpWindowView.
Thanks in advnace.

I had somewhat a similar dilemma and I'll explain how I solved it.
Let's say you have MainWindow and a SettingsWindow, which you want to display when the SettingsButton is clicked.
You have two respective view models, MainWindowViewModel and SettingsViewModel, which you will be passing as their Window.DataContext properties.
Your MainWindowViewModel should expose an ICommand property named SettingsButtonCommand (or similar). Bind this command to the SettingsButton.Command.
Now your command should invoke something like this:
void OnSettingsButtonClicked()
{
var viewModel = new SettingsViewModel();
var window = new SettingsWindow();
window.DataContext = viewModel;
window.Show();
}
There is a slight issue when you want to use Window.ShowDialog(), because you need to resume execution.
For these cases I have an asynchronous variant of the DelegateCommand:
public sealed class AsyncDelegateCommand : ICommand
{
readonly Func<object, Task> onExecute;
readonly Predicate<object> onCanExecute;
public event EventHandler CanExecuteChanged
{
add { CommandManager.RequerySuggested += value; }
remove { CommandManager.RequerySuggested -= value; }
}
public AsyncDelegateCommand(Func<object, Task> onExecute)
: this(onExecute, null) { }
public AsyncDelegateCommand(Func<object, Task> onExecute, Predicate<object> onCanExecute)
{
if (onExecute == null)
throw new ArgumentNullException("onExecute");
this.onExecute = onExecute;
this.onCanExecute = onCanExecute;
}
#region ICommand Methods
public async void Execute(object parameter)
{
await onExecute(parameter);
}
public bool CanExecute(object parameter)
{
return onCanExecute != null ? onCanExecute(parameter) : true;
}
#endregion
}

You've specifically said that the popup is a UserControl so you can use basic data templating. First create view models for your main window and popup control:
public class MainViewModel : ViewModelBase
{
private PopUpViewModel _PopUp;
public PopUpViewModel PopUp
{
get { return _PopUp; }
set { _PopUp = value; RaisePropertyChanged(() => this.PopUp); }
}
}
public class PopUpViewModel : ViewModelBase
{
private string _Message;
public string Message
{
get { return _Message; }
set { _Message = value; RaisePropertyChanged(() => this.Message); }
}
}
The MainViewModel's PopUp member is initially null, we'll set it to an instance of PopUpViewModel when we want the popup to appear. To do that we create a content control on the main window and set it's content to that member. We also use a data template to specify the type of child control to create when the popup view model has been set:
<Window.Resources>
<DataTemplate DataType="{x:Type local:PopUpViewModel}">
<local:PopUpWindow />
</DataTemplate>
</Window.Resources>
<StackPanel>
<Button Content="Show PopUp" Click="Button_Click_1" HorizontalAlignment="Left"/>
<ContentControl Content="{Binding PopUp}" />
</StackPanel>
I'm doing a big no-no here by creating the view model in the code-behind along with a click handler, but it's just for illustrative purposes:
public partial class MainWindow : Window
{
MainViewModel VM = new MainViewModel();
public MainWindow()
{
InitializeComponent();
this.DataContext = this.VM;
}
private void Button_Click_1(object sender, RoutedEventArgs e)
{
this.VM.PopUp = new PopUpViewModel { Message = "Hello World!" };
}
}
That's it! Click the button, popup window appears underneath it showing the content. Now it may not always be this simple, sometimes you may want to create multiple children on a parent control...in that case you'd set up an ItemsControl, set its panel to a Grid (say) and modify the data templates to set the Margin etc on each element to position them. Or you may not always know what type of view model is going to be created, in which case you need to add multiple data templates for each type you're expecting. Either way you still have good separation of concerns because it is the views that are deciding how to display the content in the view models. The view models themselves still don't know anything about the views and they can be unit-tested etc independently.

MVVM DataBinding

I've started an MVVM project and now I'm stucking with correct DataBinding.
My project has:
A UserControl whit a ViewModel as DataContext like:
public partial class TestUserControl: UserControl
{
public TestUserControl()
{
this.DataContext = new TestUserControlViewModel();
}
}
ViewModel code is (BaseViewModel class contains PropertyChangedEventHandler):
public class TestUserControlViewModel : BaseViewModel
{
public KrankenkasseControlViewModel()
{}
public IEnumerable<DataItem> GetAllData
{
get
{
IGetTheData src= new DataRepository();
return src.GetData();
}
}
}
IGetTheData is the interface to DataContext:
public interface IGetTheData
{
IEnumerable<DataItem> GetData();
}
}
and finally the DataRepository code:
public class DataRepository : IGetTheData
{
private TestProjectDataContext dax = new TestProjectDataContext();
public IEnumerable<DataItem> GetData()
{
return (from d in this.dax.TestData
select new DataItem
{
ID = d.ID,
SomeOtherData = d.SomeOtherData
});
}
}
My UserControl has a few TextBoxes, but what's the best way to bind correctly?
Thanks for your help, regards.

