I have the following code:
int width = 10;
int height = 7;
bool[,] array1 = new bool[width, height];
string values =
"1100000000" +
"1100000011" +
"0001100011" +
"0001100000" +
"0001110000" +
"0000000110" +
"0000000110";
for (int x = 0; x < width; x++)
{
for (int y = 0; y < height; y++)
{
array1[x, y] = (values[x + y * width] == '1');
}
}
im looking for a algorithm that would extract Ranges where we have a 1.
so from this data we would get rectangles
(0,0,2,2),
(8,1,2,2),
(3,2,3,3),
(7,5,2,2)
the order of the rectangles do not matter!
But i have no idea how to do this any one got any pointers?
After reading Rusty Weber answer i came up with the following:
private static List<Rectangle> GetRectangles(bool[,] array)
{
List<Rectangle> rectangles = new List<Rectangle>();
for (int x = 0; x < array.GetLength(0); x++)
{
for (int y = 0; y < array.GetLength(1); y++)
{
if (array[x, y])
{
rectangles.Add(GetRectangle(array, new Point(x, y)));
}
}
}
return rectangles;
}
static Rectangle GetRectangle(bool[,] array, Point startLocation)
{
int maxX = int.MinValue;
int minX = int.MaxValue;
int maxY = int.MinValue;
int minY = int.MaxValue;
HashSet<Point> visitedLocations = new HashSet<Point>();
Stack<Point> pointsToGo = new Stack<Point>();
Point location;
pointsToGo.Push(startLocation);
while (pointsToGo.Count > 0)
{
location = pointsToGo.Pop();
if (!location.X.IsBetween(0, array.GetLength(0) - 1))
continue;
if (!location.Y.IsBetween(0, array.GetLength(1) - 1))
continue;
if (!array[location.X, location.Y])
continue;
if (visitedLocations.Contains(location))
continue;
visitedLocations.Add(location);
pointsToGo.Push(new Point(location.X + 1, location.Y));
pointsToGo.Push(new Point(location.X, location.Y + 1));
pointsToGo.Push(new Point(location.X - 1, location.Y));
pointsToGo.Push(new Point(location.X, location.Y - 1));
}
foreach (Point location2 in visitedLocations)
{
array[location2.X, location2.Y] = false;
if (location2.X > maxX)
maxX = location2.X;
if (location2.X < minX)
minX = location2.X;
if (location2.Y > maxY)
maxY = location2.Y;
if (location2.Y < minY)
minY = location2.Y;
}
return new Rectangle(minX, minY, maxX - minX + 1, maxY - minY + 1);
}
public static bool IsBetween<T>(this T item, T start, T end)
{
return Comparer<T>.Default.Compare(item, start) >= 0
&& Comparer<T>.Default.Compare(item, end) <= 0;
}
COMMENT :: It might help me to answer your question if you have better defined coordinates. (0,0,2,2) isn't exactly Cartesian and it may need some explaining. Is this the top left corner followed by the widths?
Ok. The easiest to program way, in my opinion at least, to extract all possible rectangles from the graph is to have a recursively defined method that searches in a specific direction for the symmetric rectangle pattern. This however could end up being really slow so I hope that speed isn't a constraint for you. Looking at the style of code, I would say that this is a school assignment for either recursion or dynamic programming.
something along the lines of the following pseudocode
`
for i in width
{
for j in height
{
if(point[i,j] == 1)
{
potentials = searh_in_direction(i,j,graph,width,height,RIGHT,[[i,j]] )
listOfAllRects.append(potentials)
}
}
}
list_of_rectangle searh_in_direction(i,j,graph,width,height,direction, listofpoints )
{
nextdirection = direction.nextdirection; //Right -> down -> left-> up
//DEVELOP METHOD FOR RECURSION HERE THAT RETURNS ALL SETS OF 4 POINTS THAT
for every point in the direction of travel
if the point is the origional point and we have 4 points including the point we are looking at, we have a rectangle and we need to return
if point on direction of travel is a one travel on the next direction
posiblerects.append(searh_in_direction(i,j,graph,width,height,nextdirection , listofpoints.append(currentpoint)))
//after all points in direction have bee searched
return posiblerects.
