I have a page that has a search function in a controller which works well
[HttpPost]
public virtual ActionResult Search(SearchModel model)
{
...adds to IEnumerable and such
return View(model);
}
My problem is I have another page with a search box, which I need to redirect to the same view as above. (parameters in the URL is not an option)
#using (Html.BeginForm("Search", "Home", FormMethod.Post, null))
{
#Html.TextBoxFor(t => t.SearchModel)
<input.....
}
but it's not loading up the right URL, it's just adding it to the current one. so instead of example.com/Home/Search it's adding it to the end of where that form is currently located. So if the page was in example.com/About/SearchPage its adding the t.SearchModel to the About/Searchpage
Edit: I have two different Controllers and Views, ControllerA and ViewA works fine, it brings back the search results. I want ViewB, which has an input box, to call ViewA and use ControllerA search technique
You have a nested form. This is not valid HTML. HTML does not allow you to put one form inside another form. You can have more than one form on a page, but you cannot nest them.
I'm also not sure what you mean by "another section", do you mean the #section keyword in Razor? Or do you mean an MVC area? Or something else?
Related
How do I render a full fledged view (not partial view) inside another view?
Scenario, I have different controller and want the exactly same view to render which is already there under other controller with different layout.
I have Wishlist page in Home Controller which shows list of added products, and when user logged in , when I click on wish list it also show me navigation when user is signed in.
How would I do that??
Not many developers know about this but you can use RenderPage, it's specifically designed for that purpose(to render an MVC view inside another view)
#RenderPage("~/Views/Shared/SampleView.cshtml")
You can still create or use a partial view with its own controller and use the RenderAction()
[ChildActionOnly]
public ActionResult ActionPartialView(string p1)
{
//code...
return PartialView();
}
The above code can be in any controller, its own controller, just call it in razor with that controller.
Razor:
#{ Html.RenderAction("Index", "Home"); }
Hope that helps
I want to call a controller ActionResult method from anchor tag without changing the url in MVC3 razor engine.
My url is: "http://localhost:2993/admin/adminindex" and I have one anchor tag "SingOut" and i want to remove my session.
This is my syntax on View page:
<div>#Html.ActionLink("SingOut", "signout", "Admin")</div>
And on Admincontroller I want to call this ActionResult method
public ActionResult signout()
{
Session.Abandon();
return View("~/Views/admin/admin.cshtml");
}
When I click on signout, it always goes to Index ActionResult method.
Is it Possible to call Controller ActionResult method from javascrit not jquery?
I want it only pure javascript not jquery.
Abandoning the session will most likely cause a redirect to the index page. The page you are viewing is protected (as far as i understand) so when you sign out you cant stay on the same page. Then why would you do it asynch if the system is redirecting you anyway (or worse you are logged out and showing a page that doesnt work) ?
On my site, I want to display a Login box on all pages. So I wanted to make a partial view page, which I use on my _Layout.cshtml file in Shared.
But where would the controller for this partial view go? And how would my Login button have access to it?
So, when the Request.IsAuthenticated is true, the login box shows 'Logged in as ...', but when the result is false, I get a little table with the usual Username/Password form.
Edit: After trying some answers below, I seem to be stuck in an endless lopp on the GET method below. It it because my partial view is trying to load me _Layout.cshtml file, as it want to accosiate the 'masterpage' with the partial view? And because my partial view is being rendered in _Layout.cshtml, it's lopping?
public class LoginController : Controller
{
//
// GET: /Login/
public ActionResult Index()
{
return View();
}
[HttpPost]
public ActionResult Index(LoginModel loginModel)
{
if(ModelState.IsValid)
{
var g = new GallaryImage();
var user = g.LoginUser(loginModel.Username, loginModel.Password);
if(user != null)
{
FormsAuthentication.SetAuthCookie(user.username, false);
return RedirectToAction("index", "Home");
}
ModelState.AddModelError("", "Invalid Username/Password");
}
return View();
}
In my _Layout.cshtml, I am trying to load the partial view like this:
<div style="text-align: right">
#Html.Action("Index", "Login")
</div>
See the issue?
FYI, Views don't have controllers. Controllers have Views. The distinction may seem subtle, but it's not. A view can be used by any number of controllers, and views don't care or know about the controllers. So you have to think about the current URL, which means the current Action Method.
In the case of your login partial, it doesn't need much if anything from the Controller. It's directly accessing the User property of the page to find out if it's authenticated. Your login button is just a form with it's action method set to your login method of your account controller.
Even the username can be displayed from the User property of the page.
Just look at the default MVC app that is generated when you create a new Internet project. It has all this functionality already implemented. Just copy it.
