<ContentControl Content="Test">
<ContentControl.ContentTemplate>
<DataTemplate>
<Border>
<ContentPresenter />
</Border>
</DataTemplate>
</ContentControl.ContentTemplate>
</ContentControl>
It throws stackoverflow exception. However if i use any other control else than ContentPresenter it works fine even ItemPresenter also works.I knows it doesnt make any sense to have ContentPresenter there but just for Knowledge want to know. Why it throws StackOverFlow exception and also Why does Intellisense shows it can be added(I mean it comes there in Intellisense that means syntatically its not wrong to have ContentPresenter there). Any help will be highly appericiated. Or is it any flaw in Wpf.
The MSDN page for ContentPresenter says:
When a ContentPresenter object is in a ControlTemplate of a
ContentControl, the Content, ContentTemplate, and
ContentTemplateSelector properties get their values from the
properties of the same names of the ContentControl. You can have the
ContentPresenter property get the values of these properties from
other properties of the templated parent by setting the ContentSource
property or binding to them.
I imagine it gives a StackOverflow because it just keeps on trying to apply the template to the ContentPresenter in the ContentTemplate, and then on the next one inside it, and then the one inside it, etc.
You also can do things like the following, so this pattern probably isn't always wrong, even though IntelliSense probably doesn't do any checking for these sorts of scenarios.
<ContentControl Content="Test">
<ContentControl.ContentTemplate>
<DataTemplate>
<Border>
<ContentPresenter ContentStringFormat="{}{0}" />
</Border>
</DataTemplate>
</ContentControl.ContentTemplate>
</ContentControl>
Related
I'm trying to use the PropertyGrid component from PropertyTools to display information on an object. I can bind the object easily enough -- it's a property on my DataContext -- but one of the things that can't be derived from the object is the name that should be displayed in the tab header. (And I can't change that; the object I'm inspecting comes from a third party.) The proper name is a different property on my DataContext.
PropertyGrid has a way to change the way the tab header is displayed, by passing a DataTemplate to its TabHeaderTemplate property. But something bizarre happens inside of the template: my DataContext is gone, replaced by something else. When I try to say {Binding TabName} in the appropriate place inside the context, it errors out and tells me that TabName is not a valid property on class Tab. But my DataContext class isn't called Tab; that's something inside of PropertyTools's codebase!
I'm still new to WPF, so I have no clue what's going on here. Why is the in-scope DataContext that's perfectly valid in the rest of the XAML file being yoinked out from under me inside this template, and how can I fix it?
EDIT: Posting the XAML as requested. The template is literally just the simplest possible thing:
<UserControl.Resources>
<DataTemplate x:Key="HeaderTemplate">
<TextBlock Text="{Binding TabName}" />
</DataTemplate>
</UserControl.Resources>
And then further down the page,
<props:PropertyGrid
SelectedObject="{Binding Value}"
TabHeaderTemplate="{StaticResource HeaderTemplate}" />
But for some bizarre reason, in the template it's trying to interpret the binding inside the wrong DataContext!
In this case, just be sure to specify the source in your binding. There are a few ways to do this. One is to use the RelativeSource property of the Binding. Another is to use ElementName
Give your UserControl this attribute:
x:Name="Root".
Then change your binding to use it
<TextBlock Text="{Binding ElementName=Root, Path=DataContext.TabName}" />
Or use this:
<TextBlock Text="{Binding RelativeSource={RelativeSource AncestorType={x:Type local:MyUserControl}}, Path=DataContext.TabName}"/>
I want to know is there anyway to put contentpresenter in itemtemplate of an itemscontrol to display my data. I don't want hard code binding like Text="{Binding username}" cause I am building a custom control, I think ContentPresenter is what I want. But after I tried using contentpresenter, it give me stackoverflowexception.
<ItemsControl ItemsSource="{Binding SelectedItems, ElementName=listbox}" DisplayMemberPath={Binding DisplayMemberPath}">
<ItemsControl.ItemPanel>
<ItemsPanelTemplate>
<StackPanel Orientation="Horizontal" IsItemsHost="True"/>
</ItemsPanelTemplate>
</ItemsControl.ItemPanel>
<ItemsControl.ItemTemplate>
<DataTemplate>
<StackPanel Orientation="Horizontal">
<TextBlock x:Name="Separator" Text=", "/>
<ContentPresenter/>
<!--<TextBlock Text="{Binding username}"/>-->
</StackPanel>
</DataTemplate>
</ItemsControl.ItemTemplate>
</ItemsControl>
That's my code.
If without those seperator and itemtemplate, I able to display my data by just using the displaymemberpath, but it stack all the name together. I still finding any solution to solve it. I hope you can provide some ideas to do this.