}
`
I know that this code could be very confusing but that is the gist of what you need as a recursive element.
I will also note that I can already see several bugs in this code but I have run out of the 15 minutes that I said that I was going to spend on this post so you might have to pick them out yourself.
This gives you the same results you're looking for:
static void Main(string[] args)
{
string values =
"1100000000" +
"1100000011" +
"0001100011" +
"0001100000" +
"0001110000" +
"0000000110" +
"0000000110";
int width = 10;
int height = 7;
bool[,] array = new bool[width, height];
for (int x = 0; x < width; x++)
for (int y = 0; y < height; y++)
array[x, y] = (values[x + y * width] == '1');
List<Rectangle> rectangles = new List<Rectangle>();
for (int x = 0; x < width; ++x)
{
for (int y = 0; y < height; ++y)
{
if (array[x, y] && !Used(rectangles, x, y))
{
int rHeight = 1;
for (int rX = x + 1; rX < width && array[rX, y] && !Used(rectangles, rX, y); ++rX)
for (int rY = y + 1; rY < height && array[rX, rY] && !Used(rectangles, rX, rY); ++rY)
if (rY - y >= rHeight)
rHeight = rY - y + 1;
int rWidth = 1;
for (int rY = y + 1; rY < height && rY - y <= rHeight && array[x, rY] && !Used(rectangles, x, rY); ++rY)
for (int rX = x + 1; rX < width && array[rX, rY] && !Used(rectangles, rX, rY); ++rX)
if (rX - x >= rWidth)
rWidth = rX - x + 1;
rectangles.Add(new Rectangle(x, y, rWidth, rHeight));
}
}
}
foreach (Rectangle rect in rectangles)
Console.WriteLine(rect);
}
private static bool Used(IEnumerable<Rectangle> rectangles, int x, int y)
{
return rectangles.Any(r => r.Contains(x, y));
}
I made an adhoc Rectangle struct since I didn't reference System.Drawing, but you can pass a System.Drawing.Point to the System.Drawing.Rectangle.Contains() and get the same results.
Also, notice that the width of your array should actually be 10 and your indexing math was wrong. You should be multiplying y by the width, not the height.
It is not clear from the question if you really want rectangles that cover the 1's exactly, or if you want bounding volumes that can contain zeroes, but will cover all the 1's with a reasonably small number of rectangles.
Assuming you want rectangles to cover the 1's, and you don't need a perfect solution:
Make a temporary copy of the array.
Iterate over the temporary looking for 1's
When you hit a 1, begin a new rectagle that starts as 1x1, offset to that location ( e.g. covers just that 1 )
Expand that rectangle rightward so long as there is a 1 in the next cell
Expand that rectangle downards so long as the row below has 1's matching the width
of the current rectangle.
ONce you can't expand down any more, emit that recgantle, and clear all the 1's covered by that rectangle from the temporary
continue scanning for 1's starting with the cell directly after the top right corner of the current rectangle.
This will produce a decent covering - but by no means ideal. If you need a perfect covering - e.g. the guaranteed minimum number of rectangles then it is harder.
Related
I am trying to generate a grid across my map and add nodes depending on the perlin noise value. Depending on the value obtained from the perlin noise at a location, I will add a new Node which will be of a certain type e.g. Mountain, Water etc to represent terrian. Here I am trying to make it so that if the value is > 0.5, this mean it's only mountains and so a black coloured cubes should surround the mountain areas, However, my black cubes do not match the mountain areas from the perlin noise and I cannot seem to figure out why I am going wrong. Would appreciate any insight into how I could go about achieving this.