You can give controller name as attribute to Html.Action method
Html.Action("ActionName", "ControllerName")
If you use Razor syntax, you must write #Html.Action("ActionName", "ControllerName") in your view and your Action with name ActionName should return PartialView(which wil be your login area).
Try to use HTML.RenderAction("Action", "Controller") and make sure you are not calling your master page from within the partial view. This has the potential to produce a loop.
I'm using MVC 3 ASPX view engine not razor though.
Let's assume I have 2 Controllers, TopicsController and PostsController.
For each controller, I have a couple of views (Index & Details).
The Topic (Index) view inherits System.Web.Mvc.ViewPage<IEnumerable<MessageBoard.Models.Topic>>
The Topic (Details) view inherits System.Web.Mvc.ViewPage<MessageBoard.Models.TopicFormViewModel>
I'm using a TopicFormViewModel because I'm sending additional data along with the Model.
The Post (Details) view just inherits System.Web.Mvc.ViewPage<MessageBoard.Models.Post>
Now, I've created a partial view (CreatePost.ascx) which is (obviously :p) used to create a new Post. I want to be able to re-use this control on all of the views you see above.
Update
I've tried rendering the partial view using <% Html.RenderPartial("New"); %> from my Topics/Index.aspx View, but that results in an exception
The model item passed into the dictionary is of type 'System.Data.Linq.Table`1[MessageBoard.Models.Topic]', but this dictionary requires a model item of type 'MessageBoard.Models.Post'.
Now the problem is that my partial view (CreatePost.ascx) accepts a System.Web.Mvc.ViewUserControl<MessageBoard.Models.Post> and I'm not sure how to pass that from all my views above.
I'm also unsure know how to submit the .ascx values to a certain URL (i.e. /Topics/1/CreatePost), how do I tell the submit button to post to that URL?
Thanks in advance,
Marko
Ciao Marko,
Now the problem is that my partial
view (CreatePost.ascx) accepts a
System.Web.Mvc.ViewUserControl
and I'm not sure how to pass that from
all my views above.
I am not sure I understand what do you mean by "how to pass that from all my views above" but I am sure that you dont have to pass an instance of Post from your views. What is going on is that from your views you will invoke a controller action that creates the Post model object and then bind it to the CreatePost.ascx partial.
I'm also unsure know how to submit the
.ascx values to a certain URL (i.e.
/Topics/1/CreatePost), how do I tell
the submit button to post to that URL?
You have two options:
Inside your CreatePost.ascx partial you are probably using a form.
<% using (Html.BeginForm("action", "controller", FormMethod.Post, new {} )) { %>
If you use in the way I am showing you can change the first and the second params respectively to the names of the Action and the Controller that would habndle your submit.
The second option is using jQuery. Simply set an ID for your form and then
$("#myForm").submit(function(event) {
//post an ajax request to the server
});
Hope this helps!
P.S. To be able to reuse your CreatePost.ascx partial place it inside the shared view folder (where your master page is).
In regards to reusing a partial view which is not in the same view folder, use the following and pass in the model required, alternatively you can define a custom route for it.
<% html.RenderPartial("~/Views/<ControllerName>/<PartialViewName>.ascx", <model>);
#Marko
Another way would be to have in the PostController an Action like the following:
[HttpGet]
public ActionResult CreatePost( int topicId ) {
PostModel pm = _manager.CreateDefaultPost();
pm.TopicID = id;
return PartialView( "CreatePost", pm );
}
Then wherever you want to create a Post you can simply call this action that returns the strong-typed view for your new post.
Even if you have a supplementary http call over the network IMO this solution has the advantage to keep the initialization code of a new Post centralized to a single place.
From the View "point-of-view" the call to the action can be done when the user press the "New Post" button and then inject the received markup inside a modal dialog or in a place of your pleasure in the current page.
Hope it helps!
I have a customer index page that displays customer lists. I have a search functionality within this page and I want the url to be http://mysite/search?id=434 when i perform the search. The index page will also display the search result.
Thanks
public class CustomerController : Controller
...
public ActionResult Search(int id)
{
ViewData["SearchResult"] = MySearchBLL.GetSearchResults(id);
return View("Index");
}
...
Hope this helps
No, you shouldn't have. Just use View("ViewName"); in the controller to show the appropriate view in other actions.
In the URL that you suggest, you should have a Controller method called 'search' and using the 'index' view for that controller.
If thats the case, you can post it back to the same action and in the Controller have different sets of code for the 'GET' and 'POST' to give the functionality that you are looking for.
Have the HTML form post to the same action that rendered it. That action can decide if it's a non-search (first visit) or a search results rendering. That action can populate ViewData with the appropriate data. That is, if you want to do that.
You can also have two views, really easily. And the action can transparently decide which one to render.