Adding numbers from 1 to N in C# - c#

I'm writing code in C# and trying to add all of the numbers between the number 1 and N, N being the number that is inputted in a textbox. I'm doing this, at least trying to do this, by putting it into a while loop.
I have added all the numbers between 2 textboxes before but for some reason I'm driving myself crazy and can't figure this out. I'm a beginning programmer so please be gentle.
Any help would be greatly appreciated.
Edit:
One of the six thousand things I've tried. I think this has me in an infinite loop?
private void btnAddAll_Click(object sender, EventArgs e)
{
int n;
int count = 0;
int answer = 0;
n = int.Parse(txtNum.Text);
count = n;
while (count >= 1)
{
answer = answer + count;
count++;
}
lstShow.Items.Add("Sum = " + answer);
lstShow.Text = answer.ToString();
}

Why not use Gauss formula. (N*(N+1))/2
private void btnAddAll_Click(object sender, EventArgs e)
{
int n, answer;
n = int.Parse(txtNum.Text);
answer = (n*(n+1))/2;
lstShow.Items.Add("Sum = " + answer);
lstShow.Text = answer.ToString();
}

If you change the ++ to a -- it should work as you want it to.
int n;
int count = 0;
int answer = 0;
n = 3;
count = n;
while (count >= 1)
{
answer = answer + count;
count--; // here was the error
}
Console.WriteLine (answer);
Output: 6
Also, just for a point of additional interest you can use That uses Enumerable.Range and Enumerable.Sum instead of the while loop (probably goes beyond what is expected for a homework but it's useful to know what's out there).
answer = Enumerable.Range(1, n).Sum();

Your edit: you should decrement count..
Another edit, it appears I need to explain more:
By decrement I mean --. The post or pre decrement operator decreases the value by 1.
If count keeps increasing by 1, count >=1 will never be met. You need to reduce count to 1.. hence count--;
Also I suggest you use TryParse(string,out int) ; or at least wrap the Parse call in a try catch block.
Here is a pointer in pseudocode:
GetInput From User
TryParse Input
If Between 1 and N
Declare sum = 1;
for i to N-1
sum+=i;
/* if you don't want to use the for loop
while i < N
sum+=i;
inc i; */
Print sum

Debugging is an important skill for any programmer. There are some good tools in Visual Studio to help with debugging.
A good way to debug your code when you are stuck is to use 'breakpoints' and step through the code.
Select the line you want your code to stop at (e.g. n = int.Parse(txtNum.Text);) and press F9 - this will add a breakpoint at this line.
Now, when you run your programme, it will stop at the breakpoint. If you press F11, you can 'step' through the code one line at a time. You can hold your mouse over a variable to see its value while you are doing this.
You will quickly find the problem in your code if you do this.

