I have one label and textbox1 and textbox2 and one button . I enter the text in textbox1
then click the button and how to show that textbox1 value in textbox2?
Add a click eventHandler to your button and set the text property of textbox2
<form id="form1" runat="server">
<div>
<asp:TextBox ID="TextBox1" runat="server"></asp:TextBox>
<asp:TextBox ID="TextBox2" runat="server"></asp:TextBox>
<asp:Button ID="Button1" runat="server" Text="Button" OnClick="Button1_Click" />
</div>
</form>
Within your code file ...
protected void Button1_Click(object sender, EventArgs e)
{
TextBox2.Text = TextBox1.Text;
}
this.textbox2.Text = this.textbox1.Text;
in your button click add this code
textbox2.Text = textbox1.Text;
Double click the button. This will get you into codebehind text. After this write
textBox1.Text = textBox2.Text;
void Button1_Click(object sender, eventargs e)
{
TextBox1.Text = TextBox2.Text;
}
Related
I have calculated the two textbox values and displayed successfully it into third textbox but the issues are when I enter value to textbox1 and move to textbox2 the page get reload as I have mentioned AutoPostBack="true" for textbox1 and textbox2 and when I remove this AutoPostBack="true" the calculated value is not displayed in third textbox.
Here is my code behind
protected void txttotal_TextChanged(object sender, EventArgs e)
{
if (!string.IsNullOrEmpty(txttotal.Text) && !string.IsNullOrEmpty(txtdiscount.Text))
txtgrandtotal.Text = (Convert.ToInt32(txttotal.Text) - Convert.ToInt32(txtdiscount.Text)).ToString();
}
protected void txtdiscount_TextChanged(object sender, EventArgs e)
{
if (!string.IsNullOrEmpty(txttotal.Text) && !string.IsNullOrEmpty(txtdiscount.Text))
txtgrandtotal.Text = (Convert.ToInt32(txttotal.Text) - Convert.ToInt32(txtdiscount.Text)).ToString();
}
Here is aspx code
<asp:TextBox ID="txttotal" runat="server" CssClass="textstyle" OnTextChanged="txttotal_TextChanged" AutoPostBack="true"></asp:TextBox>
<asp:TextBox ID="txtdiscount" runat="server" CssClass="textstyle" OnTextChanged="txtdiscount_TextChanged" AutoPostBack="true"></asp:TextBox>
<asp:TextBox ID="txtgrandtotal" runat="server" CssClass="textstyle" ReadOnly="true"></asp:TextBox>
To add the two text box value and show it on third text box you can add them on button click event here is the code
aspx page
<div>
<asp:TextBox runat="server" ID="txt1"></asp:TextBox>
<asp:TextBox runat="server" ID="txt2"></asp:TextBox>
<br />
<asp:Label runat="server" Text="Answer"></asp:Label> <asp:TextBox runat="server" ID="txt3"></asp:TextBox>
<asp:Button runat="server" ID="btn1" Text="CLICK TO ADD" OnClick="btn1_Click"/>
</div>
.cs
protected void btn1_Click(object sender, EventArgs e)
{
if (!string.IsNullOrEmpty(txt1.Text) && !string.IsNullOrEmpty(txt2.Text))
{
txt3.Text = (Convert.ToInt32(txt1.Text) + Convert.ToInt32(txt2.Text)).ToString();
}
else {
Response.Write("Please Enter Value");
}
}
If i enter below text in my multi line textbox
Nitin
Kumar
Shukla
then i got this result
Nitin Kumar Shukla
but i want result same as i write in my multi line textbox
Here is my aspx page code
<asp:TextBox ID="ttt" TextMode="MultiLine" runat="server"></asp:TextBox>
<asp:Button ID="btn" runat="server" Text="hjhj" onclick="btn_Click" />
<asp:Label ID="lll" runat="server"></asp:Label>
here is my cs page code
protected void btn_Click(object sender, EventArgs e)
{
lll.Text = ttt.Text;
}
try this
lll.Text = ttt.Text.Replace(Environment.NewLine, "<br />");
I have 2 textbox on my page and a Button. When I click on a button, the text from the textbox is emailed. But, then when i refresh the page and no content is there, then also i get an email.
protected void Button1_Click(object sender, EventArgs e)
{
if (!string.IsNullOrEmpty(TextBox1.Text) && !string.IsNullOrEmpty(TextBox2.Text))
{
//email logic
TextBox1.Text = "";
TextBox2.Text = "";
}
else
{
//do nothing
}
}
Here, on clicking the button, i get an email but then when i refresh the page, even though there is no data, then also it goes inside the loop and i get an email.
How do i stop this ?
Do the following in your Page_Load event and keep your TextBoxes and Button in an <asp:UpdatePanel>. Then the page will not ask to re-submit each time you refresh the page.
protected void Page_Load(object sender, EventArgs e)
{
if (!IsPostBack)
{
TextBox1.Text = string.Empty;
TextBox2.Text = string.Empty;
}
}
UPDATE
Keep the controls within an UpdatePanel as follows
<asp:UpdatePanel ID="UpdatePanel1" runat="server" UpdateMode="Conditional" >
<ContentTemplate>
<asp:TextBox ID="TextBox1" runat="server"></asp:TextBox>
<asp:TextBox ID="TextBox2" runat="server"></asp:TextBox>
<asp:Button ID="Button1" runat="server" Text="Send mail" onclick="Button1_Click" />
</ContentTemplate>
</asp:UpdatePanel>
You need to use the the POST > Redirect > GET pattern. Here is explanation link
I designed a simple page with, two text boxes, one checkbox, one button, and one label.