private void LocateWalkableCells()
{
for(int z = 0; z < Height; z++)
{
for(int x = 0; x < Width; x++)
{
noise = GetNoiseValue(x, z);
if(noise > 0.5) {
grid[x,z] = new Node(new Vector3(x, 0, z), TerrainType.Mountain, 1);
}
else {
grid[x,z] = new Node(new Vector3(x, 0, z), TerrainType.Grass, 1);
}
}
}
}
private float GetNoiseValue(int x, int z)
{
int pos = (x * Width) + z;
return Mathf.Round(terrainGenerator.noiseArray[pos] * 10) / 10;
}
// Draw gizmos to visualize colour
void OnDrawGizmos()
{
Gizmos.DrawWireCube(transform.position, new Vector3(Width, 1, Height));
if(grid != null)
{
foreach(Node n in grid)
{
if(n.TerrainType == TerrainType.Grass)
{
Gizmos.color = Color.green;
}
else if(n.TerrainType == TerrainType.Mountain)
{
Gizmos.color = Color.black;
}
Gizmos.DrawCube(n.Position, Vector3.one * (nodeDiameter - .1f));
}
}
}
noiseArray is used for the vertices of the terrain in the following code:
vertices = new Vector3[(Width + 1) * (Depth + 1)];
noiseArray = PerlinNoise();
int i = 0;
for(int z = 0; z <= Depth; z++)
{
for(int x = 0; x <= Width; x++)
{
var currentHeight = noiseArray[i];
if(currentHeight > HeightThreshold)
{
currentHeight *= HeightMultiplier;
}
vertices[i] = new Vector3(x, currentHeight, z);
i++;
}
}
Output
Result from suggested answer
Still seems to miss some mountain areas, colouring green instead of black.
It think the issue is in
var pos = (x * Width) + z;
since x is you index on the width of the grid you would probably rather want
var pos = z * Width + x;
in other words you want to
skip z rows
each row has Width elements
then from there take the xth element
assuming your terrain is laid out row-wise.
Or if it is laid out column-wise (which is rather unusual but possible)
var pos = x * Height + z;
or in other words
skip x columns
each column has Height elements
then from there take the zth element
See also Converting index of one dimensional array into two dimensional array i. e. row and column
Update
Now that you have showed the terrain generation code it needs to be
var pos = z * (Width + 1) + x;
since the terrain array has actually Width + 1 elements per row.
It works for most of it:
The problem starts when the height is alot larger than the width (3x9, 3x11, 5x11 etc.)
As you can see the first line is out of place, increasing the height further will repeat this pattern.
Here is the code (Note: my z and y for cube coordinates is swapped):
void SpawnHexGrid(int Width, int Height)
{
int yStart = -Height / 2;
int yEnd = yStart + Height;
for (int y = yStart; y < yEnd; y++)
{
int xStart = -(Width + y) / 2;
int xEnd = xStart + Width;
if (Width % 2 == 0)
{
if (y % 2 == 0)
{
xStart++;
}
}
else
{
if (y % 2 != 0)
{
xStart++;
}
}
Debug.Log("y: " + y + " , Start: " + xStart + " , End: " + xEnd);
for (int x = xStart; x < xEnd; x++)
{
SetHexagon(new Cube(x, y));
}
}
}
Edit:
After changing to #Idle_Mind solution my grid looks like this:
Edit again:
I found a solution, after changing to #Idle_Mind's solution I corrected the tilting by using y again:
int xStart = -Width / 2 - (y / 2);
but this caused a similar problem as before, but this time I realized it had something to do with the way an int is rounded, when y is negative xStart would be 1 lower then expected, so I just add 1 whenever y is negative:
int add = 0;
if (y < 0)
{
add = 1;
}
int xStart = -Width / 2 - ((y - add) / 2);
This works like a charm now, thanks everyone.
Change your SpawnHexGrid() to:
void SpawnHexGrid(int Width, int Height)
{
int xStart = -Width / 2;
int yStart = -Height / 2;
int yEnd = yStart + Height;
for (int y = yStart; y < yEnd; y++)
{
int xEnd = xStart + Width + (y%2==0 ? 0 : -1);
for (int x = xStart; x < xEnd; x++)
{
SetHexagon(new Cube(x, y));
}
}
}
My test rig:
---------- EDIT ----------
I don't understand why you're using the y value as part of your calculation for x. Make the x constant for a whole column as you'd expect for a regular grid. In my code, the shorter rows still start at the SAME x coord as the longer ones; it's the length of them that changes. Then, when you draw, I simply calculate the position for a normal grid, but add half the width of the hexagon for all odd y positions resulting in the offset you need for the hexagons.
