How to get full file path from file name? - c#

How do I get the full path for a given file?
e.g. I provide:
string filename = #"test.txt";
Result should be:
Full File Path = C:\Windows\ABC\Test\test.txt

Try
string fileName = "test.txt";
FileInfo f = new FileInfo(fileName);
string fullname = f.FullName;

Use Path.GetFullPath():
http://msdn.microsoft.com/en-us/library/system.io.path.getfullpath.aspx
This should return the full path information.

You Can use:
string path = Path.GetFullPath(FileName);
it will return the Full path of that mentioned file.

Directory.GetCurrentDirectory
string dirpath = Directory.GetCurrentDirectory();
Prepend this dirpath to the filename to get the complete path.
As #Dan Puzey indicated in the comments, it would be better to use Path.Combine
Path.Combine(Directory.GetCurrentDirectory(), filename)

I know my answer it's too late, but it might helpful to other's
Try,
Void Main()
{
string filename = #"test.txt";
string filePath= AppDomain.CurrentDomain.BaseDirectory + filename ;
Console.WriteLine(filePath);
}

try..
Server.MapPath(FileUpload1.FileName);

try:
string fileName = #"test.txt";
string currentDirectory = Directory.GetCurrentDirectory();
string[] fullFilePath = Directory.GetFiles(currentDirectory, filename, SearchOption.AllDirectories);
it will return full path of all such files in the current directory and its sub directories to string array fullFilePath. If only one file exist it will be in "fullFileName[0]".

private const string BulkSetPriceFile = "test.txt";
...
var fullname = Path.GetFullPath(BulkSetPriceFile);

You can get the current path:
string AssemblyPath = Path.GetDirectoryName(System.Reflection.Assembly.GetExecutingAssembly().Location).ToString();
Good luck!

Related

Insert string into a filepath string before the file extension C#

I have a string that defines the path of a file:
string duplicateFilePath = D:\User\Documents\processed\duplicate_files\file1.jpg;
I am going to move a file to this location but sometimes a file with the identical name exists all ready. In this case I want to differentiate the filename. I have the crc value of each file available so I figured that may be good to use to ensure individual file names. I can create:
string duplicateFilePathWithCrc = duplicateFilePath + "(" + crcValue + ")";
But this gives:
D:\User\Documents\processed\duplicate_files\file1.jpg(crcvalue);
and I need:
D:\User\Documents\processed\duplicate_files\file1(crcvalue).jpg;
How can I put the crcvalue into the string before the file extension, bearing in mind there could be other .'s in the file path and file extensions vary?
Use the static methods in the System.IO.Path class to split the filename and add a suffix before the extension.
string AddSuffix(string filename, string suffix)
{
string fDir = Path.GetDirectoryName(filename);
string fName = Path.GetFileNameWithoutExtension(filename);
string fExt = Path.GetExtension(filename);
return Path.Combine(fDir, String.Concat(fName, suffix, fExt));
}
string newFilename = AddSuffix(filename, String.Format("({0})", crcValue));
int value = 42;
var path = #"D:\User\Documents\processed\duplicate_files\file1.jpg";
var fileName = String.Format("{0}({1}){2}",
Path.GetFileNameWithoutExtension(path), value, Path.GetExtension(path));
var result = Path.Combine(Path.GetDirectoryName(path), fileName);
Result:
D:\User\Documents\processed\duplicate_files\file1(42).jpg
Something like this
string duplicateFilePath = #"D:\User\Documents\processed\duplicate_files\file1.jpg";
string crcValue = "ABCDEF";
string folder = Path.GetDirectoryName(duplicateFilePath);
string filename = Path.GetFileNameWithoutExtension(duplicateFilePath);
string extension = Path.GetExtension(duplicateFilePath);
string newFilename = String.Format("{0}({1}){2}", filename, crcValue, extension);
string path_with_crc = Path.Combine(folder,newFilename );
This can also be achieved by using Replace:
using System.IO;
string duplicateFilePathWithCrc = duplicateFilePath.Replace(
Path.GetFileNameWithoutExtension(duplicateFilePath),
Path.GetFileNameWithoutExtension(duplicateFilePath + "(" + crcValue + ")"),
);
Try using the Path class (it's in the System.IO namespace):
string duplicateFilePathWithCrc = Path.Combine(
Path.GetDirectoryName(duplicateFilePath),
string.Format(
"{0}({1}){2}",
Path.GetFileNameWithoutExtension(duplicateFilePath),
crcValue,
Path.GetExtension(duplicateFilePath)
)
);

