In an MVVM implementation, is every ViewModel coupled to just one Model?
I am trying to implement the MVVM pattern in a project but I found that sometimes, a View may need information from multiple Models.
For example, for a UserProfileView, its UserProfileViewModel may need information from UserAccountModel, UserProfileSettingsModel, UserPostsDataModel, etc.
However, in most articles I read about MVVM, the ViewModel only consists on one Model via Dependency Injection. So the constructor takes in only one Model.
How would the ViewModel work when it has to get information from multiple Models? Or would such a situation ever occur in MVVM?
PS: I am not using the Prism or Unity Framework. I am trying to implement similar patterns into a project that I am working on which doesn't use Prism or Unity. That's why I need to understand exactly how some of these things work.
In my understanding of the MVVM pattern, the only practical requirement is that the View gets all its data from the properties of a ViewModel (probably through a binding mechanism). The ViewModel is a class that you craft specifically for that view, and takes on the responsability of populating itself as required. You could think of it like ActiveRecord for the view.
As such, it doesn't matter what you do inside the ViewModel to obtain the data that its properties should show. You could get it by querying some services, reading one or more business entity models, generating it on the spot, or all of the above. It's perfectly normal to need a combination of all these things to make a functional view.
As in any presentation pattern, the point is just to separate the process of showing some data on the screen, from the process of obtaining that data. That way you can test each part of the process separately.
Edit: Here's a small but hopefully complete example of the flow of dependencies.
// Model/service layer
public class MyModelA
{
public string GetSomeData()
{
return "Some Data";
}
}
public class MyModelB
{
public string GetOtherData()
{
return "Other Data";
}
}
// Presentation layer
public class MyViewModel
{
readonly MyModelA modelA;
readonly MyModelB modelB;
public MyViewModel(MyModelA modelA, MyModelB modelB)
{
this.modelA = modelA;
this.modelB = modelB;
}
public string TextBox1Value { get; set; }
public string TextBox2Value { get; set; }
public void Load()
{
// These need not necessarily be populated this way.
// You could load an entity and have your properties read data directly from it.
this.TextBox1Value = modelA.GetSomeData();
this.TextBox2Value = modelB.GetOtherData();
// raise INotifyPropertyChanged events here
}
}
public class MyView
{
readonly MyViewModel vm;
public MyView(MyViewModel vm)
{
this.vm = vm;
// bind to vm here
}
}
// Application layer
public class Program
{
public void Run()
{
var mA = new MyModelA();
var mB = new MyModelB();
var vm = new MyViewModel(mA, mB);
var view = new MyView(vm);
vm.Load();
// show view here
}
}
You can use multiple models in a view model. The purpose of the view model is to abstract away the business / data layer (i.e. the model).
However, using more than one model usually indicates that the view is too large. You might want to split it into user controls (which have their own view models).
a viewmodel contains the "view logic" - so all you wanna show on the view is exposed through the viewmodel. if you wanna show data from diffenrent "models" then your viewmodel agregate this and the view can bind to.
the main purpose from mvvm was btw unit test. this mean easy testing of view logic without UI.
EDIT: why do you think:
ViewModel only has one single parameter for the View in its constructor
EDIT2:
there btw two main approaches to work with mvvm, first is "View First" second is "Viewmodel First" you can of course mix up both and choose the best approach for you needs.
A ViewModel may and in many cases does use multiple Models. It is itself a "Model" of your view.
Consider a profile screen that a user enters their personal information including address. If the address is stored in an "addresses" table and the rest in a "profile" table, then the ViewModel uses both the Profile and Address models to create a unified ViewModel.
As jgauffin mentioned in his answer, many times you can use user controls to achieve a one to one relationship, but you can also introduce needless complexity by trying for this 100% of the time.
I would make sure you understand the difference between view, viewmodel, and all other model classes. The ViewModel is the model object that is filled with data that the view can be bound to. It just exists to provide data to the view, which makes the ViewModel object unit-testable, and the whole business logic separate from the view. So, you can develop your business logic entirely without using the view itself, and can replace the view with just building or using another view and binding to the ViewModel object's properties. If a view is full of empty text fields for example, the contents of the text fields can be bound to different properties of the view model.