For example, here is a 5x5 grid drawn "normally" without offsetting the odd Y rows. It's clear that the starting X coordinate for all rows is the same:
So the stored x,y coord are all based on a normal grid, but the drawing code shifts the odd y rows. Here's where I change the X coord, only for drawing, of the odd y rows:
if (pt.Y % 2 != 0)
{
center.Offset(Width / 2, 0);
}
So, after adding the offset (again, only at drawing time) for odd Y rows, it now looks like:
And here is the grid shown with the internal coord of each hexagon being displayed:
Hope that makes it clear how I approached it.
I believe you're just alternating a different row size for a hexagonal map. If so something like this should work:
class Program
{
static void Main(string[] args)
{
const int Height = 4;
const int Width = 4;
for (int y = 0; y < Height; ++y)
{
int rowSize = y % 2 > 0 ? Width + 1 : Width;
for (int x = 0; x < rowSize; ++x)
{
Console.WriteLine($"{x}:{y}");
}
}
Console.ReadLine();
}
}
In c#, I want to loop through every square possible in a rectangle. The square size is much smaller than the rectangle dimensions. But note that I don't mean loop through every square in a grid pattern, I mean every square at any type of location (not limited to a grid). Its like randomly picking a square at a random location, but it needs to go through all possible locations and only get each one once (no duplicates).
Does anyone know of an algorithm for this?
Thanks
Al you need to do is set an origin (say, left-top), find out the maximum side length from that location, and iterate from 1 to that value for every pixel in your image.
Class names are fictional, adapt to your own needs.
IEnumerable<Rectangle> AllSquaresIn(Rectangle rect)
{
for (int x = 0; i x < rect.Width; x++)
{
for (int y = 0; y < rect.Height; y++)
{
int maxLength = Math.Min(rect.Width - x, rect.Height - y);
for (int i = 1; i <= maxLength; i++)
{
yield return new Rectangle(x, y, x + i, y + i);
}
}
}
}
Since i is always positive, it will be impossible to have duplicate rectangles.
Since it appears from the comments that you only want the rectangles of a given size:
IEnumerable<Rectangle> AllSquaresIn(Rectangle rect, int length)
{
for (int x = 0; i x < rect.Width - length; x++)
{
for (int y = 0; y < rect.Height - length; y++)
{
yield return new Rectangle(x, y, x + length, y + length);
}
}
}
Does anyone know of any code to render an Ellipse to an array in C#? I had a look about, I couldn't find anything that answered my problem.
Given the following array:
bool[,] pixels = new bool[100, 100];
I'm looking for functions to render both a hollow and filled ellipse within a rectangular area. e.g:
public void Ellipse(bool[,] pixels, Rectangle area)
{
// fill pixels[x,y] = true here for the ellipse within area.
}
public void FillEllipse(bool[,] pixels, Rectangle area)
{
// fill pixels[x,y] = true here for the ellipse within area.
}
Ellipse(pixels, new Rectangle(20, 20, 60, 60));
FillEllipse(pixels, new Rectangle(40, 40, 20, 20));
Any help would be greatly appreciated.