Could not find a part of the path

I am getting " Could not find a part of the path" error while copying a file from server to local machine. here is my code sample:
try
{
string serverfile = #"E:\installer.msi";
string localFile = Path.GetTempPath();
FileInfo fileInfo = new FileInfo(serverfile);
fileInfo.CopyTo(localFile);
return true;
}
catch (Exception ex)
{
return false;
}
Can anyone tell me what's wrong with my code.
Path.GetTempPath
is returning you folder path. you need to specify file path as well. You can do it like this
string tempPath = Path.GetTempPath();
string serverfile = #"E:\installer.msi";
string path = Path.Combine(tempPath, Path.GetFileName(serverfile));
File.Copy(serverfile, path); //you can use the overload to specify do you want to overwrite or not
You should copy file to file, not file to directory:
...
string serverfile = #"E:\installer.msi";
string localFile = Path.GetTempPath();
FileInfo fileInfo = new FileInfo(serverfile);
// Copy to localFile (which is TempPath) + installer.msi
fileInfo.CopyTo(Path.Combine(localFile, Path.GetFileName(serverfile)));
...

Change file name of image path in C#

My image URL is like this:
photo\myFolder\image.jpg
I want to change it so it looks like this:
photo\myFolder\image-resize.jpg
Is there any short way to do it?
This following code snippet changes the filename and leaves the path and the extenstion unchanged:
string path = #"photo\myFolder\image.jpg";
string newFileName = #"image-resize";
string dir = Path.GetDirectoryName(path);
string ext = Path.GetExtension(path);
path = Path.Combine(dir, newFileName + ext); // #"photo\myFolder\image-resize.jpg"
You can use Path.GetFileNameWithoutExtension method.
Returns the file name of the specified path string without the extension.
string path = #"photo\myFolder\image.jpg";
string file = Path.GetFileNameWithoutExtension(path);
string NewPath = path.Replace(file, file + "-resize");
Console.WriteLine(NewPath); //photo\myFolder\image-resize.jpg
Here is a DEMO.
This is what i use for file renaming
public static string AppendToFileName(string source, string appendValue)
{
return $"{Path.Combine(Path.GetDirectoryName(source), Path.GetFileNameWithoutExtension(source))}{appendValue}{Path.GetExtension(source)}";
}
I would use a method like this:
private static string GetFileNameAppendVariation(string fileName, string variation)
{
string finalPath = Path.GetDirectoryName(fileName);
string newfilename = String.Concat(Path.GetFileNameWithoutExtension(fileName), variation, Path.GetExtension(fileName));
return Path.Combine(finalPath, newfilename);
}
In this way:
string result = GetFileNameAppendVariation(#"photo\myFolder\image.jpg", "-resize");
Result: photo\myFolder\image-resize.jpg
Or the File.Move method:
System.IO.File.Move(#"photo\myFolder\image.jpg", #"photo\myFolder\image-resize.jpg");
BTW: \ is a relative Path and / a web Path, keep that in mind.
You can try this
string fileName = #"photo\myFolder\image.jpg";
string newFileName = fileName.Substring(0, fileName.LastIndexOf('.')) +
"-resize" + fileName.Substring(fileName.LastIndexOf('.'));
File.Copy(fileName, newFileName);
File.Delete(fileName);
try this
File.Copy(Server.MapPath("~/") +"photo/myFolder/image.jpg",Server.MapPath("~/") +"photo/myFolder/image-resize.jpg",true);
File.Delete(Server.MapPath("~/") + "photo/myFolder/image.jpg");