There usually really should only be one view model. BUT if it's too complex, you can use subproperties of the bound objects like described in Binding to ViewModel.SubClass.Property (sub-property)
The ViewModel can get the data it returns to the view from a lot of different sources, business objects, databases, whatever.
Usually there is one ViewModel per Model. These ViewModels contain the logic to handle the model's data. On the other side every view has it's own view model, too. So this means:
class ModelA
{
bool TestValue{get;set;}
}
class ViewModelA<ModelA>
{
ValueViewModel<bool> TestValue{get; private set;}
public ViewModelA(ModelA model)
{
base.Model = model;
this.Initialize();
}
}
class ModelB
{
string Username;
}
class ViewModelB<ModelB>
{
ValueViewModel<string> Username{get; private set;}
public ViewModelB(ModelB model)
{
base.Model = model;
this.Initialize();
}
}
These are the ViewModels that encapsulate the models. The views have their own ViewModels:
public ViewModelForExactlyOneView
{
public ViewModelA{get;set;}
public ViewModelB{get;set;}
}
To answer your question, ViewModel1 refers to ViewModelA and ViewModelB. The View therefore can get it's data from ViewModel1.ViewModelA.TestValue.
just use the User model in your view
public partial class User : Login
{
public string Password { get; set; }
public List<Customer> customer { get; set; }
}
in this the another model login inherited and the customer model also used in this model..
Related
I'm currently learning about WPF and MVVM so I've decided to create a sample application.
To my knowledge a Model is for the back end. E.g. if you have "Spaghetti" as a Model, it would have properties like "Name", "colour", "length" etc. It follows a 1:1 relationship
View Model is for the front end so the View will use what you add to the View Model. e.g. displaying a list of the different names of Spaghetti.
I'm trying to read data from the database and display all the spaghetti names to the View. I've managed to do it but I feel like I'm missing the objective of MVVM as the way I have done it does not require the Model.
Here is the code:
MainWindow.xaml.cs
public partial class MainWindow : Window
{
MainWindowSpaghettiViewModel vm = new MainWindowSpaghettiViewModel();
Service businessLogic = new Service();
public MainWindow()
{
InitializeComponent();
vm.SpaghettiNameCollection = businessLogic.GetSpaghettiNames();
DataContext = vm;
}
}
Model: Spaghetti.cs
public class Spaghetti
{
public string Name { get; set; }
public double Length { get; set; }
public string Colour { get; set; }
public decimal Price { get; set; }
}
View Model: MainWindowSpaghettiViewModel.cs
public class MainWindowSpaghettiViewModel
{
public List<string> SpaghettiNameCollection { get; set; }
}
BusinessLogic Layer: Service.cs
public class Service : IService
{
DBHelper db = new DBHelper();
public List<string> GetSpaghettiNames()
{
return db.GetSpaghettiNames();
}
}
DataAccess Layer : DBHelper.cs returns a list of spaghetti names by using a select statement.
Am I approaching this correctly as I've seen examples before where others have populated the View Model properties directly from the database?
How would the application flow? For example, in this window, I would like the user to select the name of the spaghetti they would like more information for, from the list I have just created.
After they select a spaghetti, they go to the next window where they can see all the information about the spaghetti (like the properties in the Model). Do I just create a new ViewModel with the same properties and do what I did above or do I populate the Model and then populate the ViewModel from that?
Looks good so far but you could use List<Spaghetti> instead of List<string>
and directly read the items into this List in the ViewModel from the database. So the Model is actually the template.
Do I understand you correctly? Your question is why do you need the Model class while you load the data directly into a ViewModel class?
The Model actually holds the data and provides the data for the ViewModel.
The ViewModel is the logic for the View.
If you need more data for the view than the Model can provide but the Model also should not have and provide you create a ViewModel for data Model exclusive for the View but populate it with the Data from the Model which gets populated from for example an SQL Database. Otherwise, it's the same. If you only need a small portion from an entire Model for the View you create a ViewModel which has only the Properties needed for that purpose.