Related

Kattis run time error solving Jumbo Javelin with C#

I am new to Kattis and trying solve the challenge Jumbo Javelin with C# but I get run time error even though I am exiting my program with 0.
Here is my code:
using System;
namespace JumboJavelin
{
class Program
{
static void Main(string[] args)
{
int l = int.Parse(Console.ReadLine());
int sum = 0;
int loss = 1;
for (int n = 0; n <= 100; n++)
{
sum += l;
if((n + 1) % 2 == 0 && !n.Equals(0))
{
sum -= ((n + 1) / 2)*loss;
}
try
{
l = int.Parse(Console.ReadLine());
}
catch (FormatException)
{
break;
}
}
Console.WriteLine(sum);
Environment.Exit(0);
}
}
}
Can someone please help me? I know my solution eventually outputs the wrong answer but right now I am trying to get rid of the run time error since it works perfectly fine on Visual Studio 2019.
All help is appreciated. Thanks
If you change the error your catch to Exception you will see that it is actually a wrong answer, so something goes wrong. You do exit your program with an exit code 0 at the bottom of your code, however, it throws an Exception somewhere else. Two things to consider:
First, the problem statement explains that as a first input, you get an integer N (this N indicates the amount of steel rods he has) and CAN BE between 1 and 100 (1 not inclusive hence, 1<N<=100). You now have a loop that always loops from 1 to 100. And the loop should loop from 1 up to and including whatever value N is. Try to see what you can do about that.
Second you read the input at the "tail" of the loop. This means that after the last cycle you do another read input. And that you do not read the first l. Try changing reading the input for l at the beginning of the loop. (and the first input you read in your Main, should not be for l (see point 1)).
See how far this gets you, is something is not clear please let me know.
As Kasper pointed out, n is dynamically provided on the first line; don't assume you have 100 lines to collect with for (int n = 0; n <= 100; n++).
There's no need to handle errors with the format; Kattis will always adhere to the format they specify. If something goes wrong parsing their input, there's no point trying to catch it; it's up to you to fix the misunderstanding. It's better to crash instead of catch so that you won't be fooled by Kattis telling you the failure was due to a wrong answer.
A simple approach is as follows:
Collect n from the first line of input; this is the preamble
Loop from 0 to n, collecting each line
Accumulate the values per line into a sum
Print sum - n + 1, the formula you can derive from their samples
using System;
class JumboJavelin
{
static void Main(string[] args)
{
int n = int.Parse(Console.ReadLine());
int sum = 0;
for (int i = 0; i < n; i++)
{
sum += int.Parse(Console.ReadLine());
}
Console.WriteLine(sum - n + 1);
}
}
You can use this pattern on other problems. You won't always aggregate one result after n lines of input though; sometimes the input is a single line or you have to print something per test case. Some problems require you to split and parse each line on a delimiter.
Regardless of the case, focus on gathering input cleanly as a separate step from solving the problem; only combine the two if you're confident you can do it without confusion or if your solution is exceeding the time limit and you're sure it's correct otherwise.

learning C#, need help understanding this code

I am learning C# and I came to this "for" function and something really bothers me about it:
int[] arrayNumbers = new int[numberAmmount];
// take "numberAmmount" as 5 so numberAmmount = 5;
for (int i = 0; i < numberAmmount; i++)
{
Console.Write("{0} Number: ", i + 1);
numberAmmount[i] = int.Parse(Console.ReadLine());
}
Isn't "i++" in for function the same i as in the Console.Write "i + 1"
Shouldn't i after the first cycle be 2?
and after the second cycle be 4 because of the i + 1 in console.write???
Basically I am trying to get in a number from the user which will be the amount of numberAmmount and by this for function i give every numberAmmount[x] a value and then have my program decide the highest and the lowest number but I don't understand why the i + 1 doesn't add an extra 1
edit: got it thanks
The syntax i + 1 does not have an assignment operator. That code is printing the value of i plus a constant. So when your loop is looping from 0...n Console.write is printing the counting value of each loop 1...n+1.

