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Can I find total time of 1st time and 2nd time in DATETIME?

I would like to find total time of 2 DATETIME. Now I have 2 DATETIMES: loginDT and logoutDT. For loginDT I get from Database and logoutDT is now. like this code below
DateTime loginDT = (DateTime)readerS["login_Date_Time"];
DateTime logoutDT = DateTime.Now;
DateTime total = ??????????????
How should I do?
Thanks All

Time intervals in C# are measured with TimeSpan structure. You can get it simply by substracting two DateTime variables:
DateTime loginDT = (DateTime)readerS["login_Date_Time"];
DateTime logoutDT = DateTime.Now;
TimeSpan total = logoutDT - loginDT;

DateTime loginDT = (DateTime)readerS["login_Date_Time"];
DateTime logoutDT = DateTime.Now;
TimeSpan difference = loginDT.Subtract(logoutDT);

It seems, that you want something like that:
DateTime loginDT = (DateTime)readerS["login_Date_Time"];
DateTime logoutDT = DateTime.Now;
//TODO: have look at TotalHours, TotalSeconds, TotalMilliseconds
// Difference in Days;
// store this value as a Number field of the RDBMS table
Double totalDays = (logoutDT - loginDT).TotalDays;

Difference between two times C# [duplicate]

How do I get the time difference between two DateTime objects using C#?

The following example demonstrates how to do this:
DateTime a = new DateTime(2010, 05, 12, 13, 15, 00);
DateTime b = new DateTime(2010, 05, 12, 13, 45, 00);
Console.WriteLine(b.Subtract(a).TotalMinutes);
When executed this prints "30" since there is a 30 minute difference between the date/times.
The result of DateTime.Subtract(DateTime x) is a TimeSpan Object which gives other useful properties.

You want the TimeSpan struct:
TimeSpan diff = dateTime1 - dateTime2;
A TimeSpan object represents a time interval (duration of time or elapsed time) that is measured as a positive or negative number of days, hours, minutes, seconds, and fractions of a second. The TimeSpan structure can also be used to represent the time of day, but only if the time is unrelated to a particular date.
There are various methods for getting the days, hours, minutes, seconds and milliseconds back from this structure.
If you are just interested in the difference then:
TimeSpan diff = (dateTime1 - dateTime2)).Duration();
will give you the positive difference between the times regardless of the order.
If you have just got the time component but the times could be split by midnight then you need to add 24 hours to the span to get the actual difference:
TimeSpan diff = dateTime1 - dateTime2;
if (diff < 0)
{
diff = diff + TimeSpan.FromDays(1);
}

What you need is to use the DateTime classs Subtract method, which returns a TimeSpan.
var dateOne = DateTime.Now;
var dateTwo = DateTime.Now.AddMinutes(-5);
var diff = dateTwo.Subtract(dateOne);
var res = String.Format("{0}:{1}:{2}", diff.Hours,diff.Minutes,diff.Seconds));

The way I usually do it is subtracting the two DateTime and this gets me a TimeSpan that will tell me the diff.
Here's an example:
DateTime start = DateTime.Now;
// Do some work
TimeSpan timeDiff = DateTime.Now - start;
timeDiff.TotalMilliseconds;

IF they are both UTC date-time values you can do TimeSpan diff = dateTime1 - dateTime2;
Otherwise your chance of getting the correct answer in every single possible case is zero.

var startDate = new DateTime(2007, 3, 24);
var endDate = new DateTime(2009, 6, 26);
var dateDiff = endDate.Subtract(startDate);
var date = string.Format("{0} years {1} months {2} days", (int)dateDiff.TotalDays / 365,
(int)(dateDiff.TotalDays % 365) / 30, (int)(dateDiff.TotalDays % 365) / 30);
Console.WriteLine(date);

private void button1_Click(object sender, EventArgs e)
{
TimeSpan timespan;
timespan = dateTimePicker2.Value - dateTimePicker1.Value;
int timeDifference = timespan.Days;
MessageBox.Show(timeDifference.ToString());
}

You can use in following manner to achieve difference between two Datetime Object. Suppose there are DateTime objects dt1 and dt2 then the code.
TimeSpan diff = dt2.Subtract(dt1);