copy all type format file from folder in c#

I am trying to copy all format file (.txt,.pdf,.doc ...) file from source folder to destination.
I have write code only for text file.
What should I do to copy all format files?
My code:
string fileName = "test.txt";
string sourcePath = #"E:\test222";
string targetPath = #"E:\TestFolder";
string sourceFile = System.IO.Path.Combine(sourcePath, fileName);
string destFile = System.IO.Path.Combine(targetPath, fileName);
Code to copy file:
System.IO.File.Copy(sourceFile, destFile, true);
Use Directory.GetFiles and loop the paths
string sourcePath = #"E:\test222";
string targetPath = #"E:\TestFolder";
foreach (var sourceFilePath in Directory.GetFiles(sourcePath))
{
string fileName = Path.GetFileName(sourceFilePath);
string destinationFilePath = Path.Combine(targetPath, fileName);
System.IO.File.Copy(sourceFilePath, destinationFilePath , true);
}
I kinda got the impression you wanted to filter by extension. If so, this will do it. Comment out the parts I indicate below if you don't.
string sourcePath = #"E:\test222";
string targetPath = #"E:\TestFolder";
var extensions = new[] {".txt", ".pdf", ".doc" }; // not sure if you really wanted to filter by extension or not, it kinda seemed like maybe you did. if not, comment this out
var files = (from file in Directory.EnumerateFiles(sourcePath)
where extensions.Contains(Path.GetExtension(file), StringComparer.InvariantCultureIgnoreCase) // comment this out if you don't want to filter extensions
select new
{
Source = file,
Destination = Path.Combine(targetPath, Path.GetFileName(file))
});
foreach(var file in files)
{
File.Copy(file.Source, file.Destination);
}
string[] filePaths = Directory.GetFiles(#"E:\test222\", "*", SearchOption.AllDirectories);
use this, and loop through all the files to copy into destination folder

Extracting Path from OpenFileDialog path/filename

I'm writing a little utility that starts with selecting a file, and then I need to select a folder. I'd like to default the folder to where the selected file was.
OpenFileDialog.FileName returns the full path & filename - what I want is to obtain just the path portion (sans filename), so I can use that as the initial selected folder.
private System.Windows.Forms.OpenFileDialog ofd;
private System.Windows.Forms.FolderBrowserDialog fbd;
...
if (ofd.ShowDialog() == DialogResult.OK)
{
string sourceFile = ofd.FileName;
string sourceFolder = ???;
}
...
fbd.SelectedPath = sourceFolder; // set initial fbd.ShowDialog() folder
if (fbd.ShowDialog() == DialogResult.OK)
{
...
}
Are there any .NET methods to do this, or do I need to use regex, split, trim, etc??
Use the Path class from System.IO. It contains useful calls for manipulating file paths, including GetDirectoryName which does what you want, returning the directory portion of the file path.
Usage is simple.
string directoryPath = Path.GetDirectoryName(filePath);
how about this:
string fullPath = ofd.FileName;
string fileName = ofd.SafeFileName;
string path = fullPath.Replace(fileName, "");
if (openFileDialog1.ShowDialog(this) == DialogResult.OK)
{
strfilename = openFileDialog1.InitialDirectory + openFileDialog1.FileName;
}
You can use FolderBrowserDialog instead of FileDialog and get the path from the OK result.
FolderBrowserDialog browser = new FolderBrowserDialog();
string tempPath ="";
if (browser.ShowDialog() == DialogResult.OK)
{
tempPath = browser.SelectedPath; // prints path
}
Here's the simple way to do It !
string fullPath =openFileDialog1.FileName;
string directory;
directory = fullPath.Substring(0, fullPath.LastIndexOf('\\'));
This was all I needed for the full path to a file
#openFileDialog1.FileName

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