var g = urls;
if (g.Count > 1)
{
for(int i = g.Count - 1; i > 0; i--)
{
if (!g[i].Contains("Test"))
{
g.RemoveAt(i);
}
}
}
I create a copy of the List then checking for specific string in each item but there are 23 items left in g one of them is not containing the word "Test" but was not removed it's the first item in the list at index 0.
Because your for loop is not touching element present at index 0, to fix this issue update your for loop to
for(int i = g.Count - 1; i >= 0; i--)
{ //^^^^ This is missing in your code
if (!g[i].Contains("Test"))
{
g.RemoveAt(i);
}
}
To make it more readable, you can traverse from start instead of reverse traversal and store expected element of g into a new list.
var result = new List<string>();
for(int i = 0; i < g.Count; i++)
{
if (g[i].Contains("Test"))
{
result.Add(g[i]);
}
}
To make it more elegant you can use Linq Where() clause,
var result = g.Where(x => x.Contains("Test")).ToList();
If you are looking for a solution which actually update input list (in Your case it is g), then you can use solution suggested by #canton7,
g.RemoveAll(item => !item.Contains("Test"))
Console.WriteLine(string.Join(" ", g));
.RemoveAll()
.NET Fiddle
var g = urls.Where(u => u.Contains("Test")).ToList();
I want to save the result of zarb function which repeats for 1000 times in a list with size 1000. Then I must to increase the index of the list for every calculation to avoid to save the next calculation at the same index of previous one. How can I do that?
var results = new List<float>(1000);
for (int z = 0; z < 1000; z++)
{
results.Add(zarb(sc,z));
//increase the index of resukts
}
foreach (var resultwithindex in results.Select((r, index) => new { result = r, Index = index }).OrderByDescending(r => r.result).Take(20))
{
MessageBox.Show(string.Format("{0}: {1}", resultwithindex.Index, resultwithindex.result));
}
Zarb function
public float zarb(int userid, int itemid)
{
float[] u_f = a[userid];
float[] i_f = b[itemid];
for (int i = 0; i < u_f.Length; i++)
{
result += u_f[i] * i_f[i];
}
return result;
}
No you don't. The Add method (surprisingly) adds an item into the list. It doesn't replace anything. You should read MSDN documentation for List<T>. Also, don't be afraid of trying and seeing the results before asking—you'll save time.
Maybe I don't understand the question, but you do not need index for list. The add method will deal with the it.
Is there a more elegant way to implement going 5 items at a time than a for loop like this?
var q = Campaign_stats.OrderByDescending(c=>c.Leads).Select(c=>c.PID).Take(23);
var count = q.Count();
for (int i = 0; i < (count/5)+1; i++)
{
q.Skip(i*5).Take(5).Dump();
}
for(int i = 0; i <= count; i+=5)
{
}
So you want to efficiently call Dump() on every 5 items in q.
The solution you have now will re-iterate the IEnumerable<T> every time through the for loop. It may be more efficient to do something like this: (I don't know what your type is so I'm using T)
const int N = 5;
T[] ar = new T[N]; // Temporary array of N items.
int i=0;
foreach(var item in q) { // Just one iterator.
ar[i++] = item; // Store a reference to this item.
if (i == N) { // When we have N items,
ar.Dump(); // dump them,
i = 0; // and reset the array index.
}
}
// Dump the remaining items
if (i > 0) {
ar.Take(i).Dump();
}
This only uses one iterator. Considering your variable is named q, I'm assuming that is short for "query", which implies this is against a database. So using just one iterator may be very beneficial.
I may keep this code, and wrap it up in an extension method. How about "clump"?
public static IEnumerable<IEnumerable<T>> Clump<T>(this IEnumerable<T> items, int clumpSize) {
T[] ar = new T[clumpSize];
int i=0;
foreach(var item in items) {
ar[i++] = item;
if (i == clumpSize) {
yield return ar;
i = 0;
}
}
if (i > 0)
yield return ar.Take(i);
}
Calling it in the context of your code:
foreach (var clump in q.Clump(5)) {
clump.Dump();
}
try iterating by 5 instead!
for(int i = 0; i < count; i += 5)
{
//etc
}
Adding more LINQ with GroupBy and Zip:
q
// add indexes
.Zip(Enumerable.Range(0, Int32.MaxValue),(a,index)=> new {Index=index, Value=a})
.GroupBy(m=>m.Index /5) // divide in groups by 5 items each
.Select(k => {
k.Select(v => v.Value).Dump(); // Perform operation on 5 elements
return k.Key; // return something to satisfy Select.