Something like this should do the trick
public class EllipseDrawer
{
private static PointF GetEllipsePointFromX(float x, float a, float b)
{
//(x/a)^2 + (y/b)^2 = 1
//(y/b)^2 = 1 - (x/a)^2
//y/b = -sqrt(1 - (x/a)^2) --Neg root for upper portion of the plane
//y = b*-sqrt(1 - (x/a)^2)
return new PointF(x, b * -(float)Math.Sqrt(1 - (x * x / a / a)));
}
public static void Ellipse(bool[,] pixels, Rectangle area)
{
DrawEllipse(pixels, area, false);
}
public static void FillEllipse(bool[,] pixels, Rectangle area)
{
DrawEllipse(pixels, area, true);
}
private static void DrawEllipse(bool[,] pixels, Rectangle area, bool fill)
{
// Get the size of the matrix
var matrixWidth = pixels.GetLength(0);
var matrixHeight = pixels.GetLength(1);
var offsetY = area.Top;
var offsetX = area.Left;
// Figure out how big the ellipse is
var ellipseWidth = (float)area.Width;
var ellipseHeight = (float)area.Height;
// Figure out the radiuses of the ellipses
var radiusX = ellipseWidth / 2;
var radiusY = ellipseHeight / 2;
//Keep track of the previous y position
var prevY = 0;
var firstRun = true;
// Loop through the points in the matrix
for (var x = 0; x <= radiusX; ++x)
{
var xPos = x + offsetX;
var rxPos = (int)ellipseWidth - x - 1 + offsetX;
if (xPos < 0 || rxPos < xPos || xPos >= matrixWidth)
{
continue;
}
var pointOnEllipseBoundCorrespondingToXMatrixPosition = GetEllipsePointFromX(x - radiusX, radiusX, radiusY);
var y = (int) Math.Floor(pointOnEllipseBoundCorrespondingToXMatrixPosition.Y + (int)radiusY);
var yPos = y + offsetY;
var ryPos = (int)ellipseHeight - y - 1 + offsetY;
if (yPos >= 0)
{
if (xPos > -1 && xPos < matrixWidth && yPos > -1 && yPos < matrixHeight)
{
pixels[xPos, yPos] = true;
}
if(xPos > -1 && xPos < matrixWidth && ryPos > -1 && ryPos < matrixHeight)
{
pixels[xPos, ryPos] = true;
}
if (rxPos > -1 && rxPos < matrixWidth)
{
if (yPos > -1 && yPos < matrixHeight)
{
pixels[rxPos, yPos] = true;
}
if (ryPos > -1 && ryPos < matrixHeight)
{
pixels[rxPos, ryPos] = true;
}
}
}
//While there's a >1 jump in y, fill in the gap (assumes that this is not the first time we've tracked y, x != 0)
for (var j = prevY - 1; !firstRun && j > y - 1 && y > 0; --j)
{
var jPos = j + offsetY;
var rjPos = (int)ellipseHeight - j - 1 + offsetY;
if(jPos == rjPos - 1)
{
continue;
}
if(jPos > -1 && jPos < matrixHeight)
{
pixels[xPos, jPos] = true;
}
if(rjPos > -1 && rjPos < matrixHeight)
{
pixels[xPos, rjPos] = true;
}
if (rxPos > -1 && rxPos < matrixWidth)
{
if(jPos > -1 && jPos < matrixHeight)
{
pixels[rxPos, jPos] = true;
}
if(rjPos > -1 && rjPos < matrixHeight)
{
pixels[rxPos, rjPos] = true;
}
}
}
firstRun = false;
prevY = y;
var countTarget = radiusY - y;
for (var count = 0; fill && count < countTarget; ++count)
{
++yPos;
--ryPos;
// Set all four points in the matrix we just learned about
// also, make the indication that for the rest of this row, we need to fill the body of the ellipse
if(yPos > -1 && yPos < matrixHeight)
{
pixels[xPos, yPos] = true;
}
if(ryPos > -1 && ryPos < matrixHeight)
{
pixels[xPos, ryPos] = true;
}
if (rxPos > -1 && rxPos < matrixWidth)
{
if(yPos > -1 && yPos < matrixHeight)
{
pixels[rxPos, yPos] = true;
}
if(ryPos > -1 && ryPos < matrixHeight)
{
pixels[rxPos, ryPos] = true;
}
}
}
}
}
}
Although there already seems to be a perfectly valid answer with source code and all to this question, I just want to point out that the WriteableBitmapEx project also contains a lot of efficient source code for drawing and filling different polygon types (such as ellipses) in so-called WriteableBitmap objects.