When I start I want to check the checkbox to make the button enabled, and then enter two numbers into the two textboxes, click the button to do addition, and show the result in the label.
But when I click the checkbox the page postback is not working; it's not writing Page is posted back on the page and the button is still disabled.
However, if I make the button enabled and do the addition it invokes the page postback and also invokes the checkedchanged method.
<asp:TextBox ID="txtFirst" runat="server"></asp:TextBox>
<asp:TextBox ID="txtSecond" runat="server"></asp:TextBox>
<asp:Label ID="result" runat="server"></asp:Label>
<td>
<asp:CheckBox ID="cboptions" runat="server" AutoPostBack="True"
onCheckedChanged="cboptions_CheckedChanged" />
</td>
<asp:Button ID="submit" runat="server" Text ="addition" onclick="Button_Click"/>
Code:
protected void Page_Load(object sender, EventArgs e)
{
if (Page.IsPostBack == true)
{
Response.Write("Page is posted back");
}
}
protected void cboptions_CheckedChanged(object sender, EventArgs e)
{
submit.Enabled = cboptions.Checked;
}
protected void submit_Click(object sender, EventArgs e)
{
int a = Convert.ToInt32(txtFirst.Text);
int b = Convert.ToInt32(txtSecond.Text)+a;
result.Text = b.ToString();
}
There were many formatting errors in your code, do it this way
Aspx
<asp:TextBox ID="txtFirst" runat="server"></asp:TextBox>
<asp:TextBox ID="txtSecond" runat="server"></asp:TextBox>
<asp:Label ID="result" runat="server"></asp:Label>
<asp:CheckBox ID="cboptions" runat="server" AutoPostBack="True"
onCheckedChanged="cboptions_CheckedChanged" />
<asp:Button ID="btn" runat="server" Text ="addition" onclick="Button_Click"/>
C#
protected void Page_Load(object sender, EventArgs e)
{
if (Page.IsPostBack == true)
{
Response.Write("Page is posted back");
}
}
protected void cboptions_CheckedChanged(object sender, EventArgs e)
{
btn.Enabled = cboptions.Checked;
}
protected void Button_Click(object sender, EventArgs e)
{
int a = Convert.ToInt32(txtFirst.Text);
int b = Convert.ToInt32(txtSecond.Text) + a;
result.Text = b.ToString();
}
I have 2 labels and 2 text boxes and 1 buttons displayed.
When the page loads the Name and Button (will be initially displayed). Later when i click on the Button i need to display the age label and textbox. How can i do this ?
<ol>
<li>
<asp:Label runat="server" AssociatedControlID="Name">
User name
</asp:Label>
<asp:TextBox runat="server" ID="Name" Width="167px" />
<asp:Button ID="Button1" runat="server" Text="Button" />
</li>
<li>
<asp:Label runat="server" AssociatedControlID="age">age</asp:Label>
<asp:TextBox runat="server" ID="age" TextMode="age" Width="240px" />
</li>
</ol>
code for button press
protected void Button1_Click(object sender, EventArgs e)
{
}
You could set the label/textbox Visible property to True in server side. Alternatively, you could use JavaScript to avoid post backs to the server.
Add OnClientClick to your button :
<asp:Button ID="Button1" runat="server" Text="Button" OnClientClick="ShowLabel();"/>
and declare the JavaScript function on page:
<script type="text/javascript">
function ShowLabel() {
// Note that the client ID might be different from the server side ID
document.getElementById('lblAge').style.display = 'inherit';
}
</script>
You need to set the Label Display style to none initially.
<asp:Label ID="lblAge" style="display: none;" runat="server" AssociatedControlID="age">age</asp:Label>
Try below code:
You need to set Visible property of controls to True or False according to your requirement. By default, all controls are visible on the screen whenever they are added on the page.You need to do following thing:
You need to remove TextMode="age" as there is not any supported textmode of type age.
Need to define id of control if you want to access a control server side in code behind. So define the ID of Label that you put corresponding to Age textbox.
By Default age label and textbox will not be visible by using below code:
<asp:Label ID="lblAge" runat="server" AssociatedControlID="age" Visible="false">age</asp:Label>
<asp:TextBox runat="server" ID="age" Width="240px" Visible="false"/>
Code behind:
After button click age label and the textbox will be visible by using below code:
protected void Button1_Click(object sender, EventArgs e)
{
lblAge.Visible = true;
age.Visible = true;
}
First add id to elements and set visible false
<asp:Label runat="server" AssociatedControlID="age" Visible="false" Id="lbl1">age</asp:Label>
<asp:TextBox runat="server" ID="age" TextMode="age" Width="240px" Visible="false" />
button click event set visible true
protected void Button1_Click(object sender, EventArgs e)
{
lbl1.Visible = True;
age.Visible = True;
}
this is the basic concept of asp.net. you can use visible property of the control.
your TextMode enumeration is wrong. there is no Age enumeration for Textbox.TextMode TextMode
<li>
<asp:Label runat="server" AssociatedControlID="age" id="lblAge">age</asp:Label>
<asp:TextBox runat="server" ID="age" TextMode="age" Width="240px" />
</li>
in code behind
protected void Button1_Click(object sender, EventArgs e)
{
lblAge.Visible=true;
age.Visible=true;
}
protected void Page_Load(object sender, EventArgs e)
{
NameLabel.Visible = false;
NameBox.Visible = false;
}
protected void Button1_Click(object sender, EventArgs e)
{
NameLabel.Visible = true;
NameBox.Visible = true;
}