You need to use a TimeSpan. Here is some sample code:
TimeSpan sincelast = TimeSpan.FromTicks(DateTime.Now.Ticks - LastUpdate.Ticks);

Year, Month, Day differ counter(Date) in C#

I was wondering if there was already an implemented Datecounter which will count how many years, month and days it differs from a date to another? And if there is a difference, the function will count how many years, month and days in difference and store it and we only need to use Console.Writeline(timecomparer.yearDiffCounter); to tell them how many years it is in difference
For example (pseudocode, not 100% correct)!
Date date1 = new Date("2013-07-05");
Date date2 = new Date("2010-07-05");
TimeComparer compare = new TimeComparer();
compare.differDate(date1,date2); //here it will count and give 3 years difference

Using Noda Time:
LocalDate date1 = new LocalDate(2013, 07, 05);
LocalDate date2 = new LocalDate(2010, 07, 05);
Period period = Period.Between(date2, date1, PeriodUnits.YearMonthDay);
Console.WriteLine("{0} years, {1} months, {2} days",
period.Years, period.Months, period.Days);
// "3 years, 0 months, 0 days"

Powerful solution for time is Noda Time by Jon Skeet.

public string DateDiff(DateTime DateTime1, DateTime DateTime2)
{
string dateDiff = null;
TimeSpan ts1 = new TimeSpan(DateTime1.Ticks);
TimeSpan ts2 = new TimeSpan(DateTime2.Ticks);
TimeSpan ts = ts1.Subtract(ts2).Duration();
dateDiff = ts.Days.ToString() + "day"
+ ts.Hours.ToString() + "hours"
+ ts.Minutes.ToString() + "minutest"
+ ts.Seconds.ToString() + "seconds";
return dateDiff;
}
my way you can change.

Boolean operations on DateTime objects in C# yield TimeSpan objects
DateTime Yesterday = DateTime.Now().AddDays(-1);
DateTime Today = DateTime.Now();
TimeSpan difference = Today - Yesterday;
A timespan can then tell you how many days, hours, minutes, seconds etc it has.
If you want years from a Timespan, see this answer by brianary

how to subtract previous date from current date using c# [duplicate]

This question already has answers here:
C#: how do I subtract two dates?
(11 answers)
Closed 10 years ago.
i want to subtract previous date from current date. previous date may be 2 months and 15 days or 1 year 9 month and 10 days... like this etc... So please how can i write the Coding in C#. thanks a lot.

Any answer using TimeSpan will not be able to give you "2 months and 15 days" - as the length of a month changes over time.
Doing this using the base class libraries is a pain... which is one of the reasons I started the Noda Time project. Amongst its other features, it allows you to determine the Period between to dates (or dates and times, etc).
For example, let's see how long I've been on Stack Overflow:
LocalDate today = new LocalDate(2013, 2, 8);
LocalDate start = new LocalDate(2008, 9, 26);
// This defaults to using year, month, day units. You can specify alternatives.
Period period = Period.Between(start, today);
Console.WriteLine("{0} years; {1} months; {2} days",
period.Years, period.Months, period.Days);
Output:
4 years; 4 months; 13 days
Or if you actually wanted to subtract a period from a date (the question isn't very clear) you can do that too:
Period period = new PeriodBuilder { Years = 4, Months = 4, Days = 13 }.Build();
LocalDate today = new LocalDate(2013, 2, 8);
LocalDate start = today - period;
Console.WriteLine(start);
Output:
25 September 2008
Note that this doesn't give September 26th, because of the somewhat crazy nature of date/time arithmetic. If you added the period to September 26th you'd get today... but that's not the same thing. Treat this as a warning that you need to be really careful about describing what you want to achieve :)
This second side you can do with the BCL fairly easily though:
DateTime today = new DateTime(2013, 2, 8);
DateTime start = today.PlusYears(-4).PlusMonths(-4).PlusDays(-13);
There's no BCL type to represent that "years, months, days" value though.