This code can easily be adapted to the general scenario where a 2D-array (or 1D representation of a 2D-array) should be rendered in different ways.
For the ellipse case, pay special attention to the DrawEllipse... methods in the WriteableBitmapShapeExtensions.cs file and FillEllipse... methods in the WriteableBitmapFillExtensions.cs file, everything located in the trunk/Source/WriteableBitmapEx sub-folder.
This more applies to all languages in general, and I'm not sure why you're looking for things like this in particular rather than using a pre-existing graphics library (homework?), but for drawing an ellipse, I would suggest using the midpoint line drawing algorithm which can be adapted to an ellipse (also to a circle):
http://en.wikipedia.org/wiki/Midpoint_circle_algorithm
I'm not sure I fully agree that it's a generalisation of Bresenham's algorithm (certainly we were taught that Bresenham's and the Midpoint algorithm are different but proved to produce identical results), but that page should give you a start on it. See the link to the paper near the bottom for an algorithm specific to ellipses.
As for filling the ellipse, I'd say your best bet is to take a scanline approach - look at each row in turn, work out which pixels the lines on the left and right are at, and then fill every pixel inbetween.
The simplest thing to do would do is iterate over each element of your matrix, and check whether some ellipse equation evaluates to true
taken from http://en.wikipedia.org/wiki/Ellipse
What I would start with is something resembling
bool[,] pixels = new bool[100, 100];
double a = 30;
double b = 20;
for (int i = 0; i < 100; i++)
for (int j = 0; j < 100; j++ )
{
double x = i-50;
double y = j-50;
pixels[i, j] = (x / a) * (x / a) + (y / b) * (y / b) > 1;
}
and if your elipse is in reverse, than just change the > to <
For a hollow one, you can check whether the difference between (x / a) * (x / a) + (y / b) * (y / b) and 1 is within a certain threshold. If you just change the inequality to an equation, it will probably miss some pixels.
Now, I haven't actually tested this fully, so I don't know if the equation being applied correctly, but I just want to illustrate the concept.
Basically I'm creating a forest fire program that depends on the wind / dryness of the surround elements. I have an array var Trees [,] that is 20 x 20. The middle square is set "on fire". This is what needs to be done once you click button1: Evaluate each square around the one that is set on fire to determine the probability for the others to catch fire.
Color[,] map = new Color[WIDTH, HEIGHT];
for (int x = 0; x < WIDTH; x++)
for (int y = 0; y < HEIGHT; y++)
{
if (x == WIDTH / 2 && y == HEIGHT / 2)
map[x, y] = Color.Red;
else
map[x, y] = Color.Green;
}
fireBox1.box = map;
This is the 20 x 20 array that I have setup with the middle square set on fire. I just have no idea how to get the squares (array elements) around the one that is currently on fire.
You can start with a simple loop.
for (int i = 0; i < 20; i++)
{
for (int j = 0; j < 20; j++)
{
var tree = Trees[i, j];
// ...
}
}
After you have built your matrix the center should look like this.
[G][G][G]
[G][R][G]
[G][G][G]
Then we can loop through only the points that touch the center point.
int centerX = 9;
int centerY = 9;
int beginX = centerX - 1;
int endX = centerX + 1;
int beginY = centerY - 1;
int endY = centerY + 1;
for (int y = beginY; y <= endY; y++)
{
for (int x = beginX ; x <= endX; x++)
{
//Skip the center
if (x == centerX && y == centerY)
continue;
// Calculate the chance of catching on fire.
if (IsWindyPoint(x, y) || IsDryPoint(x, y))
map[x, y] = Color.Yellow;
}
}
So assuming we have wind blowing east we should see this as the matrix.
[G][G][G]
[G][R][Y]
[G][G][G]
And eventually it will expand out like this.
[G][G][G][G]
[G][G][Y][Y]
[G][R][R][Y]
[G][G][Y][Y]
[G][G][G][G]