An example would be you have a TreeView and you need a Property named "IsExpanded" to have control about that. This Property has nothing to do with the pure Data and therefore should not be in a Model class itself. A non purist would say okay, but you could write a partial class for that model and ignore some View needed properties via attributes for the database.
If you only show a Name of that Model to the user, it would be enough to have a List of type string.
So there is no direct answer. You may expose your Data directly via ViewModel or via another ViewModel for the Model class with less or more properties, fields etc.
After they select a spaghetti, they go to the next window where they
can see all the information about the spaghetti (like the properties
in the Model). Do I just create a new ViewModel with the same
properties and do what I did above or do I populate the Model and then
populate the ViewModel from that?
It looks like you need the same properties stored in the database for the View itself.
You could load all items directly and populate a List of Spaghettis with it or just populate strings but load the required data for the item if requested on the next page or wherever.
In general if you got loads of data many would say:
You shouldn't load all the data from the Database, load only what you need.
It think it just depends on the data. Some MVVM purist would always say, create a ViewModel for the Model and load and expose only the Data needed at that time.
I suggest you to read this, I hope it helps. If you have further questions ask.
https://www.wintellect.com/model-view-viewmodel-mvvm-explained/
So I was looking at https://github.com/xamarin/Sport as an example I came across when googling something for my current project. It is similar to what Im working on because I use an azure backend as well.
I have a question about their mvvm layout. I thought that in mvvm the models were sort of POCOs and not supposed to implement INotifyPropertyChanged. Arent they acting as both a Model and a ViewModel in this case? Look at the Athlete model and the AthleteViewModel. The VM has a property for for Athlete and so the model is used as a VM as well.
In my project, if I had the same types, I would have an Athlete model, an AthleteViewModel and an AthletePageViewModel. Where the Athlete and AthleteVM would be automapped. The only reason to populate and or create the Athlete is to persist it to the service or local storage.
Is one way more "correct" than the other way? Or am I just doing it wrong and over complicating it? I almost don't want to continue with the way I'm doing it because I dont want to have a bunch of "extra" model files if I can just use some of my VMs as models.
Thanks.
There's no ultimate master set of strict rules that you need to follow in order to implement the MVVM design pattern. In fact, the guidelines are generally quite blurry.
From what I've seen, there are a couple of different methods of which a model may be exposed to the view. Here they are:
Method 1 - INotifyPropertyChanged in the Model
public class Car : INotifyPropertyChanged
{
private string _Model;
public string Model
{
get { return _Model; }
set
{
_Model = value;
NotifyOfPropertyChange();
}
}
...
}
public class CarViewModel
{
//The entire model is exposed to the view.
public Car Model { get; set; }
...
Method 2 - INotifyPropertyChanged in the View Model
public class CarViewModel
{
private Car _Car;
//The model property is exposed to the view, not the model itself.
public string CarModel
{
get { return _Car.Model; }
set
{
_Car.Model = value;
NotifyOfPropertyChange();
}
}
...
In terms of a preferred method, I would say method 2 is the better option. Why?
The Model object is not exposed to the view.
The View Model only exposes what the View needs.
Method 2 does have its downsides. Imagine if you needed to expose lots of model properties, or imagine if your model changes, it is certainly easier to simply implement INotifyPropertyChanged in the model and expose it to the view. Programmers are lazy by nature, therefore in order to save hassle, you'll see method 1 just as much as method 2.
But that isn't a bad thing.
Is one way more "correct" than the other way? Or am I just doing it wrong and over complicating it?
Remember, the MVVM design pattern is just a pattern. Neither options are correct, it's mostly down to the developers preference how they choose to approach the implementation of the pattern, as long as the main MVVM concepts are there, that's all that matters.
What is the best practice for binding a list of items to an ItemsControl when using the MVVM pattern?
1. Bind a list of ViewModels
Load the items from the database, create the models and all viewmodels and then bind a list of viewmodels to the ItemsControl.ItemsSource:
public class MyMainViewModel
{
public List<PersonViewModel> Persons { get; set; }
}
2. Bind a list of Models
Load the items from the database, create the models and then bind a list of those models directly to the ItemsControl.ItemsSource:
public class MyMainViewModel
{
public List<Person> Persons { get; set; }
}
I think the answer here is really it depends.
