I am working on a WinForm Application using c#. I am using a button to browse for an image file (.jpeg or .bmp). When the user browses the file and clicks ok, on the click of another "Proceed or Update" button, I want that the browsed file should be renamed and saved to a predefined directory where all image files will be saved by default, without much user interaction!
How can I achieve this? I have used openFileDialog for browsing the file, but dont know what else to do.
//detination filename
string newFileName = #"C:\NewImages\NewFileName.jpg";
// if the user presses OK instead of Cancel
if (openFileDialog1.ShowDialog() == DialogResult.OK)
{
//get the selected filename
string filename = openFileDialog1.FileName;
//copy the file to the new filename location and overwrite if it already exists
//(set last parameter to false if you don't want to overwrite)
System.IO.File.Copy(filename, newFileName, true);
}
More information on the Copy method.
First you have to implement a copy function that can make unique file names:
private void CopyWithUniqueName(string source,
string targetPath,
string targetFileName)
{
string fileName = Path.GetFileNameWithoutExtension(targetFileName);
string extension = Path.GetExtension(targetFileName);
string target = File.Exists(Path.Combine(targetPath, targetFileName);
for (int i=1; File.Exists(target); ++i)
{
target = Path.Combine(targetPath, String.Format("{0} ({1}){2}",
targetFileName, i, extension));
}
File.Copy(source, target);
}
Then you can use it, suppose defaultTargetPath is the default target file where to copy images and defaultFileName is the default file name for images:
void button1_Click(object sender, EventArgs e)
{
if (openFileDialog1.ShowDialog() != DialogResult.OK)
return;
CopyWithUniqueName(openFileDialog1.FileName,
defaultTargetPath, defaultFileName);
}
In case of multiple selection:
foreach (string fileName in openFileDialog1.FileNames)
{
CopyWithUniqueName(fileName,
defaultTargetPath, defaultFileName);
}
You'll get this (suppose defaultFileName is "Image.png"):
Source Target
A.png Image.png
B.png Image (1).png
C.png Image (2).png
You can do that with the File.Copy()-method. Just put the predefined directory and the new filename as the destination parameter.
For more info see here
Related
The product I'm using is a Beijer HMI, currently i can generate a report and save it to a known location (my desktop - C:\Users\mrdav\Desktop).
I need to be able to search on my desktop for a file extension .xls and change its name.
When the report is generated by the HMI, it uses the date and time which means when the file is generated the name will be different every time.
On the press of a button i need to search my desktop for the .xls file and change its name to a variable.
// This is my variable with my program
string NewName = Globals.Tags.Tag1.Value;
The code that is generated needs to sit within the below example.
public partial class Screen1
{
void Button1_Click(System.Object sender, System.EventArgs e)
{
// Code to be added here...
}
}
Hopefully someone can help, I’m using windows compact framework so limited on functionality.
Any questions please let me know.
Thanks in advance,
Dave
Here is an example how you can do that:
DirectoryInfo dir = new DirectoryInfo(sExportPath);
FileInfo[] Files = dir.GetFiles("*.csv");
foreach(FileInfo file in Files )
{
// rename file
System.IO.File.Move(file.FullName, GenerateNewFileName());
}
//elsewhere in the class
private string GenerateNewFileName()
{
//here is where you implement creating or getting the filename that you want your file to be renamed to. An example might look like the below
string serialNumber = GetSerialNumber(); //Get the serial number that you talked about in the question. I've made it a string, but it could be an int (it should be a string)
return Path.ChangeExtension(serialNumber,".xls"); //to use path you will need a using statement at the top of your class file 'using System.IO'
}
This seems to work...but i know its not as tidy as it could be.
Any suggestions?
Thanks to all that helped, got there in the end!
void Button_Click(System.Object sender, System.EventArgs e)
{
try
{
// Location for new file
string NewFileName = #"c:\users\mrdav\desktop\testfolder\";
// Add varibale name to new file
NewFileName += Globals.Tags.Tag1.Value;
// add .xls extention to new file
NewFileName += ".xls";
//show new file name to check all ok
MessageBox.Show (NewFileName);
//search for .xls in known directory
DirectoryInfo di = new DirectoryInfo(#"c:\users\mrdav\desktop");
FileInfo[] Files = di.GetFiles("*.xls");
// if files exist with .xls extention
foreach(FileInfo file in Files )
{
// show full file name
MessageBox.Show (file.FullName);
//rename old file to new file name and move to new folder
File.Move(file.FullName, NewFileName);
}
}
catch (Exception ex)
{
MessageBox.Show (ex.ToString());
}
}
In my form I have a button that launches the SaveFileDialog module. Then when I load a file, I want to save the path as a string and put that text into a text box on the form. I'm not sure how to do this, or even where to start?
Well the problem with your question is that you say when you "load a file", but you cannot load a file from the SaveFileDialog module. However, if you are opening a file via the OpenFileDialog module, then you are able to use this solution to get the directory path of the file you just loaded:
if (openFileDialog1.ShowDialog(this) == DialogResult.OK)
{
var directoryPath = Path.GetDirectoryName(openFileDialog1.FileName);
if(!string.IsNullOrEmpty(directoryPath))
textBox1.Text = directoryPath;
}
Otherwise, if you are wanting to get the file path of whatever file you saved originally, you can use pretty much the same solution to get the directory path:
if (saveFileDialog1.ShowDialog(this) == DialogResult.OK)
{
var directoryPath = Path.GetDirectoryName(saveFileDialog1.FileName);
if (!string.IsNullOrEmpty(directoryPath))
textBox1.Text = directoryPath;
}
I want to create a browse (OpenFile Dialog) Button to search my local drive and then write out the selected file name (not the full path ) to a TextBox. It should show Only .dat extension files.