While Looping an Array

I'm trying to understand a book from Don Gosselin on ASP.NET Programming with Visual C#. To solve it I just simply make it to work by adhering to while loops: one while loop is to assign a number to an array element, the other while loop is to display that array. Total array count displays 1 through 100. This should have worked but didn't. Visual Studio 2013 debugger for some reason assigns count = 100, that's why it's failing.
<%
int count = 0;
int[] numbers = new int[100];
while (count <= 100)
{
numbers[count] = count;
++count;
}
while (count <= 100)
{
Response.Write(numbers[count] + "<br />");
++count;
}
%>
You should set count to 0 after first while loop:
int count = 0;
int[] numbers = new int[100];
while (count <= 100)
{
numbers[count] = count;
++count;
}
count = 0;
while (count <= 100)
{
Response.Write(numbers[count] + "<br />");
++count;
}
You need to reset the count to 0 before you attempt the next while statement. Currently, the first loop ends when it reaches a count equal to 101. WHen you proceed to the next while, the count is 101 so the loop automatically ends. Just set count = 0; before the second while loop.
This seems like a very convoluted and unrealistic way of using while loops and arrays. In order to understand it better, it may be worth thinking about it per step.
var i = 0;
while (i < 100)
{
Response.Write(++i + "<br />");
}
The first important distinction is between i++ and ++i. The former utilises the value, and then increments by one; the latter, increments the number and then utilises the value.
In C#, you should really be working with Collections, rather than Arrays. Arrays are zero-indexed, and are renowned for causing serious errors, including exposing potential exploits. Being statically allocated, there is no failsafe when attempting to access indicies outside of the bounds of the Array. Collections, on the other hand, are (for the most part) one-indexed, dynamically allocated, and provide fallbacks when accessing indicies. The most commonly used Collection is a List.
var i = 1;
var list = new List<int>();
while (i <= 100)
{
list.Add(i++);
}
For the second while loop, it's not really suitable to use a while loop here, for any practical example. The excercise is forcing while loops where they are not needed. In this instance, the aim is to iterate through each element in the array (List) and dump its contents to the screen. Because we want to perform an action for each element, a while loop may cause issues. If the array has less than 100 elements, the program will crash, if the array has more than 100 elements, we'll miss some of them. By using a foreach loop, instead of a while, we can eliminate these potential errors.
foreach (var num in list)
{
Response.Write(num + "<br />");
}
Now, I realise that the excercise is about while loops, however, it is teaching you to use them in the wrong way. A much better way - and how you'll most often use them - is to perform an action until a particular condition is met, rather than for simple iteration. By this, I mean, a condition is set to false, then inside the while loop, we manipulate a variable, test the condition, and if it's still false, we go round again. The most common example of this is to work out factorials of numbers.
var num = 5;
var factorial = 1;
while (counter > 1)
{
factorial *= num--;
}
Response.Write(String.Format("{0}! = {1}", input, factorial));
The other main way in which while loops are used is to force an infinite loop, unless a break condition is met. I'll show a very arbitrary use of this here, but a real world example would be the loop() method in Arduino C coding, or a HTTP Listener that constantly repeats the same procedures, until stopped.
var stop = 13;
Response.Write("Pick a number between 1 and 100...<br /><br />");
while (true)
{
var num = new Random().Next(1, 101);
Response.Write(num + " ..... ");
if (num == stop) break;
Response.Write("You got lucky!<br />");
}
Response.Write("Unlucky for you!);
The best way to learn these things is to practice them. Pick a task and find out just how many ways there are to complete it. There is one last important distinction to mention though. a while loop tests the condition at the beginning of the loop. A do while loop, tests the condition at the end.
while(false)
{
// This code will never be run.
}
Compared to:
do
{
// This code will be run once only.
}
while(false)
As a final thought, here's how I'd write the original code (using a LINQ foreach loop):
var numbers = new List<int>();
for (var count = 1; count <= 100; count++)
{
numbers.Add(count);
}
numbers.ForEach(num => Response.Write(num + "<br />")));

How to display all members of a given subsequence on the console?

I'm trying to understand why I can't print only the members of a subsequence of an array, that is equal to an integer from the input. The array is also read from the console. When i run the program only the first of these members does come up, but with him also a seemingly random number of zeros, while the rest of the subsequence is omitted. If there's a better way than to use a second array, I'll be grateful if you share it. Okay, to specify- I want to know how to print all the members of the aforementioned subsequence, can you please give me a useful advice or sample? Here's the input, output and code:
4 4 56 57 58
8
4 0 0 0 0
instead of 4 4
int v = int.Parse(Console.ReadLine());
int[] valueHolder = new int[arr1.Length];
int currentSum = 0;
for (int endIndex = 0; endIndex <= arr1.Length -1; endIndex++)
{
currentSum = 0;
for (int currentSumIndex = endIndex; currentSumIndex >= 0; currentSumIndex--)
{
currentSum += arr1[currentSumIndex];
if (currentSum == v)
{
valueHolder[currentSumIndex] = arr1[currentSumIndex];
}
if (currentSum == v)
{
for (int i = 0; i <= valueHolder.Length - 1; i++)
{
Console.Write(valueHolder[i] + " ");
}
}
}
I think you would be best served by putting a break point on the line of the first for loop then stepping through your code. If you take a pad of paper and write each of the variables states as you go through it then it will be pretty obvious what's going on.
However, just to help you out.
In the first pass of the outer loop (endIndex = 0), the inner loop does NOT execute. currentSumIndex = endIndex which equals zero, which does not pass the currentSumIndex >= 0 test. Therefore the first 4 is skipped.
In the second pass, the number 4 is emitted because currentSum equals 4. However, the values of 0 are also emitted because you are walking the entire valueHolder array and spitting all of the empty values out.
From the third pass forward, currentSum will never equal the number you typed in:
The first pass of the inner loop sets currentSum to 56, which does not equal v. The second pass of the inner loops sets it to 56+4 ( currentSum += arr1[currentSumIndex] ) which is 60. Therefore, nothing will ever be emitted again as currentSum will always be the sum of all numbers from the current array position going backward to the beginning array position and therefore will always be greater than v
You don't need a second array. You just need to pay attention to what your code is doing. Side note: I have absolutely no idea why you have that inner loop or even what the 8 is supposed to represent in your example entry above.
If I was writing this, I'd change it to (assuming you can't use LINQ):
int v = int.Parse(Console.ReadLine());
for (int i= 0; i <= arr1.Length -1; i++)
{
if (arr1[i] == v) {
Console.Write(arr1[i].ToString() + " ");
}
}
Console.WriteLine();