});
I have a 2-dimensional jagged array (though it's always rectangular), which I initialize using the traditional loop:
var myArr = new double[rowCount][];
for (int i = 0; i < rowCount; i++) {
myArr[i] = new double[colCount];
}
I thought maybe some LINQ function would give me an elegant way to do this in one statement. However, the closest I can come up with is this:
double[][] myArr = Enumerable.Repeat(new double[colCount], rowCount).ToArray();
The problem is that it seems to be creating a single double[colCount] and assigning references to that intsead of allocating a new array for each row. Is there a way to do this without getting too cryptic?
double[][] myArr = Enumerable
.Range(0, rowCount)
.Select(i => new double[colCount])
.ToArray();
What you have won't work as the new occurs before the call to Repeat. You need something that also repeats the creation of the array. This can be achieved using the Enumerable.Range method to generate a range and then performing a Select operation that maps each element of the range to a new array instance (as in Amy B's answer).
However, I think that you are trying to use LINQ where it isn't really appropriate to do so in this case. What you had prior to the LINQ solution is just fine. Of course, if you wanted a LINQ-style approach similar to Enumerable.Repeat, you could write your own extension method that generates a new item, such as:
public static IEnumerable<TResult> Repeat<TResult>(
Func<TResult> generator,
int count)
{
for (int i = 0; i < count; i++)
{
yield return generator();
}
}
Then you can call it as follows:
var result = Repeat(()=>new double[rowCount], columnCount).ToArray();
The behavior is correct - Repeat() returns a sequence that contains the supplied object multiple times. You can do the following trick.
double[][] myArr = Enumerable
.Repeat(0, rowCount)
.Select(i => new double[colCount])
.ToArray();
You can't do that with the Repeat method : the element parameter is only evaluated once, so indeed it always repeats the same instance. Instead, you could create a method to do what you want, which would take a lambda instead of a value :
public static IEnumerable<T> Sequence<T>(Func<T> generator, int count)
{
for (int i = 0; i < count; i++)
{
yield return generator();
}
}
...
var myArr = Sequence(() => new double[colCount], rowCount).ToArray();
I just wrote this function...
public static T[][] GetMatrix<T>(int m, int n)
{
var v = new T[m][];
for(int i=0;i<m; ++i) v[i] = new T[n];
return v;
}
Seems to work.
Usage:
float[][] vertices = GetMatrix<float>(8, 3);
What about
var myArr = new double[rowCount, colCount];
or
double myArr = new double[rowCount, colCount];
Reference: http://msdn.microsoft.com/en-us/library/aa691346(v=vs.71).aspx
Probably a really simple one this - I'm starting out with C# and need to add values to an array, for example:
int[] terms;
for(int runs = 0; runs < 400; runs++)
{
terms[] = runs;
}
For those who have used PHP, here's what I'm trying to do in C#:
$arr = array();
for ($i = 0; $i < 10; $i++) {
$arr[] = $i;
}
You can do this way -
int[] terms = new int[400];
for (int runs = 0; runs < 400; runs++)
{
terms[runs] = value;
}
Alternatively, you can use Lists - the advantage with lists being, you don't need to know the array size when instantiating the list.
List<int> termsList = new List<int>();
for (int runs = 0; runs < 400; runs++)
{
termsList.Add(value);
}
// You can convert it back to an array if you would like to
int[] terms = termsList.ToArray();
Edit: a) for loops on List<T> are a bit more than 2 times cheaper than foreach loops on List<T>, b) Looping on array is around 2 times cheaper than looping on List<T>, c) looping on array using for is 5 times cheaper than looping on List<T> using foreach (which most of us do).
Using Linq's method Concat makes this simple
int[] array = new int[] { 3, 4 };
array = array.Concat(new int[] { 2 }).ToArray();
result
3,4,2
If you're writing in C# 3, you can do it with a one-liner:
int[] terms = Enumerable.Range(0, 400).ToArray();
This code snippet assumes that you have a using directive for System.Linq at the top of your file.
On the other hand, if you're looking for something that can be dynamically resized, as it appears is the case for PHP (I've never actually learned it), then you may want to use a List instead of an int[]. Here's what that code would look like:
List<int> terms = Enumerable.Range(0, 400).ToList();
Note, however, that you cannot simply add a 401st element by setting terms[400] to a value. You'd instead need to call Add() like this:
terms.Add(1337);
By 2019 you can use Append, Prepend using LinQ in just one line
using System.Linq;
and then in NET 6.0:
terms = terms.Append(21);
or versions lower than NET 6.0
terms = terms.Append(21).ToArray();
Answers on how to do it using an array are provided here.