EDIT: Binding the data against multiple textboxes
After reading your comment, I will elaborate my example for textboxes.
First important thing is that the ViewModel will model the things in the View, so that the View gets all information it needs in the structure it needs. That means, if you have multiple textboses in the View, you will need multiple string Properties in your ViewModel, one for each textbox.
In your XAML you could have something like
<TextBox Text="{Binding ID, Mode=TwoWay}" />
<TextBox Text="{Binding SomeOtherData, Mode=TwoWay}" />
and in your ViewModel
public class TestUserControlViewModel : BaseViewModel {
private string id;
private string someOtherData;
public TestUserControlViewModel() {
DataItem firstItem = new DataRepository().GetData().First();
this.ID = firstItem.ID;
this.SomeOtherData = firstItem.SomeOtherData;
}
public string ID {
get {
return this.id;
}
set {
if (this.id == value) return;
this.id = value;
this.OnPropertyChangedEvent("ID");
}
}
public string SomeOtherData {
get {
return this.someOtherData;
}
set {
if (this.someOtherData == value) return;
this.someOtherData = value;
this.OnPropertyChangedEvent("SomeOtherData");
}
}
}
Here I assume that in your BaseViewModel there is an OnPropertyChangedEvent method to fire the corresponding event. This tells the View that the property has changed and it must update itself.
Note the Mode=TwoWay in the XAML. This means, that it doesn't matter on which side the value changes, the other side will reflect the change immediately. So if the user changes a value in a TwoWay bound TextBox, then the corresponding ViewModel property will automatically change! And also vice versa: if you change the ViewModel property programmatically, the View will refresh.
If you want to show multiple textboxes for more than one data item, then you must introduce more Properties in the ViewModel and bind them accordingly. Maybe a ListBox with a flexible number of TextBoxes inside is a solution then, like #Haspemulator already answered.
Binding the data against a collection control
In the TestUserControl I guess you have a control (like a ListView) to show the list of loaded things. So bind that control against the list in the ViewModel with
<ListView ... ItemsSource="{Binding GetAllData}" ... />
First you must understand that Binding means not "read the data and then forget the ViewModel". Instead you bind the View to the ViewModel (and its Properties) as long as the View lasts. From this point of view, AllData is a much better name than GetAllData (thanks #Malcolm O'Hare).
Now in your code, every time the View reads the AllData property, a new DataRepository is created. Because of the Binding, that is not what you want, instead you want to have one instance of DataRepository for the whole lifetime of the View, which is used to read the initial data and can later be used to update the View, if the underlying database changes (maybe with an event).
To enable such a behavior you should change the type of the AllData property to an ObservableCollection, so that the View can automatically update the list if changes occur.
public class TestUserControlViewModel : BaseViewModel
private ObservableCollection<DataItem> allData;
public TestUserControlViewModel() {
IGetTheData src = new DataRepository();
this.allData = new ObservableCollection<DataItem>(src.GetData());
}
public ObservableCollection<DataItem> AllData {
get {
return this.allData;
}
}
public void AddDataItem(DataItem item) {
this.allData.Add(item);
}
}
Now if you call AddDataItem later, the ListView will update itself automatically.

Your Property Name is bad. You should call it AllData, not GetAllData.
Since you are returning a collection, you probably should be using some sort of list control (ListBox, ListView).
In that case you'd be doing
<ListBox ItemsSource="{Binding GetAllData}" />

Guten Abend. :) As it already mentioned, since you're returning the collection, it's better to use a ListBox. The comment about having ObservableCollection as a cache is also absolutely valid. I would add that if you need to have your data editable, you should use TextBox inside the ItemTemplate:
<ListBox.ItemTemplate>
<DataTemplate>
<TextBox Text={Binding SomeOtherData,Mode=TwoWay} />
</DataTemplate>
</ListBox.ItemTemplate>
In this case if user edits the text in the box, data will be updated in your data object, so that it could be saved in the database later.