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how to detect input that is not in english?

I'm trying to detect if input is not in English chars, will disallow the input and i'm using code below to validate the input. The code works fine if the input is in Non-English, for example, 'ກັ​ຫ​ກ່​ຫ່', '你好'. When the input contains English chars and Non-English chars, the code below will allow the input to go through and i don't want this to happen. How can i disallow the input if there is any Non-English chars detected in the input?
If Not Regex.IsMatch(Edt.Text, "[A-Za-z0-9]") Then
End If

Use this regex:
^[A-Za-z0-9]*$

That Regex.IsMatch call will succeed if Edt.Text contains any Latin letter or Arabic digit.
First, you'll need to define the problem more clearly; in particular, you'll need to decide exactly which characters are permitted (think about spaces and punctuation).
Then you'll need to modify the regular expression so it matches the entire string, probably something like:
"^[something]*$"
where something is left as an exercise.

Password Regex (client side javascript)

I need a regex for the following criteria:
Atleast 7 alphanumeric characters with 1 special character
I used this:
^.*(?=.{7,})(?=.*\d)(?=.*[a-z])(?=.*[A-Z])(?=.*[##$!%^&+=]).*$
It works fine if I type Password1! but doesnt work for PASSWORD1!.
Wont work for: Stmaryshsp1tal!
I am using the Jquery validation plugin where I specify the regex.
When I use a regular expression validator and specify the following regex:
^.*(?=.{7,})(?=(.*\W){1,}).*$
It works perfectly without any issues. When I set this regex in the Jquery validation I am using it doesnt work.
Please can someone shed some light on this? I want to understand why my first regex doesnt work.

(?=.\d)(?=.[a-z])
tries to match a digit and an alphanumeric character at the same place. Remember that (?= ... ) does not glob anything.
What you want is probably:
^(?=.*\W)(?=(.*\w){7})
This is exactly the same as veryfying that your string both matches ^.*\W (at least one special character) and ^(.*\w){7}) (7 alphanumeric characters. Note that it also matches if there are more.

Try this regex:
\S*[##$!%^&+=]+\S*(?<=\S{7,})
EDIT3: Ok, this is last edit ;).
This will match also other special characters. So if you wan't limit the number of valid characters change \S to range of all valid characters.

Here is the regex , I think it can handle all possible combination..
^(?=.{7,})\w*[.##$!%^&+=]+(\w*[.##$!%^&+=]*)*$
here is the link for this regex, http://regexr.com?2tuh5

As a good tool for quickly testing regular expressions I'd suggest http://regexpal.com/ (no relations ;) ). Sometimes simplifying your expression helps a lot.
Then you might want to try something like ^[a-zA-Z0-9##$!%^&+=]{7,}$
Update 2 now including digits
^.*(?=.{7,})(?=.*\d)(?=.*[a-zA-Z])(?=.*[##$%^&+=!]).*$
This matches:
Stmarysh3sptal!, password1!, PASSWORD1P!!!!!!##^^ASSWORD1, 122ss121a212!!
... but not:
Password1, PASSWORD1PASSWORD1, PASSWORD!, Password!, 1221121212!! etc

The reason it matches Password1! but not PASSWORD1! is this clause:
(?=.*[a-z])
That requires at least one lowercase letter in the password. The pattern says that the password must be at least 7 characters long, and contain both uppercase and lowercase letters, at least one number, and at least one of ##$!%^&+=. PASSWORD1! fails because there are no lowercase letters in it.
The second pattern accepts PASSWORD1! because it's a far, far weaker password requirement. All it requires is that the password is 7+ characters and has at least one special character in it (other than _). The {1,} is unnecessary, by the way.
If I were you, I'd avoid weakening the password and just leave it as it is. If I wanted to allow all-lowercase or all-uppercase passwords for some reason, I'd simply change it to
^(?=.*\d)(?=.*[a-zA-Z])(?=.*[##$!%^&+=]).{7,}$
...thus not weakening the password requirements any more than I had to.

C# Regex: only letters followed by an optional

I am looking for a way to get words out of a sentence. I am pretty far with the following expression:
\b([a-zA-Z]+?)\b
but there are some occurrences that it counts a word when I want it not to. E.g a word followed by more than one period like "text..". So, in my regex I want to have the period to be at the end of a word zero or one time. Inserting \.? did not do the trick, and variations on this have not yielded anything fruitful either.
Hope someone can help!

A single dot means any character. You must escape it as
\.?
Maybe you want an expression like this:
\w+\.?
or
\p{L}+\.?