The answer is no, you can't. A ContentPresenter is supposed to be used in a ControlTemplate, not a DataTemplate, so it is not the right control to use. From the linked page on MSDN:
You typically use the ContentPresenter in the ControlTemplate of a ContentControl to specify where the content is to be added.
What you can do alternatively, is to declare a number of DataTemplates in a Resources section (complete with Binding Paths) for different types of data and omit the x:Key directives, eg. do not name them. Also, do not specify one for the ItemsControl.ItemTemplate.
When doing this, WPF will implicitly select the correct DataTemplate for the relevant data type and so you can have different outputs for different data types. See the The DataType Property section of the Data Templating Overview page on MSDN for further explanation of this technique.
Yes, and it works well. Outside of a ContentControl's template, you must bind the Content by hand:
<ContentPresenter Content="{Binding username}"/>
I do this a great deal and it never misbehaves. ContentPresenter seems to be implemented for general use. I wonder if the API docs overstate its relationship to ContentControl.
I found an easier way to solve this problem by using horizontal listbox. Thanks for responses
Background:
I have a ListBox containing items defined by DataTemplates. Right now, if an object in the list has the property IsEditable set to true, the item's property information will be displayed inside of textboxes (via DataTemplate change), instead of textblocks (so the user can edit the content of that list item)
IsEditable is toggled on/off by a button inside of each list item. I have been told that we need to keep the state of all objects consistent, which means I can't just rebind the ItemsSource and lose everything.
Currently, I'm using this to re-render:
this.lbPoints.Dispatcher.Invoke(DispatcherPriority.Render, new Action(() => { }));
Question:
The aforementioned code snippet KIND OF does its job. By "kind of", I mean, it does eventually cause my data to become re-rendered, but only when I scroll to the bottom of the list and then scroll back up to the item i'm trying to re-render.
1) How can I re-render the data immediately without having to scroll around to get it to show up?
The guys commenting are right that you're going about this the wrong way... there is rarely a need to force a ListBox to re-render. You're probably causing yourself some additional grief trying to switch the DataTemplates (although it is possible). Instead of that, think about data binding the TextBox.IsReadOnly property to your IsEditable property:
<TextBox IsReadOnly="{Binding IsEditable}" Text="{Binding Text}" />
Another alternative is to use a BooleanToVisibilityConverter to show a different Grid in your DataTemplate when your IsEditable property is true. Unfortunately, that Converter doesn't have an inverse operation, so you could create an IsNotEditing property to bind to the Grid in the DataTemplate that is originally displayed. I'm not sure if that's clear... see this example:
<DataTemplate DataType="{x:Type YourPrefix:YourDataType}">
<Grid>
<Grid Visibility="{Binding IsNotEditing, Converter={StaticResource
BooleanToVisibilityConverter}}">
<!-- Define your uneditable UI here -->
</Grid>
<Grid Visibility="{Binding IsEditing, Converter={StaticResource
BooleanToVisibilityConverter}}">
<!-- Define your editable UI here -->
</Grid>
</Grid>
</DataTemplate>
You could also define your own BooleanToVisibilityConverter class that has an IsInverted property, so that you can just use the one IsEditing property. You'd need to declare two Converters still, like this:
<Converters:BoolToVisibilityConverter x:Key="BoolToVisibilityConverter" />
<Converters:BoolToVisibilityConverter x:Key="InvertedBoolToVisibilityConverter"
IsInverted="True" />
Then your XAML would be like this:
<Grid Visibility="{Binding IsEditing, Converter={StaticResource
InvertedBoolToVisibilityConverter}}">
<!-- Define your uneditable UI here -->
</Grid>
<Grid Visibility="{Binding IsEditing, Converter={StaticResource
BoolToVisibilityConverter}}">
<!-- Define your editable UI here -->
</Grid>
I have created a RadioButton style which I use across my application. The display part of which uses the content presenter to display whatever content I added to the button:
<ContentPresenter>
<ContentPresenter.ContentTemplate>
<DataTemplate>
<Grid>
<TextBlock Text="{TemplateBinding Content}" />
</Grid>
</DataTemplate>
</ContentPresenter.ContentTemplate>
</ContentPresenter>
I'm then attempting to bind a decimal with a string formatter to the styled button like so:
<RadioButton Content="{Binding Stake, StringFormat={}{0:C}}" Style="{DynamicResource NeutralSelectorButtonStyle}" />
Stake is a decimal within a ViewModel which is set as the DataContext. When I run this up the content coming through is blank.
I made a change using a label in the DataTemplate rather than a TextBlock, this displayed the decimal but had not formatted it.
Can anyone explain why this is happening and possibly provide a solution.