Firstly, you need to assess whether your view needs to interact with your model in such a way that it would make sense for a view model to be wrapped around a particular model. Let's look at an example:
public class WebsiteModel
{
public string URL { get; set; }
}
Here I have a very simple model which represents a website, nothing too fancy. I can create a view model which will encompass all websites, like a one to many relationship:
public class WebsitesViewModel
{
//A list of websites.
public List<WebsiteModel> Websites { get; set; }
//The command I will use to navigate, where the object parameter will be the WebsiteModel.
public ICommand NavigateCommand { get; set; }
...
public void Navigate(WebsiteModel model)
{
...
}
Here I want my view to be able to navigate to the URL using the browser. My view model holds a list of models and my command takes care of navigation.
The next method I can create a view model to represent a single model, I would say this is a SOLID approach:
public class WebsiteViewModel
{
//The website model
public WebsiteModel Website { get; set; }
//The command I will use to navigate, no parameters needed.
public ICommand NavigateCommand { get; set; }
...
public void Navigate()
{
...
}
In this scenario, I'll need another view model which will expose a list of WebsiteViewModel to my view.
public List<WebsiteViewModel> Websites { get; set; }
The truth is there isn't really a best practice. Neither method really trumps the other. There are benefits to each method, however the method to choose really depends on the implementation. In this scenario, method 2, I would say is overcomplicated. However it's not uncommon for a view model to become very large very quickly, and the need to separate concerns will force you to create smaller classes, and even view models to wrap your models inside, making method 2 a viable option.
So to wrap up. Neither method is best practice.
The only "correct" way to do it, is to use ViewModels all the way.
While initially more work, it gives you more flexibility and less bugs later on.
Don't for get, when you a model should only be valid in it's bounded context and when you bind your ViewModel to the view, you have a leaky abstraction. The View becomes aware of model and each change to the model, will affect your View.
Further more, refactoring doesn't work within XAML. So if you name a model property via refactoring, your XAML will still bind to the old property. This doesn't give you a compile error and your bounded element will just remain empty (in best case) or crash (in worst case).
This can be quite hard to figure out and fix. Also as Scroog1 commented, it introduces memory leaks. May not be noticeable in small applications, but ones working with big data sets it can lead to out of memory exceptions.
You should utilize an automapping library to map from Model to ViewModel in cases that allows it, this will reduce some boilerplate code. But remember to avoid ViewModel to Model automappings, as it's discouraged.
You want to avoid that a change in your model influences code in a different bounded context, i.e. you don't want to expose every database or model change in a rest service, even if the change do not influence the given rest action.
The same strategy can be applied to the n-layer model (View, ViewModel, (Domain) Model layer, Services and Infrastructure)
I think there is no correct way, using models is the pragmatic and simpler way, using view models is more time consuming but more decoupled...
You should have a look at this article:
http://blog.alner.net/archive/2010/02/09/mvvm-to-wrap-or-not-to-wrap.aspx
also: http://www.codeproject.com/Articles/61147/MVVM-Creating-ViewModel-Wrap-your-business-object
I'm having some issues with the setup i'm currently using with my mvvm application. Having seen some posts on here, i get the feeling i may be doing this slightly wrong.
I have several models which contain lists of child models such as:
Project - Contains a list of proformas
Proforma - Contains a list of shipments orderedItems
Shipment - Contains a list of Containers
Container - Contains a list of packages
We do not have any viewmodels that relate directly to these model currently, we instead simply have viewmodels that represent the list of models, for example we have a proformalistviewmodel which simply contains a list of proformas.
My issue is, that with this setup i'm a little confused as to what viewmodel should own which data, for example the ProfomalistViewModel has a reference to the currently selected Project, all the data management for these models (the loading and saving of the list of proformas) is done via manager classes which are loaded via DI.
My question is should i instead be following what I'm seeing and having a ProjectViewModel which contains a list of proformas, and a ProformaViewModel which contains a list of shipments and ordereditems and so on.
The reason for this, is that originally none of the models we're linked, projects did not own a list of proformas they were instead loaded separately via the managers using the selected project ID (using a relational db) and we're currently changing the models to the system i described above.