Calculate how many ways you can add three numbers so that they equal 1000

I need to create a program that calculates how many ways you can add three numbers so that they equal 1000.
I think this code should work, but it doesn't write out anything. What am I doing wrong? Any tips or solution?
using System;
namespace ConsoleApp02
{
class Program
{
public static void Main(string[] args)
{
for(int a = 0; a < 1000; a++)
{
for(int b = 0; b < 1000; b++)
{
for(int c = 0; c < 1000; c++)
{
for(int puls = a + b + c; puls < 1000; puls++)
{
if(puls == 1000)
{
Console.WriteLine("{0} + {1} + {2} = 1000", a, b, c);
}
}
}
}
}
Console.ReadKey(true);
}
}
}
Your innermost loop (iterating the puls variable) doesn't really make any sense, and because of the condition on it (puls < 1000) Console.WriteLine never runs.
Perhaps you should test whether A + B + C is 1000, instead.
Also, you'll find that you might be missing a couple particular combinations of numbers because of the bounds on your loops (depending on the problem statement.)
On a separate note, this particular implementation, while it'll work (with the modifications suggested by the other answers), is quite a performance hit, as the complexity of your algorithm is O(n^3). In other words, you are going through the innermost check one bilion times.
Here's a hint how you can optimize it to at least O(n^2) or just one milion iterations: for each pair of a and b generated by the two outer for loops, there's only one value for c that will result in 1000.
Question doesn't specify that negative numbers are not allowed. Answer is infinite.
You don't need the inner loop.
if (a+b+c == 1000)
write
In your final inner loop, "int puls = a + b + c; puls < 1000; puls++" you're ensuring that puls never = 1000, if puls is not less than 1000, it kicks out of the loop. That is why you are getting no values. But rethink your logic some as well.
If you get this assignment as a computer science student, you'd probably want to solve this using Dynamic Programming.
Once the inner most loop gets to 1000, it breaks out of the for loop and never even checks if it is 1000 in the 'if' statement.
That code will return no answer.
The interior for loop adds a + b + c and puts the result into puls. However, you stop the loop before puls can get to 1000, and then test inside the for statement to see if puls equals 1000. So, you won't get an answer.
Just test puls against 1000 in the inner loop. Why?
You can replace your innermost for loop with just a test for if (a+b+c == 1000) {...}.
Then you can add optimizations like - once a sum has been found with a combination, there is no need to continue with the inner loop.
The code does not cover the following cases
1000 + 0 + 0
0 + 10000 + 0
0 + 0 + 10000
The inner most loop should be an if rather for.
You don't need {} if there is only one statement in the loop or if clause.
EDIT:
Removed code answers
Try this:
{
for(a=0;a<=500;a++)
{
for (b=a;b<=500;b++)
{
c=1000-(a+b);
count

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