However, C# has a very handy thing called System.Collections
Collections are fancy alternatives to using an array, though many of them use an array internally.
For example, C# has a collection called List that functions very similar to the PHP array.
using System.Collections.Generic;
// Create a List, and it can only contain integers.
List<int> list = new List<int>();
for (int i = 0; i < 400; i++)
{
list.Add(i);
}
Using a List as an intermediary is the easiest way, as others have described, but since your input is an array and you don't just want to keep the data in a List, I presume you might be concerned about performance.
The most efficient method is likely allocating a new array and then using Array.Copy or Array.CopyTo. This is not hard if you just want to add an item to the end of the list:
public static T[] Add<T>(this T[] target, T item)
{
if (target == null)
{
//TODO: Return null or throw ArgumentNullException;
}
T[] result = new T[target.Length + 1];
target.CopyTo(result, 0);
result[target.Length] = item;
return result;
}
I can also post code for an Insert extension method that takes a destination index as input, if desired. It's a little more complicated and uses the static method Array.Copy 1-2 times.
Based on the answer of Thracx (I don't have enough points to answer):
public static T[] Add<T>(this T[] target, params T[] items)
{
// Validate the parameters
if (target == null) {
target = new T[] { };
}
if (items== null) {
items = new T[] { };
}
// Join the arrays
T[] result = new T[target.Length + items.Length];
target.CopyTo(result, 0);
items.CopyTo(result, target.Length);
return result;
}
This allows to add more than just one item to the array, or just pass an array as a parameter to join two arrays.
You have to allocate the array first:
int [] terms = new int[400]; // allocate an array of 400 ints
for(int runs = 0; runs < terms.Length; runs++) // Use Length property rather than the 400 magic number again
{
terms[runs] = value;
}
int ArraySize = 400;
int[] terms = new int[ArraySize];
for(int runs = 0; runs < ArraySize; runs++)
{
terms[runs] = runs;
}
That would be how I'd code it.
C# arrays are fixed length and always indexed. Go with Motti's solution:
int [] terms = new int[400];
for(int runs = 0; runs < 400; runs++)
{
terms[runs] = value;
}
Note that this array is a dense array, a contiguous block of 400 bytes where you can drop things. If you want a dynamically sized array, use a List<int>.
List<int> terms = new List<int>();
for(int runs = 0; runs < 400; runs ++)
{
terms.Add(runs);
}
Neither int[] nor List<int> is an associative array -- that would be a Dictionary<> in C#. Both arrays and lists are dense.
You can't just add an element to an array easily. You can set the element at a given position as fallen888 outlined, but I recommend to use a List<int> or a Collection<int> instead, and use ToArray() if you need it converted into an array.
If you really need an array the following is probly the simplest:
using System.Collections.Generic;
// Create a List, and it can only contain integers.
List<int> list = new List<int>();
for (int i = 0; i < 400; i++)
{
list.Add(i);
}
int [] terms = list.ToArray();
one approach is to fill an array via LINQ
if you want to fill an array with one element
you can simply write
string[] arrayToBeFilled;
arrayToBeFilled= arrayToBeFilled.Append("str").ToArray();
furthermore, If you want to fill an array with multiple elements you can use the
previous code in a loop
//the array you want to fill values in
string[] arrayToBeFilled;
//list of values that you want to fill inside an array
List<string> listToFill = new List<string> { "a1", "a2", "a3" };
//looping through list to start filling the array
foreach (string str in listToFill){
// here are the LINQ extensions
arrayToBeFilled= arrayToBeFilled.Append(str).ToArray();
}
Array Push Example
public void ArrayPush<T>(ref T[] table, object value)
{
Array.Resize(ref table, table.Length + 1); // Resizing the array for the cloned length (+-) (+1)
table.SetValue(value, table.Length - 1); // Setting the value for the new element
}
int[] terms = new int[10]; //create 10 empty index in array terms
//fill value = 400 for every index (run) in the array
//terms.Length is the total length of the array, it is equal to 10 in this case
for (int run = 0; run < terms.Length; run++)
{
terms[run] = 400;
}
//print value from each of the index
for (int run = 0; run < terms.Length; run++)
{
Console.WriteLine("Value in index {0}:\t{1}",run, terms[run]);
}
Console.ReadLine();
/*Output：
Value in index 0: 400
Value in index 1: 400
Value in index 2: 400
Value in index 3: 400
Value in index 4: 400
Value in index 5: 400
Value in index 6: 400
Value in index 7: 400
Value in index 8: 400
Value in index 9: 400
*/
If you don't know the size of the Array or already have an existing array that you are adding to. You can go about this in two ways. The first is using a generic List<T>:
To do this you will want convert the array to a var termsList = terms.ToList(); and use the Add method. Then when done use the var terms = termsList.ToArray(); method to convert back to an array.