You need to add \.? (and not .?) because the period has special meaning in regexes.

to avoid a match on your example "test.." you ask for you not only need to put the \.? for checking first character after the word to be a dot but also look one character further to check the second character after the word.
I did end up with something like this
\w{2,}\.?[^.]
You should also consider that a sentence not always ends with a . but also ! or ? and alike.
I usually use rubulator.com to quick test a regexp

How Can I Check If a C# Regular Expression Is Trying to Match 1-(and-only-1)-Character Strings?

Maybe this is a very rare (or even dumb) question, but I do need it in my app.
How can I check if a C# regular expression is trying to match 1-character strings?
That means, I only allow the users to search 1-character strings. If the user is trying to search multi-character strings, an error message will be displaying to the users.
Did I make myself clear?
Thanks.
Peter
P.S.: I saw an answer about calculating the final matched strings' length, but for some unknown reason, the answer is gone.
I thought it for a while, I think calculating the final matched strings length is okay, though it's gonna be kind of slow.
Yet, the original question is very rare and tedious.

a regexp would be .{1}
This will allow any char though. if you only want alpanumeric then you can use [a-z0-9]{1} or shorthand /w{1}
Another option its to limit the number of chars a user can type in an input field. set a maxlength on it.
Yet another option is to save the forms input field to a char and not a string although you may need some handling around this to prevent errors.
Why not use maxlength and save to a char.

You can look for unescaped *, +, {}, ? etc. and count the number of characters (don't forget to flatten the [] as one character).
Basically you have to parse your regex.

Instead of validating the regular expression, which could be complicated, you could apply it only on single characters instead of the whole string.
If this is not possible, you may want to limit the possibilities of regular expression to some certain features. For instance the user can only enter characters to match or characters to exclude. Then you build up the regex in your code.
eg:
ABC matches [ABC]
^ABC matches [^ABC]
A-Z matches [A-Z]
# matches [0-9]
\w matches \w
AB#x-z matches [AB]|[0-9]|[x-z]|\w
which cases do you need to support?
This would be somewhat easy to parse and validate.

I need a regular expression to convert US tel number to link

Basically, the input field is just a string. People input their phone number in various formats. I need a regular expression to find and convert those numbers into links.
Input examples:
(201) 555-1212
(201)555-1212
201-555-1212
555-1212
Here's what I want:
(201) 555-1212 - Notice the space is gone
(201)555-1212
201-555-1212
555-1212
I know it should be more robust than just removing spaces, but it is for an internal web site that my employees will be accessing from their iPhone. So, I'm willing to "just get it working."
Here's what I have so far in C# (which should show you how little I know about regular expressions):
strchk = Regex.Replace(strchk, #"\b([\d{3}\-\d{4}|\d{3}\-\d{3}\-\d{4}|\(\d{3}\)\d{3}\-\d{4}])\b", "<a href='tel:$&'>$&</a>", RegexOptions.IgnoreCase);
Can anyone help me by fixing this or suggesting a better way to do this?
EDIT:
Thanks everyone. Here's what I've got so far:
strchk = Regex.Replace(strchk, #"\b(\d{3}[-\.\s]\d{3}[-\.\s]\d{4}|\(\d{3}\)\s*\d{3}[-\.\s]\d{4}|\d{3}[-\.\s]\d{4})\b", "<a href='tel:$1'>$1</a>", RegexOptions.IgnoreCase);
It is picking up just about everything EXCEPT those with (nnn) area codes, with or without spaces between it and the 7 digit number. It does pick up the 7 digit number and link it that way. However, if the area code is specified it doesn't get matched. Any idea what I'm doing wrong?
Second Edit:
Got it working now. All I did was remove the \b from the start of the string.

Remove the [] and add \s* (zero or more whitespace characters) around each \-.
Also, you don't need to escape the -. (You can take out the \ from \-)
Explanation: [abcA-Z] is a character group, which matches a, b, c, or any character between A and Z.
It's not what you're trying to do.
Edits
In response to your updated regex:
Change [-\.\s] to [-\.\s]+ to match one or more of any of those characters (eg, a - with spaces around it)
The problem is that \b doesn't match the boundary between a space and a (.

Afaik, no phone enters the other characters, so why not replace [^0-9] with '' ?

Here's a regex I wrote for finding phone numbers:
(\+?\d[-\.\s]?)?(\(\d{3}\)\s?|\d{3}[-\.\s]?)\d{3}[-\.\s]?\d{4}
It's pretty flexible... allows a variety of formats.
Then, instead of killing yourself trying to replace it w/out spaces using a bunch of back references, instead pass the match to a function and just strip the spaces as you wanted.
C#/.net should have a method that allows a function as the replace argument...
Edit: They call it a `MatchEvaluator. That example uses a delegate, but I'm pretty sure you could use the slightly less verbose
(m) => m.Value.Replace(' ', '')
or something. working from memory here.