If you require any more information just ask :)
Thanks in advance.
You are almost there just instead of setting the string format inside binding you should use ContentStringFormat property when in ContentControls.
Take a look at this Label (it works with any content control):
<Label Content="{Binding Path=MaxLevelofInvestment}" ContentStringFormat="Amount is {0}"/>
ContentPresenter also has this property:
http://msdn.microsoft.com/en-us/library/system.windows.controls.contentpresenter.contentstringformat%28v=vs.110%29.aspx
Try it out. I hope it works for you.
I used Microsoft's Chart Control of the WPF toolkit to write my own chart control.
I blogged about it here. My Chart control stacks the yaxes in the chart on top of each other. As you can read in the article this all works quite well. Now I want to create a viewmodel that controls the data and axes in the chart. So far I'm able to add axes to the chart and show them in the chart. But I have a problem when I try to add the lineseries because it has one DependentAxis and one InDependentAxis property. I don't know how to assign the proper xAxis and yAxis controls to it.
Below you see part of the LineSeriesViewModel. It has a nested XAxisViewModel and YAxisViewModel property.
public class LineSeriesViewModel : ViewModelBase, IChartComponent
{
XAxisViewModel _xAxis;
public XAxisViewModel XAxis
{
get { return _xAxis; }
set
{
_xAxis = value;
RaisePropertyChanged(() => XAxis);
}
}
//The YAxis Property look the same
}
The viewmodels all have their own datatemplate.
The xaml code looks like this:
<UserControl.Resources>
<DataTemplate x:Key="xAxisTemplate" DataType="{x:Type l:YAxisViewModel}">
<chart:LinearAxis x:Name="yAxis" Orientation="Y" Location="Left" Minimum="0" Maximum="10" IsHitTestVisible="False" Width="50" />
</DataTemplate>
<DataTemplate x:Key="yAxisTemplate" DataType="{x:Type l:XAxisViewModel}">
<chart:LinearAxis x:Name="xAxis" Orientation="X" Location="Bottom" Minimum="0" Maximum="100" IsHitTestVisible="False" Height="50" />
</DataTemplate>
<DataTemplate DataType="{x:Type l:LineSeriesViewModel}">
<!--Binding doesn't work on the Dependent and IndependentAxis! -->
<!--YAxis XAxis and Series are properties of the LineSeriesViewModel -->
<l:FastLineSeries DependentAxis="{Binding Path=YAxis}"
IndependentAxis="{Binding Path=XAxis}"
ItemsSource="{Binding Path=Series}"/>
</DataTemplate>
<Style TargetType="ItemsControl">
<Setter Property="ItemsPanel">
<Setter.Value>
<ItemsPanelTemplate>
<!--My stacked chart control -->
<l:StackedPanel x:Name="stackedPanel" Width="Auto" Height="Auto" Background="LightBlue">
</l:StackedPanel>
</ItemsPanelTemplate>
</Setter.Value>
</Setter>
</Style>
</UserControl.Resources>
<Grid HorizontalAlignment="Stretch" VerticalAlignment="Stretch" ClipToBounds="True">
<!-- View is an ObservableCollection of all axes and series-->
<ItemsControl x:Name="chartItems" ItemsSource="{Binding Path=View}" Focusable="False">
</ItemsControl>
</Grid>
This code works quite well. When I add axes they get drawn. But the DependentAxis and InDependentAxis of the lineseries control stay null, so the series doesn't get drawn. How can I bind the nested viewmodels to the properties of a control?
It should work. A few things you can check:
Does the Series Binding work? If so, try to figure out what's the difference.
Are you sure that the XAxis and YAxis properties actually have values? Try putting a breakpoint in the getter. If it's reached, the Binding works. You can also put a converter (IValueConverter) on the Binding (that simply returns the value it receives) and place a breakpoint there.
Use PresentationTraceSources.TraceLevel=High on the Binding to get more verbose tracing (that will appear in the VS Output window).
Are DependentAxis/IndependentAxis defined as dependency properties on FastLineSeries?
Hope that helps,
Aelij.
You've probably already checked this but I find that when I'm debugging bindings the first and easiest place to start is running a debug session from VS as the debug output tells which objects and properties are failing to bind. I usually end up discovering I need to explicitly set a DataContext or something else like a typo. The output to look for start like this:
System.Windows.Data Error: 39 :
BindingExpression path error:
this is followed by the property name you tried to bind to and usually most importantly the class against which its actually trying to bind. If this doesn't help there's a great article here on the debugging bindings: http://www.beacosta.com/blog/?p=52 which discusses the use of PresentationTraceSources.TraceLevel=High which Aelij mentioned, as well as a few other techniques. Hope this gets onto the right track.
Regards,
Mike