var terms = default(int[]);
var termsList = terms == null ? new List<int>() : terms.ToList();
for(var i = 0; i < 400; i++)
termsList.Add(i);
terms = termsList.ToArray();
The second way is resizing the current array:
var terms = default(int[]);
for(var i = 0; i < 400; i++)
{
if(terms == null)
terms = new int[1];
else
Array.Resize<int>(ref terms, terms.Length + 1);
terms[terms.Length - 1] = i;
}
If you are using .NET 3.5 Array.Add(...);
Both of these will allow you to do it dynamically. If you will be adding lots of items then just use a List<T>. If it's just a couple of items then it will have better performance resizing the array. This is because you take more of a hit for creating the List<T> object.
Times in ticks:
3 items
Array Resize Time: 6
List Add Time: 16
400 items
Array Resize Time: 305
List Add Time: 20
I will add this for a another variant. I prefer this type of functional coding lines more.
Enumerable.Range(0, 400).Select(x => x).ToArray();
You can't do this directly. However, you can use Linq to do this:
List<int> termsLst=new List<int>();
for (int runs = 0; runs < 400; runs++)
{
termsLst.Add(runs);
}
int[] terms = termsLst.ToArray();
If the array terms wasn't empty in the beginning, you can convert it to List first then do your stuf. Like:
List<int> termsLst = terms.ToList();
for (int runs = 0; runs < 400; runs++)
{
termsLst.Add(runs);
}
terms = termsLst.ToArray();
Note: don't miss adding 'using System.Linq;' at the begaining of the file.
This seems like a lot less trouble to me:
var usageList = usageArray.ToList();
usageList.Add("newstuff");
usageArray = usageList.ToArray();
Just a different approach:
int runs = 0;
bool batting = true;
string scorecard;
while (batting = runs < 400)
scorecard += "!" + runs++;
return scorecard.Split("!");
int[] terms = new int[400];
for(int runs = 0; runs < 400; runs++)
{
terms[runs] = value;
}
static void Main(string[] args)
{
int[] arrayname = new int[5];/*arrayname is an array of 5 integer [5] mean in array [0],[1],[2],[3],[4],[5] because array starts with zero*/
int i, j;
/*initialize elements of array arrayname*/
for (i = 0; i < 5; i++)
{
arrayname[i] = i + 100;
}
/*output each array element value*/
for (j = 0; j < 5; j++)
{
Console.WriteLine("Element and output value [{0}]={1}",j,arrayname[j]);
}
Console.ReadKey();/*Obtains the next character or function key pressed by the user.
The pressed key is displayed in the console window.*/
}
/*arrayname is an array of 5 integer*/
int[] arrayname = new int[5];
int i, j;
/*initialize elements of array arrayname*/
for (i = 0; i < 5; i++)
{
arrayname[i] = i + 100;
}
To add the list values to string array using C# without using ToArray() method
List<string> list = new List<string>();
list.Add("one");
list.Add("two");
list.Add("three");
list.Add("four");
list.Add("five");
string[] values = new string[list.Count];//assigning the count for array
for(int i=0;i<list.Count;i++)
{
values[i] = list[i].ToString();
}
Output of the value array contains:
one
two
three
four
five
You can do this is with a list. here is how
List<string> info = new List<string>();
info.Add("finally worked");
and if you need to return this array do
return info.ToArray();
Here is one way how to deal with adding new numbers and strings to Array:
int[] ids = new int[10];
ids[0] = 1;
string[] names = new string[10];
do
{
for (int i = 0; i < names.Length; i++)
{
Console.WriteLine("Enter Name");
names[i] = Convert.ToString(Console.ReadLine());
Console.WriteLine($"The Name is: {names[i]}");
Console.WriteLine($"the index of name is: {i}");
Console.WriteLine("Enter ID");
ids[i] = Convert.ToInt32(Console.ReadLine());
Console.WriteLine($"The number is: {ids[i]}");
Console.WriteLine($"the index is: {i}");
}
} while (names.Length <= 10);