Your question is a little confusing. Do you want to subtract one date from another date, or do you want to subtract a period of time from a date.
1. Subtract one date from another date:
DateTime previousDate = new DateTime(1990, 12, 12);
DateTime currentDate = DateTime.UtcNow;
TimeSpan difference = currentDate - previousDate;
You can then use the TimeSpan methods to get the difference in various units of time as you like.
Here's more info on TimeSpan: http://msdn.microsoft.com/en-us/library/system.timespan.aspx
2. Subtract a period of time from a date
DateTime currentDate = DateTime.UtcNow;
TimeSpan periodOfTime = new TimeSpan(12, 12, 0, 0);
DateTime newDate = currentDate - periodOfTime;
However, you'll have to calculate yourself what the length of a month is, if that's what you want.

You can use DateTime.Subtract.
Examples from article:
System.DateTime date1 = new System.DateTime(1996, 6, 3, 22, 15, 0);
System.DateTime date2 = new System.DateTime(1996, 12, 6, 13, 2, 0);
System.DateTime date3 = new System.DateTime(1996, 10, 12, 8, 42, 0);
// diff1 gets 185 days, 14 hours, and 47 minutes.
System.TimeSpan diff1 = date2.Subtract(date1);
// date4 gets 4/9/1996 5:55:00 PM.
System.DateTime date4 = date3.Subtract(diff1);
// diff2 gets 55 days 4 hours and 20 minutes.
System.TimeSpan diff2 = date2 - date3;
// date5 gets 4/9/1996 5:55:00 PM.
System.DateTime date5 = date1 - diff2;

TimeSpan timeSpan = new TimeSpan(2,2,0);
DateTime dateTime = DateTime.Now.Subtract(timeSpan);

When you subtract two date in C# you get a TimeSpan object.
You can acces different properties of it to get the actual days, hours, minutes etc. taht it represents:
DateTime a;
DateTime b;
//assign some values
TimeSpan span = a.Subtract(b);
Console.WriteLine("Days: " + span.Days);

The following should do.
TimeSpan diff = DateTime.Now - previousDate;

How to set current time to a value

I was just wondering if there is a way to get the current time and set it into a value.
If its 12:06 AM.. I want to get that time and set it into currentTime.
Example
float currentTime = 0;
currentTime = 12.06;

As others have mentioned, the DateTime class would be ideal for this, and to work out the difference between 2 date/times:
DateTime end = DateTime.Now;
DateTime start = new DateTime(2011, 12, 5, 12, 6,0);
double hours = (end - start).TotalHours;
The subtraction of DateTime objects results in a TimeSpan object that you can use to see the hours/minutes etc.

try DateTime class
DateTime dt = DateTime.Now;

Is this what you're looking for?
DateTime currentTime;
currentTime = DateTime.Now;

Don't use floats or strings. You can do all kinds of cool things using DateTime.
Here's how you'd get the hours that someone worked:
var clockIn = new DateTime(2011,12,4,9,0,0); // December 4th, 9 AM
var clockOut = new DateTime(2011,12,4,17,0,0); // December 4th, 5 PM
var duration = clockOut - clockIn; // TimeSpan
Console.Write(duration.TotalHours); // 8

A few people have mentioned how, but as a 'better' recommendation you should use
DateTime currentTime = DateTime.UtcNow
Otherwise you have issues when the clocks go back, if your timing code is run on those days. (plus it is far easier to alter the UTC time to local time than it is to convert a '1am' to UTC (as there will be two of them when the clocks go back)

Well if you really what it as a float then try:
var currentDate = DateTime.Now;
float currentTime = float.Parse((currentDate.Hour > 12 ? currentDate.Hour -12 :
currentDate.Hour) + "." + currentDate.Minute);
I wouldn't recommend comparing dates or time with floats. A better options would be to use timespans.

You should be using a Timespan instance for time related values, you can use the flexibility to get the required values like
TimeSpan ts = DateTime.Now.TimeOfDay;
ts.ToString("hh:mm") // this could be what you are looking for
You could then use ts.TotalHours which would give you fractional hours (as a double) else you could construct a string specifically using ts.Hours ..ts.Minutes play around and it could be prove useful.

Try the following:
DateTime StartTime=StartTime value;
DateTime CurrentTime=DateTime.Now;
TimeSpan dt = CurrentTime.Subtract(StartTime);
In dt you will get a working time period.

If you want to have the difference between two times, then do this:
DateTime dateOne = DateTime.Parse(enteredTime);
DateTime dateTwo = DateTime.Now;
TimeSpan difference = dateOne - dateTwo;