A viewmodel should be a model of the user interaction for a particular area of functionality
For instance, if you have a project list page and the user can do certain things like delete a project, edit a project, print information about the project then you should design a viewmodel that contains the data and actions associated with this interface:
e.g. the viewmodel should contain:
* A bindable container for the project data (list of projects)
* Actions that handle edit/delete interaction
* An action to handle the print functionality
The actual functionality inside these actions may not be contained within the viewmodel (the VM may have received injected services such as the print service or the project repository) but the responsibility of execution of these actions lies with the VM.
It may also be necessary to wrap each data item (project) in a viewmodel so that additional interaction dependent properties/actions can be added - such as the 'selected' property (imagine the user wants to multi-select a load of projects in the view - you could add a selected property to the ProjectViewModel which will wrap each project which makes binding easy)
You may end up with something like the following:
public class ProjectOverviewViewModel
{
public IList<ProjectViewModel> Projects { get;set; }
public ProjectViewModel SelectedProject { get;set;}
public void EditSelected()
{
// Code to open edit page for the selected project
}
public void Print()
{
}
}
and the ProjectViewModel with a selectable property
public class ProjectViewModel
{
// Either put the actual data item in here and wrap it:
public Project Project {get;set;}
// Or copy properties onto the viewmodel using automapper or some other mapping framework...
// or manually :(
// e.g. properties mirrored from the entity object:
public int ProjectId { get;set;}
public string ProjectName { get;set;}
// The selected property - now your 'Selected' logic is a function of the view/viewmodel
// not the entity. The entity should only be concerned with data persistence
public bool IsSelected {get;set;}
}
You may also want to composite viewmodels together in order to build more complex views. Imagine you have a projects page and a "users involved in a project" page, and you wanted another page that showed both side by side (and allowed you to click a project which would refresh the users pane) - this is possible by compositing the viewmodels (by creating another viewmodel which contains the two viewmodels as properties and wires up the interaction between the two)
public class ProjectAndUserOverView
{
public ProjectOverviewViewModel ProjectOverview {get;set;}
public ProjectUsersViewModel ProjectUsers {get;set;}
// Code here to listen for property changes in ProjectOverview and if SelectedProject changes
// call ProjectUsersViewModel to refresh the data for the selected user
}
Ultimately you are just modelling the user interaction, and the more modular you can make it, the easier it will be to make cleaner more maintainable code
There are some good MVVM frameworks - my personal fave is Caliburn Micro as it makes the above very easy (it heavily uses conventions by default) and is easy to get into.
MVVM is design pattern which have 3 parts: Model, ViewModel, View. DIagram looks like this:
http://en.wikipedia.org/wiki/Model_View_ViewModel#Pattern_description
You use ViewModels wrong. Only data for displaying should be in ViewModel.
Your Model for example:
public class Project
{
public Proforma Pr{get;set;}
}
public class Proforma
{
public string Name{get; set;};
}
You have View for project display(I inject ViewModel to constructor, tou can use DataContext instead):
public partial class ProjectView
{
private ProjectViewModel vm;
public ProjectView(ProjectViewModel vm)
{
this.vm = vm;
}
}
If you want to display proforma name on Project view, you should provide it as string in ViewModel.
public class ProjectViewModel
{
private Project pr;
public string ProformaName{get{return pr.Pr.Name;}}
}
If you provide Proforma like proforma, your View will know about model. It will be a violation of the pattern.
My five cent is that MVVM is a pattern, not a religion. I use it at far as it goes and makes sense. There's many parts where MVVM is undefined (like user interaction from commands), and I read a lot about ViewModels being created just to fit MVVM (which bloats both design and object count). I would suggest you think more DataContext-wise, like "Selections of global interest are kept in a global DataContext, Proforma related data is kept in a Proforma DataContext" and so forth, where DataContext is some sort of ViewModel. In the end, you'll probably wind up rigging those up with UI.
You shouldn't create ViewModels for your model objects.
Generally speaking, a ViewModel should belong to a UserControl. Its role is to wire your view (your XAML) together with your model (business logic).
In your case, if I understand it correctly, you have a bunch of classes that implement business logic (Project, Shipment etc.). Your ViewModel will have access to the business logic, and provide properties for your view to bind to.
