I'm super new to C# and this is my third question here regarding it.
I'm making an app which can be minimized to the system tray. I have two forms named Form1 and Form2. What I have done so far is:
In Form1, I have a button which is showing the Form2 using this code:
this.Hide();
Form2 form2 = new Form2();
form2.Show();
The Form2 has a button which is hiding it, using this code:
this.Hide();
Now, I have the tray icon on the task bar. The tray icon has a ContexMenuStrip, and there is an option named show using this code:
Form1 form1 = new Form1();
form1.Show();
The problem is that when I click on it, a second tray icon is appearing on the taskbar. Both tray icons have the same menu and both are working. If I click on show again another window with Form1 pops up, and there are three tray icons, and so on....
Can someone help me?
It's because you are creating a new Form1 everytime.
Form1 form1 = new Form1();
You don't want to create a new Form1, you want to show the old one. Give Form2 a reference to your first form1 (call it theMainform1 for example). And then instead of
Form1 form1 = new Form1();
form1.Show();
You want to do
theMainform1.Show();
So you would have:
this.Hide();
Form2 form2 = new Form2();
form2.theMainform1 = this;
form2.Show();
The issue is that you are making a new instance of Form1. This creates a brand new window instead of reviving your old one.
Form1 form1 = new Form1();
form1.Show();
You need to have Form2 reference the original instance of Form1. You can make a constructor to pass in a self reference that would look like
Form2 form2 = new Form2(this);
You can prevent windows from having icons in the taskbar by settings ShowInTaskbar to false on the form. However, the other answers are correct when they say you're creating a new form over and over.
Why would you want two forms to show at the same time? Should they both be on the screen at the same time and be active at the same time? If so, you might try a MDI interface. http://en.wikipedia.org/wiki/Multiple_document_interface
It's possible in WinForms, but I think Microsoft is moving away from them in WPF.
Here is a working code in case that someone is looking for it:
Form1:
/* Hiding Form1 and showing Form2 */
private void btnHideForm1_Click(object sender, EventArgs e)
{
Form mod = new Form2();
mod.Owner = this;
mod.Show();
this.Hide();
}
Form2:
/* Hiding Form2 and showing Form1 */
private void btnHideForm2_Click(object sender, EventArgs e)
{
this.Owner.Show();
this.Close();
}
Thanks for your help guys!!!
I LOVE YOU!!!
Related
Having a strange behaviour with my application whereby when navigation between web browser (or any other application) and clicking back into the application seems to open the wrong Form? So user literally has to make use of Tab window to open the correct Form.
For e.g. Form1 is the main form. User clicks a button which opens Form2. Form1 is hidden behind the scene while Form2 opens. Now if user goes to a different application e.g. browser and clicks back into the application Form1 is displayed and there is no other way of going back to Form2 without the Tab window?
I have used the .ShowDialog() property when opening Form2 which disabled the parent form Form1 but still seems to do it occasionally?!?
I have also set the ShowInTaskBar for Form2 to False so that there is one icon in taskbar for all forms.
Not really sure what can cause this behaviour to happen?
private void button1_Click(object sender, EventArgs e)
{
Form2 form2 = new Form2();
form2.ShowDialog();
}
I think you need to tell Form2 who its owner form is.
Like this:
private void button1_Click(object sender, EventArgs e)
{
Form2 form2 = new Form2();
form2.Owner = this;
form2.ShowDialog();
}
see System.Windows.Forms for more information
When you open form2, you need set mdiParent of form1.
First, set form1 as "isMdiParent" to "true" in properties, and then use the follow code:
private void button1_Click(object sender, EventArgs e)
{
Form2 form2 = new Form2();
form2.MdiParent = this;
form2.Show();
}
I have two Forms in a project.
When my application runs, Form1 is opened. After that I am opening Form2.
How can I access Form1 from Form2 with reflection?
Why would you want to use reflection for this?
