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How to remove the parent node and xml declaration in a xml file using C#?

I wish to remove the Parent node and xml declaration from the file. Below is the input file.
<?xml version="1.0" encoding="utf-8"?>
<Items>
<Product>
<ID>001</ID>
<Name>John</Name>
<Designation>Developer</Designation>
</Product>
</Items>
I need to remove the XML declaration and parent node . Like below.
<Product>
<ID>001</ID>
<Name>John</Name>
<Designation>Developer</Designation>
</Product>
How could I do it using C#.NET?

You simply parse the XML with XDocument, like this:
var xml = #"<?xml version=""1.0"" encoding=""utf-8""?>
<Items>
<Product>
<ID>001</ID>
<Name>John</Name>
<Designation>Developer</Designation>
</Product>
</Items>";
var doc = XDocument.Parse(xml);
var s = doc.Root.Element("Product").ToString();
Console.WriteLine(s);
Which outputs
<Product>
<ID>001</ID>
<Name>John</Name>
<Designation>Developer</Designation>
</Product>

Format and rewrite xml file

I have this xml file.
<?xml version="1.0" encoding="utf-8"?><test1 name="all">
<section name="Header"><holder name="top" >top</holder><holder name="banner">banner</holder></section>
</test1>
I want to format this file in a manage way like this(at least line break):
<?xml version="1.0" encoding="utf-8"?>
<test1 name="all">
<section name="Header">
<holder name="top" >top</holder>
<holder name="banner">banner</holder>
</section>
</test1>
in c#
XDocument xmlDoc = XDocument.Load("file.xml"); //load file
foreach(xml node ...) //Need help for this logic
{
//...Add line break ....
}

If you want to get file with formatted XML, then you just save xmlDoc.
XDocument xmlDoc = XDocument.Load("file.xml"); //load file
xmlDoc.Save("formatted.file.xml");
But it will be fully formatted (with indentations).

Reading and Editing XML file

I have an XML file which contains employee details. How can i edit the existing employee names in that MXL file using C# .NET.
Here is the xml file.
<?xml version="1.0" encoding="utf-8"?>
<Employees>
<Employee id="1">
<Name>Employee 1</Name>
<Designation>SE </Designation>
<Qualification>MCA </Qualification>
</Employee>
<Employee id="2">
<Name>Employee 2</Name>
<Designation>SE </Designation>
<Qualification>MCA </Qualification>
</Employee>
<Employee id="3">
<Name>Employee 3</Name>
<Designation>SE </Designation>
<Qualification>MCA </Qualification>
</Employee>
</Employees>
How can i edit the employee names. I am new to xml. For example using Console Application

You can simple do that using Linq to Xml.
using System.Xml.Linq;
...
XDocument xDoc = XDocument.Load(#"Your xml file path goes here"); // or XDocument.Parse("Your xml string goes here");
xDoc.Root.Elements("Employee").First(xe => xe.Attribute("id").Value == "1").Element("Name").Value = "your value";
Here is a good reference for head start: Programming Guide (LINQ to XML)

you can use XML Serialization, in my opinion this is the most comfortable way
of working with c# and xml,
some examples are here:
http://msdn.microsoft.com/en-us/library/58a18dwa(v=vs.110).aspx

Reading different XML with C#/DOM

I am currently using DOM to navigate xml in my C# project. However, some XML that i've come across lately is a bit different.
whereas usually I have:
<?xml version="1.0" encoding="UTF-8"?>
<feed xmlns="http://www.w3.org/2005/Atom">
<entry>
<author>
<name>Me =)</name>
</author>
<content>
<somefield1>
<Subfield>subfield data</subfield>
</somefield>
</content>
</entry>
</feed>
and can navigate using foreach entry as entry, selectsinglenode(/content/somefield1/subfield), innertext to get the data from the subfield for each entry, the new XML looks like this:
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<atom:feed xmlns:atom="http://www.w3.org/2005/Atom">
<atom:entry>
<atom:author>
<name>Me =)</name>
</atom:author>
<atom:content>
<somefield1>
<Subfield>subfield data</subfield>
</somefield>
</atom:content>
</atom:entry>
</atom:feed>
selectsinglenode(/atom:content/somefield1/subfield) is definitely not going to work...any suggestions?

atom: is just the namespace, and possibly you might just ignore it. If it still not works, you may have to use:
XmlNamespaceManager nsmgr = new XmlNamespaceManager(doc.NameTable);
nsmgr.AddNamespace("atom", "http://www.w3.org/2005/Atom");
selectsinglenode("atom:content/somefield1/subfield", nsmgr);
Which is documented here

Create a new XMLDocument by filtering an existing document in c# using xpath

I have a situation where I receive an XML (document) file from an external company. I need to filter the document to remove all data I am not interested in.
The file is about 500KB but will be requested very often.
let say the following file:
<dvdlist>
<dvd>
<title>title 1</title>
<director>directory 2</director>
<price>1</price>
<location>
<city>denver</city>
</location>
</dvd>
<dvd>
<title>title 2</title>
<director>directory 2</director>
<price>2</price>
<location>
<city>london</city>
</location>
</dvd>
<dvd>
<title>title 3</title>
<director>directory 3</director>
<price>3</price>
<location>
<city>london</city>
</location>
</dvd>
</dvdlist>
What I need is simply filter the document based on the city = london in order to end up with this new XML document
<dvdlist>
<dvd>
<title>title 2</title>
<director>directory 2</director>
<price>2</price>
<location>
<city>london</city>
</location>
</dvd>
<dvd>
<title>title 3</title>
<director>directory 3</director>
<price>3</price>
<location>
<city>london</city>
</location>
</dvd>
</dvdlist>
I have tried the following
XmlDocument doc = new XmlDocument();
doc.Load(#"C:\Development\Website\dvds.xml");
XmlNode node = doc.SelectSingleNode("dvdlist/dvd/location/city[text()='london']");
Any help or links will appreciate
Thanks

XPath is a selection expression language -- it never modifies the XML document(s) it operates on.
Therefore, in order to obtain the desired new XML document, you need to either use XML DOM (not recommended) or apply an XSLT transformation to the XML document. The latter is the recommended way to go, since XSLT is a language especially designed for tree transformations.
In .NET one can use the XslCompiledTransform class and its Transform() method. Read more about these in the relevant MSDN documentation.
The XSLT transformation itself is extremely simple:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:template match="node()|#*">
<xsl:copy>
<xsl:apply-templates select="node()|#*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="dvd[not(location/city='london')]"/>
</xsl:stylesheet>
Here, you can find a complete code example how to obtain the result of the transformation as an XmlDocument (or if desired, as an XDocument).

Here's an example using LINQ to XML.
//load the document
var document = XDocument.Load(#"C:\Development\Website\dvds.xml");
//get all dvd nodes
var dvds = document.Descendants().Where(node => node.Name == "dvd");
//get all dvd nodes that have a city node with a value of "london"
var londonDVDs = dvds.Where(dvd => dvd.Descendants().Any(child => child.Name == "city" && child.Value == "london"));