I do not see any problem with having view models that wrap model data objects. Viewmodels do not have to be "one per view". They can represent a row in a list or whatever.
Having said that, I am quite happy binding directly to model objects and I do it a lot. The only time I create a view model to wrap it is if I need extra state per object that is required by the view.
In my application I have different pages: Contact Us, About Us, Home
They all have the same base elements that needs to populate the view:
Page Title
Meta Description
User Information
However on each page, they have some elements that are different:
Contact Us
Contact Information Model
Contact Form Model
About Us
Extended User Information Model
Home
Home Page Text Property
They are all routed to the same Controller Action Method because most of the functionality is similar other than populating the "extra" information dependent on page type.
So far I have done something where:
PageDetailViewData pageDetailViewData = new PageDetailViewData {Title = title, Desc = desc....}
and following this I have:
switch ((PageType)page.PageType)
{
case (PageType.Contact):
return View("ContactUsDetails", pageDetailViewData);
default:
return View(pageDetailViewData);
}
The question is how do I populate the "extra" information? I am not sure if I am going about doing this the right way. Any insight to better structure the logic flow would be appreciated.
The answer of using interfaces to imply some commonality between your view models is certainly going to help to answer some of the points in your questions.
I would however ask how wise it is to "refactor" your Action to support multiple views of differing data structures.
MVC controller actions typically represent the minimum amount of code required to gather the specific data required to generate the intended view. It's not completely uncommon for a single action to return different views of the same model data (Html view or Mobile view for example) but by varying both the structure of the data and view that will generated you introduce a few problems.
In particular you violate common best practices like the Single Responsibility Principle and make your code much more complicated to test - and Pain free testing and TDD are part of the big win with ASP.Net MVC after all.
Personally I would have a separate Action.
As far as your view models are concerned, how would you do it if this was a database?
You would have separate queries for separate data right?
A user's profile information would be queried separately from the page meta data information. This would be done for a number of reasons that could include the ability to cache certain parts of the data but not others for example.
So with the above suggestions your code might look like this (Warning: this code wasn't written in Visual Studio and is probably full of syntax issues):
public interface IMetaDataViewModel
{
PageMetaData MetaData{get; set;}
}
public class HomeViewModel : IMetaDataViewModel
{
public PageMetaData MetaData{get; set;}
public string HomePageText{get; set;}
}
//other view models go here....
public class CommonPagesController : Controller
{
private MetaDataProvider _metaProvider = new MetaDataProvider();
private PageDataProvider _pageDataProvider = new PageDataProvider();
private ContactDataProvider _contactDataProvider = new ContactDataProvider();
public ActionResult Home()
{
var viewModel = new HomeViewModel
{
MetaData = _metaProvider.GetPageMeta();
HomePageText = _pageDataProvider.GetPageData();
};
return View(viewModel);
}
public ActionResult Contact()
{
var viewModel = new ContactViewModel
{
MetaData = _metaProvider.GetPageMeta();
ContactFormData = _contactDataProvider.GetData();
};
return View(viewModel);
}
//you get the picture...
}
There are several ways you could also refactor out the generation of the view model code but thats one possible pattern.
I appreciate that this answer does have a certain amount of opinion in it but I would consider having separate actions to be best practice.
Hope that helps.
The title of your question almost gives you the answer. You can use some form of polymorphism to accomplish this. You could define a base class with the shared properties, or alternatively an interface like this:
public interface ICommonPage
{
string Title { get; }
string MetaDescription { get; }
string UserInformation { get; }
}
Then define three strongly typed ViewModel classes that all implement this interface (or derive from the base class):
ContactUsViewModel : ICommonPage
AboutUsViewModel : ICommonPage
HomeViewModel : ICommonPage
On each of those ViewModel classes, you add the extra properties that you need for those Views.
In your Controller Action, you will need to switch on PageType to select the correct ViewModel and populate it with data.
You will also need to creat three different Views (.aspx) that are strongly typed to each ViewModel class.
If you have shared rendering for the common data, you can extract that into a strongly typed UserControl (.ascx) that is typed to ICommonPage.