When you create the second form, just pass in a reference to the first one:
// I assume it's code within Form1 which opens Form2
Form2 form2 = new Form2(this);
form2.Show();
That's assuming you're happy to add a constructor with Form2 as a parameter. Alternatively, make it a property in Form2:
Form2 form2 = new Form2 { Form1 = this };
form2.Show();
if you open just one instance of form2 you can do this too: Form2 f2 = Application.OpenForms["Form2"];
I have a Main form.I want to launch another form from it and launch another from the launched form.I want to ensure that the Main form is not editable when sub forms are displayed so i use showdialog()
Mainform>(Showdialog)>form1>(showDialog+dispose)>form2(dispose)>Mainform
From Mainform i call form2.ShowDialog() then from form2 i use the following code to launch another form
this.visible=false;
form3.showdialog();
this.dispose();
But there are some problems in this.Is there a better way to achieve what im looking for?
edit:more description
I have a Main form,User clicks a Button on Mainform>Form1 is lauched>User clicks a Button in Form1>Form 2 is lauched(diposing/hiding form1) after form2 is closed Mainform should be brought to front and made editable,until then all other forms should be on top of Mainform and Mainform should be un-editable
The problem is that you have to specify the MainForm as the parent for (both) form2 and form3. When you use the overload of ShowDialog that has no parameters, WinForms uses the active form as the parent, so form3's parent becomes form2 automatically. You are then trying to close/dispose form2 causing form3 to become orphaned.
There are several options for getting the reference to MainForm, but the simplest is to use:
form2/3.ShowDialog(Application.OpenForms["MainForm"]);
Assuming that you have set the Name property on MainForm to "MainForm".
In your code, this.dispose() is executed only after form3 is closed. What i think you want is to close form2 after form3 was closed, so you can call this.Close() instead of this.Dispose().
this.visible=false;
form3.showdialog();
this.Close();
Or maybe, after form3 is shown up you dont need form2 any more. That meas:
this.visible=false;
//show instead of showdialog so it wont wait until form3 is closed
form3.show();
this.Close();
It looks like you are trying to implement something like a wizard. The best solution would be to launch all the child forms sequentially, in the main form.
If you need to pass data along the sequence, you should pass it from each dialog to the main form, which then passes it to the next dialog.
MainForm:
Form1 f = new Form1();
if (f.ShowDialog(this) == DialogResult.OK) {
Form2 f2 = new Form2();
f2.ShowDialog(this);
}
Form1 (button click which will open the form 2):
button1_click(object sender, EvengArgs e) {
this.DialogResult = DialogResult.OK;
Close();
}
Does anyone know how to maximize a form from another form, in c#?
I tried the code below but it won't work:
Form1 form1 = new Form1();
form1.WindowState = FormWindowState.Maximized;
Any ideas?
Well two possible problems, either you don't get any form at all, then the solution is to Show the form.
Form1 form1 = new Form1();
form1.WindowState = FormWindowState.Maximized;
form1.Show();
But I guess that you already have a form1 loaded somewhere, then you can not use
Form1 form1 = new Form1();
because then you creates a new form that you don't display, remove this line and find a way to pass a reference to form1 from where it was originally created to the method where the above code is located.
Go To Load Form Or Button As View Code and use This Code :
C#
this.WindowState = System.Windows.Forms.FormWindowState.Maximized;
I hope it will be useful for you ;)
I'm encountering strange behavior with forms on a c# 3.5 app. On a button click, my form1 hides itself, creates a new form2, and shows form2. Form1 also contains the event method triggered when form2 closes. Here's the code inside Form1:
Form2 form2;
void button1_Click(object sender, EventArgs e)
{
this.Hide();
form2 = new form2();
form2.Show();
form2.FormClosed += new FormClosedEventHandler(form2_FormClosed);
}
void form2_FormClosed(object sender, FormClosedEventArgs e)
{
form2.Dispose();
form2 = null;
this.Show();
}
Now, my problem is that sometimes when I open form2 (hiding form1), or when I close form2 (showing form1), the new form will come up on the screen for a blink and then hide itself. It's still open and I can click it from the taskbar to show it again, but the window itself is sent behind any other open windows. It looks like it opens up but minimizes instantly.
This behavior occurs randomly. Sometimes forms will open up and hide without a problem, but sometimes they'll lose focus over another window. I've tried using focus(), activate(), and topmost but all have failed to prevent the sudden hiding.
Does anyone know why is this happening and how to fix it?
Thanks.
You hide your form too soon. For a brief moment, your app has no window that can contain the focus. That forces Windows to go hunting for another window to give the focus to, it will pick one from another application. That window will now be the foreground window, your second form will not get the focus and appear lower in the Z-order. The fix is simple:
void button1_Click(object sender, EventArgs e)
{
form2 = new form2();
form2.Show();
form2.FormClosed += new FormClosedEventHandler(form2_FormClosed);
this.Hide(); // Moved
}