I am using Visual Studio 2008
Any help much appreciated!
Next time you ask anything, show some examples of what you have tried please.
private string GetDatFileName()
{
// Create Open File Dialog with the correct filter
using (OpenFileDialog ofd = new OpenFileDialog()) {
ofd.Filter = "dat-file (*.dat) | *.dat";
string fileNameAndFolder = "";
string fileName = "";
// Get file plus folder.
if (ofd.ShowDialog() == DialogResult.OK)
{
fileNameAndFolder = ofd.FileName;
// Split folder and filename
fileName = Path.GetFileName(fileNameAndFolder);
}
// Return the fileName;
return fileName;
}
}
What I have done here is create an OpenFileDialog and set its filter to the required "dat"-format. Only .dat-files will show up in the browserdialog.
Next, you show the dialog and check if the result is OK. If the result is, you will get the full filename (with folder) into a variable. All thats left then, is to get the filename from fileNameAndFolder.
I've Method that carry the uploaded Image and I need to rename it to have Fixed Name in my application But when using File.Copy Method it returns result with (File not Exist)
I don't Know how is that
I tried This File.Copy (UploadFile.FileName, newFilName);
also not responding
string filename = Path.GetFileName(FileUpload.FileName);
string extension = Path.GetExtension(FileUpload.PostedFile.FileName);
string oldFileName = FileUpload.FileName;
string newFileName = ("aboutusImage" + extension);
File.Copy(oldFileName, newFileName);
File.Delete(oldFileName);
File.Move(FileUpload.FileName, newFileName);
FileUpload.SaveAs(Server.MapPath("~/Styles/aboutusImages/") + newFileName);
var updateAboutus = (from a in dbContext.DynamicText
where a.Id == 1
select a).Single();
updateAboutus.Id = updateAboutus.Id;
updateAboutus.Name = updateAboutus.Name;
updateAboutus.Image = Path.Combine("~/Styles/aboutusImages/", "aboutusImage.jpg");
dbContext.SaveChanges();
FileUpload.FileName property represents the file name on the client machine, not on your server.
Trying to File.Copy on it have very few possibility to succeed unless you have the same file in your own server in the current folder.
From the MSDN example
protected void UploadButton_Click(object sender, EventArgs e)
{
// Specify the path on the server to
// save the uploaded file to.
String savePath = #"c:\temp\uploads\";
// Before attempting to perform operations
// on the file, verify that the FileUpload
// control contains a file.
if (FileUpload1.HasFile)
{
String fileName = FileUpload1.FileName;
// Append the name of the file to upload to the path.
savePath += fileName;
// Call the SaveAs method to save the
// uploaded file to the specified path.
// This example does not perform all
// the necessary error checking.
// If a file with the same name
// already exists in the specified path,
// the uploaded file overwrites it.
FileUpload1.SaveAs(savePath);
Of course, the following File.Delete, File.Move have the same problem and should be removed
The name you are trying to move from is just the name that was given on the client side, not the current name on the server. It is probably on some temporary location on the server.
You probably want the FileUpload.SaveAs function.
I'm trying to build a copier so that you use the openFileDialog to chose a file and then the folderBrowserDialog to choose the location to copy it to.
The problem I'm having is that when I use File.Copy(copyFrom,copyTo) it gives me an exception that I can't copy to a directory.
Is there anyway around this, or am I just missing something stupid and noobish. I've tryed useing openFD for choosing both locations and have just tried using the folderBD to see if it made a difference.
I know there should be if statements there to catch the exceptions but this is a rough draft of the code to get working 1st.
Thanks in advance for the help, code attached.
// Declare for use in all methods
public string copyFrom;
public string copyTo;
public string rootFolder = #"C:\Documents and Settings\cmolloy\My Documents";
private void btnCopyFrom_Click(object sender, EventArgs e)
{
// uses a openFileDialog, openFD, to chose the file to copy
copyFrom = "";
openFD.InitialDirectory = rootFolder;
openFD.FileName = "";
openFD.ShowDialog();
// sets copyFrom = to the file chosen from the openFD
copyFrom = openFD.FileName;
// shows it in a textbox
txtCopyFrom.Text = copyFrom;
}
private void btnCopyTo_Click(object sender, EventArgs e)
{
//uses folderBrowserDialog, folderBD, to chose the folder to copy to
copyTo = "";
this.folderBD.RootFolder = System.Environment.SpecialFolder.MyDocuments;
this.folderBD.ShowNewFolderButton = false;
folderBD.ShowDialog();
DialogResult result = this.folderBD.ShowDialog();
// sets copyTo = to the folder chosen from folderBD
copyTo = this.folderBD.SelectedPath;
//shows it in a textbox.
txtCopyTo.Text = copyTo;
}
private void btnCopy_Click(object sender, EventArgs e)
{
// copys file
File.Copy(copyFrom, copyTo);
MessageBox.Show("File Copied");
You have to append the file name to the directory path. Do this:
string destinationPath = Path.Combine(copyTo, Path.GetFileName(copyFrom));
File.Copy(copyFrom, destinationPath);
(with this you'll copy selected file to another directory with the same name of the original one and it'll throw an exception if the same file already exist in that directory)
Edit
Side note: do not hard code the path in your source code, use this:
rootFolder = Environment.GetFolderPath(Environment.SpecialFolder.MyDocuments)
to get the path of current user's documents folder.
Do this:
File.Copy(copyFrom, Path.Combine(copyTo, Path.GetFileName(copyFrom)));
File.Copy needs to know the full path of the new file you want, including the file name. If you just want to use the same file name, you can use this to append the file name to the path:
copyTo = Path.Combine(copyTo, Path.GetFileName(copyFrom));